Generating forward Euler method in numerical methods
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In the following example I was able to use Adams Bashforth Method of order $r$ and in this case when $r=2$. I will show the details of this below to show how I executed it. But my question is how would I execute it using $r=1$ which would give the forward Euler method? Hopefully my details below will help someone solve this problem, thanks!
$$u_{n+2} = u_{n+1}+Delta t(c_0f(u_n)+c_1f(u_{n+1}))$$
Here $$P_1(t) = frac{t-t_n}{t_{n+1}-t_n}f(u_{n+1})+frac{t-t_{n+1}}{t_n-t_{n+1}}f(u_n)$$
and these denominators are $Delta t$ and $-Delta t$ respecitively.
Therefore,
$$int^{t_{n+2}}_{t_{n+1}}P_1(tau)dtau = int^{t_{n+2}}_{t_{n+1}}left( frac{tau - t_n}{Delta t}f(u_{n+1})-frac{tau -t_{n+1}}{Delta t}f(u_n) right)dtau = frac{3}{2}Delta t f(u_{n+1})-frac{1}{2}Delta f(u_n)$$
Thus $$u_{n+2} = u_{n+1} + Delta t left( frac{3}{2}f(u_{n+1}) - frac{1}{2} f(u_n)right)$$
which is the adam bashford of order $2$
linear-algebra numerical-methods
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In the following example I was able to use Adams Bashforth Method of order $r$ and in this case when $r=2$. I will show the details of this below to show how I executed it. But my question is how would I execute it using $r=1$ which would give the forward Euler method? Hopefully my details below will help someone solve this problem, thanks!
$$u_{n+2} = u_{n+1}+Delta t(c_0f(u_n)+c_1f(u_{n+1}))$$
Here $$P_1(t) = frac{t-t_n}{t_{n+1}-t_n}f(u_{n+1})+frac{t-t_{n+1}}{t_n-t_{n+1}}f(u_n)$$
and these denominators are $Delta t$ and $-Delta t$ respecitively.
Therefore,
$$int^{t_{n+2}}_{t_{n+1}}P_1(tau)dtau = int^{t_{n+2}}_{t_{n+1}}left( frac{tau - t_n}{Delta t}f(u_{n+1})-frac{tau -t_{n+1}}{Delta t}f(u_n) right)dtau = frac{3}{2}Delta t f(u_{n+1})-frac{1}{2}Delta f(u_n)$$
Thus $$u_{n+2} = u_{n+1} + Delta t left( frac{3}{2}f(u_{n+1}) - frac{1}{2} f(u_n)right)$$
which is the adam bashford of order $2$
linear-algebra numerical-methods
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
In the following example I was able to use Adams Bashforth Method of order $r$ and in this case when $r=2$. I will show the details of this below to show how I executed it. But my question is how would I execute it using $r=1$ which would give the forward Euler method? Hopefully my details below will help someone solve this problem, thanks!
$$u_{n+2} = u_{n+1}+Delta t(c_0f(u_n)+c_1f(u_{n+1}))$$
Here $$P_1(t) = frac{t-t_n}{t_{n+1}-t_n}f(u_{n+1})+frac{t-t_{n+1}}{t_n-t_{n+1}}f(u_n)$$
and these denominators are $Delta t$ and $-Delta t$ respecitively.
Therefore,
$$int^{t_{n+2}}_{t_{n+1}}P_1(tau)dtau = int^{t_{n+2}}_{t_{n+1}}left( frac{tau - t_n}{Delta t}f(u_{n+1})-frac{tau -t_{n+1}}{Delta t}f(u_n) right)dtau = frac{3}{2}Delta t f(u_{n+1})-frac{1}{2}Delta f(u_n)$$
Thus $$u_{n+2} = u_{n+1} + Delta t left( frac{3}{2}f(u_{n+1}) - frac{1}{2} f(u_n)right)$$
which is the adam bashford of order $2$
linear-algebra numerical-methods
In the following example I was able to use Adams Bashforth Method of order $r$ and in this case when $r=2$. I will show the details of this below to show how I executed it. But my question is how would I execute it using $r=1$ which would give the forward Euler method? Hopefully my details below will help someone solve this problem, thanks!
$$u_{n+2} = u_{n+1}+Delta t(c_0f(u_n)+c_1f(u_{n+1}))$$
Here $$P_1(t) = frac{t-t_n}{t_{n+1}-t_n}f(u_{n+1})+frac{t-t_{n+1}}{t_n-t_{n+1}}f(u_n)$$
and these denominators are $Delta t$ and $-Delta t$ respecitively.
Therefore,
$$int^{t_{n+2}}_{t_{n+1}}P_1(tau)dtau = int^{t_{n+2}}_{t_{n+1}}left( frac{tau - t_n}{Delta t}f(u_{n+1})-frac{tau -t_{n+1}}{Delta t}f(u_n) right)dtau = frac{3}{2}Delta t f(u_{n+1})-frac{1}{2}Delta f(u_n)$$
Thus $$u_{n+2} = u_{n+1} + Delta t left( frac{3}{2}f(u_{n+1}) - frac{1}{2} f(u_n)right)$$
which is the adam bashford of order $2$
linear-algebra numerical-methods
linear-algebra numerical-methods
asked Dec 6 at 1:05
fr14
38318
38318
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