why i can't find critical points for this function
0
$begingroup$
$(2x-4)^{100}$ I tried to get the derivative of this function which is equal to $200(2x-4)^{99}$ now I need to get the critical points so when I set the function = 0 I can't get a value how to solve this, please?
calculus derivatives
asked Dec 15 '18 at 14:25
faisalfaisal
274
$endgroup$
add a comment |
0
$begingroup$
$(2x-4)^{100}$ I tried to get the derivative of this function which is equal to $200(2x-4)^{99}$ now I need to get the critical points so when I set the function = 0 I can't get a value how to solve this, please?
calculus derivatives
asked Dec 15 '18 at 14:25
faisalfaisal
274
$endgroup$
4
$begingroup$
Where is the difficulty? If $z^{99}=0$ then $z=0$.
$endgroup$
– lulu
Dec 15 '18 at 14:26
1
$begingroup$
so there is only one critical point right ?
$endgroup$
– faisal
Dec 15 '18 at 14:40
$begingroup$
Right. $quad ;;$
$endgroup$
– lulu
Dec 15 '18 at 14:50
$begingroup$
$200(2x-4)^{99}=0$ then $2x-4=0$ so $x=2$.
$endgroup$
– yavar
Dec 15 '18 at 15:28
add a comment |
0
0
0
$begingroup$
$(2x-4)^{100}$ I tried to get the derivative of this function which is equal to $200(2x-4)^{99}$ now I need to get the critical points so when I set the function = 0 I can't get a value how to solve this, please?
calculus derivatives
asked Dec 15 '18 at 14:25
faisalfaisal
274
$endgroup$
$(2x-4)^{100}$ I tried to get the derivative of this function which is equal to $200(2x-4)^{99}$ now I need to get the critical points so when I set the function = 0 I can't get a value how to solve this, please?
calculus derivatives
calculus derivatives
asked Dec 15 '18 at 14:25
faisalfaisal
274
asked Dec 15 '18 at 14:25
faisalfaisal
274
asked Dec 15 '18 at 14:25
faisalfaisal
274
asked Dec 15 '18 at 14:25
faisalfaisal
274
asked Dec 15 '18 at 14:25
faisalfaisal
274
274
4
$begingroup$
Where is the difficulty? If $z^{99}=0$ then $z=0$.
$endgroup$
– lulu
Dec 15 '18 at 14:26
1
$begingroup$
so there is only one critical point right ?
$endgroup$
– faisal
Dec 15 '18 at 14:40
$begingroup$
Right. $quad ;;$
$endgroup$
– lulu
Dec 15 '18 at 14:50
$begingroup$
$200(2x-4)^{99}=0$ then $2x-4=0$ so $x=2$.
$endgroup$
– yavar
Dec 15 '18 at 15:28
add a comment |
4
$begingroup$
Where is the difficulty? If $z^{99}=0$ then $z=0$.
$endgroup$
– lulu
Dec 15 '18 at 14:26
1
$begingroup$
so there is only one critical point right ?
$endgroup$
– faisal
Dec 15 '18 at 14:40
$begingroup$
Right. $quad ;;$
$endgroup$
– lulu
Dec 15 '18 at 14:50
$begingroup$
$200(2x-4)^{99}=0$ then $2x-4=0$ so $x=2$.
$endgroup$
– yavar
Dec 15 '18 at 15:28
4
4
$begingroup$
Where is the difficulty? If $z^{99}=0$ then $z=0$.
$endgroup$
– lulu
Dec 15 '18 at 14:26
$begingroup$
Where is the difficulty? If $z^{99}=0$ then $z=0$.
$endgroup$
– lulu
Dec 15 '18 at 14:26
1
1
$begingroup$
so there is only one critical point right ?
$endgroup$
– faisal
Dec 15 '18 at 14:40
$begingroup$
so there is only one critical point right ?
$endgroup$
– faisal
Dec 15 '18 at 14:40
$begingroup$
Right. $quad ;;$
$endgroup$
– lulu
Dec 15 '18 at 14:50
$begingroup$
Right. $quad ;;$
$endgroup$
– lulu
Dec 15 '18 at 14:50
$begingroup$
$200(2x-4)^{99}=0$ then $2x-4=0$ so $x=2$.
$endgroup$
– yavar
Dec 15 '18 at 15:28
$begingroup$
$200(2x-4)^{99}=0$ then $2x-4=0$ so $x=2$.
$endgroup$
– yavar
Dec 15 '18 at 15:28
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3041542%2fwhy-i-cant-find-critical-points-for-this-function%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
draft saved
draft discarded
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3041542%2fwhy-i-cant-find-critical-points-for-this-function%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
4
$begingroup$
Where is the difficulty? If $z^{99}=0$ then $z=0$.
$endgroup$
– lulu
Dec 15 '18 at 14:26
1
$begingroup$
so there is only one critical point right ?
$endgroup$
– faisal
Dec 15 '18 at 14:40
$begingroup$
Right. $quad ;;$
$endgroup$
– lulu
Dec 15 '18 at 14:50
$begingroup$
$200(2x-4)^{99}=0$ then $2x-4=0$ so $x=2$.
$endgroup$
– yavar
Dec 15 '18 at 15:28