Given a map $X to text{GL}_2(mathbb{R})$ how do I determine a flat connection on this Riemann surface?












2












$begingroup$


I need help determining the Euler class of this vector bundle $phi:Eto X$.



The base space is the torus $X = mathbb{R}^2/mathbb{Z}^2$ and the fiber over each point, $f^{-1}(x) simeq mathbb{R}^2$. So it is a vector bundle of rank $2$.



The fundamental group of this torus is the $pi_0(X) simeq mathbb{Z}^2$ and consider the map from $pi_0(X) to text{GL}_2(mathbb{R})$




  • $(1,0) to frac{1}{sqrt{5}}left[ begin{array}{rr} 2 & -1 \ 1 & 2 end{array} right]$

  • $(0,1) to ;;,frac{1}{5}left[ begin{array}{rr} 3 & -4 \ 4 & 3 end{array} right]$


These are commuting matrices so this is a well-defined map. There should be a flat vector bundle with these properties.



How can I find a chart for this vector bundles? Can I just take a chart from the torus and lift it?



What is a formula for the flat conneciton $nabla$ ?










share|cite|improve this question









$endgroup$

















    2












    $begingroup$


    I need help determining the Euler class of this vector bundle $phi:Eto X$.



    The base space is the torus $X = mathbb{R}^2/mathbb{Z}^2$ and the fiber over each point, $f^{-1}(x) simeq mathbb{R}^2$. So it is a vector bundle of rank $2$.



    The fundamental group of this torus is the $pi_0(X) simeq mathbb{Z}^2$ and consider the map from $pi_0(X) to text{GL}_2(mathbb{R})$




    • $(1,0) to frac{1}{sqrt{5}}left[ begin{array}{rr} 2 & -1 \ 1 & 2 end{array} right]$

    • $(0,1) to ;;,frac{1}{5}left[ begin{array}{rr} 3 & -4 \ 4 & 3 end{array} right]$


    These are commuting matrices so this is a well-defined map. There should be a flat vector bundle with these properties.



    How can I find a chart for this vector bundles? Can I just take a chart from the torus and lift it?



    What is a formula for the flat conneciton $nabla$ ?










    share|cite|improve this question









    $endgroup$















      2












      2








      2





      $begingroup$


      I need help determining the Euler class of this vector bundle $phi:Eto X$.



      The base space is the torus $X = mathbb{R}^2/mathbb{Z}^2$ and the fiber over each point, $f^{-1}(x) simeq mathbb{R}^2$. So it is a vector bundle of rank $2$.



      The fundamental group of this torus is the $pi_0(X) simeq mathbb{Z}^2$ and consider the map from $pi_0(X) to text{GL}_2(mathbb{R})$




      • $(1,0) to frac{1}{sqrt{5}}left[ begin{array}{rr} 2 & -1 \ 1 & 2 end{array} right]$

      • $(0,1) to ;;,frac{1}{5}left[ begin{array}{rr} 3 & -4 \ 4 & 3 end{array} right]$


      These are commuting matrices so this is a well-defined map. There should be a flat vector bundle with these properties.



      How can I find a chart for this vector bundles? Can I just take a chart from the torus and lift it?



      What is a formula for the flat conneciton $nabla$ ?










      share|cite|improve this question









      $endgroup$




      I need help determining the Euler class of this vector bundle $phi:Eto X$.



      The base space is the torus $X = mathbb{R}^2/mathbb{Z}^2$ and the fiber over each point, $f^{-1}(x) simeq mathbb{R}^2$. So it is a vector bundle of rank $2$.



      The fundamental group of this torus is the $pi_0(X) simeq mathbb{Z}^2$ and consider the map from $pi_0(X) to text{GL}_2(mathbb{R})$




      • $(1,0) to frac{1}{sqrt{5}}left[ begin{array}{rr} 2 & -1 \ 1 & 2 end{array} right]$

      • $(0,1) to ;;,frac{1}{5}left[ begin{array}{rr} 3 & -4 \ 4 & 3 end{array} right]$


      These are commuting matrices so this is a well-defined map. There should be a flat vector bundle with these properties.



      How can I find a chart for this vector bundles? Can I just take a chart from the torus and lift it?



      What is a formula for the flat conneciton $nabla$ ?







      vector-bundles connections k-theory






      share|cite|improve this question













      share|cite|improve this question











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      asked Dec 22 '18 at 4:38









      cactus314cactus314

      15.4k42269




      15.4k42269






















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