double sequence












0












$begingroup$


Simple question, rather linguistic one.



Having two sequence
begin{align*}
R_1&={a,b,c,d,e,ldots}\
R_2&={a,a,b,b,c,c,d,d,e,e,ldots}
end{align*}

I want to say (mathematically corect): $R_2$ is doubled(?) sequence of $R_1$.



Any better, more informative, ideas?
Of course I will also give this sequences in my work.










share|cite|improve this question









$endgroup$

















    0












    $begingroup$


    Simple question, rather linguistic one.



    Having two sequence
    begin{align*}
    R_1&={a,b,c,d,e,ldots}\
    R_2&={a,a,b,b,c,c,d,d,e,e,ldots}
    end{align*}

    I want to say (mathematically corect): $R_2$ is doubled(?) sequence of $R_1$.



    Any better, more informative, ideas?
    Of course I will also give this sequences in my work.










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      Simple question, rather linguistic one.



      Having two sequence
      begin{align*}
      R_1&={a,b,c,d,e,ldots}\
      R_2&={a,a,b,b,c,c,d,d,e,e,ldots}
      end{align*}

      I want to say (mathematically corect): $R_2$ is doubled(?) sequence of $R_1$.



      Any better, more informative, ideas?
      Of course I will also give this sequences in my work.










      share|cite|improve this question









      $endgroup$




      Simple question, rather linguistic one.



      Having two sequence
      begin{align*}
      R_1&={a,b,c,d,e,ldots}\
      R_2&={a,a,b,b,c,c,d,d,e,e,ldots}
      end{align*}

      I want to say (mathematically corect): $R_2$ is doubled(?) sequence of $R_1$.



      Any better, more informative, ideas?
      Of course I will also give this sequences in my work.







      sequences-and-series






      share|cite|improve this question













      share|cite|improve this question











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      asked Dec 22 '18 at 15:27









      EnderEnder

      807




      807






















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          $begingroup$

          I expect this not to be a common definition, so it probably has no agreed upon name. This means you can pick any name you want, as long as you define it explicitly. Do try to come up with a good descriptive name though. Naming it the doubled sequence seems a bit too ambiguous to me. Maybe call it the element repetitor? Or the double copy?






          share|cite|improve this answer









          $endgroup$





















            0












            $begingroup$

            Let's call the first sequence $(a_n)_n$. If I were you, I would introduce the "doubled sequence" of $(a_n)_n$ as the sequence $(b_n)_n$ defined by
            $$
            b_{2n} = b_{2n-1} := a_n.
            $$

            After you've defined what it means to be a "doubled sequence" then there's no harm in using the term even if it's not a commonly used term.






            share|cite|improve this answer









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              2 Answers
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              2 Answers
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              0












              $begingroup$

              I expect this not to be a common definition, so it probably has no agreed upon name. This means you can pick any name you want, as long as you define it explicitly. Do try to come up with a good descriptive name though. Naming it the doubled sequence seems a bit too ambiguous to me. Maybe call it the element repetitor? Or the double copy?






              share|cite|improve this answer









              $endgroup$


















                0












                $begingroup$

                I expect this not to be a common definition, so it probably has no agreed upon name. This means you can pick any name you want, as long as you define it explicitly. Do try to come up with a good descriptive name though. Naming it the doubled sequence seems a bit too ambiguous to me. Maybe call it the element repetitor? Or the double copy?






                share|cite|improve this answer









                $endgroup$
















                  0












                  0








                  0





                  $begingroup$

                  I expect this not to be a common definition, so it probably has no agreed upon name. This means you can pick any name you want, as long as you define it explicitly. Do try to come up with a good descriptive name though. Naming it the doubled sequence seems a bit too ambiguous to me. Maybe call it the element repetitor? Or the double copy?






                  share|cite|improve this answer









                  $endgroup$



                  I expect this not to be a common definition, so it probably has no agreed upon name. This means you can pick any name you want, as long as you define it explicitly. Do try to come up with a good descriptive name though. Naming it the doubled sequence seems a bit too ambiguous to me. Maybe call it the element repetitor? Or the double copy?







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Dec 22 '18 at 15:51









                  SmileyCraftSmileyCraft

                  3,566517




                  3,566517























                      0












                      $begingroup$

                      Let's call the first sequence $(a_n)_n$. If I were you, I would introduce the "doubled sequence" of $(a_n)_n$ as the sequence $(b_n)_n$ defined by
                      $$
                      b_{2n} = b_{2n-1} := a_n.
                      $$

                      After you've defined what it means to be a "doubled sequence" then there's no harm in using the term even if it's not a commonly used term.






                      share|cite|improve this answer









                      $endgroup$


















                        0












                        $begingroup$

                        Let's call the first sequence $(a_n)_n$. If I were you, I would introduce the "doubled sequence" of $(a_n)_n$ as the sequence $(b_n)_n$ defined by
                        $$
                        b_{2n} = b_{2n-1} := a_n.
                        $$

                        After you've defined what it means to be a "doubled sequence" then there's no harm in using the term even if it's not a commonly used term.






                        share|cite|improve this answer









                        $endgroup$
















                          0












                          0








                          0





                          $begingroup$

                          Let's call the first sequence $(a_n)_n$. If I were you, I would introduce the "doubled sequence" of $(a_n)_n$ as the sequence $(b_n)_n$ defined by
                          $$
                          b_{2n} = b_{2n-1} := a_n.
                          $$

                          After you've defined what it means to be a "doubled sequence" then there's no harm in using the term even if it's not a commonly used term.






                          share|cite|improve this answer









                          $endgroup$



                          Let's call the first sequence $(a_n)_n$. If I were you, I would introduce the "doubled sequence" of $(a_n)_n$ as the sequence $(b_n)_n$ defined by
                          $$
                          b_{2n} = b_{2n-1} := a_n.
                          $$

                          After you've defined what it means to be a "doubled sequence" then there's no harm in using the term even if it's not a commonly used term.







                          share|cite|improve this answer












                          share|cite|improve this answer



                          share|cite|improve this answer










                          answered Dec 22 '18 at 16:11









                          BigbearZzzBigbearZzz

                          8,62921652




                          8,62921652






























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