how to prove the matrix A^(n) equals stuff [closed]












-1














how to prove that A^(n) = U(n)A + V(n)I



the matrices I = (1 1 1)
(1 1 1)
(1 1 1)
the discription is in here please helpme out



I tried to find this in order to figuer out the equation of U(n) and V(n) you can see in here










share|cite|improve this question















closed as off-topic by Michael Seifert, Xander Henderson, Leucippus, user10354138, Brahadeesh Dec 12 at 8:30


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Michael Seifert, Xander Henderson, Leucippus, user10354138, Brahadeesh

If this question can be reworded to fit the rules in the help center, please edit the question.













  • Did you try to diagonalize $A$?
    – Botond
    Dec 7 at 15:07










  • sorry I didn't get it .. could U please give me more details
    – plus plus
    Dec 7 at 15:08










  • Can you calculate the eigenvectors and eigenvalues of $A$?
    – Botond
    Dec 7 at 15:11










  • actually not ... because we didnt talk about them in classes ..we are in a very low level yet .. but its a homework and we are not supposed to use stuff we didnt talk about it yet ... please have a look on the post again I added sth ..
    – plus plus
    Dec 7 at 15:15










  • Shouldn't $I$ be the identity matrix instead of the full $1$ matrix?
    – Botond
    Dec 7 at 15:25
















-1














how to prove that A^(n) = U(n)A + V(n)I



the matrices I = (1 1 1)
(1 1 1)
(1 1 1)
the discription is in here please helpme out



I tried to find this in order to figuer out the equation of U(n) and V(n) you can see in here










share|cite|improve this question















closed as off-topic by Michael Seifert, Xander Henderson, Leucippus, user10354138, Brahadeesh Dec 12 at 8:30


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Michael Seifert, Xander Henderson, Leucippus, user10354138, Brahadeesh

If this question can be reworded to fit the rules in the help center, please edit the question.













  • Did you try to diagonalize $A$?
    – Botond
    Dec 7 at 15:07










  • sorry I didn't get it .. could U please give me more details
    – plus plus
    Dec 7 at 15:08










  • Can you calculate the eigenvectors and eigenvalues of $A$?
    – Botond
    Dec 7 at 15:11










  • actually not ... because we didnt talk about them in classes ..we are in a very low level yet .. but its a homework and we are not supposed to use stuff we didnt talk about it yet ... please have a look on the post again I added sth ..
    – plus plus
    Dec 7 at 15:15










  • Shouldn't $I$ be the identity matrix instead of the full $1$ matrix?
    – Botond
    Dec 7 at 15:25














-1












-1








-1







how to prove that A^(n) = U(n)A + V(n)I



the matrices I = (1 1 1)
(1 1 1)
(1 1 1)
the discription is in here please helpme out



I tried to find this in order to figuer out the equation of U(n) and V(n) you can see in here










share|cite|improve this question















how to prove that A^(n) = U(n)A + V(n)I



the matrices I = (1 1 1)
(1 1 1)
(1 1 1)
the discription is in here please helpme out



I tried to find this in order to figuer out the equation of U(n) and V(n) you can see in here







matrices






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 7 at 15:12

























asked Dec 7 at 15:02









plus plus

34




34




closed as off-topic by Michael Seifert, Xander Henderson, Leucippus, user10354138, Brahadeesh Dec 12 at 8:30


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Michael Seifert, Xander Henderson, Leucippus, user10354138, Brahadeesh

If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by Michael Seifert, Xander Henderson, Leucippus, user10354138, Brahadeesh Dec 12 at 8:30


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Michael Seifert, Xander Henderson, Leucippus, user10354138, Brahadeesh

If this question can be reworded to fit the rules in the help center, please edit the question.












  • Did you try to diagonalize $A$?
    – Botond
    Dec 7 at 15:07










  • sorry I didn't get it .. could U please give me more details
    – plus plus
    Dec 7 at 15:08










  • Can you calculate the eigenvectors and eigenvalues of $A$?
    – Botond
    Dec 7 at 15:11










  • actually not ... because we didnt talk about them in classes ..we are in a very low level yet .. but its a homework and we are not supposed to use stuff we didnt talk about it yet ... please have a look on the post again I added sth ..
    – plus plus
    Dec 7 at 15:15










  • Shouldn't $I$ be the identity matrix instead of the full $1$ matrix?
    – Botond
    Dec 7 at 15:25


















  • Did you try to diagonalize $A$?
    – Botond
    Dec 7 at 15:07










  • sorry I didn't get it .. could U please give me more details
    – plus plus
    Dec 7 at 15:08










  • Can you calculate the eigenvectors and eigenvalues of $A$?
    – Botond
    Dec 7 at 15:11










  • actually not ... because we didnt talk about them in classes ..we are in a very low level yet .. but its a homework and we are not supposed to use stuff we didnt talk about it yet ... please have a look on the post again I added sth ..
    – plus plus
    Dec 7 at 15:15










  • Shouldn't $I$ be the identity matrix instead of the full $1$ matrix?
    – Botond
    Dec 7 at 15:25
















Did you try to diagonalize $A$?
– Botond
Dec 7 at 15:07




Did you try to diagonalize $A$?
– Botond
Dec 7 at 15:07












sorry I didn't get it .. could U please give me more details
– plus plus
Dec 7 at 15:08




sorry I didn't get it .. could U please give me more details
– plus plus
Dec 7 at 15:08












Can you calculate the eigenvectors and eigenvalues of $A$?
– Botond
Dec 7 at 15:11




Can you calculate the eigenvectors and eigenvalues of $A$?
– Botond
Dec 7 at 15:11












actually not ... because we didnt talk about them in classes ..we are in a very low level yet .. but its a homework and we are not supposed to use stuff we didnt talk about it yet ... please have a look on the post again I added sth ..
– plus plus
Dec 7 at 15:15




actually not ... because we didnt talk about them in classes ..we are in a very low level yet .. but its a homework and we are not supposed to use stuff we didnt talk about it yet ... please have a look on the post again I added sth ..
– plus plus
Dec 7 at 15:15












Shouldn't $I$ be the identity matrix instead of the full $1$ matrix?
– Botond
Dec 7 at 15:25




Shouldn't $I$ be the identity matrix instead of the full $1$ matrix?
– Botond
Dec 7 at 15:25










1 Answer
1






active

oldest

votes


















1














Let's use induction:

For $n=2$, I will leave it to you to prove that
$$A^2=3A-2I$$
Now let's suppose that it's true for $n$:
$$A^n=u_nA+v_nI$$
And now we can use induction:
$$begin{align}
A^{n+1}&=A^nA\
&=(u_nA+v_nI)A\
&=u_nA^2+v_nA\
&=u_n(3A-2I)+v_nA\
&=(3u_n+v_n)A-2u_nI
end{align}$$

Can you continue the work?






share|cite|improve this answer





















  • Yuup thanks very very much
    – plus plus
    Dec 7 at 15:56










  • sorry for bothering again but how can I find the dimension of the vector field E, where , E=vect (A^(k)) , k belongs to Z
    – plus plus
    Dec 10 at 17:02










  • @plusplus Next time please make a new question. What so you mean by $text{vec}(A^k)$? Is it a vector space with basis $A^1,A^2,...$?
    – Botond
    Dec 10 at 17:10










  • Actually I thought it would be easier to continue in the same question .. I'm really sorry next time I'll do it .. yes it is a vector space with basis A^1,A^2,.. but also with( I , A^(-1) , A^(-2) .....)
    – plus plus
    Dec 10 at 17:13










  • @plusplus It's fine. First of all, can you find a basis if $k in mathbb{N}$ only?
    – Botond
    Dec 10 at 17:15


















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














Let's use induction:

For $n=2$, I will leave it to you to prove that
$$A^2=3A-2I$$
Now let's suppose that it's true for $n$:
$$A^n=u_nA+v_nI$$
And now we can use induction:
$$begin{align}
A^{n+1}&=A^nA\
&=(u_nA+v_nI)A\
&=u_nA^2+v_nA\
&=u_n(3A-2I)+v_nA\
&=(3u_n+v_n)A-2u_nI
end{align}$$

Can you continue the work?






share|cite|improve this answer





















  • Yuup thanks very very much
    – plus plus
    Dec 7 at 15:56










  • sorry for bothering again but how can I find the dimension of the vector field E, where , E=vect (A^(k)) , k belongs to Z
    – plus plus
    Dec 10 at 17:02










  • @plusplus Next time please make a new question. What so you mean by $text{vec}(A^k)$? Is it a vector space with basis $A^1,A^2,...$?
    – Botond
    Dec 10 at 17:10










  • Actually I thought it would be easier to continue in the same question .. I'm really sorry next time I'll do it .. yes it is a vector space with basis A^1,A^2,.. but also with( I , A^(-1) , A^(-2) .....)
    – plus plus
    Dec 10 at 17:13










  • @plusplus It's fine. First of all, can you find a basis if $k in mathbb{N}$ only?
    – Botond
    Dec 10 at 17:15
















1














Let's use induction:

For $n=2$, I will leave it to you to prove that
$$A^2=3A-2I$$
Now let's suppose that it's true for $n$:
$$A^n=u_nA+v_nI$$
And now we can use induction:
$$begin{align}
A^{n+1}&=A^nA\
&=(u_nA+v_nI)A\
&=u_nA^2+v_nA\
&=u_n(3A-2I)+v_nA\
&=(3u_n+v_n)A-2u_nI
end{align}$$

Can you continue the work?






share|cite|improve this answer





















  • Yuup thanks very very much
    – plus plus
    Dec 7 at 15:56










  • sorry for bothering again but how can I find the dimension of the vector field E, where , E=vect (A^(k)) , k belongs to Z
    – plus plus
    Dec 10 at 17:02










  • @plusplus Next time please make a new question. What so you mean by $text{vec}(A^k)$? Is it a vector space with basis $A^1,A^2,...$?
    – Botond
    Dec 10 at 17:10










  • Actually I thought it would be easier to continue in the same question .. I'm really sorry next time I'll do it .. yes it is a vector space with basis A^1,A^2,.. but also with( I , A^(-1) , A^(-2) .....)
    – plus plus
    Dec 10 at 17:13










  • @plusplus It's fine. First of all, can you find a basis if $k in mathbb{N}$ only?
    – Botond
    Dec 10 at 17:15














1












1








1






Let's use induction:

For $n=2$, I will leave it to you to prove that
$$A^2=3A-2I$$
Now let's suppose that it's true for $n$:
$$A^n=u_nA+v_nI$$
And now we can use induction:
$$begin{align}
A^{n+1}&=A^nA\
&=(u_nA+v_nI)A\
&=u_nA^2+v_nA\
&=u_n(3A-2I)+v_nA\
&=(3u_n+v_n)A-2u_nI
end{align}$$

Can you continue the work?






share|cite|improve this answer












Let's use induction:

For $n=2$, I will leave it to you to prove that
$$A^2=3A-2I$$
Now let's suppose that it's true for $n$:
$$A^n=u_nA+v_nI$$
And now we can use induction:
$$begin{align}
A^{n+1}&=A^nA\
&=(u_nA+v_nI)A\
&=u_nA^2+v_nA\
&=u_n(3A-2I)+v_nA\
&=(3u_n+v_n)A-2u_nI
end{align}$$

Can you continue the work?







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Dec 7 at 15:31









Botond

5,4382732




5,4382732












  • Yuup thanks very very much
    – plus plus
    Dec 7 at 15:56










  • sorry for bothering again but how can I find the dimension of the vector field E, where , E=vect (A^(k)) , k belongs to Z
    – plus plus
    Dec 10 at 17:02










  • @plusplus Next time please make a new question. What so you mean by $text{vec}(A^k)$? Is it a vector space with basis $A^1,A^2,...$?
    – Botond
    Dec 10 at 17:10










  • Actually I thought it would be easier to continue in the same question .. I'm really sorry next time I'll do it .. yes it is a vector space with basis A^1,A^2,.. but also with( I , A^(-1) , A^(-2) .....)
    – plus plus
    Dec 10 at 17:13










  • @plusplus It's fine. First of all, can you find a basis if $k in mathbb{N}$ only?
    – Botond
    Dec 10 at 17:15


















  • Yuup thanks very very much
    – plus plus
    Dec 7 at 15:56










  • sorry for bothering again but how can I find the dimension of the vector field E, where , E=vect (A^(k)) , k belongs to Z
    – plus plus
    Dec 10 at 17:02










  • @plusplus Next time please make a new question. What so you mean by $text{vec}(A^k)$? Is it a vector space with basis $A^1,A^2,...$?
    – Botond
    Dec 10 at 17:10










  • Actually I thought it would be easier to continue in the same question .. I'm really sorry next time I'll do it .. yes it is a vector space with basis A^1,A^2,.. but also with( I , A^(-1) , A^(-2) .....)
    – plus plus
    Dec 10 at 17:13










  • @plusplus It's fine. First of all, can you find a basis if $k in mathbb{N}$ only?
    – Botond
    Dec 10 at 17:15
















Yuup thanks very very much
– plus plus
Dec 7 at 15:56




Yuup thanks very very much
– plus plus
Dec 7 at 15:56












sorry for bothering again but how can I find the dimension of the vector field E, where , E=vect (A^(k)) , k belongs to Z
– plus plus
Dec 10 at 17:02




sorry for bothering again but how can I find the dimension of the vector field E, where , E=vect (A^(k)) , k belongs to Z
– plus plus
Dec 10 at 17:02












@plusplus Next time please make a new question. What so you mean by $text{vec}(A^k)$? Is it a vector space with basis $A^1,A^2,...$?
– Botond
Dec 10 at 17:10




@plusplus Next time please make a new question. What so you mean by $text{vec}(A^k)$? Is it a vector space with basis $A^1,A^2,...$?
– Botond
Dec 10 at 17:10












Actually I thought it would be easier to continue in the same question .. I'm really sorry next time I'll do it .. yes it is a vector space with basis A^1,A^2,.. but also with( I , A^(-1) , A^(-2) .....)
– plus plus
Dec 10 at 17:13




Actually I thought it would be easier to continue in the same question .. I'm really sorry next time I'll do it .. yes it is a vector space with basis A^1,A^2,.. but also with( I , A^(-1) , A^(-2) .....)
– plus plus
Dec 10 at 17:13












@plusplus It's fine. First of all, can you find a basis if $k in mathbb{N}$ only?
– Botond
Dec 10 at 17:15




@plusplus It's fine. First of all, can you find a basis if $k in mathbb{N}$ only?
– Botond
Dec 10 at 17:15



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