Derivation of curl in two dimension












1












$begingroup$


Let $f(x,y) = u(x,y) e_x + v(x,y) e_y$ be a vector valued function on $mathbb{R}^2$. I'm not sure how the formula is determined.



I take this definition of curl:




The curl at point $P$ is the (directed) anglular velocity a "infinitesemal" disc would rotate with, when it's center is aligned with $P$




From this, it's easy to see (by eg: treating it as torque) for a curve $gamma$ with enclosed area $A$, the torque experined by it is $frac{1}{|A|} oint_{gamma} f cdot dS $ where the integral is taken along the surface of the curve.



Now, we need to prove that $displaystyle lim_{|A| rightarrow 0} frac{1}{|A|} oint_{gamma} f cdot dS = frac{partial u}{partial x} - frac{partial v}{partial y}$ for any curve $gamma$, but how do you do that ?



I'm stuck even for the very simple case when $gamma$ is a circle, and I'm finding it very counterintuive why would the limit even be the same and not depending on the shape of $gamma$.










share|cite|improve this question









$endgroup$

















    1












    $begingroup$


    Let $f(x,y) = u(x,y) e_x + v(x,y) e_y$ be a vector valued function on $mathbb{R}^2$. I'm not sure how the formula is determined.



    I take this definition of curl:




    The curl at point $P$ is the (directed) anglular velocity a "infinitesemal" disc would rotate with, when it's center is aligned with $P$




    From this, it's easy to see (by eg: treating it as torque) for a curve $gamma$ with enclosed area $A$, the torque experined by it is $frac{1}{|A|} oint_{gamma} f cdot dS $ where the integral is taken along the surface of the curve.



    Now, we need to prove that $displaystyle lim_{|A| rightarrow 0} frac{1}{|A|} oint_{gamma} f cdot dS = frac{partial u}{partial x} - frac{partial v}{partial y}$ for any curve $gamma$, but how do you do that ?



    I'm stuck even for the very simple case when $gamma$ is a circle, and I'm finding it very counterintuive why would the limit even be the same and not depending on the shape of $gamma$.










    share|cite|improve this question









    $endgroup$















      1












      1








      1





      $begingroup$


      Let $f(x,y) = u(x,y) e_x + v(x,y) e_y$ be a vector valued function on $mathbb{R}^2$. I'm not sure how the formula is determined.



      I take this definition of curl:




      The curl at point $P$ is the (directed) anglular velocity a "infinitesemal" disc would rotate with, when it's center is aligned with $P$




      From this, it's easy to see (by eg: treating it as torque) for a curve $gamma$ with enclosed area $A$, the torque experined by it is $frac{1}{|A|} oint_{gamma} f cdot dS $ where the integral is taken along the surface of the curve.



      Now, we need to prove that $displaystyle lim_{|A| rightarrow 0} frac{1}{|A|} oint_{gamma} f cdot dS = frac{partial u}{partial x} - frac{partial v}{partial y}$ for any curve $gamma$, but how do you do that ?



      I'm stuck even for the very simple case when $gamma$ is a circle, and I'm finding it very counterintuive why would the limit even be the same and not depending on the shape of $gamma$.










      share|cite|improve this question









      $endgroup$




      Let $f(x,y) = u(x,y) e_x + v(x,y) e_y$ be a vector valued function on $mathbb{R}^2$. I'm not sure how the formula is determined.



      I take this definition of curl:




      The curl at point $P$ is the (directed) anglular velocity a "infinitesemal" disc would rotate with, when it's center is aligned with $P$




      From this, it's easy to see (by eg: treating it as torque) for a curve $gamma$ with enclosed area $A$, the torque experined by it is $frac{1}{|A|} oint_{gamma} f cdot dS $ where the integral is taken along the surface of the curve.



      Now, we need to prove that $displaystyle lim_{|A| rightarrow 0} frac{1}{|A|} oint_{gamma} f cdot dS = frac{partial u}{partial x} - frac{partial v}{partial y}$ for any curve $gamma$, but how do you do that ?



      I'm stuck even for the very simple case when $gamma$ is a circle, and I'm finding it very counterintuive why would the limit even be the same and not depending on the shape of $gamma$.







      calculus multivariable-calculus curl






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      asked Jan 7 at 13:50









      alxchenalxchen

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