What is the limit of $frac{sin(5x)}{operatorname{tg}(3x)}$ when $x rightarrow pi$? [closed]











up vote
-3
down vote

favorite












How to solve this limit without applying L'Hospital's Rule?










share|cite|improve this question















closed as off-topic by José Carlos Santos, user302797, Brahadeesh, RRL, Lord_Farin Dec 4 at 17:58


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – José Carlos Santos, user302797, Brahadeesh, RRL, Lord_Farin

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 1




    Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    – José Carlos Santos
    Dec 4 at 16:00















up vote
-3
down vote

favorite












How to solve this limit without applying L'Hospital's Rule?










share|cite|improve this question















closed as off-topic by José Carlos Santos, user302797, Brahadeesh, RRL, Lord_Farin Dec 4 at 17:58


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – José Carlos Santos, user302797, Brahadeesh, RRL, Lord_Farin

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 1




    Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    – José Carlos Santos
    Dec 4 at 16:00













up vote
-3
down vote

favorite









up vote
-3
down vote

favorite











How to solve this limit without applying L'Hospital's Rule?










share|cite|improve this question















How to solve this limit without applying L'Hospital's Rule?







calculus






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 4 at 16:42









Bernard

117k637109




117k637109










asked Dec 4 at 16:00









Edgaras

1




1




closed as off-topic by José Carlos Santos, user302797, Brahadeesh, RRL, Lord_Farin Dec 4 at 17:58


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – José Carlos Santos, user302797, Brahadeesh, RRL, Lord_Farin

If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by José Carlos Santos, user302797, Brahadeesh, RRL, Lord_Farin Dec 4 at 17:58


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – José Carlos Santos, user302797, Brahadeesh, RRL, Lord_Farin

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 1




    Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    – José Carlos Santos
    Dec 4 at 16:00














  • 1




    Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    – José Carlos Santos
    Dec 4 at 16:00








1




1




Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
– José Carlos Santos
Dec 4 at 16:00




Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
– José Carlos Santos
Dec 4 at 16:00










2 Answers
2






active

oldest

votes

















up vote
1
down vote













Hint:



$pi-x=y$



$sin5x=sin5(pi-y)=?$



Now for $yne0$ $$dfrac{sin5y}{tan3y}=dfrac53cdotdfrac{dfrac{sin5y}{5y}}{dfrac{tan3y}{3y}}$$






share|cite|improve this answer




























    up vote
    0
    down vote













    Variant, with equivalents:



    Near $0$, $;sin usim u$, $; tan usim u$, so
    $$frac{sin 5y}{tan 3y}sim_{y=0}frac{5y}{3y}=frac53.$$






    share|cite|improve this answer




























      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      1
      down vote













      Hint:



      $pi-x=y$



      $sin5x=sin5(pi-y)=?$



      Now for $yne0$ $$dfrac{sin5y}{tan3y}=dfrac53cdotdfrac{dfrac{sin5y}{5y}}{dfrac{tan3y}{3y}}$$






      share|cite|improve this answer

























        up vote
        1
        down vote













        Hint:



        $pi-x=y$



        $sin5x=sin5(pi-y)=?$



        Now for $yne0$ $$dfrac{sin5y}{tan3y}=dfrac53cdotdfrac{dfrac{sin5y}{5y}}{dfrac{tan3y}{3y}}$$






        share|cite|improve this answer























          up vote
          1
          down vote










          up vote
          1
          down vote









          Hint:



          $pi-x=y$



          $sin5x=sin5(pi-y)=?$



          Now for $yne0$ $$dfrac{sin5y}{tan3y}=dfrac53cdotdfrac{dfrac{sin5y}{5y}}{dfrac{tan3y}{3y}}$$






          share|cite|improve this answer












          Hint:



          $pi-x=y$



          $sin5x=sin5(pi-y)=?$



          Now for $yne0$ $$dfrac{sin5y}{tan3y}=dfrac53cdotdfrac{dfrac{sin5y}{5y}}{dfrac{tan3y}{3y}}$$







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Dec 4 at 16:06









          lab bhattacharjee

          222k15155273




          222k15155273






















              up vote
              0
              down vote













              Variant, with equivalents:



              Near $0$, $;sin usim u$, $; tan usim u$, so
              $$frac{sin 5y}{tan 3y}sim_{y=0}frac{5y}{3y}=frac53.$$






              share|cite|improve this answer

























                up vote
                0
                down vote













                Variant, with equivalents:



                Near $0$, $;sin usim u$, $; tan usim u$, so
                $$frac{sin 5y}{tan 3y}sim_{y=0}frac{5y}{3y}=frac53.$$






                share|cite|improve this answer























                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                  Variant, with equivalents:



                  Near $0$, $;sin usim u$, $; tan usim u$, so
                  $$frac{sin 5y}{tan 3y}sim_{y=0}frac{5y}{3y}=frac53.$$






                  share|cite|improve this answer












                  Variant, with equivalents:



                  Near $0$, $;sin usim u$, $; tan usim u$, so
                  $$frac{sin 5y}{tan 3y}sim_{y=0}frac{5y}{3y}=frac53.$$







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Dec 4 at 16:45









                  Bernard

                  117k637109




                  117k637109















                      Popular posts from this blog

                      Bressuire

                      Cabo Verde

                      Gyllenstierna