Find convolution of $operatorname{sinc}(t-3)*operatorname{sinc}(pi(t+3))$
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How can I find the following convolution?$$operatorname{sinc}(t-3)*operatorname{sinc}(pi(t+3))$$
Where $operatorname{sinc}$ refers to this function.
I can't understand how to use integration to compute this function.
convolution
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add a comment |
$begingroup$
How can I find the following convolution?$$operatorname{sinc}(t-3)*operatorname{sinc}(pi(t+3))$$
Where $operatorname{sinc}$ refers to this function.
I can't understand how to use integration to compute this function.
convolution
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1
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Use the Fourier Transform, which lets you say $f(t)*g(t)=mathcal{F}^{-1}{mathcal{F}{f(t)}cdotmathcal{F}{g(t)}}$
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– Andy Walls
Dec 18 '18 at 22:38
$begingroup$
@AndyWalls, I understood, thank for help
$endgroup$
– Thien Hoang Dang
Dec 24 '18 at 11:02
add a comment |
$begingroup$
How can I find the following convolution?$$operatorname{sinc}(t-3)*operatorname{sinc}(pi(t+3))$$
Where $operatorname{sinc}$ refers to this function.
I can't understand how to use integration to compute this function.
convolution
$endgroup$
How can I find the following convolution?$$operatorname{sinc}(t-3)*operatorname{sinc}(pi(t+3))$$
Where $operatorname{sinc}$ refers to this function.
I can't understand how to use integration to compute this function.
convolution
convolution
edited Dec 18 '18 at 21:17
Mason
1,9551530
1,9551530
asked Dec 18 '18 at 19:24
Thien Hoang DangThien Hoang Dang
64
64
1
$begingroup$
Use the Fourier Transform, which lets you say $f(t)*g(t)=mathcal{F}^{-1}{mathcal{F}{f(t)}cdotmathcal{F}{g(t)}}$
$endgroup$
– Andy Walls
Dec 18 '18 at 22:38
$begingroup$
@AndyWalls, I understood, thank for help
$endgroup$
– Thien Hoang Dang
Dec 24 '18 at 11:02
add a comment |
1
$begingroup$
Use the Fourier Transform, which lets you say $f(t)*g(t)=mathcal{F}^{-1}{mathcal{F}{f(t)}cdotmathcal{F}{g(t)}}$
$endgroup$
– Andy Walls
Dec 18 '18 at 22:38
$begingroup$
@AndyWalls, I understood, thank for help
$endgroup$
– Thien Hoang Dang
Dec 24 '18 at 11:02
1
1
$begingroup$
Use the Fourier Transform, which lets you say $f(t)*g(t)=mathcal{F}^{-1}{mathcal{F}{f(t)}cdotmathcal{F}{g(t)}}$
$endgroup$
– Andy Walls
Dec 18 '18 at 22:38
$begingroup$
Use the Fourier Transform, which lets you say $f(t)*g(t)=mathcal{F}^{-1}{mathcal{F}{f(t)}cdotmathcal{F}{g(t)}}$
$endgroup$
– Andy Walls
Dec 18 '18 at 22:38
$begingroup$
@AndyWalls, I understood, thank for help
$endgroup$
– Thien Hoang Dang
Dec 24 '18 at 11:02
$begingroup$
@AndyWalls, I understood, thank for help
$endgroup$
– Thien Hoang Dang
Dec 24 '18 at 11:02
add a comment |
0
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$begingroup$
Use the Fourier Transform, which lets you say $f(t)*g(t)=mathcal{F}^{-1}{mathcal{F}{f(t)}cdotmathcal{F}{g(t)}}$
$endgroup$
– Andy Walls
Dec 18 '18 at 22:38
$begingroup$
@AndyWalls, I understood, thank for help
$endgroup$
– Thien Hoang Dang
Dec 24 '18 at 11:02