Understanding of a proof












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In (1) and (3), $ M' subseteq L'$ and $H subseteq H''$ are proved respectively. But I didn't understand how these imply $ M' leq L'$ and $H leq H''$ again respectively.



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    $begingroup$


    In (1) and (3), $ M' subseteq L'$ and $H subseteq H''$ are proved respectively. But I didn't understand how these imply $ M' leq L'$ and $H leq H''$ again respectively.



    enter image description here










    share|cite|improve this question









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      1





      $begingroup$


      In (1) and (3), $ M' subseteq L'$ and $H subseteq H''$ are proved respectively. But I didn't understand how these imply $ M' leq L'$ and $H leq H''$ again respectively.



      enter image description here










      share|cite|improve this question









      $endgroup$




      In (1) and (3), $ M' subseteq L'$ and $H subseteq H''$ are proved respectively. But I didn't understand how these imply $ M' leq L'$ and $H leq H''$ again respectively.



      enter image description here







      galois-theory extension-field






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      asked Dec 30 '18 at 0:20









      Leyla AlkanLeyla Alkan

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          $begingroup$

          I'm assuming you're reading [this PDF}(http://feyzioglu.boun.edu.tr/book/chapter5/ch5(54).pdf). Thus, Lemma 54.8 implies that $M', L'$ are indeed subgroups of $G$. Thus, if $M' subseteq L'$, then $M'$ is a group contained within the group $L'$. In other words, $M'$ is a subgroup of $L'$, and thus $M' leq L'$.



          Also according to Lemma 54.8, $H'$ is an intermediate field of $E/K$ and thus $H''$ is a subgroup of $G$. Also, by definition, $H$ is a subgroup of $G$. Therefore, $H subseteq H''$ implies that $H$ is a group contained within the group $H''$. Similarly to above, in other words, this means that $H$ is a subgroup of $H''$ and thus $H leq H''$.






          share|cite|improve this answer









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          • $begingroup$
            I totally dismissed the use of Lemma 54.8 there. I really appreciated your help, thanks a lot!
            $endgroup$
            – Leyla Alkan
            Dec 30 '18 at 0:45











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          $begingroup$

          I'm assuming you're reading [this PDF}(http://feyzioglu.boun.edu.tr/book/chapter5/ch5(54).pdf). Thus, Lemma 54.8 implies that $M', L'$ are indeed subgroups of $G$. Thus, if $M' subseteq L'$, then $M'$ is a group contained within the group $L'$. In other words, $M'$ is a subgroup of $L'$, and thus $M' leq L'$.



          Also according to Lemma 54.8, $H'$ is an intermediate field of $E/K$ and thus $H''$ is a subgroup of $G$. Also, by definition, $H$ is a subgroup of $G$. Therefore, $H subseteq H''$ implies that $H$ is a group contained within the group $H''$. Similarly to above, in other words, this means that $H$ is a subgroup of $H''$ and thus $H leq H''$.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            I totally dismissed the use of Lemma 54.8 there. I really appreciated your help, thanks a lot!
            $endgroup$
            – Leyla Alkan
            Dec 30 '18 at 0:45
















          1












          $begingroup$

          I'm assuming you're reading [this PDF}(http://feyzioglu.boun.edu.tr/book/chapter5/ch5(54).pdf). Thus, Lemma 54.8 implies that $M', L'$ are indeed subgroups of $G$. Thus, if $M' subseteq L'$, then $M'$ is a group contained within the group $L'$. In other words, $M'$ is a subgroup of $L'$, and thus $M' leq L'$.



          Also according to Lemma 54.8, $H'$ is an intermediate field of $E/K$ and thus $H''$ is a subgroup of $G$. Also, by definition, $H$ is a subgroup of $G$. Therefore, $H subseteq H''$ implies that $H$ is a group contained within the group $H''$. Similarly to above, in other words, this means that $H$ is a subgroup of $H''$ and thus $H leq H''$.






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            I totally dismissed the use of Lemma 54.8 there. I really appreciated your help, thanks a lot!
            $endgroup$
            – Leyla Alkan
            Dec 30 '18 at 0:45














          1












          1








          1





          $begingroup$

          I'm assuming you're reading [this PDF}(http://feyzioglu.boun.edu.tr/book/chapter5/ch5(54).pdf). Thus, Lemma 54.8 implies that $M', L'$ are indeed subgroups of $G$. Thus, if $M' subseteq L'$, then $M'$ is a group contained within the group $L'$. In other words, $M'$ is a subgroup of $L'$, and thus $M' leq L'$.



          Also according to Lemma 54.8, $H'$ is an intermediate field of $E/K$ and thus $H''$ is a subgroup of $G$. Also, by definition, $H$ is a subgroup of $G$. Therefore, $H subseteq H''$ implies that $H$ is a group contained within the group $H''$. Similarly to above, in other words, this means that $H$ is a subgroup of $H''$ and thus $H leq H''$.






          share|cite|improve this answer









          $endgroup$



          I'm assuming you're reading [this PDF}(http://feyzioglu.boun.edu.tr/book/chapter5/ch5(54).pdf). Thus, Lemma 54.8 implies that $M', L'$ are indeed subgroups of $G$. Thus, if $M' subseteq L'$, then $M'$ is a group contained within the group $L'$. In other words, $M'$ is a subgroup of $L'$, and thus $M' leq L'$.



          Also according to Lemma 54.8, $H'$ is an intermediate field of $E/K$ and thus $H''$ is a subgroup of $G$. Also, by definition, $H$ is a subgroup of $G$. Therefore, $H subseteq H''$ implies that $H$ is a group contained within the group $H''$. Similarly to above, in other words, this means that $H$ is a subgroup of $H''$ and thus $H leq H''$.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Dec 30 '18 at 0:35









          Noble MushtakNoble Mushtak

          15.3k1835




          15.3k1835












          • $begingroup$
            I totally dismissed the use of Lemma 54.8 there. I really appreciated your help, thanks a lot!
            $endgroup$
            – Leyla Alkan
            Dec 30 '18 at 0:45


















          • $begingroup$
            I totally dismissed the use of Lemma 54.8 there. I really appreciated your help, thanks a lot!
            $endgroup$
            – Leyla Alkan
            Dec 30 '18 at 0:45
















          $begingroup$
          I totally dismissed the use of Lemma 54.8 there. I really appreciated your help, thanks a lot!
          $endgroup$
          – Leyla Alkan
          Dec 30 '18 at 0:45




          $begingroup$
          I totally dismissed the use of Lemma 54.8 there. I really appreciated your help, thanks a lot!
          $endgroup$
          – Leyla Alkan
          Dec 30 '18 at 0:45


















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