Property of set $left {y in Bbb R : y =limlimits_{n rightarrow infty} f(x_n), text {for some sequence } x_n...
Let $f : Bbb R longrightarrow Bbb R$ be a continuous function and $A subseteq Bbb R$ be defined by
$$A=left {y in Bbb R : y =lim_{n rightarrow infty} f(x_n), text {for some sequence } x_n rightarrow +infty right }.$$
Then the set $A$ is necessarily
$(1)$ a connected set.
$(2)$ a compact set.
$(3)$ a singleton set.
$(4)$ None of the above.
How to tackle this problem? Any valuable suggestions will be highly appreciated.
Thank you in advance.
real-analysis sequences-and-series continuity compactness connectedness
closed as off-topic by José Carlos Santos, GNUSupporter 8964民主女神 地下教會, Federico, Cesareo, user10354138 Dec 8 at 6:10
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, GNUSupporter 8964民主女神 地下教會, Federico, Cesareo, user10354138
If this question can be reworded to fit the rules in the help center, please edit the question.
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Let $f : Bbb R longrightarrow Bbb R$ be a continuous function and $A subseteq Bbb R$ be defined by
$$A=left {y in Bbb R : y =lim_{n rightarrow infty} f(x_n), text {for some sequence } x_n rightarrow +infty right }.$$
Then the set $A$ is necessarily
$(1)$ a connected set.
$(2)$ a compact set.
$(3)$ a singleton set.
$(4)$ None of the above.
How to tackle this problem? Any valuable suggestions will be highly appreciated.
Thank you in advance.
real-analysis sequences-and-series continuity compactness connectedness
closed as off-topic by José Carlos Santos, GNUSupporter 8964民主女神 地下教會, Federico, Cesareo, user10354138 Dec 8 at 6:10
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, GNUSupporter 8964民主女神 地下教會, Federico, Cesareo, user10354138
If this question can be reworded to fit the rules in the help center, please edit the question.
1
what would you say?
– Federico
Dec 7 at 19:02
I think (1) is the correct one.
– math maniac.
Dec 7 at 19:19
1
What we have to show is that if $a,b in A$ and $c in (a,b)$ then $c in A$.
– math maniac.
Dec 7 at 19:22
1
@Federico the most trivial theorem in continuity I remember is "intermediate value theorem".
– math maniac.
Dec 7 at 19:26
1
You mean $f(z_n)to c$. Yes, that is what you have to do
– Federico
Dec 7 at 19:35
|
show 12 more comments
Let $f : Bbb R longrightarrow Bbb R$ be a continuous function and $A subseteq Bbb R$ be defined by
$$A=left {y in Bbb R : y =lim_{n rightarrow infty} f(x_n), text {for some sequence } x_n rightarrow +infty right }.$$
Then the set $A$ is necessarily
$(1)$ a connected set.
$(2)$ a compact set.
$(3)$ a singleton set.
$(4)$ None of the above.
How to tackle this problem? Any valuable suggestions will be highly appreciated.
Thank you in advance.
real-analysis sequences-and-series continuity compactness connectedness
Let $f : Bbb R longrightarrow Bbb R$ be a continuous function and $A subseteq Bbb R$ be defined by
$$A=left {y in Bbb R : y =lim_{n rightarrow infty} f(x_n), text {for some sequence } x_n rightarrow +infty right }.$$
Then the set $A$ is necessarily
$(1)$ a connected set.
$(2)$ a compact set.
$(3)$ a singleton set.
$(4)$ None of the above.
How to tackle this problem? Any valuable suggestions will be highly appreciated.
Thank you in advance.
real-analysis sequences-and-series continuity compactness connectedness
real-analysis sequences-and-series continuity compactness connectedness
edited Dec 8 at 5:29
asked Dec 7 at 18:54
math maniac.
214
214
closed as off-topic by José Carlos Santos, GNUSupporter 8964民主女神 地下教會, Federico, Cesareo, user10354138 Dec 8 at 6:10
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, GNUSupporter 8964民主女神 地下教會, Federico, Cesareo, user10354138
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by José Carlos Santos, GNUSupporter 8964民主女神 地下教會, Federico, Cesareo, user10354138 Dec 8 at 6:10
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, GNUSupporter 8964民主女神 地下教會, Federico, Cesareo, user10354138
If this question can be reworded to fit the rules in the help center, please edit the question.
1
what would you say?
– Federico
Dec 7 at 19:02
I think (1) is the correct one.
– math maniac.
Dec 7 at 19:19
1
What we have to show is that if $a,b in A$ and $c in (a,b)$ then $c in A$.
– math maniac.
Dec 7 at 19:22
1
@Federico the most trivial theorem in continuity I remember is "intermediate value theorem".
– math maniac.
Dec 7 at 19:26
1
You mean $f(z_n)to c$. Yes, that is what you have to do
– Federico
Dec 7 at 19:35
|
show 12 more comments
1
what would you say?
– Federico
Dec 7 at 19:02
I think (1) is the correct one.
– math maniac.
Dec 7 at 19:19
1
What we have to show is that if $a,b in A$ and $c in (a,b)$ then $c in A$.
– math maniac.
Dec 7 at 19:22
1
@Federico the most trivial theorem in continuity I remember is "intermediate value theorem".
– math maniac.
Dec 7 at 19:26
1
You mean $f(z_n)to c$. Yes, that is what you have to do
– Federico
Dec 7 at 19:35
1
1
what would you say?
– Federico
Dec 7 at 19:02
what would you say?
– Federico
Dec 7 at 19:02
I think (1) is the correct one.
– math maniac.
Dec 7 at 19:19
I think (1) is the correct one.
– math maniac.
Dec 7 at 19:19
1
1
What we have to show is that if $a,b in A$ and $c in (a,b)$ then $c in A$.
– math maniac.
Dec 7 at 19:22
What we have to show is that if $a,b in A$ and $c in (a,b)$ then $c in A$.
– math maniac.
Dec 7 at 19:22
1
1
@Federico the most trivial theorem in continuity I remember is "intermediate value theorem".
– math maniac.
Dec 7 at 19:26
@Federico the most trivial theorem in continuity I remember is "intermediate value theorem".
– math maniac.
Dec 7 at 19:26
1
1
You mean $f(z_n)to c$. Yes, that is what you have to do
– Federico
Dec 7 at 19:35
You mean $f(z_n)to c$. Yes, that is what you have to do
– Federico
Dec 7 at 19:35
|
show 12 more comments
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1
what would you say?
– Federico
Dec 7 at 19:02
I think (1) is the correct one.
– math maniac.
Dec 7 at 19:19
1
What we have to show is that if $a,b in A$ and $c in (a,b)$ then $c in A$.
– math maniac.
Dec 7 at 19:22
1
@Federico the most trivial theorem in continuity I remember is "intermediate value theorem".
– math maniac.
Dec 7 at 19:26
1
You mean $f(z_n)to c$. Yes, that is what you have to do
– Federico
Dec 7 at 19:35