what is a the differential form of the Riemann zeta function?
So I understand the function and the summation as:
$sum_{n=0}^{infty} 1/n^a= zeta(a) $
but I recently came across a term as :
$d zeta(a)$, but I don't know how to interpret this.
The function was as follows:
Solution to a geodesic equation.
https://i.stack.imgur.com/ykX8G.png
functional-analysis number-theory notation mathematical-physics
|
show 7 more comments
So I understand the function and the summation as:
$sum_{n=0}^{infty} 1/n^a= zeta(a) $
but I recently came across a term as :
$d zeta(a)$, but I don't know how to interpret this.
The function was as follows:
Solution to a geodesic equation.
https://i.stack.imgur.com/ykX8G.png
functional-analysis number-theory notation mathematical-physics
Use$zeta$
for $zeta$.
– Shaun
Dec 7 at 22:45
Use$infty$
for $infty$.
– Shaun
Dec 7 at 22:46
thank you very much!
– bguner
Dec 7 at 22:49
Can you provide more context? Did you see $int_a^b f(x) dzeta(x)$?
– Chickenmancer
Dec 7 at 22:50
You're welcome. Do you mean to sum over $n$ and not $i$?
– Shaun
Dec 7 at 22:51
|
show 7 more comments
So I understand the function and the summation as:
$sum_{n=0}^{infty} 1/n^a= zeta(a) $
but I recently came across a term as :
$d zeta(a)$, but I don't know how to interpret this.
The function was as follows:
Solution to a geodesic equation.
https://i.stack.imgur.com/ykX8G.png
functional-analysis number-theory notation mathematical-physics
So I understand the function and the summation as:
$sum_{n=0}^{infty} 1/n^a= zeta(a) $
but I recently came across a term as :
$d zeta(a)$, but I don't know how to interpret this.
The function was as follows:
Solution to a geodesic equation.
https://i.stack.imgur.com/ykX8G.png
functional-analysis number-theory notation mathematical-physics
functional-analysis number-theory notation mathematical-physics
edited Dec 7 at 22:56
asked Dec 7 at 22:18
bguner
11
11
Use$zeta$
for $zeta$.
– Shaun
Dec 7 at 22:45
Use$infty$
for $infty$.
– Shaun
Dec 7 at 22:46
thank you very much!
– bguner
Dec 7 at 22:49
Can you provide more context? Did you see $int_a^b f(x) dzeta(x)$?
– Chickenmancer
Dec 7 at 22:50
You're welcome. Do you mean to sum over $n$ and not $i$?
– Shaun
Dec 7 at 22:51
|
show 7 more comments
Use$zeta$
for $zeta$.
– Shaun
Dec 7 at 22:45
Use$infty$
for $infty$.
– Shaun
Dec 7 at 22:46
thank you very much!
– bguner
Dec 7 at 22:49
Can you provide more context? Did you see $int_a^b f(x) dzeta(x)$?
– Chickenmancer
Dec 7 at 22:50
You're welcome. Do you mean to sum over $n$ and not $i$?
– Shaun
Dec 7 at 22:51
Use
$zeta$
for $zeta$.– Shaun
Dec 7 at 22:45
Use
$zeta$
for $zeta$.– Shaun
Dec 7 at 22:45
Use
$infty$
for $infty$.– Shaun
Dec 7 at 22:46
Use
$infty$
for $infty$.– Shaun
Dec 7 at 22:46
thank you very much!
– bguner
Dec 7 at 22:49
thank you very much!
– bguner
Dec 7 at 22:49
Can you provide more context? Did you see $int_a^b f(x) dzeta(x)$?
– Chickenmancer
Dec 7 at 22:50
Can you provide more context? Did you see $int_a^b f(x) dzeta(x)$?
– Chickenmancer
Dec 7 at 22:50
You're welcome. Do you mean to sum over $n$ and not $i$?
– Shaun
Dec 7 at 22:51
You're welcome. Do you mean to sum over $n$ and not $i$?
– Shaun
Dec 7 at 22:51
|
show 7 more comments
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Use
$zeta$
for $zeta$.– Shaun
Dec 7 at 22:45
Use
$infty$
for $infty$.– Shaun
Dec 7 at 22:46
thank you very much!
– bguner
Dec 7 at 22:49
Can you provide more context? Did you see $int_a^b f(x) dzeta(x)$?
– Chickenmancer
Dec 7 at 22:50
You're welcome. Do you mean to sum over $n$ and not $i$?
– Shaun
Dec 7 at 22:51