How many integer solutions with negative numbers?












0














If a question asked: How many integer solutions of $x_1+x_2+x_3+x_4=30$ with $-9 leq x_i leq 21$? How would this be solved?



I understand how to solve if the inequality was $0 leq x_i leq 21$?, but how to solve between a negative and positive inequality?



$N = binom{30 + 4-1}{30}$



$N(A_i) = binom{(30 - ?) +4-1}{30 - ?}$



...










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  • It is the coefficient of $x^{30}$ in $$frac{x^{-36}(1-x^{30})^4}{(1-x)^4}$$
    – Matt Samuel
    Dec 10 '18 at 20:44










  • @MattSamuel Could you explain this? We have to use sets (finished generating functions chapter).
    – Math Newbie
    Dec 10 '18 at 20:46












  • The formula for $N$ you give is the unrestricted value. That is, it would be the answer if the question was how many solutions are there to $x_1+x_2+x_3+x_4=30$ with $x_i≥0$. More work is needed to handle a cap, as in $0≤x_i≤21$.
    – lulu
    Dec 10 '18 at 20:58










  • "set theory" has nothing to do with your question.
    – Jean Marie
    Dec 10 '18 at 21:47










  • @JeanMarie Ah, sorry, I assumed so because that's our current chapter.
    – Math Newbie
    Dec 10 '18 at 22:34
















0














If a question asked: How many integer solutions of $x_1+x_2+x_3+x_4=30$ with $-9 leq x_i leq 21$? How would this be solved?



I understand how to solve if the inequality was $0 leq x_i leq 21$?, but how to solve between a negative and positive inequality?



$N = binom{30 + 4-1}{30}$



$N(A_i) = binom{(30 - ?) +4-1}{30 - ?}$



...










share|cite|improve this question
























  • It is the coefficient of $x^{30}$ in $$frac{x^{-36}(1-x^{30})^4}{(1-x)^4}$$
    – Matt Samuel
    Dec 10 '18 at 20:44










  • @MattSamuel Could you explain this? We have to use sets (finished generating functions chapter).
    – Math Newbie
    Dec 10 '18 at 20:46












  • The formula for $N$ you give is the unrestricted value. That is, it would be the answer if the question was how many solutions are there to $x_1+x_2+x_3+x_4=30$ with $x_i≥0$. More work is needed to handle a cap, as in $0≤x_i≤21$.
    – lulu
    Dec 10 '18 at 20:58










  • "set theory" has nothing to do with your question.
    – Jean Marie
    Dec 10 '18 at 21:47










  • @JeanMarie Ah, sorry, I assumed so because that's our current chapter.
    – Math Newbie
    Dec 10 '18 at 22:34














0












0








0







If a question asked: How many integer solutions of $x_1+x_2+x_3+x_4=30$ with $-9 leq x_i leq 21$? How would this be solved?



I understand how to solve if the inequality was $0 leq x_i leq 21$?, but how to solve between a negative and positive inequality?



$N = binom{30 + 4-1}{30}$



$N(A_i) = binom{(30 - ?) +4-1}{30 - ?}$



...










share|cite|improve this question















If a question asked: How many integer solutions of $x_1+x_2+x_3+x_4=30$ with $-9 leq x_i leq 21$? How would this be solved?



I understand how to solve if the inequality was $0 leq x_i leq 21$?, but how to solve between a negative and positive inequality?



$N = binom{30 + 4-1}{30}$



$N(A_i) = binom{(30 - ?) +4-1}{30 - ?}$



...







combinatorics






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share|cite|improve this question













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edited Dec 10 '18 at 22:34

























asked Dec 10 '18 at 20:41









Math Newbie

428




428












  • It is the coefficient of $x^{30}$ in $$frac{x^{-36}(1-x^{30})^4}{(1-x)^4}$$
    – Matt Samuel
    Dec 10 '18 at 20:44










  • @MattSamuel Could you explain this? We have to use sets (finished generating functions chapter).
    – Math Newbie
    Dec 10 '18 at 20:46












  • The formula for $N$ you give is the unrestricted value. That is, it would be the answer if the question was how many solutions are there to $x_1+x_2+x_3+x_4=30$ with $x_i≥0$. More work is needed to handle a cap, as in $0≤x_i≤21$.
    – lulu
    Dec 10 '18 at 20:58










  • "set theory" has nothing to do with your question.
    – Jean Marie
    Dec 10 '18 at 21:47










  • @JeanMarie Ah, sorry, I assumed so because that's our current chapter.
    – Math Newbie
    Dec 10 '18 at 22:34


















  • It is the coefficient of $x^{30}$ in $$frac{x^{-36}(1-x^{30})^4}{(1-x)^4}$$
    – Matt Samuel
    Dec 10 '18 at 20:44










  • @MattSamuel Could you explain this? We have to use sets (finished generating functions chapter).
    – Math Newbie
    Dec 10 '18 at 20:46












  • The formula for $N$ you give is the unrestricted value. That is, it would be the answer if the question was how many solutions are there to $x_1+x_2+x_3+x_4=30$ with $x_i≥0$. More work is needed to handle a cap, as in $0≤x_i≤21$.
    – lulu
    Dec 10 '18 at 20:58










  • "set theory" has nothing to do with your question.
    – Jean Marie
    Dec 10 '18 at 21:47










  • @JeanMarie Ah, sorry, I assumed so because that's our current chapter.
    – Math Newbie
    Dec 10 '18 at 22:34
















It is the coefficient of $x^{30}$ in $$frac{x^{-36}(1-x^{30})^4}{(1-x)^4}$$
– Matt Samuel
Dec 10 '18 at 20:44




It is the coefficient of $x^{30}$ in $$frac{x^{-36}(1-x^{30})^4}{(1-x)^4}$$
– Matt Samuel
Dec 10 '18 at 20:44












@MattSamuel Could you explain this? We have to use sets (finished generating functions chapter).
– Math Newbie
Dec 10 '18 at 20:46






@MattSamuel Could you explain this? We have to use sets (finished generating functions chapter).
– Math Newbie
Dec 10 '18 at 20:46














The formula for $N$ you give is the unrestricted value. That is, it would be the answer if the question was how many solutions are there to $x_1+x_2+x_3+x_4=30$ with $x_i≥0$. More work is needed to handle a cap, as in $0≤x_i≤21$.
– lulu
Dec 10 '18 at 20:58




The formula for $N$ you give is the unrestricted value. That is, it would be the answer if the question was how many solutions are there to $x_1+x_2+x_3+x_4=30$ with $x_i≥0$. More work is needed to handle a cap, as in $0≤x_i≤21$.
– lulu
Dec 10 '18 at 20:58












"set theory" has nothing to do with your question.
– Jean Marie
Dec 10 '18 at 21:47




"set theory" has nothing to do with your question.
– Jean Marie
Dec 10 '18 at 21:47












@JeanMarie Ah, sorry, I assumed so because that's our current chapter.
– Math Newbie
Dec 10 '18 at 22:34




@JeanMarie Ah, sorry, I assumed so because that's our current chapter.
– Math Newbie
Dec 10 '18 at 22:34










1 Answer
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Let $y_i=x_i+9$. Then
$$
y_1+y_2+y_3+y_4=66\
0leq y_ileq 30
$$

Now find the number of solutions the way you say you know.






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    1 Answer
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    3














    Let $y_i=x_i+9$. Then
    $$
    y_1+y_2+y_3+y_4=66\
    0leq y_ileq 30
    $$

    Now find the number of solutions the way you say you know.






    share|cite|improve this answer


























      3














      Let $y_i=x_i+9$. Then
      $$
      y_1+y_2+y_3+y_4=66\
      0leq y_ileq 30
      $$

      Now find the number of solutions the way you say you know.






      share|cite|improve this answer
























        3












        3








        3






        Let $y_i=x_i+9$. Then
        $$
        y_1+y_2+y_3+y_4=66\
        0leq y_ileq 30
        $$

        Now find the number of solutions the way you say you know.






        share|cite|improve this answer












        Let $y_i=x_i+9$. Then
        $$
        y_1+y_2+y_3+y_4=66\
        0leq y_ileq 30
        $$

        Now find the number of solutions the way you say you know.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 10 '18 at 20:48









        Arthur

        111k7105186




        111k7105186






























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