Fourier inversion formula and Plancherel formula for finite groups












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The following problem is from an exercise sheet from a lecture, but it is a bit off-topic, so I would appreaciate some help/hints on it.
I've seen some similar posts, but either with different notation or already assuming a similar formula as the first one below.
Let $G$ be a finite group and $phi , psi : G to mathbb{C}$ and $(V, rho_V) $ be a complex representation of $G$. Let $ operatorname{Irr}(G) = { S_1, ldots, S_t } $ be the irreducible representations of $G$. Then the Fourier transform is defined as $hat{phi} (rho_V) := sum_{g in G} phi (g) g$.



I want to show the following two formulas:



$$ phi(g) = frac{1}{left| G right|} sum_{i= 1}^t dim(S_i) operatorname{Tr}(rho_{S_i} (g^{-1}) circ hat{phi}(rho_{S_i}))$$



$$ sum_{g in G} phi(g^{-1})psi(g) = frac{1}{left| G right|} sum_{i= 1}^t dim(S_i) operatorname{Tr}(hat{phi}(rho_{S_i}) circ hat{psi}(rho_{S_i}))$$










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    $begingroup$


    The following problem is from an exercise sheet from a lecture, but it is a bit off-topic, so I would appreaciate some help/hints on it.
    I've seen some similar posts, but either with different notation or already assuming a similar formula as the first one below.
    Let $G$ be a finite group and $phi , psi : G to mathbb{C}$ and $(V, rho_V) $ be a complex representation of $G$. Let $ operatorname{Irr}(G) = { S_1, ldots, S_t } $ be the irreducible representations of $G$. Then the Fourier transform is defined as $hat{phi} (rho_V) := sum_{g in G} phi (g) g$.



    I want to show the following two formulas:



    $$ phi(g) = frac{1}{left| G right|} sum_{i= 1}^t dim(S_i) operatorname{Tr}(rho_{S_i} (g^{-1}) circ hat{phi}(rho_{S_i}))$$



    $$ sum_{g in G} phi(g^{-1})psi(g) = frac{1}{left| G right|} sum_{i= 1}^t dim(S_i) operatorname{Tr}(hat{phi}(rho_{S_i}) circ hat{psi}(rho_{S_i}))$$










    share|cite|improve this question











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      $begingroup$


      The following problem is from an exercise sheet from a lecture, but it is a bit off-topic, so I would appreaciate some help/hints on it.
      I've seen some similar posts, but either with different notation or already assuming a similar formula as the first one below.
      Let $G$ be a finite group and $phi , psi : G to mathbb{C}$ and $(V, rho_V) $ be a complex representation of $G$. Let $ operatorname{Irr}(G) = { S_1, ldots, S_t } $ be the irreducible representations of $G$. Then the Fourier transform is defined as $hat{phi} (rho_V) := sum_{g in G} phi (g) g$.



      I want to show the following two formulas:



      $$ phi(g) = frac{1}{left| G right|} sum_{i= 1}^t dim(S_i) operatorname{Tr}(rho_{S_i} (g^{-1}) circ hat{phi}(rho_{S_i}))$$



      $$ sum_{g in G} phi(g^{-1})psi(g) = frac{1}{left| G right|} sum_{i= 1}^t dim(S_i) operatorname{Tr}(hat{phi}(rho_{S_i}) circ hat{psi}(rho_{S_i}))$$










      share|cite|improve this question











      $endgroup$




      The following problem is from an exercise sheet from a lecture, but it is a bit off-topic, so I would appreaciate some help/hints on it.
      I've seen some similar posts, but either with different notation or already assuming a similar formula as the first one below.
      Let $G$ be a finite group and $phi , psi : G to mathbb{C}$ and $(V, rho_V) $ be a complex representation of $G$. Let $ operatorname{Irr}(G) = { S_1, ldots, S_t } $ be the irreducible representations of $G$. Then the Fourier transform is defined as $hat{phi} (rho_V) := sum_{g in G} phi (g) g$.



      I want to show the following two formulas:



      $$ phi(g) = frac{1}{left| G right|} sum_{i= 1}^t dim(S_i) operatorname{Tr}(rho_{S_i} (g^{-1}) circ hat{phi}(rho_{S_i}))$$



      $$ sum_{g in G} phi(g^{-1})psi(g) = frac{1}{left| G right|} sum_{i= 1}^t dim(S_i) operatorname{Tr}(hat{phi}(rho_{S_i}) circ hat{psi}(rho_{S_i}))$$







      group-theory representation-theory






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      share|cite|improve this question













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      share|cite|improve this question








      edited Jan 5 at 22:36









      Bernard

      123k741117




      123k741117










      asked Jan 5 at 22:32









      MPB94MPB94

      27017




      27017






















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