Is List f() a useful signature? Is there any problem with it / using it?
Is <T> List<? extends T> f()
a useful signature? Is there any problem with it / using it?
This was an interview question. I know this:
- It compiles fine
- Use it like
List<? extends Number> lst = obj.<Number>f()
, and then I can call on lst only those List methods that do not contain T in their signatures (say, isEmpty(), size(), but not add(T), remove(T)
Does that fully answer the question?
java generics signature
|
show 5 more comments
Is <T> List<? extends T> f()
a useful signature? Is there any problem with it / using it?
This was an interview question. I know this:
- It compiles fine
- Use it like
List<? extends Number> lst = obj.<Number>f()
, and then I can call on lst only those List methods that do not contain T in their signatures (say, isEmpty(), size(), but not add(T), remove(T)
Does that fully answer the question?
java generics signature
3
Returning a wildcard is not really useful
– NEGR KITAEC
Jan 2 at 10:41
1
You can still calladd(null)
etc.
– Andy Turner
Jan 2 at 10:46
1
Using type inference you can just doList<? extends Number> lst = s.f();
. Also, you can doNumber number = lst.get(0); System.out.println(number);
.
– DodgyCodeException
Jan 2 at 10:48
3
I think that what the interviewer was getting at was the fact that the return type of the method contains a wildcard. From Effective Java, 2nd Ed. "You should not return a wildcard type because it forces the users of an API to deal with wildcards." (paraphrased) Perhaps the best answer is that the return type is appropriate for use in package-private or private methods within a system, but it should not be used as part of an exported API.
– scottb
Jan 2 at 16:04
1
@ArtB no, the advice of the 2nd ed still very much stands: wildcards are to increase the flexibility of parameters; they should not be used in return types.
– Andy Turner
Jan 2 at 20:10
|
show 5 more comments
Is <T> List<? extends T> f()
a useful signature? Is there any problem with it / using it?
This was an interview question. I know this:
- It compiles fine
- Use it like
List<? extends Number> lst = obj.<Number>f()
, and then I can call on lst only those List methods that do not contain T in their signatures (say, isEmpty(), size(), but not add(T), remove(T)
Does that fully answer the question?
java generics signature
Is <T> List<? extends T> f()
a useful signature? Is there any problem with it / using it?
This was an interview question. I know this:
- It compiles fine
- Use it like
List<? extends Number> lst = obj.<Number>f()
, and then I can call on lst only those List methods that do not contain T in their signatures (say, isEmpty(), size(), but not add(T), remove(T)
Does that fully answer the question?
java generics signature
java generics signature
edited Jan 23 at 7:14
gudok
2,78121223
2,78121223
asked Jan 2 at 10:38
user10777718user10777718
319110
319110
3
Returning a wildcard is not really useful
– NEGR KITAEC
Jan 2 at 10:41
1
You can still calladd(null)
etc.
– Andy Turner
Jan 2 at 10:46
1
Using type inference you can just doList<? extends Number> lst = s.f();
. Also, you can doNumber number = lst.get(0); System.out.println(number);
.
– DodgyCodeException
Jan 2 at 10:48
3
I think that what the interviewer was getting at was the fact that the return type of the method contains a wildcard. From Effective Java, 2nd Ed. "You should not return a wildcard type because it forces the users of an API to deal with wildcards." (paraphrased) Perhaps the best answer is that the return type is appropriate for use in package-private or private methods within a system, but it should not be used as part of an exported API.
– scottb
Jan 2 at 16:04
1
@ArtB no, the advice of the 2nd ed still very much stands: wildcards are to increase the flexibility of parameters; they should not be used in return types.
– Andy Turner
Jan 2 at 20:10
|
show 5 more comments
3
Returning a wildcard is not really useful
– NEGR KITAEC
Jan 2 at 10:41
1
You can still calladd(null)
etc.
– Andy Turner
Jan 2 at 10:46
1
Using type inference you can just doList<? extends Number> lst = s.f();
. Also, you can doNumber number = lst.get(0); System.out.println(number);
.
– DodgyCodeException
Jan 2 at 10:48
3
I think that what the interviewer was getting at was the fact that the return type of the method contains a wildcard. From Effective Java, 2nd Ed. "You should not return a wildcard type because it forces the users of an API to deal with wildcards." (paraphrased) Perhaps the best answer is that the return type is appropriate for use in package-private or private methods within a system, but it should not be used as part of an exported API.
– scottb
Jan 2 at 16:04
1
@ArtB no, the advice of the 2nd ed still very much stands: wildcards are to increase the flexibility of parameters; they should not be used in return types.
– Andy Turner
Jan 2 at 20:10
3
3
Returning a wildcard is not really useful
– NEGR KITAEC
Jan 2 at 10:41
Returning a wildcard is not really useful
– NEGR KITAEC
Jan 2 at 10:41
1
1
You can still call
add(null)
etc.– Andy Turner
Jan 2 at 10:46
You can still call
add(null)
etc.– Andy Turner
Jan 2 at 10:46
1
1
Using type inference you can just do
List<? extends Number> lst = s.f();
. Also, you can do Number number = lst.get(0); System.out.println(number);
.– DodgyCodeException
Jan 2 at 10:48
Using type inference you can just do
List<? extends Number> lst = s.f();
. Also, you can do Number number = lst.get(0); System.out.println(number);
.– DodgyCodeException
Jan 2 at 10:48
3
3
I think that what the interviewer was getting at was the fact that the return type of the method contains a wildcard. From Effective Java, 2nd Ed. "You should not return a wildcard type because it forces the users of an API to deal with wildcards." (paraphrased) Perhaps the best answer is that the return type is appropriate for use in package-private or private methods within a system, but it should not be used as part of an exported API.
– scottb
Jan 2 at 16:04
I think that what the interviewer was getting at was the fact that the return type of the method contains a wildcard. From Effective Java, 2nd Ed. "You should not return a wildcard type because it forces the users of an API to deal with wildcards." (paraphrased) Perhaps the best answer is that the return type is appropriate for use in package-private or private methods within a system, but it should not be used as part of an exported API.
– scottb
Jan 2 at 16:04
1
1
@ArtB no, the advice of the 2nd ed still very much stands: wildcards are to increase the flexibility of parameters; they should not be used in return types.
– Andy Turner
Jan 2 at 20:10
@ArtB no, the advice of the 2nd ed still very much stands: wildcards are to increase the flexibility of parameters; they should not be used in return types.
– Andy Turner
Jan 2 at 20:10
|
show 5 more comments
4 Answers
4
active
oldest
votes
This method signature is "useful", in the sense that you can implement non-trivial, non-degenerate methods with it (that is, returning null
and throwing errors are not your only options). As the following example shows, such a method can be useful for implementing some algebraic structures like e.g. monoids.
First, observe that List<? extends T>
is a type with the following properties:
- You know that all elements of this list conform to the type
T
, so whenever you extract an element from this list, you can use it in position where aT
is expected. You can read from this list. - The exact type is unknown, so you can never be certain that an instance of a particular subtype of
T
can be added to this list. That is, you effectively cannot add new elements to such a list (unless you usenull
s / type casts / exploit unsoundness of Java's type system, that is).
In combination, it means that List<? extends T>
is kind-of like an append-protected list, with type-level append-protection.
You can actually do meaningful computations with such "append-protected" lists. Here are a few examples:
You can create append-protected lists with a single element:
public static <T> List<? extends T> pure(T t) {
List<T> result = new LinkedList<T>();
result.add(t);
return result;
}
You can create append-protected lists from ordinary lists:
public static <T> List<? extends T> toAppendProtected(List<T> original) {
List<T> result = new LinkedList<T>();
result.addAll(original);
return result;
}
You can combine append-protected lists:
public static <T> List<? extends T> combineAppendProtected(
List<? extends T> a,
List<? extends T> b
) {
List<T> result = new LinkedList<T>();
result.addAll(a);
result.addAll(b);
return result;
}
And, most importantly for this question, you can implement a method that returns an empty append-protected list of given type:
public static <T> List<? extends T> emptyAppendProtected() {
return new LinkedList<T>();
}
Together, combine
and empty
form an actual algebraic structure (a monoid), and methods like pure
ensure that it's non-degenerate (i.e. it has more elements that just an empty list). Indeed, if you had an interface similar to the usual Monoid typeclass:
public static interface Monoid<X> {
X empty();
X combine(X a, X b);
}
then you could use the above methods to implement it as follows:
public static <T> Monoid<List<? extends T>> appendProtectedListsMonoid() {
return new Monoid<List<? extends T>>() {
public List<? extends T> empty() {
return ReadOnlyLists.<T>emptyAppendProtected();
}
public List<? extends T> combine(
List<? extends T> a,
List<? extends T> b
) {
return combineAppendProtected(a, b);
}
};
}
This shows that methods with the signature given in your question can be used to implement some common design patterns / algebraic structures (monoids). Admittedly, the example is somewhat contrived, you probably wouldn't want to use it in practice, because you don't want to astonish the users of your API too much.
Full compilable example:
import java.util.*;
class AppendProtectedLists {
public static <T> List<? extends T> emptyAppendProtected() {
return new LinkedList<T>();
}
public static <T> List<? extends T> combineAppendProtected(
List<? extends T> a,
List<? extends T> b
) {
List<T> result = new LinkedList<T>();
result.addAll(a);
result.addAll(b);
return result;
}
public static <T> List<? extends T> toAppendProtected(List<T> original) {
List<T> result = new LinkedList<T>();
result.addAll(original);
return result;
}
public static <T> List<? extends T> pure(T t) {
List<T> result = new LinkedList<T>();
result.add(t);
return result;
}
public static interface Monoid<X> {
X empty();
X combine(X a, X b);
}
public static <T> Monoid<List<? extends T>> appendProtectedListsMonoid() {
return new Monoid<List<? extends T>>() {
public List<? extends T> empty() {
return AppendProtectedLists.<T>emptyAppendProtected();
}
public List<? extends T> combine(
List<? extends T> a,
List<? extends T> b
) {
return combineAppendProtected(a, b);
}
};
}
public static void main(String args) {
Monoid<List<? extends String>> monoid = appendProtectedListsMonoid();
List<? extends String> e = monoid.empty();
// e.add("hi"); // refuses to compile, which is good: write protection!
List<? extends String> a = pure("a");
List<? extends String> b = pure("b");
List<? extends String> c = monoid.combine(e, monoid.combine(a, b));
System.out.println(c); // output: [a, b]
}
}
add a comment |
I interpret "is it a useful signature" to mean "can you think of a use-case for it".
T
is determined at the call site, not inside the method, so there are only two things that you can return from the method: null or an empty list.
Given that you can create both of these values in roughly as much code as invoking this method, there isn't really a good reason to use it.
Actually, another value that can be safely returned is a list where all of the elements are null. But this isn't useful either, since you can only invoke methods which add or remove literal null from the return value, because of the ? extends
in the type bound. So all you've got is thing which counts the number of nulls it contains. Which isn't useful either.
Well, looking very desperately for a contrived way of making it useful, you could have called asetReturnType(Class<?> cls)
method on the same object beforehand, and thenf()
would use that information to return a list of the required type.
– DodgyCodeException
Jan 2 at 10:53
1
@DodgyCodeException I suppose - but this would be the protocol anti-pattern.
– Boris the Spider
Jan 2 at 11:38
"Given that you can create both of these values in roughly as much code as invoking this method, there isn't really a good reason to use it." Really? Invoking.<String>empty()
seems way more pleasant than invoking((List<? extends String>) new List<String>())
. How would you construct an expression of typeList<? extends String>
without such a method?
– Andrey Tyukin
Jan 2 at 14:45
1
@AndreyTyukinList<? extends String> list = new ArrayList<>();
. Or even justnew List<String>
- that's aList<? extends String>
.
– Andy Turner
Jan 2 at 14:45
@AndyTurner That's a statement, not an expression. One would have to pollute the local scope with extra variables (likelist
). The simple idea of instantiating an empty append-protected list would be spread over two different lines in code. And this statement is still way longer than a simple.<String>empty()
. Thenew List<String>()
is aList<? extends String>
only if it's in a context where the type inference expects aList<? extends String>
. It's not so useful if you want to create an expression that guides type inference instead of relying on it.
– Andrey Tyukin
Jan 2 at 14:48
add a comment |
The official Generics tutorial suggests not to use wildcard return types.
These guidelines do not apply to a method's return type. Using a wildcard as a return type should be avoided because it forces programmers using the code to deal with wildcards."
The reasoning given isn't exactly convincing, though.
add a comment |
It's not particularly useful, for the reasons given in other answers. However, consider it's "usefulness" in a class like the following (although it's probably a bit of an antipattern):
public class Repository {
private List<Object> lst = new ArrayList<>();
public <T> void add(T item) {
lst.add(item);
}
@SuppressWarnings("unchecked")
public <T> List<? extends T> f() {
return (List<? extends T>) lst;
}
public static void main(String args) {
Repository rep = new Repository();
rep.add(BigInteger.ONE);
rep.add(Double.valueOf(2.0));
List<? extends Number> list = rep.f();
System.out.println(list.get(0).doubleValue() + list.get(1).doubleValue());
}
}
Note the following features:
- The declared return type of f() means that the caller can set whatever T they like and the method will return the required type. If f() weren't declared like that, then the caller would need to cast every call to
get(N)
to the required type. - As it uses a wildcard, the declared return type makes the returned list read-only. This can often be a useful feature. When caller a getter, you don't want it to return a list you can write to. Often, getters use
Collections.unmodifiableList()
which forces a list to be read-only at run-time, but using the wildcard generic parameter forces the list to be read-only at compile-time! - The drawback is that it's not particularly type-safe. It is up to the caller to ensure that f() returns a type where T is a common superclass of all the previously added items.
- It would typically be much better to make the class Repository generic instead of the method f().
3
Wildcard lists aren't read-only. You can remove elements, you can addnull
to the list, and you can use a wildcard capturing helper method to add and reorder its own elements.
– Radiodef
Jan 2 at 14:37
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54004821%2fis-t-list-extends-t-f-a-useful-signature-is-there-any-problem-with-it%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
This method signature is "useful", in the sense that you can implement non-trivial, non-degenerate methods with it (that is, returning null
and throwing errors are not your only options). As the following example shows, such a method can be useful for implementing some algebraic structures like e.g. monoids.
First, observe that List<? extends T>
is a type with the following properties:
- You know that all elements of this list conform to the type
T
, so whenever you extract an element from this list, you can use it in position where aT
is expected. You can read from this list. - The exact type is unknown, so you can never be certain that an instance of a particular subtype of
T
can be added to this list. That is, you effectively cannot add new elements to such a list (unless you usenull
s / type casts / exploit unsoundness of Java's type system, that is).
In combination, it means that List<? extends T>
is kind-of like an append-protected list, with type-level append-protection.
You can actually do meaningful computations with such "append-protected" lists. Here are a few examples:
You can create append-protected lists with a single element:
public static <T> List<? extends T> pure(T t) {
List<T> result = new LinkedList<T>();
result.add(t);
return result;
}
You can create append-protected lists from ordinary lists:
public static <T> List<? extends T> toAppendProtected(List<T> original) {
List<T> result = new LinkedList<T>();
result.addAll(original);
return result;
}
You can combine append-protected lists:
public static <T> List<? extends T> combineAppendProtected(
List<? extends T> a,
List<? extends T> b
) {
List<T> result = new LinkedList<T>();
result.addAll(a);
result.addAll(b);
return result;
}
And, most importantly for this question, you can implement a method that returns an empty append-protected list of given type:
public static <T> List<? extends T> emptyAppendProtected() {
return new LinkedList<T>();
}
Together, combine
and empty
form an actual algebraic structure (a monoid), and methods like pure
ensure that it's non-degenerate (i.e. it has more elements that just an empty list). Indeed, if you had an interface similar to the usual Monoid typeclass:
public static interface Monoid<X> {
X empty();
X combine(X a, X b);
}
then you could use the above methods to implement it as follows:
public static <T> Monoid<List<? extends T>> appendProtectedListsMonoid() {
return new Monoid<List<? extends T>>() {
public List<? extends T> empty() {
return ReadOnlyLists.<T>emptyAppendProtected();
}
public List<? extends T> combine(
List<? extends T> a,
List<? extends T> b
) {
return combineAppendProtected(a, b);
}
};
}
This shows that methods with the signature given in your question can be used to implement some common design patterns / algebraic structures (monoids). Admittedly, the example is somewhat contrived, you probably wouldn't want to use it in practice, because you don't want to astonish the users of your API too much.
Full compilable example:
import java.util.*;
class AppendProtectedLists {
public static <T> List<? extends T> emptyAppendProtected() {
return new LinkedList<T>();
}
public static <T> List<? extends T> combineAppendProtected(
List<? extends T> a,
List<? extends T> b
) {
List<T> result = new LinkedList<T>();
result.addAll(a);
result.addAll(b);
return result;
}
public static <T> List<? extends T> toAppendProtected(List<T> original) {
List<T> result = new LinkedList<T>();
result.addAll(original);
return result;
}
public static <T> List<? extends T> pure(T t) {
List<T> result = new LinkedList<T>();
result.add(t);
return result;
}
public static interface Monoid<X> {
X empty();
X combine(X a, X b);
}
public static <T> Monoid<List<? extends T>> appendProtectedListsMonoid() {
return new Monoid<List<? extends T>>() {
public List<? extends T> empty() {
return AppendProtectedLists.<T>emptyAppendProtected();
}
public List<? extends T> combine(
List<? extends T> a,
List<? extends T> b
) {
return combineAppendProtected(a, b);
}
};
}
public static void main(String args) {
Monoid<List<? extends String>> monoid = appendProtectedListsMonoid();
List<? extends String> e = monoid.empty();
// e.add("hi"); // refuses to compile, which is good: write protection!
List<? extends String> a = pure("a");
List<? extends String> b = pure("b");
List<? extends String> c = monoid.combine(e, monoid.combine(a, b));
System.out.println(c); // output: [a, b]
}
}
add a comment |
This method signature is "useful", in the sense that you can implement non-trivial, non-degenerate methods with it (that is, returning null
and throwing errors are not your only options). As the following example shows, such a method can be useful for implementing some algebraic structures like e.g. monoids.
First, observe that List<? extends T>
is a type with the following properties:
- You know that all elements of this list conform to the type
T
, so whenever you extract an element from this list, you can use it in position where aT
is expected. You can read from this list. - The exact type is unknown, so you can never be certain that an instance of a particular subtype of
T
can be added to this list. That is, you effectively cannot add new elements to such a list (unless you usenull
s / type casts / exploit unsoundness of Java's type system, that is).
In combination, it means that List<? extends T>
is kind-of like an append-protected list, with type-level append-protection.
You can actually do meaningful computations with such "append-protected" lists. Here are a few examples:
You can create append-protected lists with a single element:
public static <T> List<? extends T> pure(T t) {
List<T> result = new LinkedList<T>();
result.add(t);
return result;
}
You can create append-protected lists from ordinary lists:
public static <T> List<? extends T> toAppendProtected(List<T> original) {
List<T> result = new LinkedList<T>();
result.addAll(original);
return result;
}
You can combine append-protected lists:
public static <T> List<? extends T> combineAppendProtected(
List<? extends T> a,
List<? extends T> b
) {
List<T> result = new LinkedList<T>();
result.addAll(a);
result.addAll(b);
return result;
}
And, most importantly for this question, you can implement a method that returns an empty append-protected list of given type:
public static <T> List<? extends T> emptyAppendProtected() {
return new LinkedList<T>();
}
Together, combine
and empty
form an actual algebraic structure (a monoid), and methods like pure
ensure that it's non-degenerate (i.e. it has more elements that just an empty list). Indeed, if you had an interface similar to the usual Monoid typeclass:
public static interface Monoid<X> {
X empty();
X combine(X a, X b);
}
then you could use the above methods to implement it as follows:
public static <T> Monoid<List<? extends T>> appendProtectedListsMonoid() {
return new Monoid<List<? extends T>>() {
public List<? extends T> empty() {
return ReadOnlyLists.<T>emptyAppendProtected();
}
public List<? extends T> combine(
List<? extends T> a,
List<? extends T> b
) {
return combineAppendProtected(a, b);
}
};
}
This shows that methods with the signature given in your question can be used to implement some common design patterns / algebraic structures (monoids). Admittedly, the example is somewhat contrived, you probably wouldn't want to use it in practice, because you don't want to astonish the users of your API too much.
Full compilable example:
import java.util.*;
class AppendProtectedLists {
public static <T> List<? extends T> emptyAppendProtected() {
return new LinkedList<T>();
}
public static <T> List<? extends T> combineAppendProtected(
List<? extends T> a,
List<? extends T> b
) {
List<T> result = new LinkedList<T>();
result.addAll(a);
result.addAll(b);
return result;
}
public static <T> List<? extends T> toAppendProtected(List<T> original) {
List<T> result = new LinkedList<T>();
result.addAll(original);
return result;
}
public static <T> List<? extends T> pure(T t) {
List<T> result = new LinkedList<T>();
result.add(t);
return result;
}
public static interface Monoid<X> {
X empty();
X combine(X a, X b);
}
public static <T> Monoid<List<? extends T>> appendProtectedListsMonoid() {
return new Monoid<List<? extends T>>() {
public List<? extends T> empty() {
return AppendProtectedLists.<T>emptyAppendProtected();
}
public List<? extends T> combine(
List<? extends T> a,
List<? extends T> b
) {
return combineAppendProtected(a, b);
}
};
}
public static void main(String args) {
Monoid<List<? extends String>> monoid = appendProtectedListsMonoid();
List<? extends String> e = monoid.empty();
// e.add("hi"); // refuses to compile, which is good: write protection!
List<? extends String> a = pure("a");
List<? extends String> b = pure("b");
List<? extends String> c = monoid.combine(e, monoid.combine(a, b));
System.out.println(c); // output: [a, b]
}
}
add a comment |
This method signature is "useful", in the sense that you can implement non-trivial, non-degenerate methods with it (that is, returning null
and throwing errors are not your only options). As the following example shows, such a method can be useful for implementing some algebraic structures like e.g. monoids.
First, observe that List<? extends T>
is a type with the following properties:
- You know that all elements of this list conform to the type
T
, so whenever you extract an element from this list, you can use it in position where aT
is expected. You can read from this list. - The exact type is unknown, so you can never be certain that an instance of a particular subtype of
T
can be added to this list. That is, you effectively cannot add new elements to such a list (unless you usenull
s / type casts / exploit unsoundness of Java's type system, that is).
In combination, it means that List<? extends T>
is kind-of like an append-protected list, with type-level append-protection.
You can actually do meaningful computations with such "append-protected" lists. Here are a few examples:
You can create append-protected lists with a single element:
public static <T> List<? extends T> pure(T t) {
List<T> result = new LinkedList<T>();
result.add(t);
return result;
}
You can create append-protected lists from ordinary lists:
public static <T> List<? extends T> toAppendProtected(List<T> original) {
List<T> result = new LinkedList<T>();
result.addAll(original);
return result;
}
You can combine append-protected lists:
public static <T> List<? extends T> combineAppendProtected(
List<? extends T> a,
List<? extends T> b
) {
List<T> result = new LinkedList<T>();
result.addAll(a);
result.addAll(b);
return result;
}
And, most importantly for this question, you can implement a method that returns an empty append-protected list of given type:
public static <T> List<? extends T> emptyAppendProtected() {
return new LinkedList<T>();
}
Together, combine
and empty
form an actual algebraic structure (a monoid), and methods like pure
ensure that it's non-degenerate (i.e. it has more elements that just an empty list). Indeed, if you had an interface similar to the usual Monoid typeclass:
public static interface Monoid<X> {
X empty();
X combine(X a, X b);
}
then you could use the above methods to implement it as follows:
public static <T> Monoid<List<? extends T>> appendProtectedListsMonoid() {
return new Monoid<List<? extends T>>() {
public List<? extends T> empty() {
return ReadOnlyLists.<T>emptyAppendProtected();
}
public List<? extends T> combine(
List<? extends T> a,
List<? extends T> b
) {
return combineAppendProtected(a, b);
}
};
}
This shows that methods with the signature given in your question can be used to implement some common design patterns / algebraic structures (monoids). Admittedly, the example is somewhat contrived, you probably wouldn't want to use it in practice, because you don't want to astonish the users of your API too much.
Full compilable example:
import java.util.*;
class AppendProtectedLists {
public static <T> List<? extends T> emptyAppendProtected() {
return new LinkedList<T>();
}
public static <T> List<? extends T> combineAppendProtected(
List<? extends T> a,
List<? extends T> b
) {
List<T> result = new LinkedList<T>();
result.addAll(a);
result.addAll(b);
return result;
}
public static <T> List<? extends T> toAppendProtected(List<T> original) {
List<T> result = new LinkedList<T>();
result.addAll(original);
return result;
}
public static <T> List<? extends T> pure(T t) {
List<T> result = new LinkedList<T>();
result.add(t);
return result;
}
public static interface Monoid<X> {
X empty();
X combine(X a, X b);
}
public static <T> Monoid<List<? extends T>> appendProtectedListsMonoid() {
return new Monoid<List<? extends T>>() {
public List<? extends T> empty() {
return AppendProtectedLists.<T>emptyAppendProtected();
}
public List<? extends T> combine(
List<? extends T> a,
List<? extends T> b
) {
return combineAppendProtected(a, b);
}
};
}
public static void main(String args) {
Monoid<List<? extends String>> monoid = appendProtectedListsMonoid();
List<? extends String> e = monoid.empty();
// e.add("hi"); // refuses to compile, which is good: write protection!
List<? extends String> a = pure("a");
List<? extends String> b = pure("b");
List<? extends String> c = monoid.combine(e, monoid.combine(a, b));
System.out.println(c); // output: [a, b]
}
}
This method signature is "useful", in the sense that you can implement non-trivial, non-degenerate methods with it (that is, returning null
and throwing errors are not your only options). As the following example shows, such a method can be useful for implementing some algebraic structures like e.g. monoids.
First, observe that List<? extends T>
is a type with the following properties:
- You know that all elements of this list conform to the type
T
, so whenever you extract an element from this list, you can use it in position where aT
is expected. You can read from this list. - The exact type is unknown, so you can never be certain that an instance of a particular subtype of
T
can be added to this list. That is, you effectively cannot add new elements to such a list (unless you usenull
s / type casts / exploit unsoundness of Java's type system, that is).
In combination, it means that List<? extends T>
is kind-of like an append-protected list, with type-level append-protection.
You can actually do meaningful computations with such "append-protected" lists. Here are a few examples:
You can create append-protected lists with a single element:
public static <T> List<? extends T> pure(T t) {
List<T> result = new LinkedList<T>();
result.add(t);
return result;
}
You can create append-protected lists from ordinary lists:
public static <T> List<? extends T> toAppendProtected(List<T> original) {
List<T> result = new LinkedList<T>();
result.addAll(original);
return result;
}
You can combine append-protected lists:
public static <T> List<? extends T> combineAppendProtected(
List<? extends T> a,
List<? extends T> b
) {
List<T> result = new LinkedList<T>();
result.addAll(a);
result.addAll(b);
return result;
}
And, most importantly for this question, you can implement a method that returns an empty append-protected list of given type:
public static <T> List<? extends T> emptyAppendProtected() {
return new LinkedList<T>();
}
Together, combine
and empty
form an actual algebraic structure (a monoid), and methods like pure
ensure that it's non-degenerate (i.e. it has more elements that just an empty list). Indeed, if you had an interface similar to the usual Monoid typeclass:
public static interface Monoid<X> {
X empty();
X combine(X a, X b);
}
then you could use the above methods to implement it as follows:
public static <T> Monoid<List<? extends T>> appendProtectedListsMonoid() {
return new Monoid<List<? extends T>>() {
public List<? extends T> empty() {
return ReadOnlyLists.<T>emptyAppendProtected();
}
public List<? extends T> combine(
List<? extends T> a,
List<? extends T> b
) {
return combineAppendProtected(a, b);
}
};
}
This shows that methods with the signature given in your question can be used to implement some common design patterns / algebraic structures (monoids). Admittedly, the example is somewhat contrived, you probably wouldn't want to use it in practice, because you don't want to astonish the users of your API too much.
Full compilable example:
import java.util.*;
class AppendProtectedLists {
public static <T> List<? extends T> emptyAppendProtected() {
return new LinkedList<T>();
}
public static <T> List<? extends T> combineAppendProtected(
List<? extends T> a,
List<? extends T> b
) {
List<T> result = new LinkedList<T>();
result.addAll(a);
result.addAll(b);
return result;
}
public static <T> List<? extends T> toAppendProtected(List<T> original) {
List<T> result = new LinkedList<T>();
result.addAll(original);
return result;
}
public static <T> List<? extends T> pure(T t) {
List<T> result = new LinkedList<T>();
result.add(t);
return result;
}
public static interface Monoid<X> {
X empty();
X combine(X a, X b);
}
public static <T> Monoid<List<? extends T>> appendProtectedListsMonoid() {
return new Monoid<List<? extends T>>() {
public List<? extends T> empty() {
return AppendProtectedLists.<T>emptyAppendProtected();
}
public List<? extends T> combine(
List<? extends T> a,
List<? extends T> b
) {
return combineAppendProtected(a, b);
}
};
}
public static void main(String args) {
Monoid<List<? extends String>> monoid = appendProtectedListsMonoid();
List<? extends String> e = monoid.empty();
// e.add("hi"); // refuses to compile, which is good: write protection!
List<? extends String> a = pure("a");
List<? extends String> b = pure("b");
List<? extends String> c = monoid.combine(e, monoid.combine(a, b));
System.out.println(c); // output: [a, b]
}
}
edited Jan 9 at 11:11
answered Jan 2 at 14:37
Andrey TyukinAndrey Tyukin
28.9k42350
28.9k42350
add a comment |
add a comment |
I interpret "is it a useful signature" to mean "can you think of a use-case for it".
T
is determined at the call site, not inside the method, so there are only two things that you can return from the method: null or an empty list.
Given that you can create both of these values in roughly as much code as invoking this method, there isn't really a good reason to use it.
Actually, another value that can be safely returned is a list where all of the elements are null. But this isn't useful either, since you can only invoke methods which add or remove literal null from the return value, because of the ? extends
in the type bound. So all you've got is thing which counts the number of nulls it contains. Which isn't useful either.
Well, looking very desperately for a contrived way of making it useful, you could have called asetReturnType(Class<?> cls)
method on the same object beforehand, and thenf()
would use that information to return a list of the required type.
– DodgyCodeException
Jan 2 at 10:53
1
@DodgyCodeException I suppose - but this would be the protocol anti-pattern.
– Boris the Spider
Jan 2 at 11:38
"Given that you can create both of these values in roughly as much code as invoking this method, there isn't really a good reason to use it." Really? Invoking.<String>empty()
seems way more pleasant than invoking((List<? extends String>) new List<String>())
. How would you construct an expression of typeList<? extends String>
without such a method?
– Andrey Tyukin
Jan 2 at 14:45
1
@AndreyTyukinList<? extends String> list = new ArrayList<>();
. Or even justnew List<String>
- that's aList<? extends String>
.
– Andy Turner
Jan 2 at 14:45
@AndyTurner That's a statement, not an expression. One would have to pollute the local scope with extra variables (likelist
). The simple idea of instantiating an empty append-protected list would be spread over two different lines in code. And this statement is still way longer than a simple.<String>empty()
. Thenew List<String>()
is aList<? extends String>
only if it's in a context where the type inference expects aList<? extends String>
. It's not so useful if you want to create an expression that guides type inference instead of relying on it.
– Andrey Tyukin
Jan 2 at 14:48
add a comment |
I interpret "is it a useful signature" to mean "can you think of a use-case for it".
T
is determined at the call site, not inside the method, so there are only two things that you can return from the method: null or an empty list.
Given that you can create both of these values in roughly as much code as invoking this method, there isn't really a good reason to use it.
Actually, another value that can be safely returned is a list where all of the elements are null. But this isn't useful either, since you can only invoke methods which add or remove literal null from the return value, because of the ? extends
in the type bound. So all you've got is thing which counts the number of nulls it contains. Which isn't useful either.
Well, looking very desperately for a contrived way of making it useful, you could have called asetReturnType(Class<?> cls)
method on the same object beforehand, and thenf()
would use that information to return a list of the required type.
– DodgyCodeException
Jan 2 at 10:53
1
@DodgyCodeException I suppose - but this would be the protocol anti-pattern.
– Boris the Spider
Jan 2 at 11:38
"Given that you can create both of these values in roughly as much code as invoking this method, there isn't really a good reason to use it." Really? Invoking.<String>empty()
seems way more pleasant than invoking((List<? extends String>) new List<String>())
. How would you construct an expression of typeList<? extends String>
without such a method?
– Andrey Tyukin
Jan 2 at 14:45
1
@AndreyTyukinList<? extends String> list = new ArrayList<>();
. Or even justnew List<String>
- that's aList<? extends String>
.
– Andy Turner
Jan 2 at 14:45
@AndyTurner That's a statement, not an expression. One would have to pollute the local scope with extra variables (likelist
). The simple idea of instantiating an empty append-protected list would be spread over two different lines in code. And this statement is still way longer than a simple.<String>empty()
. Thenew List<String>()
is aList<? extends String>
only if it's in a context where the type inference expects aList<? extends String>
. It's not so useful if you want to create an expression that guides type inference instead of relying on it.
– Andrey Tyukin
Jan 2 at 14:48
add a comment |
I interpret "is it a useful signature" to mean "can you think of a use-case for it".
T
is determined at the call site, not inside the method, so there are only two things that you can return from the method: null or an empty list.
Given that you can create both of these values in roughly as much code as invoking this method, there isn't really a good reason to use it.
Actually, another value that can be safely returned is a list where all of the elements are null. But this isn't useful either, since you can only invoke methods which add or remove literal null from the return value, because of the ? extends
in the type bound. So all you've got is thing which counts the number of nulls it contains. Which isn't useful either.
I interpret "is it a useful signature" to mean "can you think of a use-case for it".
T
is determined at the call site, not inside the method, so there are only two things that you can return from the method: null or an empty list.
Given that you can create both of these values in roughly as much code as invoking this method, there isn't really a good reason to use it.
Actually, another value that can be safely returned is a list where all of the elements are null. But this isn't useful either, since you can only invoke methods which add or remove literal null from the return value, because of the ? extends
in the type bound. So all you've got is thing which counts the number of nulls it contains. Which isn't useful either.
edited Jan 2 at 10:55
answered Jan 2 at 10:50
Andy TurnerAndy Turner
83.3k983141
83.3k983141
Well, looking very desperately for a contrived way of making it useful, you could have called asetReturnType(Class<?> cls)
method on the same object beforehand, and thenf()
would use that information to return a list of the required type.
– DodgyCodeException
Jan 2 at 10:53
1
@DodgyCodeException I suppose - but this would be the protocol anti-pattern.
– Boris the Spider
Jan 2 at 11:38
"Given that you can create both of these values in roughly as much code as invoking this method, there isn't really a good reason to use it." Really? Invoking.<String>empty()
seems way more pleasant than invoking((List<? extends String>) new List<String>())
. How would you construct an expression of typeList<? extends String>
without such a method?
– Andrey Tyukin
Jan 2 at 14:45
1
@AndreyTyukinList<? extends String> list = new ArrayList<>();
. Or even justnew List<String>
- that's aList<? extends String>
.
– Andy Turner
Jan 2 at 14:45
@AndyTurner That's a statement, not an expression. One would have to pollute the local scope with extra variables (likelist
). The simple idea of instantiating an empty append-protected list would be spread over two different lines in code. And this statement is still way longer than a simple.<String>empty()
. Thenew List<String>()
is aList<? extends String>
only if it's in a context where the type inference expects aList<? extends String>
. It's not so useful if you want to create an expression that guides type inference instead of relying on it.
– Andrey Tyukin
Jan 2 at 14:48
add a comment |
Well, looking very desperately for a contrived way of making it useful, you could have called asetReturnType(Class<?> cls)
method on the same object beforehand, and thenf()
would use that information to return a list of the required type.
– DodgyCodeException
Jan 2 at 10:53
1
@DodgyCodeException I suppose - but this would be the protocol anti-pattern.
– Boris the Spider
Jan 2 at 11:38
"Given that you can create both of these values in roughly as much code as invoking this method, there isn't really a good reason to use it." Really? Invoking.<String>empty()
seems way more pleasant than invoking((List<? extends String>) new List<String>())
. How would you construct an expression of typeList<? extends String>
without such a method?
– Andrey Tyukin
Jan 2 at 14:45
1
@AndreyTyukinList<? extends String> list = new ArrayList<>();
. Or even justnew List<String>
- that's aList<? extends String>
.
– Andy Turner
Jan 2 at 14:45
@AndyTurner That's a statement, not an expression. One would have to pollute the local scope with extra variables (likelist
). The simple idea of instantiating an empty append-protected list would be spread over two different lines in code. And this statement is still way longer than a simple.<String>empty()
. Thenew List<String>()
is aList<? extends String>
only if it's in a context where the type inference expects aList<? extends String>
. It's not so useful if you want to create an expression that guides type inference instead of relying on it.
– Andrey Tyukin
Jan 2 at 14:48
Well, looking very desperately for a contrived way of making it useful, you could have called a
setReturnType(Class<?> cls)
method on the same object beforehand, and then f()
would use that information to return a list of the required type.– DodgyCodeException
Jan 2 at 10:53
Well, looking very desperately for a contrived way of making it useful, you could have called a
setReturnType(Class<?> cls)
method on the same object beforehand, and then f()
would use that information to return a list of the required type.– DodgyCodeException
Jan 2 at 10:53
1
1
@DodgyCodeException I suppose - but this would be the protocol anti-pattern.
– Boris the Spider
Jan 2 at 11:38
@DodgyCodeException I suppose - but this would be the protocol anti-pattern.
– Boris the Spider
Jan 2 at 11:38
"Given that you can create both of these values in roughly as much code as invoking this method, there isn't really a good reason to use it." Really? Invoking
.<String>empty()
seems way more pleasant than invoking ((List<? extends String>) new List<String>())
. How would you construct an expression of type List<? extends String>
without such a method?– Andrey Tyukin
Jan 2 at 14:45
"Given that you can create both of these values in roughly as much code as invoking this method, there isn't really a good reason to use it." Really? Invoking
.<String>empty()
seems way more pleasant than invoking ((List<? extends String>) new List<String>())
. How would you construct an expression of type List<? extends String>
without such a method?– Andrey Tyukin
Jan 2 at 14:45
1
1
@AndreyTyukin
List<? extends String> list = new ArrayList<>();
. Or even just new List<String>
- that's a List<? extends String>
.– Andy Turner
Jan 2 at 14:45
@AndreyTyukin
List<? extends String> list = new ArrayList<>();
. Or even just new List<String>
- that's a List<? extends String>
.– Andy Turner
Jan 2 at 14:45
@AndyTurner That's a statement, not an expression. One would have to pollute the local scope with extra variables (like
list
). The simple idea of instantiating an empty append-protected list would be spread over two different lines in code. And this statement is still way longer than a simple .<String>empty()
. The new List<String>()
is a List<? extends String>
only if it's in a context where the type inference expects a List<? extends String>
. It's not so useful if you want to create an expression that guides type inference instead of relying on it.– Andrey Tyukin
Jan 2 at 14:48
@AndyTurner That's a statement, not an expression. One would have to pollute the local scope with extra variables (like
list
). The simple idea of instantiating an empty append-protected list would be spread over two different lines in code. And this statement is still way longer than a simple .<String>empty()
. The new List<String>()
is a List<? extends String>
only if it's in a context where the type inference expects a List<? extends String>
. It's not so useful if you want to create an expression that guides type inference instead of relying on it.– Andrey Tyukin
Jan 2 at 14:48
add a comment |
The official Generics tutorial suggests not to use wildcard return types.
These guidelines do not apply to a method's return type. Using a wildcard as a return type should be avoided because it forces programmers using the code to deal with wildcards."
The reasoning given isn't exactly convincing, though.
add a comment |
The official Generics tutorial suggests not to use wildcard return types.
These guidelines do not apply to a method's return type. Using a wildcard as a return type should be avoided because it forces programmers using the code to deal with wildcards."
The reasoning given isn't exactly convincing, though.
add a comment |
The official Generics tutorial suggests not to use wildcard return types.
These guidelines do not apply to a method's return type. Using a wildcard as a return type should be avoided because it forces programmers using the code to deal with wildcards."
The reasoning given isn't exactly convincing, though.
The official Generics tutorial suggests not to use wildcard return types.
These guidelines do not apply to a method's return type. Using a wildcard as a return type should be avoided because it forces programmers using the code to deal with wildcards."
The reasoning given isn't exactly convincing, though.
edited Jan 2 at 11:53
Andy Turner
83.3k983141
83.3k983141
answered Jan 2 at 11:22
togorkstogorks
486
486
add a comment |
add a comment |
It's not particularly useful, for the reasons given in other answers. However, consider it's "usefulness" in a class like the following (although it's probably a bit of an antipattern):
public class Repository {
private List<Object> lst = new ArrayList<>();
public <T> void add(T item) {
lst.add(item);
}
@SuppressWarnings("unchecked")
public <T> List<? extends T> f() {
return (List<? extends T>) lst;
}
public static void main(String args) {
Repository rep = new Repository();
rep.add(BigInteger.ONE);
rep.add(Double.valueOf(2.0));
List<? extends Number> list = rep.f();
System.out.println(list.get(0).doubleValue() + list.get(1).doubleValue());
}
}
Note the following features:
- The declared return type of f() means that the caller can set whatever T they like and the method will return the required type. If f() weren't declared like that, then the caller would need to cast every call to
get(N)
to the required type. - As it uses a wildcard, the declared return type makes the returned list read-only. This can often be a useful feature. When caller a getter, you don't want it to return a list you can write to. Often, getters use
Collections.unmodifiableList()
which forces a list to be read-only at run-time, but using the wildcard generic parameter forces the list to be read-only at compile-time! - The drawback is that it's not particularly type-safe. It is up to the caller to ensure that f() returns a type where T is a common superclass of all the previously added items.
- It would typically be much better to make the class Repository generic instead of the method f().
3
Wildcard lists aren't read-only. You can remove elements, you can addnull
to the list, and you can use a wildcard capturing helper method to add and reorder its own elements.
– Radiodef
Jan 2 at 14:37
add a comment |
It's not particularly useful, for the reasons given in other answers. However, consider it's "usefulness" in a class like the following (although it's probably a bit of an antipattern):
public class Repository {
private List<Object> lst = new ArrayList<>();
public <T> void add(T item) {
lst.add(item);
}
@SuppressWarnings("unchecked")
public <T> List<? extends T> f() {
return (List<? extends T>) lst;
}
public static void main(String args) {
Repository rep = new Repository();
rep.add(BigInteger.ONE);
rep.add(Double.valueOf(2.0));
List<? extends Number> list = rep.f();
System.out.println(list.get(0).doubleValue() + list.get(1).doubleValue());
}
}
Note the following features:
- The declared return type of f() means that the caller can set whatever T they like and the method will return the required type. If f() weren't declared like that, then the caller would need to cast every call to
get(N)
to the required type. - As it uses a wildcard, the declared return type makes the returned list read-only. This can often be a useful feature. When caller a getter, you don't want it to return a list you can write to. Often, getters use
Collections.unmodifiableList()
which forces a list to be read-only at run-time, but using the wildcard generic parameter forces the list to be read-only at compile-time! - The drawback is that it's not particularly type-safe. It is up to the caller to ensure that f() returns a type where T is a common superclass of all the previously added items.
- It would typically be much better to make the class Repository generic instead of the method f().
3
Wildcard lists aren't read-only. You can remove elements, you can addnull
to the list, and you can use a wildcard capturing helper method to add and reorder its own elements.
– Radiodef
Jan 2 at 14:37
add a comment |
It's not particularly useful, for the reasons given in other answers. However, consider it's "usefulness" in a class like the following (although it's probably a bit of an antipattern):
public class Repository {
private List<Object> lst = new ArrayList<>();
public <T> void add(T item) {
lst.add(item);
}
@SuppressWarnings("unchecked")
public <T> List<? extends T> f() {
return (List<? extends T>) lst;
}
public static void main(String args) {
Repository rep = new Repository();
rep.add(BigInteger.ONE);
rep.add(Double.valueOf(2.0));
List<? extends Number> list = rep.f();
System.out.println(list.get(0).doubleValue() + list.get(1).doubleValue());
}
}
Note the following features:
- The declared return type of f() means that the caller can set whatever T they like and the method will return the required type. If f() weren't declared like that, then the caller would need to cast every call to
get(N)
to the required type. - As it uses a wildcard, the declared return type makes the returned list read-only. This can often be a useful feature. When caller a getter, you don't want it to return a list you can write to. Often, getters use
Collections.unmodifiableList()
which forces a list to be read-only at run-time, but using the wildcard generic parameter forces the list to be read-only at compile-time! - The drawback is that it's not particularly type-safe. It is up to the caller to ensure that f() returns a type where T is a common superclass of all the previously added items.
- It would typically be much better to make the class Repository generic instead of the method f().
It's not particularly useful, for the reasons given in other answers. However, consider it's "usefulness" in a class like the following (although it's probably a bit of an antipattern):
public class Repository {
private List<Object> lst = new ArrayList<>();
public <T> void add(T item) {
lst.add(item);
}
@SuppressWarnings("unchecked")
public <T> List<? extends T> f() {
return (List<? extends T>) lst;
}
public static void main(String args) {
Repository rep = new Repository();
rep.add(BigInteger.ONE);
rep.add(Double.valueOf(2.0));
List<? extends Number> list = rep.f();
System.out.println(list.get(0).doubleValue() + list.get(1).doubleValue());
}
}
Note the following features:
- The declared return type of f() means that the caller can set whatever T they like and the method will return the required type. If f() weren't declared like that, then the caller would need to cast every call to
get(N)
to the required type. - As it uses a wildcard, the declared return type makes the returned list read-only. This can often be a useful feature. When caller a getter, you don't want it to return a list you can write to. Often, getters use
Collections.unmodifiableList()
which forces a list to be read-only at run-time, but using the wildcard generic parameter forces the list to be read-only at compile-time! - The drawback is that it's not particularly type-safe. It is up to the caller to ensure that f() returns a type where T is a common superclass of all the previously added items.
- It would typically be much better to make the class Repository generic instead of the method f().
edited Jan 2 at 13:55
answered Jan 2 at 13:42
DodgyCodeExceptionDodgyCodeException
3,5561424
3,5561424
3
Wildcard lists aren't read-only. You can remove elements, you can addnull
to the list, and you can use a wildcard capturing helper method to add and reorder its own elements.
– Radiodef
Jan 2 at 14:37
add a comment |
3
Wildcard lists aren't read-only. You can remove elements, you can addnull
to the list, and you can use a wildcard capturing helper method to add and reorder its own elements.
– Radiodef
Jan 2 at 14:37
3
3
Wildcard lists aren't read-only. You can remove elements, you can add
null
to the list, and you can use a wildcard capturing helper method to add and reorder its own elements.– Radiodef
Jan 2 at 14:37
Wildcard lists aren't read-only. You can remove elements, you can add
null
to the list, and you can use a wildcard capturing helper method to add and reorder its own elements.– Radiodef
Jan 2 at 14:37
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54004821%2fis-t-list-extends-t-f-a-useful-signature-is-there-any-problem-with-it%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
3
Returning a wildcard is not really useful
– NEGR KITAEC
Jan 2 at 10:41
1
You can still call
add(null)
etc.– Andy Turner
Jan 2 at 10:46
1
Using type inference you can just do
List<? extends Number> lst = s.f();
. Also, you can doNumber number = lst.get(0); System.out.println(number);
.– DodgyCodeException
Jan 2 at 10:48
3
I think that what the interviewer was getting at was the fact that the return type of the method contains a wildcard. From Effective Java, 2nd Ed. "You should not return a wildcard type because it forces the users of an API to deal with wildcards." (paraphrased) Perhaps the best answer is that the return type is appropriate for use in package-private or private methods within a system, but it should not be used as part of an exported API.
– scottb
Jan 2 at 16:04
1
@ArtB no, the advice of the 2nd ed still very much stands: wildcards are to increase the flexibility of parameters; they should not be used in return types.
– Andy Turner
Jan 2 at 20:10