Isometric isomorphism between $L^2$ and $mathcal{L}^2$












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I was reading and trying to understand the proof that the space $mathcal{L}^2 (mathcal{H})$ (Hilbert-Schmidt operators) is made by all the $T_K:L^2(X,mu) rightarrow L^2(X,mu)$ with $K in L^2(X times X, mu times mu)$.



Basically we assume $T in mathcal{L}^2$ and show $K in L^2(X times X, mu times mu) $ such that $T = T_K$. I really don't understand pretty much about the proof.. anyone could help?










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    $begingroup$


    I was reading and trying to understand the proof that the space $mathcal{L}^2 (mathcal{H})$ (Hilbert-Schmidt operators) is made by all the $T_K:L^2(X,mu) rightarrow L^2(X,mu)$ with $K in L^2(X times X, mu times mu)$.



    Basically we assume $T in mathcal{L}^2$ and show $K in L^2(X times X, mu times mu) $ such that $T = T_K$. I really don't understand pretty much about the proof.. anyone could help?










    share|cite|improve this question









    $endgroup$















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      0








      0





      $begingroup$


      I was reading and trying to understand the proof that the space $mathcal{L}^2 (mathcal{H})$ (Hilbert-Schmidt operators) is made by all the $T_K:L^2(X,mu) rightarrow L^2(X,mu)$ with $K in L^2(X times X, mu times mu)$.



      Basically we assume $T in mathcal{L}^2$ and show $K in L^2(X times X, mu times mu) $ such that $T = T_K$. I really don't understand pretty much about the proof.. anyone could help?










      share|cite|improve this question









      $endgroup$




      I was reading and trying to understand the proof that the space $mathcal{L}^2 (mathcal{H})$ (Hilbert-Schmidt operators) is made by all the $T_K:L^2(X,mu) rightarrow L^2(X,mu)$ with $K in L^2(X times X, mu times mu)$.



      Basically we assume $T in mathcal{L}^2$ and show $K in L^2(X times X, mu times mu) $ such that $T = T_K$. I really don't understand pretty much about the proof.. anyone could help?







      functional-analysis hilbert-spaces compact-operators






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      asked Jan 10 at 16:06









      James ArtenJames Arten

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