The ampleness of canonical sheaves and the proof of “$X simeq mathrm{Proj}left(bigoplus_k H^0(X,...












0












$begingroup$


In Bondal and Orlov's paper, ''Reconstruction of a variety from the derived category and groups of autoequivalences'' (http://www.mi-ras.ru/~orlov/papers/Compositio2001.pdf), I think that they use the following result:




Let X be the smooth projective variety, $omega_X$ is the canonical
sheaf of $X$. If $omega_X$ is ample,
$$X simeqmathrm{Proj}left(bigoplus_k H^0(X, omega_X^k)right). $$




I am looking for a complete proof of this fact. I have read some literature, but the proof is omitted in them. Is this a simple fact? Could you tell me the proof or the literature on which it is listed?










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$endgroup$








  • 1




    $begingroup$
    If $R=oplus_{kgeq 0} R_k$ with $R_0=K$, the base field and $R$ finitely generated $K$-algebra, then consider $S=oplus_{n|k} R_ksubset R$ for some integer $n>0$. One easily checks that there is an induced isomorphism $mathrm{Proj},Rtomathrm{Proj}, S$. In your case, $omega_X$ is ample, so for a large enough $n$, $omega_X^n$ is very ample. Rest should be clear.
    $endgroup$
    – Mohan
    Jan 10 at 16:38
















0












$begingroup$


In Bondal and Orlov's paper, ''Reconstruction of a variety from the derived category and groups of autoequivalences'' (http://www.mi-ras.ru/~orlov/papers/Compositio2001.pdf), I think that they use the following result:




Let X be the smooth projective variety, $omega_X$ is the canonical
sheaf of $X$. If $omega_X$ is ample,
$$X simeqmathrm{Proj}left(bigoplus_k H^0(X, omega_X^k)right). $$




I am looking for a complete proof of this fact. I have read some literature, but the proof is omitted in them. Is this a simple fact? Could you tell me the proof or the literature on which it is listed?










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    If $R=oplus_{kgeq 0} R_k$ with $R_0=K$, the base field and $R$ finitely generated $K$-algebra, then consider $S=oplus_{n|k} R_ksubset R$ for some integer $n>0$. One easily checks that there is an induced isomorphism $mathrm{Proj},Rtomathrm{Proj}, S$. In your case, $omega_X$ is ample, so for a large enough $n$, $omega_X^n$ is very ample. Rest should be clear.
    $endgroup$
    – Mohan
    Jan 10 at 16:38














0












0








0





$begingroup$


In Bondal and Orlov's paper, ''Reconstruction of a variety from the derived category and groups of autoequivalences'' (http://www.mi-ras.ru/~orlov/papers/Compositio2001.pdf), I think that they use the following result:




Let X be the smooth projective variety, $omega_X$ is the canonical
sheaf of $X$. If $omega_X$ is ample,
$$X simeqmathrm{Proj}left(bigoplus_k H^0(X, omega_X^k)right). $$




I am looking for a complete proof of this fact. I have read some literature, but the proof is omitted in them. Is this a simple fact? Could you tell me the proof or the literature on which it is listed?










share|cite|improve this question









$endgroup$




In Bondal and Orlov's paper, ''Reconstruction of a variety from the derived category and groups of autoequivalences'' (http://www.mi-ras.ru/~orlov/papers/Compositio2001.pdf), I think that they use the following result:




Let X be the smooth projective variety, $omega_X$ is the canonical
sheaf of $X$. If $omega_X$ is ample,
$$X simeqmathrm{Proj}left(bigoplus_k H^0(X, omega_X^k)right). $$




I am looking for a complete proof of this fact. I have read some literature, but the proof is omitted in them. Is this a simple fact? Could you tell me the proof or the literature on which it is listed?







algebraic-geometry category-theory homology-cohomology sheaf-theory derived-categories






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 10 at 15:41









RuiSenRuiSen

61




61








  • 1




    $begingroup$
    If $R=oplus_{kgeq 0} R_k$ with $R_0=K$, the base field and $R$ finitely generated $K$-algebra, then consider $S=oplus_{n|k} R_ksubset R$ for some integer $n>0$. One easily checks that there is an induced isomorphism $mathrm{Proj},Rtomathrm{Proj}, S$. In your case, $omega_X$ is ample, so for a large enough $n$, $omega_X^n$ is very ample. Rest should be clear.
    $endgroup$
    – Mohan
    Jan 10 at 16:38














  • 1




    $begingroup$
    If $R=oplus_{kgeq 0} R_k$ with $R_0=K$, the base field and $R$ finitely generated $K$-algebra, then consider $S=oplus_{n|k} R_ksubset R$ for some integer $n>0$. One easily checks that there is an induced isomorphism $mathrm{Proj},Rtomathrm{Proj}, S$. In your case, $omega_X$ is ample, so for a large enough $n$, $omega_X^n$ is very ample. Rest should be clear.
    $endgroup$
    – Mohan
    Jan 10 at 16:38








1




1




$begingroup$
If $R=oplus_{kgeq 0} R_k$ with $R_0=K$, the base field and $R$ finitely generated $K$-algebra, then consider $S=oplus_{n|k} R_ksubset R$ for some integer $n>0$. One easily checks that there is an induced isomorphism $mathrm{Proj},Rtomathrm{Proj}, S$. In your case, $omega_X$ is ample, so for a large enough $n$, $omega_X^n$ is very ample. Rest should be clear.
$endgroup$
– Mohan
Jan 10 at 16:38




$begingroup$
If $R=oplus_{kgeq 0} R_k$ with $R_0=K$, the base field and $R$ finitely generated $K$-algebra, then consider $S=oplus_{n|k} R_ksubset R$ for some integer $n>0$. One easily checks that there is an induced isomorphism $mathrm{Proj},Rtomathrm{Proj}, S$. In your case, $omega_X$ is ample, so for a large enough $n$, $omega_X^n$ is very ample. Rest should be clear.
$endgroup$
– Mohan
Jan 10 at 16:38










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