Prove that a point in a circle equidistant from any three points on the circle is the centre












-1












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  1. Prove that a point in a circle equidistant from any three points on the circle is the centre


  2. $frac{1-1}{1-1}=?$











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  • $begingroup$
    For the second part: $0/0$ is not defined in mathematics.
    $endgroup$
    – Matti P.
    Jan 11 at 13:50










  • $begingroup$
    why both terms do not get cancelled?
    $endgroup$
    – Mohammad Noor Alam
    Jan 11 at 13:52










  • $begingroup$
    why answer is not 1
    $endgroup$
    – Mohammad Noor Alam
    Jan 11 at 13:52






  • 1




    $begingroup$
    math.stackexchange.com/questions/26445/division-by-0
    $endgroup$
    – EdOverflow
    Jan 11 at 13:59






  • 2




    $begingroup$
    @MohammadNoorAlam if $frac 00=n$, then $0 cdot n = 0$. How many ways can this be solved?
    $endgroup$
    – Rhys Hughes
    Jan 11 at 14:02
















-1












$begingroup$



  1. Prove that a point in a circle equidistant from any three points on the circle is the centre


  2. $frac{1-1}{1-1}=?$











share|cite|improve this question











$endgroup$












  • $begingroup$
    For the second part: $0/0$ is not defined in mathematics.
    $endgroup$
    – Matti P.
    Jan 11 at 13:50










  • $begingroup$
    why both terms do not get cancelled?
    $endgroup$
    – Mohammad Noor Alam
    Jan 11 at 13:52










  • $begingroup$
    why answer is not 1
    $endgroup$
    – Mohammad Noor Alam
    Jan 11 at 13:52






  • 1




    $begingroup$
    math.stackexchange.com/questions/26445/division-by-0
    $endgroup$
    – EdOverflow
    Jan 11 at 13:59






  • 2




    $begingroup$
    @MohammadNoorAlam if $frac 00=n$, then $0 cdot n = 0$. How many ways can this be solved?
    $endgroup$
    – Rhys Hughes
    Jan 11 at 14:02














-1












-1








-1





$begingroup$



  1. Prove that a point in a circle equidistant from any three points on the circle is the centre


  2. $frac{1-1}{1-1}=?$











share|cite|improve this question











$endgroup$





  1. Prove that a point in a circle equidistant from any three points on the circle is the centre


  2. $frac{1-1}{1-1}=?$








circles






share|cite|improve this question















share|cite|improve this question













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share|cite|improve this question








edited Jan 11 at 14:21









lioness99a

3,9012727




3,9012727










asked Jan 11 at 13:47









Mohammad Noor AlamMohammad Noor Alam

42




42












  • $begingroup$
    For the second part: $0/0$ is not defined in mathematics.
    $endgroup$
    – Matti P.
    Jan 11 at 13:50










  • $begingroup$
    why both terms do not get cancelled?
    $endgroup$
    – Mohammad Noor Alam
    Jan 11 at 13:52










  • $begingroup$
    why answer is not 1
    $endgroup$
    – Mohammad Noor Alam
    Jan 11 at 13:52






  • 1




    $begingroup$
    math.stackexchange.com/questions/26445/division-by-0
    $endgroup$
    – EdOverflow
    Jan 11 at 13:59






  • 2




    $begingroup$
    @MohammadNoorAlam if $frac 00=n$, then $0 cdot n = 0$. How many ways can this be solved?
    $endgroup$
    – Rhys Hughes
    Jan 11 at 14:02


















  • $begingroup$
    For the second part: $0/0$ is not defined in mathematics.
    $endgroup$
    – Matti P.
    Jan 11 at 13:50










  • $begingroup$
    why both terms do not get cancelled?
    $endgroup$
    – Mohammad Noor Alam
    Jan 11 at 13:52










  • $begingroup$
    why answer is not 1
    $endgroup$
    – Mohammad Noor Alam
    Jan 11 at 13:52






  • 1




    $begingroup$
    math.stackexchange.com/questions/26445/division-by-0
    $endgroup$
    – EdOverflow
    Jan 11 at 13:59






  • 2




    $begingroup$
    @MohammadNoorAlam if $frac 00=n$, then $0 cdot n = 0$. How many ways can this be solved?
    $endgroup$
    – Rhys Hughes
    Jan 11 at 14:02
















$begingroup$
For the second part: $0/0$ is not defined in mathematics.
$endgroup$
– Matti P.
Jan 11 at 13:50




$begingroup$
For the second part: $0/0$ is not defined in mathematics.
$endgroup$
– Matti P.
Jan 11 at 13:50












$begingroup$
why both terms do not get cancelled?
$endgroup$
– Mohammad Noor Alam
Jan 11 at 13:52




$begingroup$
why both terms do not get cancelled?
$endgroup$
– Mohammad Noor Alam
Jan 11 at 13:52












$begingroup$
why answer is not 1
$endgroup$
– Mohammad Noor Alam
Jan 11 at 13:52




$begingroup$
why answer is not 1
$endgroup$
– Mohammad Noor Alam
Jan 11 at 13:52




1




1




$begingroup$
math.stackexchange.com/questions/26445/division-by-0
$endgroup$
– EdOverflow
Jan 11 at 13:59




$begingroup$
math.stackexchange.com/questions/26445/division-by-0
$endgroup$
– EdOverflow
Jan 11 at 13:59




2




2




$begingroup$
@MohammadNoorAlam if $frac 00=n$, then $0 cdot n = 0$. How many ways can this be solved?
$endgroup$
– Rhys Hughes
Jan 11 at 14:02




$begingroup$
@MohammadNoorAlam if $frac 00=n$, then $0 cdot n = 0$. How many ways can this be solved?
$endgroup$
– Rhys Hughes
Jan 11 at 14:02










1 Answer
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Assume that $p$ is a point in the plane that is equidistant (say of length $r$) to three distinct points on the circle. Then the circle at $p$ of radius $r$ intersect the original circle at three points. If two circles intersect at three points then they must be the same and hence $p$ is the center of the original circle.






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    1 Answer
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    active

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    $begingroup$

    Assume that $p$ is a point in the plane that is equidistant (say of length $r$) to three distinct points on the circle. Then the circle at $p$ of radius $r$ intersect the original circle at three points. If two circles intersect at three points then they must be the same and hence $p$ is the center of the original circle.






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      Assume that $p$ is a point in the plane that is equidistant (say of length $r$) to three distinct points on the circle. Then the circle at $p$ of radius $r$ intersect the original circle at three points. If two circles intersect at three points then they must be the same and hence $p$ is the center of the original circle.






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        Assume that $p$ is a point in the plane that is equidistant (say of length $r$) to three distinct points on the circle. Then the circle at $p$ of radius $r$ intersect the original circle at three points. If two circles intersect at three points then they must be the same and hence $p$ is the center of the original circle.






        share|cite|improve this answer









        $endgroup$



        Assume that $p$ is a point in the plane that is equidistant (say of length $r$) to three distinct points on the circle. Then the circle at $p$ of radius $r$ intersect the original circle at three points. If two circles intersect at three points then they must be the same and hence $p$ is the center of the original circle.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Jan 11 at 13:55









        LeventLevent

        2,741925




        2,741925






























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