Prove that a point in a circle equidistant from any three points on the circle is the centre
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Prove that a point in a circle equidistant from any three points on the circle is the centre
$frac{1-1}{1-1}=?$
circles
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|
show 1 more comment
$begingroup$
Prove that a point in a circle equidistant from any three points on the circle is the centre
$frac{1-1}{1-1}=?$
circles
$endgroup$
$begingroup$
For the second part: $0/0$ is not defined in mathematics.
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– Matti P.
Jan 11 at 13:50
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why both terms do not get cancelled?
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– Mohammad Noor Alam
Jan 11 at 13:52
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why answer is not 1
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– Mohammad Noor Alam
Jan 11 at 13:52
1
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math.stackexchange.com/questions/26445/division-by-0
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– EdOverflow
Jan 11 at 13:59
2
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@MohammadNoorAlam if $frac 00=n$, then $0 cdot n = 0$. How many ways can this be solved?
$endgroup$
– Rhys Hughes
Jan 11 at 14:02
|
show 1 more comment
$begingroup$
Prove that a point in a circle equidistant from any three points on the circle is the centre
$frac{1-1}{1-1}=?$
circles
$endgroup$
Prove that a point in a circle equidistant from any three points on the circle is the centre
$frac{1-1}{1-1}=?$
circles
circles
edited Jan 11 at 14:21
lioness99a
3,9012727
3,9012727
asked Jan 11 at 13:47
Mohammad Noor AlamMohammad Noor Alam
42
42
$begingroup$
For the second part: $0/0$ is not defined in mathematics.
$endgroup$
– Matti P.
Jan 11 at 13:50
$begingroup$
why both terms do not get cancelled?
$endgroup$
– Mohammad Noor Alam
Jan 11 at 13:52
$begingroup$
why answer is not 1
$endgroup$
– Mohammad Noor Alam
Jan 11 at 13:52
1
$begingroup$
math.stackexchange.com/questions/26445/division-by-0
$endgroup$
– EdOverflow
Jan 11 at 13:59
2
$begingroup$
@MohammadNoorAlam if $frac 00=n$, then $0 cdot n = 0$. How many ways can this be solved?
$endgroup$
– Rhys Hughes
Jan 11 at 14:02
|
show 1 more comment
$begingroup$
For the second part: $0/0$ is not defined in mathematics.
$endgroup$
– Matti P.
Jan 11 at 13:50
$begingroup$
why both terms do not get cancelled?
$endgroup$
– Mohammad Noor Alam
Jan 11 at 13:52
$begingroup$
why answer is not 1
$endgroup$
– Mohammad Noor Alam
Jan 11 at 13:52
1
$begingroup$
math.stackexchange.com/questions/26445/division-by-0
$endgroup$
– EdOverflow
Jan 11 at 13:59
2
$begingroup$
@MohammadNoorAlam if $frac 00=n$, then $0 cdot n = 0$. How many ways can this be solved?
$endgroup$
– Rhys Hughes
Jan 11 at 14:02
$begingroup$
For the second part: $0/0$ is not defined in mathematics.
$endgroup$
– Matti P.
Jan 11 at 13:50
$begingroup$
For the second part: $0/0$ is not defined in mathematics.
$endgroup$
– Matti P.
Jan 11 at 13:50
$begingroup$
why both terms do not get cancelled?
$endgroup$
– Mohammad Noor Alam
Jan 11 at 13:52
$begingroup$
why both terms do not get cancelled?
$endgroup$
– Mohammad Noor Alam
Jan 11 at 13:52
$begingroup$
why answer is not 1
$endgroup$
– Mohammad Noor Alam
Jan 11 at 13:52
$begingroup$
why answer is not 1
$endgroup$
– Mohammad Noor Alam
Jan 11 at 13:52
1
1
$begingroup$
math.stackexchange.com/questions/26445/division-by-0
$endgroup$
– EdOverflow
Jan 11 at 13:59
$begingroup$
math.stackexchange.com/questions/26445/division-by-0
$endgroup$
– EdOverflow
Jan 11 at 13:59
2
2
$begingroup$
@MohammadNoorAlam if $frac 00=n$, then $0 cdot n = 0$. How many ways can this be solved?
$endgroup$
– Rhys Hughes
Jan 11 at 14:02
$begingroup$
@MohammadNoorAlam if $frac 00=n$, then $0 cdot n = 0$. How many ways can this be solved?
$endgroup$
– Rhys Hughes
Jan 11 at 14:02
|
show 1 more comment
1 Answer
1
active
oldest
votes
$begingroup$
Assume that $p$ is a point in the plane that is equidistant (say of length $r$) to three distinct points on the circle. Then the circle at $p$ of radius $r$ intersect the original circle at three points. If two circles intersect at three points then they must be the same and hence $p$ is the center of the original circle.
$endgroup$
add a comment |
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1 Answer
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1 Answer
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$begingroup$
Assume that $p$ is a point in the plane that is equidistant (say of length $r$) to three distinct points on the circle. Then the circle at $p$ of radius $r$ intersect the original circle at three points. If two circles intersect at three points then they must be the same and hence $p$ is the center of the original circle.
$endgroup$
add a comment |
$begingroup$
Assume that $p$ is a point in the plane that is equidistant (say of length $r$) to three distinct points on the circle. Then the circle at $p$ of radius $r$ intersect the original circle at three points. If two circles intersect at three points then they must be the same and hence $p$ is the center of the original circle.
$endgroup$
add a comment |
$begingroup$
Assume that $p$ is a point in the plane that is equidistant (say of length $r$) to three distinct points on the circle. Then the circle at $p$ of radius $r$ intersect the original circle at three points. If two circles intersect at three points then they must be the same and hence $p$ is the center of the original circle.
$endgroup$
Assume that $p$ is a point in the plane that is equidistant (say of length $r$) to three distinct points on the circle. Then the circle at $p$ of radius $r$ intersect the original circle at three points. If two circles intersect at three points then they must be the same and hence $p$ is the center of the original circle.
answered Jan 11 at 13:55
LeventLevent
2,741925
2,741925
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$begingroup$
For the second part: $0/0$ is not defined in mathematics.
$endgroup$
– Matti P.
Jan 11 at 13:50
$begingroup$
why both terms do not get cancelled?
$endgroup$
– Mohammad Noor Alam
Jan 11 at 13:52
$begingroup$
why answer is not 1
$endgroup$
– Mohammad Noor Alam
Jan 11 at 13:52
1
$begingroup$
math.stackexchange.com/questions/26445/division-by-0
$endgroup$
– EdOverflow
Jan 11 at 13:59
2
$begingroup$
@MohammadNoorAlam if $frac 00=n$, then $0 cdot n = 0$. How many ways can this be solved?
$endgroup$
– Rhys Hughes
Jan 11 at 14:02