What is the base of this exponent?
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Given the following, what is the value of $ 2b^5 $?
$$ b = 5 $$
$$ 2b^2 $$
I'm confused as to whether the exponent applies to $ 2b $ or just $ b $. Thus, does $ 2b^2 $ equal 50 or 100? What is the rule governing this? Can you provide a source?
notation exponentiation
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add a comment |
$begingroup$
Given the following, what is the value of $ 2b^5 $?
$$ b = 5 $$
$$ 2b^2 $$
I'm confused as to whether the exponent applies to $ 2b $ or just $ b $. Thus, does $ 2b^2 $ equal 50 or 100? What is the rule governing this? Can you provide a source?
notation exponentiation
$endgroup$
add a comment |
$begingroup$
Given the following, what is the value of $ 2b^5 $?
$$ b = 5 $$
$$ 2b^2 $$
I'm confused as to whether the exponent applies to $ 2b $ or just $ b $. Thus, does $ 2b^2 $ equal 50 or 100? What is the rule governing this? Can you provide a source?
notation exponentiation
$endgroup$
Given the following, what is the value of $ 2b^5 $?
$$ b = 5 $$
$$ 2b^2 $$
I'm confused as to whether the exponent applies to $ 2b $ or just $ b $. Thus, does $ 2b^2 $ equal 50 or 100? What is the rule governing this? Can you provide a source?
notation exponentiation
notation exponentiation
asked Jan 8 at 22:30
johnnyodonnelljohnnyodonnell
1597
1597
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2 Answers
2
active
oldest
votes
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If you say $(2b)^2$, then the exponent applies to $2b$. In your case the exponent applies to $b$ only.
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2
$begingroup$
en.wikipedia.org/wiki/Order_of_operations
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– Roman
Jan 8 at 22:33
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Thank you all for the answer and the link to an article!
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– johnnyodonnell
Jan 9 at 13:47
add a comment |
$begingroup$
In your case, the exponent applies just to $b$ so $2b^2=50$ when $b=5$.
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add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
If you say $(2b)^2$, then the exponent applies to $2b$. In your case the exponent applies to $b$ only.
$endgroup$
2
$begingroup$
en.wikipedia.org/wiki/Order_of_operations
$endgroup$
– Roman
Jan 8 at 22:33
$begingroup$
Thank you all for the answer and the link to an article!
$endgroup$
– johnnyodonnell
Jan 9 at 13:47
add a comment |
$begingroup$
If you say $(2b)^2$, then the exponent applies to $2b$. In your case the exponent applies to $b$ only.
$endgroup$
2
$begingroup$
en.wikipedia.org/wiki/Order_of_operations
$endgroup$
– Roman
Jan 8 at 22:33
$begingroup$
Thank you all for the answer and the link to an article!
$endgroup$
– johnnyodonnell
Jan 9 at 13:47
add a comment |
$begingroup$
If you say $(2b)^2$, then the exponent applies to $2b$. In your case the exponent applies to $b$ only.
$endgroup$
If you say $(2b)^2$, then the exponent applies to $2b$. In your case the exponent applies to $b$ only.
answered Jan 8 at 22:31
EuxhenHEuxhenH
482210
482210
2
$begingroup$
en.wikipedia.org/wiki/Order_of_operations
$endgroup$
– Roman
Jan 8 at 22:33
$begingroup$
Thank you all for the answer and the link to an article!
$endgroup$
– johnnyodonnell
Jan 9 at 13:47
add a comment |
2
$begingroup$
en.wikipedia.org/wiki/Order_of_operations
$endgroup$
– Roman
Jan 8 at 22:33
$begingroup$
Thank you all for the answer and the link to an article!
$endgroup$
– johnnyodonnell
Jan 9 at 13:47
2
2
$begingroup$
en.wikipedia.org/wiki/Order_of_operations
$endgroup$
– Roman
Jan 8 at 22:33
$begingroup$
en.wikipedia.org/wiki/Order_of_operations
$endgroup$
– Roman
Jan 8 at 22:33
$begingroup$
Thank you all for the answer and the link to an article!
$endgroup$
– johnnyodonnell
Jan 9 at 13:47
$begingroup$
Thank you all for the answer and the link to an article!
$endgroup$
– johnnyodonnell
Jan 9 at 13:47
add a comment |
$begingroup$
In your case, the exponent applies just to $b$ so $2b^2=50$ when $b=5$.
$endgroup$
add a comment |
$begingroup$
In your case, the exponent applies just to $b$ so $2b^2=50$ when $b=5$.
$endgroup$
add a comment |
$begingroup$
In your case, the exponent applies just to $b$ so $2b^2=50$ when $b=5$.
$endgroup$
In your case, the exponent applies just to $b$ so $2b^2=50$ when $b=5$.
answered Jan 8 at 22:38
GnumbertesterGnumbertester
6771114
6771114
add a comment |
add a comment |
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