Convert centimeters to degrees
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I am working on an autonomous robot. This robot can recognize an object and pick it up. I have a pickup algorithm already.
$$x=Dcos(θ) quad text{and} quad y=Dsin(θ),$$ where $D$ is the length of my robot arm and $θ$ is the angle that it moved in radians.
This code gives an understanding of where the arm is on the Cartesian plane. I have an object detection system and using ultrasonic sensor I want it to stop $2 ,text{cm}$ before the object. If the robot is located at the origin, $(0, 0)$, and the object is $2 ,text{cm}$ from me, I want to know its $(x, y)$ coordinates. How do I convert from centimeters to degrees so I can know the object's $x$ and $y$ values?
algebra-precalculus trigonometry
edited Dec 1 at 5:52
user302797
19.4k92251
asked Dec 1 at 4:05
Kyrylo Kalashnikov
32
add a comment |
up vote
0
down vote
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I am working on an autonomous robot. This robot can recognize an object and pick it up. I have a pickup algorithm already.
$$x=Dcos(θ) quad text{and} quad y=Dsin(θ),$$ where $D$ is the length of my robot arm and $θ$ is the angle that it moved in radians.
This code gives an understanding of where the arm is on the Cartesian plane. I have an object detection system and using ultrasonic sensor I want it to stop $2 ,text{cm}$ before the object. If the robot is located at the origin, $(0, 0)$, and the object is $2 ,text{cm}$ from me, I want to know its $(x, y)$ coordinates. How do I convert from centimeters to degrees so I can know the object's $x$ and $y$ values?
algebra-precalculus trigonometry
edited Dec 1 at 5:52
user302797
19.4k92251
asked Dec 1 at 4:05
Kyrylo Kalashnikov
32
Maybe I don't get your question, but you can use the fact that a radian has a length equal to the radius, in your case, the length of the robot arm, D1.
– Patricio
Dec 1 at 4:15
I get your point but the length of the arm can be smaller
– Kyrylo Kalashnikov
Dec 1 at 4:18
OK, I guess that's the beauty of radians. Whatever the length of the arm (whether it is fully extended or not), the length of the radian in cm is equal to that of the radius. A fully extended arm, say 100 cms long, moved 1 radian each will travel precisely 100 cms. If the arm is contract to just 10 cms long, it will travel by just 10 cms.
– Patricio
Dec 1 at 4:26
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I am working on an autonomous robot. This robot can recognize an object and pick it up. I have a pickup algorithm already.
$$x=Dcos(θ) quad text{and} quad y=Dsin(θ),$$ where $D$ is the length of my robot arm and $θ$ is the angle that it moved in radians.
This code gives an understanding of where the arm is on the Cartesian plane. I have an object detection system and using ultrasonic sensor I want it to stop $2 ,text{cm}$ before the object. If the robot is located at the origin, $(0, 0)$, and the object is $2 ,text{cm}$ from me, I want to know its $(x, y)$ coordinates. How do I convert from centimeters to degrees so I can know the object's $x$ and $y$ values?
algebra-precalculus trigonometry
edited Dec 1 at 5:52
user302797
19.4k92251
asked Dec 1 at 4:05
Kyrylo Kalashnikov
32
I am working on an autonomous robot. This robot can recognize an object and pick it up. I have a pickup algorithm already.
$$x=Dcos(θ) quad text{and} quad y=Dsin(θ),$$ where $D$ is the length of my robot arm and $θ$ is the angle that it moved in radians.
This code gives an understanding of where the arm is on the Cartesian plane. I have an object detection system and using ultrasonic sensor I want it to stop $2 ,text{cm}$ before the object. If the robot is located at the origin, $(0, 0)$, and the object is $2 ,text{cm}$ from me, I want to know its $(x, y)$ coordinates. How do I convert from centimeters to degrees so I can know the object's $x$ and $y$ values?
algebra-precalculus trigonometry
algebra-precalculus trigonometry
edited Dec 1 at 5:52
user302797
19.4k92251
asked Dec 1 at 4:05
Kyrylo Kalashnikov
32
edited Dec 1 at 5:52
user302797
19.4k92251
asked Dec 1 at 4:05
Kyrylo Kalashnikov
32
edited Dec 1 at 5:52
user302797
19.4k92251
edited Dec 1 at 5:52
user302797
19.4k92251
edited Dec 1 at 5:52
user302797
19.4k92251
19.4k92251
asked Dec 1 at 4:05
Kyrylo Kalashnikov
32
asked Dec 1 at 4:05
Kyrylo Kalashnikov
32
asked Dec 1 at 4:05
Kyrylo Kalashnikov
32
32
Maybe I don't get your question, but you can use the fact that a radian has a length equal to the radius, in your case, the length of the robot arm, D1.
– Patricio
Dec 1 at 4:15
I get your point but the length of the arm can be smaller
– Kyrylo Kalashnikov
Dec 1 at 4:18
OK, I guess that's the beauty of radians. Whatever the length of the arm (whether it is fully extended or not), the length of the radian in cm is equal to that of the radius. A fully extended arm, say 100 cms long, moved 1 radian each will travel precisely 100 cms. If the arm is contract to just 10 cms long, it will travel by just 10 cms.
– Patricio
Dec 1 at 4:26
add a comment |
Maybe I don't get your question, but you can use the fact that a radian has a length equal to the radius, in your case, the length of the robot arm, D1.
– Patricio
Dec 1 at 4:15
I get your point but the length of the arm can be smaller
– Kyrylo Kalashnikov
Dec 1 at 4:18
OK, I guess that's the beauty of radians. Whatever the length of the arm (whether it is fully extended or not), the length of the radian in cm is equal to that of the radius. A fully extended arm, say 100 cms long, moved 1 radian each will travel precisely 100 cms. If the arm is contract to just 10 cms long, it will travel by just 10 cms.
– Patricio
Dec 1 at 4:26
Maybe I don't get your question, but you can use the fact that a radian has a length equal to the radius, in your case, the length of the robot arm, D1.
– Patricio
Dec 1 at 4:15
Maybe I don't get your question, but you can use the fact that a radian has a length equal to the radius, in your case, the length of the robot arm, D1.
– Patricio
Dec 1 at 4:15
I get your point but the length of the arm can be smaller
– Kyrylo Kalashnikov
Dec 1 at 4:18
I get your point but the length of the arm can be smaller
– Kyrylo Kalashnikov
Dec 1 at 4:18
OK, I guess that's the beauty of radians. Whatever the length of the arm (whether it is fully extended or not), the length of the radian in cm is equal to that of the radius. A fully extended arm, say 100 cms long, moved 1 radian each will travel precisely 100 cms. If the arm is contract to just 10 cms long, it will travel by just 10 cms.
– Patricio
Dec 1 at 4:26
OK, I guess that's the beauty of radians. Whatever the length of the arm (whether it is fully extended or not), the length of the radian in cm is equal to that of the radius. A fully extended arm, say 100 cms long, moved 1 radian each will travel precisely 100 cms. If the arm is contract to just 10 cms long, it will travel by just 10 cms.
– Patricio
Dec 1 at 4:26
add a comment |
1 Answer
1
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You need one other piece of data. You know you are $2$ cm from the object but you have not told us you know what angle it is at. Without that it could be anywhere on a $2$ cm circle around your current point. It sounds like you are approaching it, so it can't be behind you but that still leaves a large range. You know $D=2$ but you have no data to evaluate $theta$ in what you have given.
answered Dec 1 at 6:12
Ross Millikan
288k23195366
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
You need one other piece of data. You know you are $2$ cm from the object but you have not told us you know what angle it is at. Without that it could be anywhere on a $2$ cm circle around your current point. It sounds like you are approaching it, so it can't be behind you but that still leaves a large range. You know $D=2$ but you have no data to evaluate $theta$ in what you have given.
answered Dec 1 at 6:12
Ross Millikan
288k23195366
add a comment |
up vote
0
down vote
You need one other piece of data. You know you are $2$ cm from the object but you have not told us you know what angle it is at. Without that it could be anywhere on a $2$ cm circle around your current point. It sounds like you are approaching it, so it can't be behind you but that still leaves a large range. You know $D=2$ but you have no data to evaluate $theta$ in what you have given.
answered Dec 1 at 6:12
Ross Millikan
288k23195366
add a comment |
up vote
0
down vote
up vote
0
down vote
You need one other piece of data. You know you are $2$ cm from the object but you have not told us you know what angle it is at. Without that it could be anywhere on a $2$ cm circle around your current point. It sounds like you are approaching it, so it can't be behind you but that still leaves a large range. You know $D=2$ but you have no data to evaluate $theta$ in what you have given.
answered Dec 1 at 6:12
Ross Millikan
288k23195366
You need one other piece of data. You know you are $2$ cm from the object but you have not told us you know what angle it is at. Without that it could be anywhere on a $2$ cm circle around your current point. It sounds like you are approaching it, so it can't be behind you but that still leaves a large range. You know $D=2$ but you have no data to evaluate $theta$ in what you have given.
answered Dec 1 at 6:12
Ross Millikan
288k23195366
answered Dec 1 at 6:12
Ross Millikan
288k23195366
answered Dec 1 at 6:12
Ross Millikan
288k23195366
answered Dec 1 at 6:12
Ross Millikan
288k23195366
288k23195366
add a comment |
add a comment |
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Maybe I don't get your question, but you can use the fact that a radian has a length equal to the radius, in your case, the length of the robot arm, D1.
– Patricio
Dec 1 at 4:15
I get your point but the length of the arm can be smaller
– Kyrylo Kalashnikov
Dec 1 at 4:18
OK, I guess that's the beauty of radians. Whatever the length of the arm (whether it is fully extended or not), the length of the radian in cm is equal to that of the radius. A fully extended arm, say 100 cms long, moved 1 radian each will travel precisely 100 cms. If the arm is contract to just 10 cms long, it will travel by just 10 cms.
– Patricio
Dec 1 at 4:26