Probability Question: I'm having trouble coming up with the cases for when A will win and B











up vote
-3
down vote

favorite












Players A and B take turns rolling two fair dice. Player A wins if he rolls a sum less than or equal to 5. Player B wins if she rolls a sum greater than or equal to 6. The game continues until someone wins.



(a) Assuming that Player A goes first and assuming that the rolls of the dice are independent
of each other, find the probability mass function for X where X is the random variable
which counts the number of rolls it takes for B to win.



possibilities: 2 dice 6^2 = 36possibilities



A: 10/36 chance of winning



B: 26/36 chance of winning



stuck on the cases for when x=1,2,..k










share|cite|improve this question







New contributor




alxanderapollo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • Learn to format your post, and show what you have tried and what specific difficulties you have.
    – Ya G
    Dec 1 at 3:24















up vote
-3
down vote

favorite












Players A and B take turns rolling two fair dice. Player A wins if he rolls a sum less than or equal to 5. Player B wins if she rolls a sum greater than or equal to 6. The game continues until someone wins.



(a) Assuming that Player A goes first and assuming that the rolls of the dice are independent
of each other, find the probability mass function for X where X is the random variable
which counts the number of rolls it takes for B to win.



possibilities: 2 dice 6^2 = 36possibilities



A: 10/36 chance of winning



B: 26/36 chance of winning



stuck on the cases for when x=1,2,..k










share|cite|improve this question







New contributor




alxanderapollo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • Learn to format your post, and show what you have tried and what specific difficulties you have.
    – Ya G
    Dec 1 at 3:24













up vote
-3
down vote

favorite









up vote
-3
down vote

favorite











Players A and B take turns rolling two fair dice. Player A wins if he rolls a sum less than or equal to 5. Player B wins if she rolls a sum greater than or equal to 6. The game continues until someone wins.



(a) Assuming that Player A goes first and assuming that the rolls of the dice are independent
of each other, find the probability mass function for X where X is the random variable
which counts the number of rolls it takes for B to win.



possibilities: 2 dice 6^2 = 36possibilities



A: 10/36 chance of winning



B: 26/36 chance of winning



stuck on the cases for when x=1,2,..k










share|cite|improve this question







New contributor




alxanderapollo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











Players A and B take turns rolling two fair dice. Player A wins if he rolls a sum less than or equal to 5. Player B wins if she rolls a sum greater than or equal to 6. The game continues until someone wins.



(a) Assuming that Player A goes first and assuming that the rolls of the dice are independent
of each other, find the probability mass function for X where X is the random variable
which counts the number of rolls it takes for B to win.



possibilities: 2 dice 6^2 = 36possibilities



A: 10/36 chance of winning



B: 26/36 chance of winning



stuck on the cases for when x=1,2,..k







probability probability-distributions






share|cite|improve this question







New contributor




alxanderapollo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question







New contributor




alxanderapollo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question






New contributor




alxanderapollo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked Dec 1 at 3:07









alxanderapollo

1




1




New contributor




alxanderapollo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





alxanderapollo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






alxanderapollo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • Learn to format your post, and show what you have tried and what specific difficulties you have.
    – Ya G
    Dec 1 at 3:24


















  • Learn to format your post, and show what you have tried and what specific difficulties you have.
    – Ya G
    Dec 1 at 3:24
















Learn to format your post, and show what you have tried and what specific difficulties you have.
– Ya G
Dec 1 at 3:24




Learn to format your post, and show what you have tried and what specific difficulties you have.
– Ya G
Dec 1 at 3:24










1 Answer
1






active

oldest

votes

















up vote
0
down vote













Notice that $P(A)^c=P(B)$. Then, you can simply create geometric distribution using those.



Will provide the answer if you comment what you have deduced, using the above fact.






share|cite|improve this answer























    Your Answer





    StackExchange.ifUsing("editor", function () {
    return StackExchange.using("mathjaxEditing", function () {
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    });
    });
    }, "mathjax-editing");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "69"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });






    alxanderapollo is a new contributor. Be nice, and check out our Code of Conduct.










    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3020938%2fprobability-question-im-having-trouble-coming-up-with-the-cases-for-when-a-wil%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote













    Notice that $P(A)^c=P(B)$. Then, you can simply create geometric distribution using those.



    Will provide the answer if you comment what you have deduced, using the above fact.






    share|cite|improve this answer



























      up vote
      0
      down vote













      Notice that $P(A)^c=P(B)$. Then, you can simply create geometric distribution using those.



      Will provide the answer if you comment what you have deduced, using the above fact.






      share|cite|improve this answer

























        up vote
        0
        down vote










        up vote
        0
        down vote









        Notice that $P(A)^c=P(B)$. Then, you can simply create geometric distribution using those.



        Will provide the answer if you comment what you have deduced, using the above fact.






        share|cite|improve this answer














        Notice that $P(A)^c=P(B)$. Then, you can simply create geometric distribution using those.



        Will provide the answer if you comment what you have deduced, using the above fact.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Dec 1 at 3:28

























        answered Dec 1 at 3:22









        Ya G

        35019




        35019






















            alxanderapollo is a new contributor. Be nice, and check out our Code of Conduct.










            draft saved

            draft discarded


















            alxanderapollo is a new contributor. Be nice, and check out our Code of Conduct.













            alxanderapollo is a new contributor. Be nice, and check out our Code of Conduct.












            alxanderapollo is a new contributor. Be nice, and check out our Code of Conduct.
















            Thanks for contributing an answer to Mathematics Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.





            Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


            Please pay close attention to the following guidance:


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3020938%2fprobability-question-im-having-trouble-coming-up-with-the-cases-for-when-a-wil%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Bressuire

            Cabo Verde

            Gyllenstierna