How do I solve this $z^5 + z^3 = iz^2 + i$
How can I find out what z is and the zero of this function? $z^5 + z^3 = iz^2 + i$
I tried everything but I cannot solve it...
Thanks in advance!
complex-numbers
asked Dec 9 at 15:19
jamyolive
246
add a comment |
How can I find out what z is and the zero of this function? $z^5 + z^3 = iz^2 + i$
I tried everything but I cannot solve it...
Thanks in advance!
complex-numbers
asked Dec 9 at 15:19
jamyolive
246
Is my suggested edit correct?
– AryanSonwatikar
Dec 9 at 15:24
4
Hint $z^3(z^2+1)=i(z^2+1)$
– egreg
Dec 9 at 15:26
add a comment |
How can I find out what z is and the zero of this function? $z^5 + z^3 = iz^2 + i$
I tried everything but I cannot solve it...
Thanks in advance!
complex-numbers
asked Dec 9 at 15:19
jamyolive
246
How can I find out what z is and the zero of this function? $z^5 + z^3 = iz^2 + i$
I tried everything but I cannot solve it...
Thanks in advance!
complex-numbers
complex-numbers
asked Dec 9 at 15:19
jamyolive
246
asked Dec 9 at 15:19
jamyolive
246
edited Dec 9 at 15:26
asked Dec 9 at 15:19
jamyolive
246
asked Dec 9 at 15:19
jamyolive
246
asked Dec 9 at 15:19
jamyolive
246
246
Is my suggested edit correct?
– AryanSonwatikar
Dec 9 at 15:24
4
Hint $z^3(z^2+1)=i(z^2+1)$
– egreg
Dec 9 at 15:26
add a comment |
Is my suggested edit correct?
– AryanSonwatikar
Dec 9 at 15:24
4
Hint $z^3(z^2+1)=i(z^2+1)$
– egreg
Dec 9 at 15:26
Is my suggested edit correct?
– AryanSonwatikar
Dec 9 at 15:24
Is my suggested edit correct?
– AryanSonwatikar
Dec 9 at 15:24
4
4
Hint $z^3(z^2+1)=i(z^2+1)$
– egreg
Dec 9 at 15:26
Hint $z^3(z^2+1)=i(z^2+1)$
– egreg
Dec 9 at 15:26
add a comment |
1 Answer
1
active
oldest
votes
HINT:
$$z^5+z^3-iz^2-i=(z^2+1)(z^3-i)=0$$
answered Dec 9 at 15:42
JJacquelin
42.5k21750
add a comment |
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1 Answer
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1 Answer
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active
oldest
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active
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HINT:
$$z^5+z^3-iz^2-i=(z^2+1)(z^3-i)=0$$
answered Dec 9 at 15:42
JJacquelin
42.5k21750
add a comment |
HINT:
$$z^5+z^3-iz^2-i=(z^2+1)(z^3-i)=0$$
answered Dec 9 at 15:42
JJacquelin
42.5k21750
add a comment |
HINT:
$$z^5+z^3-iz^2-i=(z^2+1)(z^3-i)=0$$
answered Dec 9 at 15:42
JJacquelin
42.5k21750
HINT:
$$z^5+z^3-iz^2-i=(z^2+1)(z^3-i)=0$$
answered Dec 9 at 15:42
JJacquelin
42.5k21750
answered Dec 9 at 15:42
JJacquelin
42.5k21750
answered Dec 9 at 15:42
JJacquelin
42.5k21750
answered Dec 9 at 15:42
JJacquelin
42.5k21750
42.5k21750
add a comment |
add a comment |
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Is my suggested edit correct?
– AryanSonwatikar
Dec 9 at 15:24
4
Hint $z^3(z^2+1)=i(z^2+1)$
– egreg
Dec 9 at 15:26