Ring structure on the Galois group of a finite field











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Let $F$ be a finite field. There is an isomorphism of topological groups $left(mathrm{Gal}(overline{F}/F),circright) cong (widehat{mathbb{Z}},+)$. It follows that the Galois group carries the structure of a topological ring isomorphic to $widehat{mathbb{Z}}$. What does the multiplication $*$ look like? If $sigma$ is the Frobenius, we have $sigma^n * sigma^m = sigma^{n*m}$, and this describes $*$ completely. Is there any way to give an explicit and natural formula for $alpha * beta$ if $alpha,beta$ are $F$-automorphisms of $overline{F}$? Also, is there any more conceptual reason why the Galois group carries the structure of a topological ring (without computing the Galois group)?



Maybe the following is a more precise version of the question: Consider the Galois category $mathcal{C}$ of finite étale $F$-algebras together with the fiber functor to $mathsf{FinSet}$. The automorphism group is exactly $pi_1(mathrm{Spec}(F))=widehat{mathbb{Z}}$. Which additional structure on the Galois category $mathcal{C}$ is responsible for the ring structure on its automorphism group?










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  • 4




    I mean, the second question seems to follow more naturally since all finite Galois subextensions of $overline{F}/F$ have Galois groups which are rings--it's merely the fact that the absolute Galois group is the limit of these that gives it the ring structure. So a more poignant question may be "why do finite fields have Galois groups that have a ring structure?" But, us thinking these have a ring structure is more a function of the notation $mathbb{Z}/nmathbb{Z}$ then it is a natural ring structure--or so it seems to me. Nice question though, +1.
    – Alex Youcis
    Nov 17 '13 at 8:01








  • 2




    I guess, my question is why you'd expect the ring structure to be natural. For example, if someone wrote $text{Gal}(mathbb{Q}(zeta_{p^infty})/mathbb{Q})=mathbb{Z}_p^times$, you may think that there is no natural ring structure. But, if instead someone had written it as $mathbb{Z}/(p-1)mathbb{Z}timesmathbb{Z}_p$, you may ask the same question there.
    – Alex Youcis
    Nov 17 '13 at 8:06










  • You are probably right, why should it be natural, and what should this mean? Actually for every $u in widehat{mathbb{Z}}$ there is a ring structure extending the group structure with unit $sigma^u$, namely $sigma^n *' sigma^m = sigma^{n+m-u}$. But there is only one ring structure (extending the group structure) with unit $sigma$.
    – Martin Brandenburg
    Nov 17 '13 at 12:32












  • Dear Martin, this is an interesting question. Have you ever seen this multiplication appear naturally somewhere? Cheers,
    – Bruno Joyal
    Nov 20 '13 at 14:21






  • 3




    Actually this question just comes out of curiosity. And I've learned in the last years that it is better not to ignore extra structures.
    – Martin Brandenburg
    Nov 21 '13 at 18:50

















up vote
70
down vote

favorite
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Let $F$ be a finite field. There is an isomorphism of topological groups $left(mathrm{Gal}(overline{F}/F),circright) cong (widehat{mathbb{Z}},+)$. It follows that the Galois group carries the structure of a topological ring isomorphic to $widehat{mathbb{Z}}$. What does the multiplication $*$ look like? If $sigma$ is the Frobenius, we have $sigma^n * sigma^m = sigma^{n*m}$, and this describes $*$ completely. Is there any way to give an explicit and natural formula for $alpha * beta$ if $alpha,beta$ are $F$-automorphisms of $overline{F}$? Also, is there any more conceptual reason why the Galois group carries the structure of a topological ring (without computing the Galois group)?



Maybe the following is a more precise version of the question: Consider the Galois category $mathcal{C}$ of finite étale $F$-algebras together with the fiber functor to $mathsf{FinSet}$. The automorphism group is exactly $pi_1(mathrm{Spec}(F))=widehat{mathbb{Z}}$. Which additional structure on the Galois category $mathcal{C}$ is responsible for the ring structure on its automorphism group?










share|cite|improve this question




















  • 4




    I mean, the second question seems to follow more naturally since all finite Galois subextensions of $overline{F}/F$ have Galois groups which are rings--it's merely the fact that the absolute Galois group is the limit of these that gives it the ring structure. So a more poignant question may be "why do finite fields have Galois groups that have a ring structure?" But, us thinking these have a ring structure is more a function of the notation $mathbb{Z}/nmathbb{Z}$ then it is a natural ring structure--or so it seems to me. Nice question though, +1.
    – Alex Youcis
    Nov 17 '13 at 8:01








  • 2




    I guess, my question is why you'd expect the ring structure to be natural. For example, if someone wrote $text{Gal}(mathbb{Q}(zeta_{p^infty})/mathbb{Q})=mathbb{Z}_p^times$, you may think that there is no natural ring structure. But, if instead someone had written it as $mathbb{Z}/(p-1)mathbb{Z}timesmathbb{Z}_p$, you may ask the same question there.
    – Alex Youcis
    Nov 17 '13 at 8:06










  • You are probably right, why should it be natural, and what should this mean? Actually for every $u in widehat{mathbb{Z}}$ there is a ring structure extending the group structure with unit $sigma^u$, namely $sigma^n *' sigma^m = sigma^{n+m-u}$. But there is only one ring structure (extending the group structure) with unit $sigma$.
    – Martin Brandenburg
    Nov 17 '13 at 12:32












  • Dear Martin, this is an interesting question. Have you ever seen this multiplication appear naturally somewhere? Cheers,
    – Bruno Joyal
    Nov 20 '13 at 14:21






  • 3




    Actually this question just comes out of curiosity. And I've learned in the last years that it is better not to ignore extra structures.
    – Martin Brandenburg
    Nov 21 '13 at 18:50















up vote
70
down vote

favorite
14









up vote
70
down vote

favorite
14






14





Let $F$ be a finite field. There is an isomorphism of topological groups $left(mathrm{Gal}(overline{F}/F),circright) cong (widehat{mathbb{Z}},+)$. It follows that the Galois group carries the structure of a topological ring isomorphic to $widehat{mathbb{Z}}$. What does the multiplication $*$ look like? If $sigma$ is the Frobenius, we have $sigma^n * sigma^m = sigma^{n*m}$, and this describes $*$ completely. Is there any way to give an explicit and natural formula for $alpha * beta$ if $alpha,beta$ are $F$-automorphisms of $overline{F}$? Also, is there any more conceptual reason why the Galois group carries the structure of a topological ring (without computing the Galois group)?



Maybe the following is a more precise version of the question: Consider the Galois category $mathcal{C}$ of finite étale $F$-algebras together with the fiber functor to $mathsf{FinSet}$. The automorphism group is exactly $pi_1(mathrm{Spec}(F))=widehat{mathbb{Z}}$. Which additional structure on the Galois category $mathcal{C}$ is responsible for the ring structure on its automorphism group?










share|cite|improve this question















Let $F$ be a finite field. There is an isomorphism of topological groups $left(mathrm{Gal}(overline{F}/F),circright) cong (widehat{mathbb{Z}},+)$. It follows that the Galois group carries the structure of a topological ring isomorphic to $widehat{mathbb{Z}}$. What does the multiplication $*$ look like? If $sigma$ is the Frobenius, we have $sigma^n * sigma^m = sigma^{n*m}$, and this describes $*$ completely. Is there any way to give an explicit and natural formula for $alpha * beta$ if $alpha,beta$ are $F$-automorphisms of $overline{F}$? Also, is there any more conceptual reason why the Galois group carries the structure of a topological ring (without computing the Galois group)?



Maybe the following is a more precise version of the question: Consider the Galois category $mathcal{C}$ of finite étale $F$-algebras together with the fiber functor to $mathsf{FinSet}$. The automorphism group is exactly $pi_1(mathrm{Spec}(F))=widehat{mathbb{Z}}$. Which additional structure on the Galois category $mathcal{C}$ is responsible for the ring structure on its automorphism group?







abstract-algebra ring-theory galois-theory finite-fields






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edited Jan 28 at 22:39









Mostafa Ayaz

13.6k3836




13.6k3836










asked Nov 17 '13 at 7:19









Martin Brandenburg

107k13156324




107k13156324








  • 4




    I mean, the second question seems to follow more naturally since all finite Galois subextensions of $overline{F}/F$ have Galois groups which are rings--it's merely the fact that the absolute Galois group is the limit of these that gives it the ring structure. So a more poignant question may be "why do finite fields have Galois groups that have a ring structure?" But, us thinking these have a ring structure is more a function of the notation $mathbb{Z}/nmathbb{Z}$ then it is a natural ring structure--or so it seems to me. Nice question though, +1.
    – Alex Youcis
    Nov 17 '13 at 8:01








  • 2




    I guess, my question is why you'd expect the ring structure to be natural. For example, if someone wrote $text{Gal}(mathbb{Q}(zeta_{p^infty})/mathbb{Q})=mathbb{Z}_p^times$, you may think that there is no natural ring structure. But, if instead someone had written it as $mathbb{Z}/(p-1)mathbb{Z}timesmathbb{Z}_p$, you may ask the same question there.
    – Alex Youcis
    Nov 17 '13 at 8:06










  • You are probably right, why should it be natural, and what should this mean? Actually for every $u in widehat{mathbb{Z}}$ there is a ring structure extending the group structure with unit $sigma^u$, namely $sigma^n *' sigma^m = sigma^{n+m-u}$. But there is only one ring structure (extending the group structure) with unit $sigma$.
    – Martin Brandenburg
    Nov 17 '13 at 12:32












  • Dear Martin, this is an interesting question. Have you ever seen this multiplication appear naturally somewhere? Cheers,
    – Bruno Joyal
    Nov 20 '13 at 14:21






  • 3




    Actually this question just comes out of curiosity. And I've learned in the last years that it is better not to ignore extra structures.
    – Martin Brandenburg
    Nov 21 '13 at 18:50
















  • 4




    I mean, the second question seems to follow more naturally since all finite Galois subextensions of $overline{F}/F$ have Galois groups which are rings--it's merely the fact that the absolute Galois group is the limit of these that gives it the ring structure. So a more poignant question may be "why do finite fields have Galois groups that have a ring structure?" But, us thinking these have a ring structure is more a function of the notation $mathbb{Z}/nmathbb{Z}$ then it is a natural ring structure--or so it seems to me. Nice question though, +1.
    – Alex Youcis
    Nov 17 '13 at 8:01








  • 2




    I guess, my question is why you'd expect the ring structure to be natural. For example, if someone wrote $text{Gal}(mathbb{Q}(zeta_{p^infty})/mathbb{Q})=mathbb{Z}_p^times$, you may think that there is no natural ring structure. But, if instead someone had written it as $mathbb{Z}/(p-1)mathbb{Z}timesmathbb{Z}_p$, you may ask the same question there.
    – Alex Youcis
    Nov 17 '13 at 8:06










  • You are probably right, why should it be natural, and what should this mean? Actually for every $u in widehat{mathbb{Z}}$ there is a ring structure extending the group structure with unit $sigma^u$, namely $sigma^n *' sigma^m = sigma^{n+m-u}$. But there is only one ring structure (extending the group structure) with unit $sigma$.
    – Martin Brandenburg
    Nov 17 '13 at 12:32












  • Dear Martin, this is an interesting question. Have you ever seen this multiplication appear naturally somewhere? Cheers,
    – Bruno Joyal
    Nov 20 '13 at 14:21






  • 3




    Actually this question just comes out of curiosity. And I've learned in the last years that it is better not to ignore extra structures.
    – Martin Brandenburg
    Nov 21 '13 at 18:50










4




4




I mean, the second question seems to follow more naturally since all finite Galois subextensions of $overline{F}/F$ have Galois groups which are rings--it's merely the fact that the absolute Galois group is the limit of these that gives it the ring structure. So a more poignant question may be "why do finite fields have Galois groups that have a ring structure?" But, us thinking these have a ring structure is more a function of the notation $mathbb{Z}/nmathbb{Z}$ then it is a natural ring structure--or so it seems to me. Nice question though, +1.
– Alex Youcis
Nov 17 '13 at 8:01






I mean, the second question seems to follow more naturally since all finite Galois subextensions of $overline{F}/F$ have Galois groups which are rings--it's merely the fact that the absolute Galois group is the limit of these that gives it the ring structure. So a more poignant question may be "why do finite fields have Galois groups that have a ring structure?" But, us thinking these have a ring structure is more a function of the notation $mathbb{Z}/nmathbb{Z}$ then it is a natural ring structure--or so it seems to me. Nice question though, +1.
– Alex Youcis
Nov 17 '13 at 8:01






2




2




I guess, my question is why you'd expect the ring structure to be natural. For example, if someone wrote $text{Gal}(mathbb{Q}(zeta_{p^infty})/mathbb{Q})=mathbb{Z}_p^times$, you may think that there is no natural ring structure. But, if instead someone had written it as $mathbb{Z}/(p-1)mathbb{Z}timesmathbb{Z}_p$, you may ask the same question there.
– Alex Youcis
Nov 17 '13 at 8:06




I guess, my question is why you'd expect the ring structure to be natural. For example, if someone wrote $text{Gal}(mathbb{Q}(zeta_{p^infty})/mathbb{Q})=mathbb{Z}_p^times$, you may think that there is no natural ring structure. But, if instead someone had written it as $mathbb{Z}/(p-1)mathbb{Z}timesmathbb{Z}_p$, you may ask the same question there.
– Alex Youcis
Nov 17 '13 at 8:06












You are probably right, why should it be natural, and what should this mean? Actually for every $u in widehat{mathbb{Z}}$ there is a ring structure extending the group structure with unit $sigma^u$, namely $sigma^n *' sigma^m = sigma^{n+m-u}$. But there is only one ring structure (extending the group structure) with unit $sigma$.
– Martin Brandenburg
Nov 17 '13 at 12:32






You are probably right, why should it be natural, and what should this mean? Actually for every $u in widehat{mathbb{Z}}$ there is a ring structure extending the group structure with unit $sigma^u$, namely $sigma^n *' sigma^m = sigma^{n+m-u}$. But there is only one ring structure (extending the group structure) with unit $sigma$.
– Martin Brandenburg
Nov 17 '13 at 12:32














Dear Martin, this is an interesting question. Have you ever seen this multiplication appear naturally somewhere? Cheers,
– Bruno Joyal
Nov 20 '13 at 14:21




Dear Martin, this is an interesting question. Have you ever seen this multiplication appear naturally somewhere? Cheers,
– Bruno Joyal
Nov 20 '13 at 14:21




3




3




Actually this question just comes out of curiosity. And I've learned in the last years that it is better not to ignore extra structures.
– Martin Brandenburg
Nov 21 '13 at 18:50






Actually this question just comes out of curiosity. And I've learned in the last years that it is better not to ignore extra structures.
– Martin Brandenburg
Nov 21 '13 at 18:50












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Yes, there is a natural way of describing the ring structure on $Gal(overline{F}backslash F)$, just using the Galois theoretic fact that Galois groups of infinite Galois extensions can be considered as inverse limits of systems of Galois groups of finite extensions.



For simplicity, suppose that $F=mathbb{F}_p$.



For each $ninmathbb{N}$, $Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)$ is cyclic of order $n$, generated by the Frobenius $sigma(x)=x^p$, so there are natural group isomorphisms $iota_n:frac{mathbb{Z}}{nmathbb{Z}}cong Gal(mathbb{F}_{p^n}backslashmathbb{F}_p), r+nmathbb{Z}mapsto sigma^r$.



Therefore $Gal(mathbb{F}_{p^m}backslashmathbb{F}_p)$ carries a natural ring structure given by $sigma^r*sigma^s=sigma^{rs}$, and this makes the maps $iota_n$ ring isomorphisms.



There are natural surjective transition maps $nu_{n,m}:Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)to Gal(mathbb{F}_{p^m}backslashmathbb{F}_p), alphatoalpha|_{mathbb{F}_{p^m}}$ whenever $mmid n$, making this collection of Galois groups into an inverse system, and it is a fact in Galois theory that $Gal(overline{F}backslashmathbb{F}_p)$ is the limit of this system.



Therefore, given general $F$-automorphisms $alpha,betain Gal(overline{F}backslashmathbb{F}_p)$, we can write $alpha=(alpha_n)_{ninmathbb{N}}$, $beta=(beta_n)_{ninmathbb{N}}$, where $alpha_n,beta_nin Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)$, $nu_{n,m}(alpha_n)=alpha_m$, $nu_{n,m}(beta_n)=beta_m$, and multiplication in $Gal(overline{F}backslashmathbb{F}_p)$ is given by $alpha*beta=(alpha_n*beta_n)_{ninmathbb{N}}$, where multiplication in $Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)$ was defined above.



This is the natural way of describing the ring structure on $Gal(overline{F}backslashmathbb{F}_p)$, and since $widehat{mathbb{Z}}$ is identivcally defined as the inverse limit of the system of cyclic groups $frac{mathbb{Z}}{nmathbb{Z}}$, it is equivalent to the ring structure on $widehat{mathbb{Z}}$.






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    Yes, there is a natural way of describing the ring structure on $Gal(overline{F}backslash F)$, just using the Galois theoretic fact that Galois groups of infinite Galois extensions can be considered as inverse limits of systems of Galois groups of finite extensions.



    For simplicity, suppose that $F=mathbb{F}_p$.



    For each $ninmathbb{N}$, $Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)$ is cyclic of order $n$, generated by the Frobenius $sigma(x)=x^p$, so there are natural group isomorphisms $iota_n:frac{mathbb{Z}}{nmathbb{Z}}cong Gal(mathbb{F}_{p^n}backslashmathbb{F}_p), r+nmathbb{Z}mapsto sigma^r$.



    Therefore $Gal(mathbb{F}_{p^m}backslashmathbb{F}_p)$ carries a natural ring structure given by $sigma^r*sigma^s=sigma^{rs}$, and this makes the maps $iota_n$ ring isomorphisms.



    There are natural surjective transition maps $nu_{n,m}:Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)to Gal(mathbb{F}_{p^m}backslashmathbb{F}_p), alphatoalpha|_{mathbb{F}_{p^m}}$ whenever $mmid n$, making this collection of Galois groups into an inverse system, and it is a fact in Galois theory that $Gal(overline{F}backslashmathbb{F}_p)$ is the limit of this system.



    Therefore, given general $F$-automorphisms $alpha,betain Gal(overline{F}backslashmathbb{F}_p)$, we can write $alpha=(alpha_n)_{ninmathbb{N}}$, $beta=(beta_n)_{ninmathbb{N}}$, where $alpha_n,beta_nin Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)$, $nu_{n,m}(alpha_n)=alpha_m$, $nu_{n,m}(beta_n)=beta_m$, and multiplication in $Gal(overline{F}backslashmathbb{F}_p)$ is given by $alpha*beta=(alpha_n*beta_n)_{ninmathbb{N}}$, where multiplication in $Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)$ was defined above.



    This is the natural way of describing the ring structure on $Gal(overline{F}backslashmathbb{F}_p)$, and since $widehat{mathbb{Z}}$ is identivcally defined as the inverse limit of the system of cyclic groups $frac{mathbb{Z}}{nmathbb{Z}}$, it is equivalent to the ring structure on $widehat{mathbb{Z}}$.






    share|cite|improve this answer

























      up vote
      0
      down vote













      Yes, there is a natural way of describing the ring structure on $Gal(overline{F}backslash F)$, just using the Galois theoretic fact that Galois groups of infinite Galois extensions can be considered as inverse limits of systems of Galois groups of finite extensions.



      For simplicity, suppose that $F=mathbb{F}_p$.



      For each $ninmathbb{N}$, $Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)$ is cyclic of order $n$, generated by the Frobenius $sigma(x)=x^p$, so there are natural group isomorphisms $iota_n:frac{mathbb{Z}}{nmathbb{Z}}cong Gal(mathbb{F}_{p^n}backslashmathbb{F}_p), r+nmathbb{Z}mapsto sigma^r$.



      Therefore $Gal(mathbb{F}_{p^m}backslashmathbb{F}_p)$ carries a natural ring structure given by $sigma^r*sigma^s=sigma^{rs}$, and this makes the maps $iota_n$ ring isomorphisms.



      There are natural surjective transition maps $nu_{n,m}:Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)to Gal(mathbb{F}_{p^m}backslashmathbb{F}_p), alphatoalpha|_{mathbb{F}_{p^m}}$ whenever $mmid n$, making this collection of Galois groups into an inverse system, and it is a fact in Galois theory that $Gal(overline{F}backslashmathbb{F}_p)$ is the limit of this system.



      Therefore, given general $F$-automorphisms $alpha,betain Gal(overline{F}backslashmathbb{F}_p)$, we can write $alpha=(alpha_n)_{ninmathbb{N}}$, $beta=(beta_n)_{ninmathbb{N}}$, where $alpha_n,beta_nin Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)$, $nu_{n,m}(alpha_n)=alpha_m$, $nu_{n,m}(beta_n)=beta_m$, and multiplication in $Gal(overline{F}backslashmathbb{F}_p)$ is given by $alpha*beta=(alpha_n*beta_n)_{ninmathbb{N}}$, where multiplication in $Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)$ was defined above.



      This is the natural way of describing the ring structure on $Gal(overline{F}backslashmathbb{F}_p)$, and since $widehat{mathbb{Z}}$ is identivcally defined as the inverse limit of the system of cyclic groups $frac{mathbb{Z}}{nmathbb{Z}}$, it is equivalent to the ring structure on $widehat{mathbb{Z}}$.






      share|cite|improve this answer























        up vote
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        Yes, there is a natural way of describing the ring structure on $Gal(overline{F}backslash F)$, just using the Galois theoretic fact that Galois groups of infinite Galois extensions can be considered as inverse limits of systems of Galois groups of finite extensions.



        For simplicity, suppose that $F=mathbb{F}_p$.



        For each $ninmathbb{N}$, $Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)$ is cyclic of order $n$, generated by the Frobenius $sigma(x)=x^p$, so there are natural group isomorphisms $iota_n:frac{mathbb{Z}}{nmathbb{Z}}cong Gal(mathbb{F}_{p^n}backslashmathbb{F}_p), r+nmathbb{Z}mapsto sigma^r$.



        Therefore $Gal(mathbb{F}_{p^m}backslashmathbb{F}_p)$ carries a natural ring structure given by $sigma^r*sigma^s=sigma^{rs}$, and this makes the maps $iota_n$ ring isomorphisms.



        There are natural surjective transition maps $nu_{n,m}:Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)to Gal(mathbb{F}_{p^m}backslashmathbb{F}_p), alphatoalpha|_{mathbb{F}_{p^m}}$ whenever $mmid n$, making this collection of Galois groups into an inverse system, and it is a fact in Galois theory that $Gal(overline{F}backslashmathbb{F}_p)$ is the limit of this system.



        Therefore, given general $F$-automorphisms $alpha,betain Gal(overline{F}backslashmathbb{F}_p)$, we can write $alpha=(alpha_n)_{ninmathbb{N}}$, $beta=(beta_n)_{ninmathbb{N}}$, where $alpha_n,beta_nin Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)$, $nu_{n,m}(alpha_n)=alpha_m$, $nu_{n,m}(beta_n)=beta_m$, and multiplication in $Gal(overline{F}backslashmathbb{F}_p)$ is given by $alpha*beta=(alpha_n*beta_n)_{ninmathbb{N}}$, where multiplication in $Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)$ was defined above.



        This is the natural way of describing the ring structure on $Gal(overline{F}backslashmathbb{F}_p)$, and since $widehat{mathbb{Z}}$ is identivcally defined as the inverse limit of the system of cyclic groups $frac{mathbb{Z}}{nmathbb{Z}}$, it is equivalent to the ring structure on $widehat{mathbb{Z}}$.






        share|cite|improve this answer












        Yes, there is a natural way of describing the ring structure on $Gal(overline{F}backslash F)$, just using the Galois theoretic fact that Galois groups of infinite Galois extensions can be considered as inverse limits of systems of Galois groups of finite extensions.



        For simplicity, suppose that $F=mathbb{F}_p$.



        For each $ninmathbb{N}$, $Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)$ is cyclic of order $n$, generated by the Frobenius $sigma(x)=x^p$, so there are natural group isomorphisms $iota_n:frac{mathbb{Z}}{nmathbb{Z}}cong Gal(mathbb{F}_{p^n}backslashmathbb{F}_p), r+nmathbb{Z}mapsto sigma^r$.



        Therefore $Gal(mathbb{F}_{p^m}backslashmathbb{F}_p)$ carries a natural ring structure given by $sigma^r*sigma^s=sigma^{rs}$, and this makes the maps $iota_n$ ring isomorphisms.



        There are natural surjective transition maps $nu_{n,m}:Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)to Gal(mathbb{F}_{p^m}backslashmathbb{F}_p), alphatoalpha|_{mathbb{F}_{p^m}}$ whenever $mmid n$, making this collection of Galois groups into an inverse system, and it is a fact in Galois theory that $Gal(overline{F}backslashmathbb{F}_p)$ is the limit of this system.



        Therefore, given general $F$-automorphisms $alpha,betain Gal(overline{F}backslashmathbb{F}_p)$, we can write $alpha=(alpha_n)_{ninmathbb{N}}$, $beta=(beta_n)_{ninmathbb{N}}$, where $alpha_n,beta_nin Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)$, $nu_{n,m}(alpha_n)=alpha_m$, $nu_{n,m}(beta_n)=beta_m$, and multiplication in $Gal(overline{F}backslashmathbb{F}_p)$ is given by $alpha*beta=(alpha_n*beta_n)_{ninmathbb{N}}$, where multiplication in $Gal(mathbb{F}_{p^n}backslashmathbb{F}_p)$ was defined above.



        This is the natural way of describing the ring structure on $Gal(overline{F}backslashmathbb{F}_p)$, and since $widehat{mathbb{Z}}$ is identivcally defined as the inverse limit of the system of cyclic groups $frac{mathbb{Z}}{nmathbb{Z}}$, it is equivalent to the ring structure on $widehat{mathbb{Z}}$.







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        answered Jul 2 at 13:38









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