Simplify $(x'+y)'(x+y)'$ with boolean algebra
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So I'm doing some homework and trying to simplify $(x'+y)'(x+y)'$. So far these are the steps I've completed, but I'm not 100% sure that they're appropriate.
$(x'+y)'(x+y)' = (x'+y)'(x’y’)$
$(x'+y)'(x’y’) = (x’’+ y’)(x’y’)$
$(x’’+y’)(x’y’) = (x+y’)(x’y’)$
I'm unsure of what to do after this step (or if I've made any actual mistakes)
boolean-algebra
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up vote
0
down vote
favorite
So I'm doing some homework and trying to simplify $(x'+y)'(x+y)'$. So far these are the steps I've completed, but I'm not 100% sure that they're appropriate.
$(x'+y)'(x+y)' = (x'+y)'(x’y’)$
$(x'+y)'(x’y’) = (x’’+ y’)(x’y’)$
$(x’’+y’)(x’y’) = (x+y’)(x’y’)$
I'm unsure of what to do after this step (or if I've made any actual mistakes)
boolean-algebra
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
So I'm doing some homework and trying to simplify $(x'+y)'(x+y)'$. So far these are the steps I've completed, but I'm not 100% sure that they're appropriate.
$(x'+y)'(x+y)' = (x'+y)'(x’y’)$
$(x'+y)'(x’y’) = (x’’+ y’)(x’y’)$
$(x’’+y’)(x’y’) = (x+y’)(x’y’)$
I'm unsure of what to do after this step (or if I've made any actual mistakes)
boolean-algebra
So I'm doing some homework and trying to simplify $(x'+y)'(x+y)'$. So far these are the steps I've completed, but I'm not 100% sure that they're appropriate.
$(x'+y)'(x+y)' = (x'+y)'(x’y’)$
$(x'+y)'(x’y’) = (x’’+ y’)(x’y’)$
$(x’’+y’)(x’y’) = (x+y’)(x’y’)$
I'm unsure of what to do after this step (or if I've made any actual mistakes)
boolean-algebra
boolean-algebra
edited Dec 2 at 7:23
Tianlalu
2,9451936
2,9451936
asked Oct 29 '14 at 2:18
Tai M.
2921218
2921218
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1 Answer
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$(x'+y)'(x+y)'=(x'+y)'(x'y')=(x''y')(x'y')=(xy')(x'y')$
Can you do the last step?
I couldn't figure it out algebraically so I drew out a truth table to figure it out and realized it was 0.
– Tai M.
Oct 29 '14 at 3:04
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
$(x'+y)'(x+y)'=(x'+y)'(x'y')=(x''y')(x'y')=(xy')(x'y')$
Can you do the last step?
I couldn't figure it out algebraically so I drew out a truth table to figure it out and realized it was 0.
– Tai M.
Oct 29 '14 at 3:04
add a comment |
up vote
0
down vote
$(x'+y)'(x+y)'=(x'+y)'(x'y')=(x''y')(x'y')=(xy')(x'y')$
Can you do the last step?
I couldn't figure it out algebraically so I drew out a truth table to figure it out and realized it was 0.
– Tai M.
Oct 29 '14 at 3:04
add a comment |
up vote
0
down vote
up vote
0
down vote
$(x'+y)'(x+y)'=(x'+y)'(x'y')=(x''y')(x'y')=(xy')(x'y')$
Can you do the last step?
$(x'+y)'(x+y)'=(x'+y)'(x'y')=(x''y')(x'y')=(xy')(x'y')$
Can you do the last step?
answered Oct 29 '14 at 2:32
Joel Reyes Noche
5,59733148
5,59733148
I couldn't figure it out algebraically so I drew out a truth table to figure it out and realized it was 0.
– Tai M.
Oct 29 '14 at 3:04
add a comment |
I couldn't figure it out algebraically so I drew out a truth table to figure it out and realized it was 0.
– Tai M.
Oct 29 '14 at 3:04
I couldn't figure it out algebraically so I drew out a truth table to figure it out and realized it was 0.
– Tai M.
Oct 29 '14 at 3:04
I couldn't figure it out algebraically so I drew out a truth table to figure it out and realized it was 0.
– Tai M.
Oct 29 '14 at 3:04
add a comment |
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