Strong and weak Ratio test?











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Is this a valid test for convergence of $sum_{n=1}^infty a_n$ where $a_n$ are all positive?
Define:



$rho_n=a_n/a_{n+1}$



The series converges if $rho_n>1$ for all n>N



The series diverges if $rho_n le 1$ for all n>N



where $N$ is some positive integer. Note this is not the same as the usual ratio test which states that the series converges if $lim_{n to infty}rho_n>1$ and diverges if $lim_{n to infty}rho_n<1$ with no conclusion for 1.



I ask this because Kummer's test has been stated as: $rho_n=D_n a_n/a_{n+1}-D_{n+1}$ where $D_n$ is a positive term series, with convergence for $rho_n>0$ and divergence for $rho_n le 0$ and $D_n$ divergent, for some $n>N$. It has also been stated in the limit form where $lim_{n to infty}rho_n<0$ and $D_n$ divergent for divergence. Substituting $D_n=1$ into Kummers test gives the above statement (no limits), along with the usual ratio test involving limits.










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    up vote
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    down vote

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    Is this a valid test for convergence of $sum_{n=1}^infty a_n$ where $a_n$ are all positive?
    Define:



    $rho_n=a_n/a_{n+1}$



    The series converges if $rho_n>1$ for all n>N



    The series diverges if $rho_n le 1$ for all n>N



    where $N$ is some positive integer. Note this is not the same as the usual ratio test which states that the series converges if $lim_{n to infty}rho_n>1$ and diverges if $lim_{n to infty}rho_n<1$ with no conclusion for 1.



    I ask this because Kummer's test has been stated as: $rho_n=D_n a_n/a_{n+1}-D_{n+1}$ where $D_n$ is a positive term series, with convergence for $rho_n>0$ and divergence for $rho_n le 0$ and $D_n$ divergent, for some $n>N$. It has also been stated in the limit form where $lim_{n to infty}rho_n<0$ and $D_n$ divergent for divergence. Substituting $D_n=1$ into Kummers test gives the above statement (no limits), along with the usual ratio test involving limits.










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    Paul R. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      up vote
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      down vote

      favorite









      up vote
      1
      down vote

      favorite











      Is this a valid test for convergence of $sum_{n=1}^infty a_n$ where $a_n$ are all positive?
      Define:



      $rho_n=a_n/a_{n+1}$



      The series converges if $rho_n>1$ for all n>N



      The series diverges if $rho_n le 1$ for all n>N



      where $N$ is some positive integer. Note this is not the same as the usual ratio test which states that the series converges if $lim_{n to infty}rho_n>1$ and diverges if $lim_{n to infty}rho_n<1$ with no conclusion for 1.



      I ask this because Kummer's test has been stated as: $rho_n=D_n a_n/a_{n+1}-D_{n+1}$ where $D_n$ is a positive term series, with convergence for $rho_n>0$ and divergence for $rho_n le 0$ and $D_n$ divergent, for some $n>N$. It has also been stated in the limit form where $lim_{n to infty}rho_n<0$ and $D_n$ divergent for divergence. Substituting $D_n=1$ into Kummers test gives the above statement (no limits), along with the usual ratio test involving limits.










      share|cite|improve this question







      New contributor




      Paul R. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      Is this a valid test for convergence of $sum_{n=1}^infty a_n$ where $a_n$ are all positive?
      Define:



      $rho_n=a_n/a_{n+1}$



      The series converges if $rho_n>1$ for all n>N



      The series diverges if $rho_n le 1$ for all n>N



      where $N$ is some positive integer. Note this is not the same as the usual ratio test which states that the series converges if $lim_{n to infty}rho_n>1$ and diverges if $lim_{n to infty}rho_n<1$ with no conclusion for 1.



      I ask this because Kummer's test has been stated as: $rho_n=D_n a_n/a_{n+1}-D_{n+1}$ where $D_n$ is a positive term series, with convergence for $rho_n>0$ and divergence for $rho_n le 0$ and $D_n$ divergent, for some $n>N$. It has also been stated in the limit form where $lim_{n to infty}rho_n<0$ and $D_n$ divergent for divergence. Substituting $D_n=1$ into Kummers test gives the above statement (no limits), along with the usual ratio test involving limits.







      sequences-and-series convergence






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      asked Dec 2 at 4:25









      Paul R.

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          2 Answers
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          No. For example, your test predicts that
          $$ sum_{n geq 1} frac{1}{n^2} $$
          diverges.






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            Ok, thanks, now I see the problem. Kummer's $rho_n$ is $D_n a_n/a_{n+1}-D_{n+1}$ and for convergence, there must be a $c>0$ such that $rho_n ge c$ which is NOT the same as $rho_n > 0$, which I mistakenly supposed. If $a_n=1/n^2$, then $rho_n=(1+1/n)^2$ which, although it is greater than zero for all $nge 1$, there is no $c>0$ that it is greater than or equal to for any $n$.






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              2 Answers
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              2 Answers
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              up vote
              1
              down vote













              No. For example, your test predicts that
              $$ sum_{n geq 1} frac{1}{n^2} $$
              diverges.






              share|cite|improve this answer

























                up vote
                1
                down vote













                No. For example, your test predicts that
                $$ sum_{n geq 1} frac{1}{n^2} $$
                diverges.






                share|cite|improve this answer























                  up vote
                  1
                  down vote










                  up vote
                  1
                  down vote









                  No. For example, your test predicts that
                  $$ sum_{n geq 1} frac{1}{n^2} $$
                  diverges.






                  share|cite|improve this answer












                  No. For example, your test predicts that
                  $$ sum_{n geq 1} frac{1}{n^2} $$
                  diverges.







                  share|cite|improve this answer












                  share|cite|improve this answer



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                  answered Dec 2 at 4:51









                  davidlowryduda

                  74.1k7117250




                  74.1k7117250






















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                      down vote













                      Ok, thanks, now I see the problem. Kummer's $rho_n$ is $D_n a_n/a_{n+1}-D_{n+1}$ and for convergence, there must be a $c>0$ such that $rho_n ge c$ which is NOT the same as $rho_n > 0$, which I mistakenly supposed. If $a_n=1/n^2$, then $rho_n=(1+1/n)^2$ which, although it is greater than zero for all $nge 1$, there is no $c>0$ that it is greater than or equal to for any $n$.






                      share|cite|improve this answer








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                      Paul R. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                        up vote
                        0
                        down vote













                        Ok, thanks, now I see the problem. Kummer's $rho_n$ is $D_n a_n/a_{n+1}-D_{n+1}$ and for convergence, there must be a $c>0$ such that $rho_n ge c$ which is NOT the same as $rho_n > 0$, which I mistakenly supposed. If $a_n=1/n^2$, then $rho_n=(1+1/n)^2$ which, although it is greater than zero for all $nge 1$, there is no $c>0$ that it is greater than or equal to for any $n$.






                        share|cite|improve this answer








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                          up vote
                          0
                          down vote










                          up vote
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                          down vote









                          Ok, thanks, now I see the problem. Kummer's $rho_n$ is $D_n a_n/a_{n+1}-D_{n+1}$ and for convergence, there must be a $c>0$ such that $rho_n ge c$ which is NOT the same as $rho_n > 0$, which I mistakenly supposed. If $a_n=1/n^2$, then $rho_n=(1+1/n)^2$ which, although it is greater than zero for all $nge 1$, there is no $c>0$ that it is greater than or equal to for any $n$.






                          share|cite|improve this answer








                          New contributor




                          Paul R. is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.









                          Ok, thanks, now I see the problem. Kummer's $rho_n$ is $D_n a_n/a_{n+1}-D_{n+1}$ and for convergence, there must be a $c>0$ such that $rho_n ge c$ which is NOT the same as $rho_n > 0$, which I mistakenly supposed. If $a_n=1/n^2$, then $rho_n=(1+1/n)^2$ which, although it is greater than zero for all $nge 1$, there is no $c>0$ that it is greater than or equal to for any $n$.







                          share|cite|improve this answer








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                          answered Dec 2 at 5:05









                          Paul R.

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