Strong and weak Ratio test?
up vote
1
down vote
favorite
Is this a valid test for convergence of $sum_{n=1}^infty a_n$ where $a_n$ are all positive?
Define:
$rho_n=a_n/a_{n+1}$
The series converges if $rho_n>1$ for all n>N
The series diverges if $rho_n le 1$ for all n>N
where $N$ is some positive integer. Note this is not the same as the usual ratio test which states that the series converges if $lim_{n to infty}rho_n>1$ and diverges if $lim_{n to infty}rho_n<1$ with no conclusion for 1.
I ask this because Kummer's test has been stated as: $rho_n=D_n a_n/a_{n+1}-D_{n+1}$ where $D_n$ is a positive term series, with convergence for $rho_n>0$ and divergence for $rho_n le 0$ and $D_n$ divergent, for some $n>N$. It has also been stated in the limit form where $lim_{n to infty}rho_n<0$ and $D_n$ divergent for divergence. Substituting $D_n=1$ into Kummers test gives the above statement (no limits), along with the usual ratio test involving limits.
sequences-and-series convergence
New contributor
add a comment |
up vote
1
down vote
favorite
Is this a valid test for convergence of $sum_{n=1}^infty a_n$ where $a_n$ are all positive?
Define:
$rho_n=a_n/a_{n+1}$
The series converges if $rho_n>1$ for all n>N
The series diverges if $rho_n le 1$ for all n>N
where $N$ is some positive integer. Note this is not the same as the usual ratio test which states that the series converges if $lim_{n to infty}rho_n>1$ and diverges if $lim_{n to infty}rho_n<1$ with no conclusion for 1.
I ask this because Kummer's test has been stated as: $rho_n=D_n a_n/a_{n+1}-D_{n+1}$ where $D_n$ is a positive term series, with convergence for $rho_n>0$ and divergence for $rho_n le 0$ and $D_n$ divergent, for some $n>N$. It has also been stated in the limit form where $lim_{n to infty}rho_n<0$ and $D_n$ divergent for divergence. Substituting $D_n=1$ into Kummers test gives the above statement (no limits), along with the usual ratio test involving limits.
sequences-and-series convergence
New contributor
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
Is this a valid test for convergence of $sum_{n=1}^infty a_n$ where $a_n$ are all positive?
Define:
$rho_n=a_n/a_{n+1}$
The series converges if $rho_n>1$ for all n>N
The series diverges if $rho_n le 1$ for all n>N
where $N$ is some positive integer. Note this is not the same as the usual ratio test which states that the series converges if $lim_{n to infty}rho_n>1$ and diverges if $lim_{n to infty}rho_n<1$ with no conclusion for 1.
I ask this because Kummer's test has been stated as: $rho_n=D_n a_n/a_{n+1}-D_{n+1}$ where $D_n$ is a positive term series, with convergence for $rho_n>0$ and divergence for $rho_n le 0$ and $D_n$ divergent, for some $n>N$. It has also been stated in the limit form where $lim_{n to infty}rho_n<0$ and $D_n$ divergent for divergence. Substituting $D_n=1$ into Kummers test gives the above statement (no limits), along with the usual ratio test involving limits.
sequences-and-series convergence
New contributor
Is this a valid test for convergence of $sum_{n=1}^infty a_n$ where $a_n$ are all positive?
Define:
$rho_n=a_n/a_{n+1}$
The series converges if $rho_n>1$ for all n>N
The series diverges if $rho_n le 1$ for all n>N
where $N$ is some positive integer. Note this is not the same as the usual ratio test which states that the series converges if $lim_{n to infty}rho_n>1$ and diverges if $lim_{n to infty}rho_n<1$ with no conclusion for 1.
I ask this because Kummer's test has been stated as: $rho_n=D_n a_n/a_{n+1}-D_{n+1}$ where $D_n$ is a positive term series, with convergence for $rho_n>0$ and divergence for $rho_n le 0$ and $D_n$ divergent, for some $n>N$. It has also been stated in the limit form where $lim_{n to infty}rho_n<0$ and $D_n$ divergent for divergence. Substituting $D_n=1$ into Kummers test gives the above statement (no limits), along with the usual ratio test involving limits.
sequences-and-series convergence
sequences-and-series convergence
New contributor
New contributor
New contributor
asked Dec 2 at 4:25
Paul R.
61
61
New contributor
New contributor
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
1
down vote
No. For example, your test predicts that
$$ sum_{n geq 1} frac{1}{n^2} $$
diverges.
add a comment |
up vote
0
down vote
Ok, thanks, now I see the problem. Kummer's $rho_n$ is $D_n a_n/a_{n+1}-D_{n+1}$ and for convergence, there must be a $c>0$ such that $rho_n ge c$ which is NOT the same as $rho_n > 0$, which I mistakenly supposed. If $a_n=1/n^2$, then $rho_n=(1+1/n)^2$ which, although it is greater than zero for all $nge 1$, there is no $c>0$ that it is greater than or equal to for any $n$.
New contributor
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
No. For example, your test predicts that
$$ sum_{n geq 1} frac{1}{n^2} $$
diverges.
add a comment |
up vote
1
down vote
No. For example, your test predicts that
$$ sum_{n geq 1} frac{1}{n^2} $$
diverges.
add a comment |
up vote
1
down vote
up vote
1
down vote
No. For example, your test predicts that
$$ sum_{n geq 1} frac{1}{n^2} $$
diverges.
No. For example, your test predicts that
$$ sum_{n geq 1} frac{1}{n^2} $$
diverges.
answered Dec 2 at 4:51
davidlowryduda♦
74.1k7117250
74.1k7117250
add a comment |
add a comment |
up vote
0
down vote
Ok, thanks, now I see the problem. Kummer's $rho_n$ is $D_n a_n/a_{n+1}-D_{n+1}$ and for convergence, there must be a $c>0$ such that $rho_n ge c$ which is NOT the same as $rho_n > 0$, which I mistakenly supposed. If $a_n=1/n^2$, then $rho_n=(1+1/n)^2$ which, although it is greater than zero for all $nge 1$, there is no $c>0$ that it is greater than or equal to for any $n$.
New contributor
add a comment |
up vote
0
down vote
Ok, thanks, now I see the problem. Kummer's $rho_n$ is $D_n a_n/a_{n+1}-D_{n+1}$ and for convergence, there must be a $c>0$ such that $rho_n ge c$ which is NOT the same as $rho_n > 0$, which I mistakenly supposed. If $a_n=1/n^2$, then $rho_n=(1+1/n)^2$ which, although it is greater than zero for all $nge 1$, there is no $c>0$ that it is greater than or equal to for any $n$.
New contributor
add a comment |
up vote
0
down vote
up vote
0
down vote
Ok, thanks, now I see the problem. Kummer's $rho_n$ is $D_n a_n/a_{n+1}-D_{n+1}$ and for convergence, there must be a $c>0$ such that $rho_n ge c$ which is NOT the same as $rho_n > 0$, which I mistakenly supposed. If $a_n=1/n^2$, then $rho_n=(1+1/n)^2$ which, although it is greater than zero for all $nge 1$, there is no $c>0$ that it is greater than or equal to for any $n$.
New contributor
Ok, thanks, now I see the problem. Kummer's $rho_n$ is $D_n a_n/a_{n+1}-D_{n+1}$ and for convergence, there must be a $c>0$ such that $rho_n ge c$ which is NOT the same as $rho_n > 0$, which I mistakenly supposed. If $a_n=1/n^2$, then $rho_n=(1+1/n)^2$ which, although it is greater than zero for all $nge 1$, there is no $c>0$ that it is greater than or equal to for any $n$.
New contributor
New contributor
answered Dec 2 at 5:05
Paul R.
61
61
New contributor
New contributor
add a comment |
add a comment |
Paul R. is a new contributor. Be nice, and check out our Code of Conduct.
Paul R. is a new contributor. Be nice, and check out our Code of Conduct.
Paul R. is a new contributor. Be nice, and check out our Code of Conduct.
Paul R. is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3022229%2fstrong-and-weak-ratio-test%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown