One question: I guess it's to do with suvat equations:Kinematics [closed]
A car moves along a straight horizontal road from a point A to a point B, where AB = 885 m. The car accelerates from rest at A to a speed of 15 m s −1 at a constant rate a m s−2. The time for which the car accelerates is T seconds. The car maintains the speed of 15 m s−1 for T seconds. The car then decelerates at a constant rate of 2.5 m s−2 stopping at B.
Find the time for which the car decelerates.
How do you approach this question?
Other details:
Here's kinematic equations for distance and speed:
$x(t)=v_0*t pm frac{a*t^2}{2} tag{1}$
$v(t)= v_0 pm a*t tag{2}$
kinematics
edited Dec 14 '18 at 16:53
peterh
2,16451731
asked Dec 11 '18 at 20:54
Yusuf123
111
closed as off-topic by Davide Giraudo, Dando18, John B, KReiser, platty Dec 12 '18 at 0:12
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Davide Giraudo, Dando18, John B, KReiser, platty
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
A car moves along a straight horizontal road from a point A to a point B, where AB = 885 m. The car accelerates from rest at A to a speed of 15 m s −1 at a constant rate a m s−2. The time for which the car accelerates is T seconds. The car maintains the speed of 15 m s−1 for T seconds. The car then decelerates at a constant rate of 2.5 m s−2 stopping at B.
Find the time for which the car decelerates.
How do you approach this question?
Other details:
Here's kinematic equations for distance and speed:
$x(t)=v_0*t pm frac{a*t^2}{2} tag{1}$
$v(t)= v_0 pm a*t tag{2}$
kinematics
edited Dec 14 '18 at 16:53
peterh
2,16451731
asked Dec 11 '18 at 20:54
Yusuf123
111
closed as off-topic by Davide Giraudo, Dando18, John B, KReiser, platty Dec 12 '18 at 0:12
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Davide Giraudo, Dando18, John B, KReiser, platty
If this question can be reworded to fit the rules in the help center, please edit the question.
update your question with picture and kinematic equations.
– yW0K5o
Dec 13 '18 at 21:52
add a comment |
A car moves along a straight horizontal road from a point A to a point B, where AB = 885 m. The car accelerates from rest at A to a speed of 15 m s −1 at a constant rate a m s−2. The time for which the car accelerates is T seconds. The car maintains the speed of 15 m s−1 for T seconds. The car then decelerates at a constant rate of 2.5 m s−2 stopping at B.
Find the time for which the car decelerates.
How do you approach this question?
Other details:
Here's kinematic equations for distance and speed:
$x(t)=v_0*t pm frac{a*t^2}{2} tag{1}$
$v(t)= v_0 pm a*t tag{2}$
kinematics
edited Dec 14 '18 at 16:53
peterh
2,16451731
asked Dec 11 '18 at 20:54
Yusuf123
111
A car moves along a straight horizontal road from a point A to a point B, where AB = 885 m. The car accelerates from rest at A to a speed of 15 m s −1 at a constant rate a m s−2. The time for which the car accelerates is T seconds. The car maintains the speed of 15 m s−1 for T seconds. The car then decelerates at a constant rate of 2.5 m s−2 stopping at B.
Find the time for which the car decelerates.
How do you approach this question?
Other details:
Here's kinematic equations for distance and speed:
$x(t)=v_0*t pm frac{a*t^2}{2} tag{1}$
$v(t)= v_0 pm a*t tag{2}$
kinematics
kinematics
edited Dec 14 '18 at 16:53
peterh
2,16451731
asked Dec 11 '18 at 20:54
Yusuf123
111
edited Dec 14 '18 at 16:53
peterh
2,16451731
asked Dec 11 '18 at 20:54
Yusuf123
111
edited Dec 14 '18 at 16:53
peterh
2,16451731
edited Dec 14 '18 at 16:53
peterh
2,16451731
edited Dec 14 '18 at 16:53
peterh
2,16451731
2,16451731
asked Dec 11 '18 at 20:54
Yusuf123
111
asked Dec 11 '18 at 20:54
Yusuf123
111
asked Dec 11 '18 at 20:54
Yusuf123
111
111
closed as off-topic by Davide Giraudo, Dando18, John B, KReiser, platty Dec 12 '18 at 0:12
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Davide Giraudo, Dando18, John B, KReiser, platty
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Davide Giraudo, Dando18, John B, KReiser, platty Dec 12 '18 at 0:12
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Davide Giraudo, Dando18, John B, KReiser, platty
If this question can be reworded to fit the rules in the help center, please edit the question.
update your question with picture and kinematic equations.
– yW0K5o
Dec 13 '18 at 21:52
add a comment |
update your question with picture and kinematic equations.
– yW0K5o
Dec 13 '18 at 21:52
update your question with picture and kinematic equations.
– yW0K5o
Dec 13 '18 at 21:52
update your question with picture and kinematic equations.
– yW0K5o
Dec 13 '18 at 21:52
add a comment |
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update your question with picture and kinematic equations.
– yW0K5o
Dec 13 '18 at 21:52