ESL - Linear Model where output is a vector. Ch 2 Pg 11
$begingroup$
In the terminology used in ESL, a vector is a column vector. Let output be a $k$-vector, i.e.$$Y=(Y_1,Y_2,cdots,Y_K)^T$$Now please refer to following line on pg 12.
In general $hat{Y}$ can be a $K$-vector, in which case $beta$ would be a $p times K$ matrix
Q1: Am I correct that the matrix representation of the linear model in above situation will be
${hat{Y}}^T =X^T.hat{beta}$
Q2: Why is there a hat i.e. ^ over $beta$, what is the significance on that?
Thanks
linear-algebra machine-learning linear-regression
$endgroup$
add a comment |
$begingroup$
In the terminology used in ESL, a vector is a column vector. Let output be a $k$-vector, i.e.$$Y=(Y_1,Y_2,cdots,Y_K)^T$$Now please refer to following line on pg 12.
In general $hat{Y}$ can be a $K$-vector, in which case $beta$ would be a $p times K$ matrix
Q1: Am I correct that the matrix representation of the linear model in above situation will be
${hat{Y}}^T =X^T.hat{beta}$
Q2: Why is there a hat i.e. ^ over $beta$, what is the significance on that?
Thanks
linear-algebra machine-learning linear-regression
$endgroup$
add a comment |
$begingroup$
In the terminology used in ESL, a vector is a column vector. Let output be a $k$-vector, i.e.$$Y=(Y_1,Y_2,cdots,Y_K)^T$$Now please refer to following line on pg 12.
In general $hat{Y}$ can be a $K$-vector, in which case $beta$ would be a $p times K$ matrix
Q1: Am I correct that the matrix representation of the linear model in above situation will be
${hat{Y}}^T =X^T.hat{beta}$
Q2: Why is there a hat i.e. ^ over $beta$, what is the significance on that?
Thanks
linear-algebra machine-learning linear-regression
$endgroup$
In the terminology used in ESL, a vector is a column vector. Let output be a $k$-vector, i.e.$$Y=(Y_1,Y_2,cdots,Y_K)^T$$Now please refer to following line on pg 12.
In general $hat{Y}$ can be a $K$-vector, in which case $beta$ would be a $p times K$ matrix
Q1: Am I correct that the matrix representation of the linear model in above situation will be
${hat{Y}}^T =X^T.hat{beta}$
Q2: Why is there a hat i.e. ^ over $beta$, what is the significance on that?
Thanks
linear-algebra machine-learning linear-regression
linear-algebra machine-learning linear-regression
edited Dec 29 '18 at 12:30
Saad
19.7k92352
19.7k92352
asked Dec 29 '18 at 12:09
aman_ccaman_cc
588
588
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3055782%2fesl-linear-model-where-output-is-a-vector-ch-2-pg-11%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3055782%2fesl-linear-model-where-output-is-a-vector-ch-2-pg-11%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown