Expectation to draw all numbers from 1 to 100












0












$begingroup$


I have 100 papers each contains numbers like
(1,2), (2,3),(3,4),..., (99,100), (100,100). I draw
each paper and note down its numbers and return that paper.
How any times I have to draw on average to note down all
numbers from 1,2, .., 100?



Let $X_n$ be the total numbers on average drawn at $n$-time.
I observed experimentally $X_{n+1}$ is around $X_n+(1-frac{X_n}{100})2$










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$endgroup$












  • $begingroup$
    Do papers contain different numbers, or also twice the same number?
    $endgroup$
    – Did
    Dec 29 '18 at 11:57












  • $begingroup$
    Papers contain all different consecutive numbers except last paper which contains (100,100).
    $endgroup$
    – str
    Dec 29 '18 at 12:28
















0












$begingroup$


I have 100 papers each contains numbers like
(1,2), (2,3),(3,4),..., (99,100), (100,100). I draw
each paper and note down its numbers and return that paper.
How any times I have to draw on average to note down all
numbers from 1,2, .., 100?



Let $X_n$ be the total numbers on average drawn at $n$-time.
I observed experimentally $X_{n+1}$ is around $X_n+(1-frac{X_n}{100})2$










share|cite|improve this question











$endgroup$












  • $begingroup$
    Do papers contain different numbers, or also twice the same number?
    $endgroup$
    – Did
    Dec 29 '18 at 11:57












  • $begingroup$
    Papers contain all different consecutive numbers except last paper which contains (100,100).
    $endgroup$
    – str
    Dec 29 '18 at 12:28














0












0








0





$begingroup$


I have 100 papers each contains numbers like
(1,2), (2,3),(3,4),..., (99,100), (100,100). I draw
each paper and note down its numbers and return that paper.
How any times I have to draw on average to note down all
numbers from 1,2, .., 100?



Let $X_n$ be the total numbers on average drawn at $n$-time.
I observed experimentally $X_{n+1}$ is around $X_n+(1-frac{X_n}{100})2$










share|cite|improve this question











$endgroup$




I have 100 papers each contains numbers like
(1,2), (2,3),(3,4),..., (99,100), (100,100). I draw
each paper and note down its numbers and return that paper.
How any times I have to draw on average to note down all
numbers from 1,2, .., 100?



Let $X_n$ be the total numbers on average drawn at $n$-time.
I observed experimentally $X_{n+1}$ is around $X_n+(1-frac{X_n}{100})2$







expected-value






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Dec 29 '18 at 11:01







str

















asked Dec 29 '18 at 10:53









strstr

425




425












  • $begingroup$
    Do papers contain different numbers, or also twice the same number?
    $endgroup$
    – Did
    Dec 29 '18 at 11:57












  • $begingroup$
    Papers contain all different consecutive numbers except last paper which contains (100,100).
    $endgroup$
    – str
    Dec 29 '18 at 12:28


















  • $begingroup$
    Do papers contain different numbers, or also twice the same number?
    $endgroup$
    – Did
    Dec 29 '18 at 11:57












  • $begingroup$
    Papers contain all different consecutive numbers except last paper which contains (100,100).
    $endgroup$
    – str
    Dec 29 '18 at 12:28
















$begingroup$
Do papers contain different numbers, or also twice the same number?
$endgroup$
– Did
Dec 29 '18 at 11:57






$begingroup$
Do papers contain different numbers, or also twice the same number?
$endgroup$
– Did
Dec 29 '18 at 11:57














$begingroup$
Papers contain all different consecutive numbers except last paper which contains (100,100).
$endgroup$
– str
Dec 29 '18 at 12:28




$begingroup$
Papers contain all different consecutive numbers except last paper which contains (100,100).
$endgroup$
– str
Dec 29 '18 at 12:28










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