How to simplify a diagonal line pattern formula
$begingroup$
I've got the following formula:
$$
clamp(floor(frac((x+y)*5) + 0.2) + floor(frac((y-x)*5) + 0.2))
$$
Frac here means fractional part $frac(x) = x - floor(x)$. Clamp means $max(0,min(x,1))$.
This equation is used to produce the following pattern:
Diagonal lines pattern note: the image got squeezed vertically - the lines are actually at 45 degree angles. The way it works is by evaluating every pixel and testing if the pixel satisfies the equation. If it does the result is a 1, if it doesn't the result is 0. 1 and 0 are then mapped to white and black and the image is produced.
Can this be expressed any simpler?
graphing-functions
asked Jan 10 at 10:34
CodeMolester69CodeMolester69
61
$endgroup$
add a comment |
$begingroup$
I've got the following formula:
$$
clamp(floor(frac((x+y)*5) + 0.2) + floor(frac((y-x)*5) + 0.2))
$$
Frac here means fractional part $frac(x) = x - floor(x)$. Clamp means $max(0,min(x,1))$.
This equation is used to produce the following pattern:
Diagonal lines pattern note: the image got squeezed vertically - the lines are actually at 45 degree angles. The way it works is by evaluating every pixel and testing if the pixel satisfies the equation. If it does the result is a 1, if it doesn't the result is 0. 1 and 0 are then mapped to white and black and the image is produced.
Can this be expressed any simpler?
graphing-functions
asked Jan 10 at 10:34
CodeMolester69CodeMolester69
61
$endgroup$
add a comment |
$begingroup$
I've got the following formula:
$$
clamp(floor(frac((x+y)*5) + 0.2) + floor(frac((y-x)*5) + 0.2))
$$
Frac here means fractional part $frac(x) = x - floor(x)$. Clamp means $max(0,min(x,1))$.
This equation is used to produce the following pattern:
Diagonal lines pattern note: the image got squeezed vertically - the lines are actually at 45 degree angles. The way it works is by evaluating every pixel and testing if the pixel satisfies the equation. If it does the result is a 1, if it doesn't the result is 0. 1 and 0 are then mapped to white and black and the image is produced.
Can this be expressed any simpler?
graphing-functions
asked Jan 10 at 10:34
CodeMolester69CodeMolester69
61
$endgroup$
I've got the following formula:
$$
clamp(floor(frac((x+y)*5) + 0.2) + floor(frac((y-x)*5) + 0.2))
$$
Frac here means fractional part $frac(x) = x - floor(x)$. Clamp means $max(0,min(x,1))$.
This equation is used to produce the following pattern:
Diagonal lines pattern note: the image got squeezed vertically - the lines are actually at 45 degree angles. The way it works is by evaluating every pixel and testing if the pixel satisfies the equation. If it does the result is a 1, if it doesn't the result is 0. 1 and 0 are then mapped to white and black and the image is produced.
Can this be expressed any simpler?
graphing-functions
graphing-functions
asked Jan 10 at 10:34
CodeMolester69CodeMolester69
61
asked Jan 10 at 10:34
CodeMolester69CodeMolester69
61
asked Jan 10 at 10:34
CodeMolester69CodeMolester69
61
asked Jan 10 at 10:34
CodeMolester69CodeMolester69
61
asked Jan 10 at 10:34
CodeMolester69CodeMolester69
61
61
add a comment |
add a comment |
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