Laurent Series Expansion of Exponential function.
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Find the Laurent series of the function $f(z) = e^{frac{lambda}{2}big(z-frac{1}{z}big)}$ as $sum_{n=-infty}^{infty} C_nz^n$ for $0<|z|<infty$ where $$C_n = frac{1}{pi}int_0^{pi} cos(nphi-lambda sin phi), dphi$$ $n = 0, pm 1, pm 2, cdots$ with $lambda$ a given complex number and taking the unit circle $C$ given by $$z = e^{iota phi} (-pileq phileq pi)$$ as contour in this region.
complex-analysis laurent-series
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Find the Laurent series of the function $f(z) = e^{frac{lambda}{2}big(z-frac{1}{z}big)}$ as $sum_{n=-infty}^{infty} C_nz^n$ for $0<|z|<infty$ where $$C_n = frac{1}{pi}int_0^{pi} cos(nphi-lambda sin phi), dphi$$ $n = 0, pm 1, pm 2, cdots$ with $lambda$ a given complex number and taking the unit circle $C$ given by $$z = e^{iota phi} (-pileq phileq pi)$$ as contour in this region.
complex-analysis laurent-series
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up vote
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down vote
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up vote
0
down vote
favorite
Find the Laurent series of the function $f(z) = e^{frac{lambda}{2}big(z-frac{1}{z}big)}$ as $sum_{n=-infty}^{infty} C_nz^n$ for $0<|z|<infty$ where $$C_n = frac{1}{pi}int_0^{pi} cos(nphi-lambda sin phi), dphi$$ $n = 0, pm 1, pm 2, cdots$ with $lambda$ a given complex number and taking the unit circle $C$ given by $$z = e^{iota phi} (-pileq phileq pi)$$ as contour in this region.
complex-analysis laurent-series
Find the Laurent series of the function $f(z) = e^{frac{lambda}{2}big(z-frac{1}{z}big)}$ as $sum_{n=-infty}^{infty} C_nz^n$ for $0<|z|<infty$ where $$C_n = frac{1}{pi}int_0^{pi} cos(nphi-lambda sin phi), dphi$$ $n = 0, pm 1, pm 2, cdots$ with $lambda$ a given complex number and taking the unit circle $C$ given by $$z = e^{iota phi} (-pileq phileq pi)$$ as contour in this region.
complex-analysis laurent-series
complex-analysis laurent-series
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Mittal G
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1,182515
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