Simply find point in circle border
This seems to silly for you expert guys in math but I am not good in this So Please help.
Suppose you have clock of 330 * 330 pixels so I have radius 165 in circle.
I want to find position of 1 (in clock ) . so circle is 360 degrees
so 360 / 12 = 30 Degree per hour
To find 1'O Clock position I have tried
x = cos(30) * 165 which is 25.4514892315. how to use this value.
Any Help would be appreciated
What I need is Put White circle at 1 O Clock position White circle size is 20 Pixel Orange circle size is 330 Pixel
circle angle spectral-radius
asked Dec 12 '18 at 7:33
Prashant TukadiyaPrashant Tukadiya
1013
|
show 1 more comment
This seems to silly for you expert guys in math but I am not good in this So Please help.
Suppose you have clock of 330 * 330 pixels so I have radius 165 in circle.
I want to find position of 1 (in clock ) . so circle is 360 degrees
so 360 / 12 = 30 Degree per hour
To find 1'O Clock position I have tried
x = cos(30) * 165 which is 25.4514892315. how to use this value.
Any Help would be appreciated
What I need is Put White circle at 1 O Clock position White circle size is 20 Pixel Orange circle size is 330 Pixel
circle angle spectral-radius
asked Dec 12 '18 at 7:33
Prashant TukadiyaPrashant Tukadiya
1013
You are correct to look at $30^circ$ and the trig functions. If the center of the circle were $(0,0)$ and up corresponded to a positive $y$ direction then the point you are interested in would be $(165sin(30^circ),165cos(30^circ))$. Since your center is probably not called $(0,0)$ however, you will likely need to translate (or even reflect) the result further.
– JMoravitz
Dec 12 '18 at 7:41
@JMoravitz Thanks for comment. As i didn't know math terms well can you explain in simple lang ? because sin(30) * 165 is -163.025217975. Not able to place it properly
– Prashant Tukadiya
Dec 12 '18 at 7:49
1
Assuming center is $(0,0)$ the point you want is $(165sin(30^circ),165cos(30^circ))approxeq (82.5, 143)$. As an aside, you want $165cos(30^circ)approx 143$ where $30^circ$ is a measurement of angle in degrees. You apparently forgot to set your calculator to degrees mode. With the calculator in radians mode instead you get $165cos(30~text{rad})approx 25.45$ which is not what you want.
– JMoravitz
Dec 12 '18 at 7:56
@JMoravitz Thanks Yes you are correct I was not using degree mode cal. I am able to get (82.5, 143). But I need to convert his to coordinates. any help. Now My circle centre = 165 , 165 so I need to put white view according to 165,165 ? with value I got 82 and 143
– Prashant Tukadiya
Dec 12 '18 at 8:04
Add 165 to both numbers
– JMoravitz
Dec 12 '18 at 8:06
|
show 1 more comment
This seems to silly for you expert guys in math but I am not good in this So Please help.
Suppose you have clock of 330 * 330 pixels so I have radius 165 in circle.
I want to find position of 1 (in clock ) . so circle is 360 degrees
so 360 / 12 = 30 Degree per hour
To find 1'O Clock position I have tried
x = cos(30) * 165 which is 25.4514892315. how to use this value.
Any Help would be appreciated
What I need is Put White circle at 1 O Clock position White circle size is 20 Pixel Orange circle size is 330 Pixel
circle angle spectral-radius
asked Dec 12 '18 at 7:33
Prashant TukadiyaPrashant Tukadiya
1013
This seems to silly for you expert guys in math but I am not good in this So Please help.
Suppose you have clock of 330 * 330 pixels so I have radius 165 in circle.
I want to find position of 1 (in clock ) . so circle is 360 degrees
so 360 / 12 = 30 Degree per hour
To find 1'O Clock position I have tried
x = cos(30) * 165 which is 25.4514892315. how to use this value.
Any Help would be appreciated
What I need is Put White circle at 1 O Clock position White circle size is 20 Pixel Orange circle size is 330 Pixel
circle angle spectral-radius
circle angle spectral-radius
asked Dec 12 '18 at 7:33
Prashant TukadiyaPrashant Tukadiya
1013
asked Dec 12 '18 at 7:33
Prashant TukadiyaPrashant Tukadiya
1013
asked Dec 12 '18 at 7:33
Prashant TukadiyaPrashant Tukadiya
1013
asked Dec 12 '18 at 7:33
Prashant TukadiyaPrashant Tukadiya
1013
asked Dec 12 '18 at 7:33
Prashant TukadiyaPrashant Tukadiya
1013
1013
You are correct to look at $30^circ$ and the trig functions. If the center of the circle were $(0,0)$ and up corresponded to a positive $y$ direction then the point you are interested in would be $(165sin(30^circ),165cos(30^circ))$. Since your center is probably not called $(0,0)$ however, you will likely need to translate (or even reflect) the result further.
– JMoravitz
Dec 12 '18 at 7:41
@JMoravitz Thanks for comment. As i didn't know math terms well can you explain in simple lang ? because sin(30) * 165 is -163.025217975. Not able to place it properly
– Prashant Tukadiya
Dec 12 '18 at 7:49
1
Assuming center is $(0,0)$ the point you want is $(165sin(30^circ),165cos(30^circ))approxeq (82.5, 143)$. As an aside, you want $165cos(30^circ)approx 143$ where $30^circ$ is a measurement of angle in degrees. You apparently forgot to set your calculator to degrees mode. With the calculator in radians mode instead you get $165cos(30~text{rad})approx 25.45$ which is not what you want.
– JMoravitz
Dec 12 '18 at 7:56
@JMoravitz Thanks Yes you are correct I was not using degree mode cal. I am able to get (82.5, 143). But I need to convert his to coordinates. any help. Now My circle centre = 165 , 165 so I need to put white view according to 165,165 ? with value I got 82 and 143
– Prashant Tukadiya
Dec 12 '18 at 8:04
Add 165 to both numbers
– JMoravitz
Dec 12 '18 at 8:06
|
show 1 more comment
You are correct to look at $30^circ$ and the trig functions. If the center of the circle were $(0,0)$ and up corresponded to a positive $y$ direction then the point you are interested in would be $(165sin(30^circ),165cos(30^circ))$. Since your center is probably not called $(0,0)$ however, you will likely need to translate (or even reflect) the result further.
– JMoravitz
Dec 12 '18 at 7:41
@JMoravitz Thanks for comment. As i didn't know math terms well can you explain in simple lang ? because sin(30) * 165 is -163.025217975. Not able to place it properly
– Prashant Tukadiya
Dec 12 '18 at 7:49
1
Assuming center is $(0,0)$ the point you want is $(165sin(30^circ),165cos(30^circ))approxeq (82.5, 143)$. As an aside, you want $165cos(30^circ)approx 143$ where $30^circ$ is a measurement of angle in degrees. You apparently forgot to set your calculator to degrees mode. With the calculator in radians mode instead you get $165cos(30~text{rad})approx 25.45$ which is not what you want.
– JMoravitz
Dec 12 '18 at 7:56
@JMoravitz Thanks Yes you are correct I was not using degree mode cal. I am able to get (82.5, 143). But I need to convert his to coordinates. any help. Now My circle centre = 165 , 165 so I need to put white view according to 165,165 ? with value I got 82 and 143
– Prashant Tukadiya
Dec 12 '18 at 8:04
Add 165 to both numbers
– JMoravitz
Dec 12 '18 at 8:06
You are correct to look at $30^circ$ and the trig functions. If the center of the circle were $(0,0)$ and up corresponded to a positive $y$ direction then the point you are interested in would be $(165sin(30^circ),165cos(30^circ))$. Since your center is probably not called $(0,0)$ however, you will likely need to translate (or even reflect) the result further.
– JMoravitz
Dec 12 '18 at 7:41
You are correct to look at $30^circ$ and the trig functions. If the center of the circle were $(0,0)$ and up corresponded to a positive $y$ direction then the point you are interested in would be $(165sin(30^circ),165cos(30^circ))$. Since your center is probably not called $(0,0)$ however, you will likely need to translate (or even reflect) the result further.
– JMoravitz
Dec 12 '18 at 7:41
@JMoravitz Thanks for comment. As i didn't know math terms well can you explain in simple lang ? because sin(30) * 165 is -163.025217975. Not able to place it properly
– Prashant Tukadiya
Dec 12 '18 at 7:49
@JMoravitz Thanks for comment. As i didn't know math terms well can you explain in simple lang ? because sin(30) * 165 is -163.025217975. Not able to place it properly
– Prashant Tukadiya
Dec 12 '18 at 7:49
1
1
Assuming center is $(0,0)$ the point you want is $(165sin(30^circ),165cos(30^circ))approxeq (82.5, 143)$. As an aside, you want $165cos(30^circ)approx 143$ where $30^circ$ is a measurement of angle in degrees. You apparently forgot to set your calculator to degrees mode. With the calculator in radians mode instead you get $165cos(30~text{rad})approx 25.45$ which is not what you want.
– JMoravitz
Dec 12 '18 at 7:56
Assuming center is $(0,0)$ the point you want is $(165sin(30^circ),165cos(30^circ))approxeq (82.5, 143)$. As an aside, you want $165cos(30^circ)approx 143$ where $30^circ$ is a measurement of angle in degrees. You apparently forgot to set your calculator to degrees mode. With the calculator in radians mode instead you get $165cos(30~text{rad})approx 25.45$ which is not what you want.
– JMoravitz
Dec 12 '18 at 7:56
@JMoravitz Thanks Yes you are correct I was not using degree mode cal. I am able to get (82.5, 143). But I need to convert his to coordinates. any help. Now My circle centre = 165 , 165 so I need to put white view according to 165,165 ? with value I got 82 and 143
– Prashant Tukadiya
Dec 12 '18 at 8:04
@JMoravitz Thanks Yes you are correct I was not using degree mode cal. I am able to get (82.5, 143). But I need to convert his to coordinates. any help. Now My circle centre = 165 , 165 so I need to put white view according to 165,165 ? with value I got 82 and 143
– Prashant Tukadiya
Dec 12 '18 at 8:04
Add 165 to both numbers
– JMoravitz
Dec 12 '18 at 8:06
Add 165 to both numbers
– JMoravitz
Dec 12 '18 at 8:06
|
show 1 more comment
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You are correct to look at $30^circ$ and the trig functions. If the center of the circle were $(0,0)$ and up corresponded to a positive $y$ direction then the point you are interested in would be $(165sin(30^circ),165cos(30^circ))$. Since your center is probably not called $(0,0)$ however, you will likely need to translate (or even reflect) the result further.
– JMoravitz
Dec 12 '18 at 7:41
@JMoravitz Thanks for comment. As i didn't know math terms well can you explain in simple lang ? because sin(30) * 165 is -163.025217975. Not able to place it properly
– Prashant Tukadiya
Dec 12 '18 at 7:49
1
Assuming center is $(0,0)$ the point you want is $(165sin(30^circ),165cos(30^circ))approxeq (82.5, 143)$. As an aside, you want $165cos(30^circ)approx 143$ where $30^circ$ is a measurement of angle in degrees. You apparently forgot to set your calculator to degrees mode. With the calculator in radians mode instead you get $165cos(30~text{rad})approx 25.45$ which is not what you want.
– JMoravitz
Dec 12 '18 at 7:56
@JMoravitz Thanks Yes you are correct I was not using degree mode cal. I am able to get (82.5, 143). But I need to convert his to coordinates. any help. Now My circle centre = 165 , 165 so I need to put white view according to 165,165 ? with value I got 82 and 143
– Prashant Tukadiya
Dec 12 '18 at 8:04
Add 165 to both numbers
– JMoravitz
Dec 12 '18 at 8:06