Given the Voronoi diagram of some points on a line, determine the points
Definition:
Assume that a set of points $P={p_1,dots,p_n}$ on a line is given. The Voronoi diagram of $P$ is a set of points $V(P)={x_1,dots,x_{n-1}}$ such that $x_i$ is the midpoint of $p_i p_{i+1}$.
Question:
- Suppose you are given a set $X={x_1,dots,x_{n-1}}$. How can we determine whether or not $X$ is a one-dimensional Voronoi diagram of a set of points?
- If $X$ is indeed a one-dimensional Voronoi diagram, How can we determine $P$?
My try:
I believe that it suffices for the points of $X$ to be on the same line in order to be a one-dimensional Voronoi diagram. Also, for the second part, I have an idea. We know that:
$$x_1 = frac{p_1+p_2}{2} implies p_2=2x_1-p_1$$
$$x_2 = frac{p_2+p_3}{2} implies p_3=2x_2-(2x_1-p_1)$$
$$dots$$
$$x_{n-1} = frac{p_{n-1}+p_n}{2} implies p_n=2x_{n-1}-p_{n-1}$$
So if we determine $p_1$, we get every other point of $P$ according to these equations. But I'm stuck at determining $p_1$.
computational-geometry voronoi-diagram
add a comment |
Definition:
Assume that a set of points $P={p_1,dots,p_n}$ on a line is given. The Voronoi diagram of $P$ is a set of points $V(P)={x_1,dots,x_{n-1}}$ such that $x_i$ is the midpoint of $p_i p_{i+1}$.
Question:
- Suppose you are given a set $X={x_1,dots,x_{n-1}}$. How can we determine whether or not $X$ is a one-dimensional Voronoi diagram of a set of points?
- If $X$ is indeed a one-dimensional Voronoi diagram, How can we determine $P$?
My try:
I believe that it suffices for the points of $X$ to be on the same line in order to be a one-dimensional Voronoi diagram. Also, for the second part, I have an idea. We know that:
$$x_1 = frac{p_1+p_2}{2} implies p_2=2x_1-p_1$$
$$x_2 = frac{p_2+p_3}{2} implies p_3=2x_2-(2x_1-p_1)$$
$$dots$$
$$x_{n-1} = frac{p_{n-1}+p_n}{2} implies p_n=2x_{n-1}-p_{n-1}$$
So if we determine $p_1$, we get every other point of $P$ according to these equations. But I'm stuck at determining $p_1$.
computational-geometry voronoi-diagram
Regarding question 1, I don’t think every set of points on a line can be a Voronoi diagram. For example consider two points ‘close’ to each other, then a large gap to another two points that are ‘close’ to each other. There must exist some relationship between the sequential gaps I’m guessing..
– T. Ford
Dec 12 '18 at 8:27
For the general problem, see the paper Recognizing Dirichlet tessellations.
– lhf
Dec 12 '18 at 10:23
add a comment |
Definition:
Assume that a set of points $P={p_1,dots,p_n}$ on a line is given. The Voronoi diagram of $P$ is a set of points $V(P)={x_1,dots,x_{n-1}}$ such that $x_i$ is the midpoint of $p_i p_{i+1}$.
Question:
- Suppose you are given a set $X={x_1,dots,x_{n-1}}$. How can we determine whether or not $X$ is a one-dimensional Voronoi diagram of a set of points?
- If $X$ is indeed a one-dimensional Voronoi diagram, How can we determine $P$?
My try:
I believe that it suffices for the points of $X$ to be on the same line in order to be a one-dimensional Voronoi diagram. Also, for the second part, I have an idea. We know that:
$$x_1 = frac{p_1+p_2}{2} implies p_2=2x_1-p_1$$
$$x_2 = frac{p_2+p_3}{2} implies p_3=2x_2-(2x_1-p_1)$$
$$dots$$
$$x_{n-1} = frac{p_{n-1}+p_n}{2} implies p_n=2x_{n-1}-p_{n-1}$$
So if we determine $p_1$, we get every other point of $P$ according to these equations. But I'm stuck at determining $p_1$.
computational-geometry voronoi-diagram
Definition:
Assume that a set of points $P={p_1,dots,p_n}$ on a line is given. The Voronoi diagram of $P$ is a set of points $V(P)={x_1,dots,x_{n-1}}$ such that $x_i$ is the midpoint of $p_i p_{i+1}$.
Question:
- Suppose you are given a set $X={x_1,dots,x_{n-1}}$. How can we determine whether or not $X$ is a one-dimensional Voronoi diagram of a set of points?
- If $X$ is indeed a one-dimensional Voronoi diagram, How can we determine $P$?
My try:
I believe that it suffices for the points of $X$ to be on the same line in order to be a one-dimensional Voronoi diagram. Also, for the second part, I have an idea. We know that:
$$x_1 = frac{p_1+p_2}{2} implies p_2=2x_1-p_1$$
$$x_2 = frac{p_2+p_3}{2} implies p_3=2x_2-(2x_1-p_1)$$
$$dots$$
$$x_{n-1} = frac{p_{n-1}+p_n}{2} implies p_n=2x_{n-1}-p_{n-1}$$
So if we determine $p_1$, we get every other point of $P$ according to these equations. But I'm stuck at determining $p_1$.
computational-geometry voronoi-diagram
computational-geometry voronoi-diagram
edited Dec 12 '18 at 8:07
Arman Malekzadeh
asked Dec 12 '18 at 7:53
Arman MalekzadehArman Malekzadeh
1,7951028
1,7951028
Regarding question 1, I don’t think every set of points on a line can be a Voronoi diagram. For example consider two points ‘close’ to each other, then a large gap to another two points that are ‘close’ to each other. There must exist some relationship between the sequential gaps I’m guessing..
– T. Ford
Dec 12 '18 at 8:27
For the general problem, see the paper Recognizing Dirichlet tessellations.
– lhf
Dec 12 '18 at 10:23
add a comment |
Regarding question 1, I don’t think every set of points on a line can be a Voronoi diagram. For example consider two points ‘close’ to each other, then a large gap to another two points that are ‘close’ to each other. There must exist some relationship between the sequential gaps I’m guessing..
– T. Ford
Dec 12 '18 at 8:27
For the general problem, see the paper Recognizing Dirichlet tessellations.
– lhf
Dec 12 '18 at 10:23
Regarding question 1, I don’t think every set of points on a line can be a Voronoi diagram. For example consider two points ‘close’ to each other, then a large gap to another two points that are ‘close’ to each other. There must exist some relationship between the sequential gaps I’m guessing..
– T. Ford
Dec 12 '18 at 8:27
Regarding question 1, I don’t think every set of points on a line can be a Voronoi diagram. For example consider two points ‘close’ to each other, then a large gap to another two points that are ‘close’ to each other. There must exist some relationship between the sequential gaps I’m guessing..
– T. Ford
Dec 12 '18 at 8:27
For the general problem, see the paper Recognizing Dirichlet tessellations.
– lhf
Dec 12 '18 at 10:23
For the general problem, see the paper Recognizing Dirichlet tessellations.
– lhf
Dec 12 '18 at 10:23
add a comment |
2 Answers
2
active
oldest
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Every point $x_i$ is equidistant of two points $p_i$ and $p_{i+1}$. Let's call that distance $d_i$. We also know that $p_{i+1} - p_i = (p_{i+1} - x_{i+1}) + (x_{i+1} - p_i) = d_{i+1} + d_i$. The $d_i$ are distances so they're all positive.
For a given set $X$ with $n$ elements, you have $n-1$ linear equations and $n$ inequalities (all the distances must be positive). One way to solve it is to compute your vector $(d_1,...d_n)$ as a function of $d_1$ and check whether there's a $d_1$ for which all the $d_i$ are positive.
All the $d_i$ are linear in $d_1$, so your inequalities will translate to linear inequalities on $d_1$ of the form $(-1)^{b_i}d_1 le c_i$, which may or may not have a solution depending on the specific values.
Edit: Computing the actual inequalities.
We're trying to express all the $d_i$ as a function of $d_1$.
$$d_2 + d_1 = (p_2 - p_1) Leftrightarrow d_2 = (p_2 - p_1) - d_1$$
$$d_3 + d_2 = (p_3 - p_2) Leftrightarrow d_3 = (p_3 - p_2) - d_2 = (p_3 - p_2) - (p_2 - p_1) + d_1$$
$$...$$
$$d_i = sum_{j = 0}^{i-1} (-1)^j(p_{i-j} - p_{i-j-1}) + (-1)^{i-1} d_1$$
So: $$d_i ge 0 Leftrightarrow (-1)^{i-1} d_1 ge -sum_{j = 0}^{i-1} (-1)^j(p_{i-j} - p_{i-j-1}) $$
Your set is a Voronoi diagram if and only if there's a $d_1$ that satisfies all these inequalities.
Can you provide an example?
– Arman Malekzadeh
Dec 12 '18 at 9:30
I'll compute the actual inequalities as soon as I have some time.
– RcnSc
Dec 12 '18 at 9:42
@ArmanMalekzadeh Let me know if something is unclear
– RcnSc
Dec 12 '18 at 10:14
Thank you... I was just wondering if the solution was unique. It seems it's not :)
– Arman Malekzadeh
Dec 12 '18 at 10:28
add a comment |
For (2), knowing $V(P)$ is not sufficient to determine $P$. For example, if $V(P) = {5,15}$ then $P$ could be ${0,10,20}$ or ${1,9,21}$ or ${2,8,22}$ etc.
Difficulty is that $V(P)$ gives you $n-1$ linear equations in $n$ unknowns, so system is underdetermined. Additional constraint that $p_{k+1} ge p_k$ is not sufficient to give a unique solution.
add a comment |
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2 Answers
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2 Answers
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Every point $x_i$ is equidistant of two points $p_i$ and $p_{i+1}$. Let's call that distance $d_i$. We also know that $p_{i+1} - p_i = (p_{i+1} - x_{i+1}) + (x_{i+1} - p_i) = d_{i+1} + d_i$. The $d_i$ are distances so they're all positive.
For a given set $X$ with $n$ elements, you have $n-1$ linear equations and $n$ inequalities (all the distances must be positive). One way to solve it is to compute your vector $(d_1,...d_n)$ as a function of $d_1$ and check whether there's a $d_1$ for which all the $d_i$ are positive.
All the $d_i$ are linear in $d_1$, so your inequalities will translate to linear inequalities on $d_1$ of the form $(-1)^{b_i}d_1 le c_i$, which may or may not have a solution depending on the specific values.
Edit: Computing the actual inequalities.
We're trying to express all the $d_i$ as a function of $d_1$.
$$d_2 + d_1 = (p_2 - p_1) Leftrightarrow d_2 = (p_2 - p_1) - d_1$$
$$d_3 + d_2 = (p_3 - p_2) Leftrightarrow d_3 = (p_3 - p_2) - d_2 = (p_3 - p_2) - (p_2 - p_1) + d_1$$
$$...$$
$$d_i = sum_{j = 0}^{i-1} (-1)^j(p_{i-j} - p_{i-j-1}) + (-1)^{i-1} d_1$$
So: $$d_i ge 0 Leftrightarrow (-1)^{i-1} d_1 ge -sum_{j = 0}^{i-1} (-1)^j(p_{i-j} - p_{i-j-1}) $$
Your set is a Voronoi diagram if and only if there's a $d_1$ that satisfies all these inequalities.
Can you provide an example?
– Arman Malekzadeh
Dec 12 '18 at 9:30
I'll compute the actual inequalities as soon as I have some time.
– RcnSc
Dec 12 '18 at 9:42
@ArmanMalekzadeh Let me know if something is unclear
– RcnSc
Dec 12 '18 at 10:14
Thank you... I was just wondering if the solution was unique. It seems it's not :)
– Arman Malekzadeh
Dec 12 '18 at 10:28
add a comment |
Every point $x_i$ is equidistant of two points $p_i$ and $p_{i+1}$. Let's call that distance $d_i$. We also know that $p_{i+1} - p_i = (p_{i+1} - x_{i+1}) + (x_{i+1} - p_i) = d_{i+1} + d_i$. The $d_i$ are distances so they're all positive.
For a given set $X$ with $n$ elements, you have $n-1$ linear equations and $n$ inequalities (all the distances must be positive). One way to solve it is to compute your vector $(d_1,...d_n)$ as a function of $d_1$ and check whether there's a $d_1$ for which all the $d_i$ are positive.
All the $d_i$ are linear in $d_1$, so your inequalities will translate to linear inequalities on $d_1$ of the form $(-1)^{b_i}d_1 le c_i$, which may or may not have a solution depending on the specific values.
Edit: Computing the actual inequalities.
We're trying to express all the $d_i$ as a function of $d_1$.
$$d_2 + d_1 = (p_2 - p_1) Leftrightarrow d_2 = (p_2 - p_1) - d_1$$
$$d_3 + d_2 = (p_3 - p_2) Leftrightarrow d_3 = (p_3 - p_2) - d_2 = (p_3 - p_2) - (p_2 - p_1) + d_1$$
$$...$$
$$d_i = sum_{j = 0}^{i-1} (-1)^j(p_{i-j} - p_{i-j-1}) + (-1)^{i-1} d_1$$
So: $$d_i ge 0 Leftrightarrow (-1)^{i-1} d_1 ge -sum_{j = 0}^{i-1} (-1)^j(p_{i-j} - p_{i-j-1}) $$
Your set is a Voronoi diagram if and only if there's a $d_1$ that satisfies all these inequalities.
Can you provide an example?
– Arman Malekzadeh
Dec 12 '18 at 9:30
I'll compute the actual inequalities as soon as I have some time.
– RcnSc
Dec 12 '18 at 9:42
@ArmanMalekzadeh Let me know if something is unclear
– RcnSc
Dec 12 '18 at 10:14
Thank you... I was just wondering if the solution was unique. It seems it's not :)
– Arman Malekzadeh
Dec 12 '18 at 10:28
add a comment |
Every point $x_i$ is equidistant of two points $p_i$ and $p_{i+1}$. Let's call that distance $d_i$. We also know that $p_{i+1} - p_i = (p_{i+1} - x_{i+1}) + (x_{i+1} - p_i) = d_{i+1} + d_i$. The $d_i$ are distances so they're all positive.
For a given set $X$ with $n$ elements, you have $n-1$ linear equations and $n$ inequalities (all the distances must be positive). One way to solve it is to compute your vector $(d_1,...d_n)$ as a function of $d_1$ and check whether there's a $d_1$ for which all the $d_i$ are positive.
All the $d_i$ are linear in $d_1$, so your inequalities will translate to linear inequalities on $d_1$ of the form $(-1)^{b_i}d_1 le c_i$, which may or may not have a solution depending on the specific values.
Edit: Computing the actual inequalities.
We're trying to express all the $d_i$ as a function of $d_1$.
$$d_2 + d_1 = (p_2 - p_1) Leftrightarrow d_2 = (p_2 - p_1) - d_1$$
$$d_3 + d_2 = (p_3 - p_2) Leftrightarrow d_3 = (p_3 - p_2) - d_2 = (p_3 - p_2) - (p_2 - p_1) + d_1$$
$$...$$
$$d_i = sum_{j = 0}^{i-1} (-1)^j(p_{i-j} - p_{i-j-1}) + (-1)^{i-1} d_1$$
So: $$d_i ge 0 Leftrightarrow (-1)^{i-1} d_1 ge -sum_{j = 0}^{i-1} (-1)^j(p_{i-j} - p_{i-j-1}) $$
Your set is a Voronoi diagram if and only if there's a $d_1$ that satisfies all these inequalities.
Every point $x_i$ is equidistant of two points $p_i$ and $p_{i+1}$. Let's call that distance $d_i$. We also know that $p_{i+1} - p_i = (p_{i+1} - x_{i+1}) + (x_{i+1} - p_i) = d_{i+1} + d_i$. The $d_i$ are distances so they're all positive.
For a given set $X$ with $n$ elements, you have $n-1$ linear equations and $n$ inequalities (all the distances must be positive). One way to solve it is to compute your vector $(d_1,...d_n)$ as a function of $d_1$ and check whether there's a $d_1$ for which all the $d_i$ are positive.
All the $d_i$ are linear in $d_1$, so your inequalities will translate to linear inequalities on $d_1$ of the form $(-1)^{b_i}d_1 le c_i$, which may or may not have a solution depending on the specific values.
Edit: Computing the actual inequalities.
We're trying to express all the $d_i$ as a function of $d_1$.
$$d_2 + d_1 = (p_2 - p_1) Leftrightarrow d_2 = (p_2 - p_1) - d_1$$
$$d_3 + d_2 = (p_3 - p_2) Leftrightarrow d_3 = (p_3 - p_2) - d_2 = (p_3 - p_2) - (p_2 - p_1) + d_1$$
$$...$$
$$d_i = sum_{j = 0}^{i-1} (-1)^j(p_{i-j} - p_{i-j-1}) + (-1)^{i-1} d_1$$
So: $$d_i ge 0 Leftrightarrow (-1)^{i-1} d_1 ge -sum_{j = 0}^{i-1} (-1)^j(p_{i-j} - p_{i-j-1}) $$
Your set is a Voronoi diagram if and only if there's a $d_1$ that satisfies all these inequalities.
edited Dec 12 '18 at 10:19
answered Dec 12 '18 at 9:19
RcnScRcnSc
1014
1014
Can you provide an example?
– Arman Malekzadeh
Dec 12 '18 at 9:30
I'll compute the actual inequalities as soon as I have some time.
– RcnSc
Dec 12 '18 at 9:42
@ArmanMalekzadeh Let me know if something is unclear
– RcnSc
Dec 12 '18 at 10:14
Thank you... I was just wondering if the solution was unique. It seems it's not :)
– Arman Malekzadeh
Dec 12 '18 at 10:28
add a comment |
Can you provide an example?
– Arman Malekzadeh
Dec 12 '18 at 9:30
I'll compute the actual inequalities as soon as I have some time.
– RcnSc
Dec 12 '18 at 9:42
@ArmanMalekzadeh Let me know if something is unclear
– RcnSc
Dec 12 '18 at 10:14
Thank you... I was just wondering if the solution was unique. It seems it's not :)
– Arman Malekzadeh
Dec 12 '18 at 10:28
Can you provide an example?
– Arman Malekzadeh
Dec 12 '18 at 9:30
Can you provide an example?
– Arman Malekzadeh
Dec 12 '18 at 9:30
I'll compute the actual inequalities as soon as I have some time.
– RcnSc
Dec 12 '18 at 9:42
I'll compute the actual inequalities as soon as I have some time.
– RcnSc
Dec 12 '18 at 9:42
@ArmanMalekzadeh Let me know if something is unclear
– RcnSc
Dec 12 '18 at 10:14
@ArmanMalekzadeh Let me know if something is unclear
– RcnSc
Dec 12 '18 at 10:14
Thank you... I was just wondering if the solution was unique. It seems it's not :)
– Arman Malekzadeh
Dec 12 '18 at 10:28
Thank you... I was just wondering if the solution was unique. It seems it's not :)
– Arman Malekzadeh
Dec 12 '18 at 10:28
add a comment |
For (2), knowing $V(P)$ is not sufficient to determine $P$. For example, if $V(P) = {5,15}$ then $P$ could be ${0,10,20}$ or ${1,9,21}$ or ${2,8,22}$ etc.
Difficulty is that $V(P)$ gives you $n-1$ linear equations in $n$ unknowns, so system is underdetermined. Additional constraint that $p_{k+1} ge p_k$ is not sufficient to give a unique solution.
add a comment |
For (2), knowing $V(P)$ is not sufficient to determine $P$. For example, if $V(P) = {5,15}$ then $P$ could be ${0,10,20}$ or ${1,9,21}$ or ${2,8,22}$ etc.
Difficulty is that $V(P)$ gives you $n-1$ linear equations in $n$ unknowns, so system is underdetermined. Additional constraint that $p_{k+1} ge p_k$ is not sufficient to give a unique solution.
add a comment |
For (2), knowing $V(P)$ is not sufficient to determine $P$. For example, if $V(P) = {5,15}$ then $P$ could be ${0,10,20}$ or ${1,9,21}$ or ${2,8,22}$ etc.
Difficulty is that $V(P)$ gives you $n-1$ linear equations in $n$ unknowns, so system is underdetermined. Additional constraint that $p_{k+1} ge p_k$ is not sufficient to give a unique solution.
For (2), knowing $V(P)$ is not sufficient to determine $P$. For example, if $V(P) = {5,15}$ then $P$ could be ${0,10,20}$ or ${1,9,21}$ or ${2,8,22}$ etc.
Difficulty is that $V(P)$ gives you $n-1$ linear equations in $n$ unknowns, so system is underdetermined. Additional constraint that $p_{k+1} ge p_k$ is not sufficient to give a unique solution.
edited Dec 12 '18 at 11:16
answered Dec 12 '18 at 10:23
gandalf61gandalf61
7,921624
7,921624
add a comment |
add a comment |
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Regarding question 1, I don’t think every set of points on a line can be a Voronoi diagram. For example consider two points ‘close’ to each other, then a large gap to another two points that are ‘close’ to each other. There must exist some relationship between the sequential gaps I’m guessing..
– T. Ford
Dec 12 '18 at 8:27
For the general problem, see the paper Recognizing Dirichlet tessellations.
– lhf
Dec 12 '18 at 10:23