Find BPM percentage difference using math - something not adding up right?
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I asked this question about 2 and a half years ago on how to find the percentage difference between 2 bpms ( I apologize if this seems extremely simple... my math / algebra skills are not that good, I fell asleep in all of my algebra classes in highschool and was put in the dumb math class):
How to find percentage change between original and final BPM
At the time all my original files were 100bpm... but now I want to be able to have different source bpms... so I changed the source bpm to 120 and desired bpm to 85 and I get -.35 but when I subtract 35% from 120bpm I get 42 not 85... what am I doing wrong?
If your initial number is a and your final number is b, then the percentage change x from a to b is given by
x=b−a100
For example, if a=100 and b=134, then
x=134−100100=0.34=34%
If a=100 and b=78, then
x=78−100100=−0.22=−22%
algebra-precalculus
asked Jan 6 at 5:11
JeffJeff
1085
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add a comment |
$begingroup$
I asked this question about 2 and a half years ago on how to find the percentage difference between 2 bpms ( I apologize if this seems extremely simple... my math / algebra skills are not that good, I fell asleep in all of my algebra classes in highschool and was put in the dumb math class):
How to find percentage change between original and final BPM
At the time all my original files were 100bpm... but now I want to be able to have different source bpms... so I changed the source bpm to 120 and desired bpm to 85 and I get -.35 but when I subtract 35% from 120bpm I get 42 not 85... what am I doing wrong?
If your initial number is a and your final number is b, then the percentage change x from a to b is given by
x=b−a100
For example, if a=100 and b=134, then
x=134−100100=0.34=34%
If a=100 and b=78, then
x=78−100100=−0.22=−22%
algebra-precalculus
asked Jan 6 at 5:11
JeffJeff
1085
$endgroup$
add a comment |
$begingroup$
I asked this question about 2 and a half years ago on how to find the percentage difference between 2 bpms ( I apologize if this seems extremely simple... my math / algebra skills are not that good, I fell asleep in all of my algebra classes in highschool and was put in the dumb math class):
How to find percentage change between original and final BPM
At the time all my original files were 100bpm... but now I want to be able to have different source bpms... so I changed the source bpm to 120 and desired bpm to 85 and I get -.35 but when I subtract 35% from 120bpm I get 42 not 85... what am I doing wrong?
If your initial number is a and your final number is b, then the percentage change x from a to b is given by
x=b−a100
For example, if a=100 and b=134, then
x=134−100100=0.34=34%
If a=100 and b=78, then
x=78−100100=−0.22=−22%
algebra-precalculus
asked Jan 6 at 5:11
JeffJeff
1085
$endgroup$
I asked this question about 2 and a half years ago on how to find the percentage difference between 2 bpms ( I apologize if this seems extremely simple... my math / algebra skills are not that good, I fell asleep in all of my algebra classes in highschool and was put in the dumb math class):
How to find percentage change between original and final BPM
At the time all my original files were 100bpm... but now I want to be able to have different source bpms... so I changed the source bpm to 120 and desired bpm to 85 and I get -.35 but when I subtract 35% from 120bpm I get 42 not 85... what am I doing wrong?
If your initial number is a and your final number is b, then the percentage change x from a to b is given by
x=b−a100
For example, if a=100 and b=134, then
x=134−100100=0.34=34%
If a=100 and b=78, then
x=78−100100=−0.22=−22%
algebra-precalculus
algebra-precalculus
asked Jan 6 at 5:11
JeffJeff
1085
asked Jan 6 at 5:11
JeffJeff
1085
asked Jan 6 at 5:11
JeffJeff
1085
asked Jan 6 at 5:11
JeffJeff
1085
asked Jan 6 at 5:11
JeffJeff
1085
1085
add a comment |
add a comment |
1 Answer
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$begingroup$
You need to do $$frac{120-85}{120}approx0.29$$
If you want in percent, multiply the answer by $100$.
Also the number $42$ is $35%$ of $120$, not $65%$.
answered Jan 6 at 5:17
AndreiAndrei
13.2k21230
$endgroup$
1
$begingroup$
Thanks Andrei... I think I was dividing by 100 not 120 and that is where I got confused... because I was thinking I was dividing by 100% but it should be the original number now I see.. Thank you!
$endgroup$
– Jeff
Jan 6 at 5:19
add a comment |
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1 Answer
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1 Answer
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$begingroup$
You need to do $$frac{120-85}{120}approx0.29$$
If you want in percent, multiply the answer by $100$.
Also the number $42$ is $35%$ of $120$, not $65%$.
answered Jan 6 at 5:17
AndreiAndrei
13.2k21230
$endgroup$
1
$begingroup$
Thanks Andrei... I think I was dividing by 100 not 120 and that is where I got confused... because I was thinking I was dividing by 100% but it should be the original number now I see.. Thank you!
$endgroup$
– Jeff
Jan 6 at 5:19
add a comment |
$begingroup$
You need to do $$frac{120-85}{120}approx0.29$$
If you want in percent, multiply the answer by $100$.
Also the number $42$ is $35%$ of $120$, not $65%$.
answered Jan 6 at 5:17
AndreiAndrei
13.2k21230
$endgroup$
1
$begingroup$
Thanks Andrei... I think I was dividing by 100 not 120 and that is where I got confused... because I was thinking I was dividing by 100% but it should be the original number now I see.. Thank you!
$endgroup$
– Jeff
Jan 6 at 5:19
add a comment |
$begingroup$
You need to do $$frac{120-85}{120}approx0.29$$
If you want in percent, multiply the answer by $100$.
Also the number $42$ is $35%$ of $120$, not $65%$.
answered Jan 6 at 5:17
AndreiAndrei
13.2k21230
$endgroup$
You need to do $$frac{120-85}{120}approx0.29$$
If you want in percent, multiply the answer by $100$.
Also the number $42$ is $35%$ of $120$, not $65%$.
answered Jan 6 at 5:17
AndreiAndrei
13.2k21230
answered Jan 6 at 5:17
AndreiAndrei
13.2k21230
answered Jan 6 at 5:17
AndreiAndrei
13.2k21230
answered Jan 6 at 5:17
AndreiAndrei
13.2k21230
13.2k21230
1
$begingroup$
Thanks Andrei... I think I was dividing by 100 not 120 and that is where I got confused... because I was thinking I was dividing by 100% but it should be the original number now I see.. Thank you!
$endgroup$
– Jeff
Jan 6 at 5:19
add a comment |
1
$begingroup$
Thanks Andrei... I think I was dividing by 100 not 120 and that is where I got confused... because I was thinking I was dividing by 100% but it should be the original number now I see.. Thank you!
$endgroup$
– Jeff
Jan 6 at 5:19
1
1
$begingroup$
Thanks Andrei... I think I was dividing by 100 not 120 and that is where I got confused... because I was thinking I was dividing by 100% but it should be the original number now I see.. Thank you!
$endgroup$
– Jeff
Jan 6 at 5:19
$begingroup$
Thanks Andrei... I think I was dividing by 100 not 120 and that is where I got confused... because I was thinking I was dividing by 100% but it should be the original number now I see.. Thank you!
$endgroup$
– Jeff
Jan 6 at 5:19
add a comment |
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