Recursive sequences: $S_0 = 1, S_n = (S_{n−1})^{2} + (S_{n−2})^{2} + · · · + (S_0)^{2}$ for all...












0












$begingroup$


The question is-

Write down the first five values of each of the following recursive sequences.
$S_0 = 1, S_n = (S_{n−1})^{2} + (S_{n−2})^{2} + · · · + (S_0)^{2}$ for all integers $n ⩾ 1$



I'm not sure if this is correct but this is what I did:



$S_1 = (1)^{2} = 1$



$S_2 = (1)^2 + (1)^2 = 2$



$S_3 = (2)^2 + (1)^2 + (1)^2 = 6$



$S_4 = (6)^2 + (2)^2 + (1)^2 + (1)^2 = 42$



$S_5 = (42)^2 + (6)^2 + (2)^2 + (1)^2 + (1)^2 = 1806$










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$endgroup$








  • 4




    $begingroup$
    Looks fine. What is the question, though? By the way, you can simplify to $S_n=S_{n-1}^2+S_{n-1}$.
    $endgroup$
    – SmileyCraft
    Jan 6 at 5:44










  • $begingroup$
    Thanks. This was the question: Write down the first five values of each of the following recursive sequences. S0 = 1, Sn = (Sn−1)^2 + (Sn−2)^2 + · · · + (S0)^2 for all integers n ⩾ 1
    $endgroup$
    – llamaro25
    Jan 6 at 5:46






  • 1




    $begingroup$
    @meromero25: Then you answered your own question? Any why is this interesting?
    $endgroup$
    – David G. Stork
    Jan 6 at 5:50












  • $begingroup$
    @DavidG.Stork I wasn't sure if the answer is correct
    $endgroup$
    – llamaro25
    Jan 6 at 5:52










  • $begingroup$
    Just for your curiosity : have a look at oeis.org/… What it seems is that $log(log(S_n))$ is a linear function of $n$.
    $endgroup$
    – Claude Leibovici
    Jan 6 at 6:14


















0












$begingroup$


The question is-

Write down the first five values of each of the following recursive sequences.
$S_0 = 1, S_n = (S_{n−1})^{2} + (S_{n−2})^{2} + · · · + (S_0)^{2}$ for all integers $n ⩾ 1$



I'm not sure if this is correct but this is what I did:



$S_1 = (1)^{2} = 1$



$S_2 = (1)^2 + (1)^2 = 2$



$S_3 = (2)^2 + (1)^2 + (1)^2 = 6$



$S_4 = (6)^2 + (2)^2 + (1)^2 + (1)^2 = 42$



$S_5 = (42)^2 + (6)^2 + (2)^2 + (1)^2 + (1)^2 = 1806$










share|cite|improve this question











$endgroup$








  • 4




    $begingroup$
    Looks fine. What is the question, though? By the way, you can simplify to $S_n=S_{n-1}^2+S_{n-1}$.
    $endgroup$
    – SmileyCraft
    Jan 6 at 5:44










  • $begingroup$
    Thanks. This was the question: Write down the first five values of each of the following recursive sequences. S0 = 1, Sn = (Sn−1)^2 + (Sn−2)^2 + · · · + (S0)^2 for all integers n ⩾ 1
    $endgroup$
    – llamaro25
    Jan 6 at 5:46






  • 1




    $begingroup$
    @meromero25: Then you answered your own question? Any why is this interesting?
    $endgroup$
    – David G. Stork
    Jan 6 at 5:50












  • $begingroup$
    @DavidG.Stork I wasn't sure if the answer is correct
    $endgroup$
    – llamaro25
    Jan 6 at 5:52










  • $begingroup$
    Just for your curiosity : have a look at oeis.org/… What it seems is that $log(log(S_n))$ is a linear function of $n$.
    $endgroup$
    – Claude Leibovici
    Jan 6 at 6:14
















0












0








0





$begingroup$


The question is-

Write down the first five values of each of the following recursive sequences.
$S_0 = 1, S_n = (S_{n−1})^{2} + (S_{n−2})^{2} + · · · + (S_0)^{2}$ for all integers $n ⩾ 1$



I'm not sure if this is correct but this is what I did:



$S_1 = (1)^{2} = 1$



$S_2 = (1)^2 + (1)^2 = 2$



$S_3 = (2)^2 + (1)^2 + (1)^2 = 6$



$S_4 = (6)^2 + (2)^2 + (1)^2 + (1)^2 = 42$



$S_5 = (42)^2 + (6)^2 + (2)^2 + (1)^2 + (1)^2 = 1806$










share|cite|improve this question











$endgroup$




The question is-

Write down the first five values of each of the following recursive sequences.
$S_0 = 1, S_n = (S_{n−1})^{2} + (S_{n−2})^{2} + · · · + (S_0)^{2}$ for all integers $n ⩾ 1$



I'm not sure if this is correct but this is what I did:



$S_1 = (1)^{2} = 1$



$S_2 = (1)^2 + (1)^2 = 2$



$S_3 = (2)^2 + (1)^2 + (1)^2 = 6$



$S_4 = (6)^2 + (2)^2 + (1)^2 + (1)^2 = 42$



$S_5 = (42)^2 + (6)^2 + (2)^2 + (1)^2 + (1)^2 = 1806$







proof-verification recursion






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share|cite|improve this question













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edited Jan 6 at 6:29









Shubham Johri

5,372718




5,372718










asked Jan 6 at 5:42









llamaro25llamaro25

528




528








  • 4




    $begingroup$
    Looks fine. What is the question, though? By the way, you can simplify to $S_n=S_{n-1}^2+S_{n-1}$.
    $endgroup$
    – SmileyCraft
    Jan 6 at 5:44










  • $begingroup$
    Thanks. This was the question: Write down the first five values of each of the following recursive sequences. S0 = 1, Sn = (Sn−1)^2 + (Sn−2)^2 + · · · + (S0)^2 for all integers n ⩾ 1
    $endgroup$
    – llamaro25
    Jan 6 at 5:46






  • 1




    $begingroup$
    @meromero25: Then you answered your own question? Any why is this interesting?
    $endgroup$
    – David G. Stork
    Jan 6 at 5:50












  • $begingroup$
    @DavidG.Stork I wasn't sure if the answer is correct
    $endgroup$
    – llamaro25
    Jan 6 at 5:52










  • $begingroup$
    Just for your curiosity : have a look at oeis.org/… What it seems is that $log(log(S_n))$ is a linear function of $n$.
    $endgroup$
    – Claude Leibovici
    Jan 6 at 6:14
















  • 4




    $begingroup$
    Looks fine. What is the question, though? By the way, you can simplify to $S_n=S_{n-1}^2+S_{n-1}$.
    $endgroup$
    – SmileyCraft
    Jan 6 at 5:44










  • $begingroup$
    Thanks. This was the question: Write down the first five values of each of the following recursive sequences. S0 = 1, Sn = (Sn−1)^2 + (Sn−2)^2 + · · · + (S0)^2 for all integers n ⩾ 1
    $endgroup$
    – llamaro25
    Jan 6 at 5:46






  • 1




    $begingroup$
    @meromero25: Then you answered your own question? Any why is this interesting?
    $endgroup$
    – David G. Stork
    Jan 6 at 5:50












  • $begingroup$
    @DavidG.Stork I wasn't sure if the answer is correct
    $endgroup$
    – llamaro25
    Jan 6 at 5:52










  • $begingroup$
    Just for your curiosity : have a look at oeis.org/… What it seems is that $log(log(S_n))$ is a linear function of $n$.
    $endgroup$
    – Claude Leibovici
    Jan 6 at 6:14










4




4




$begingroup$
Looks fine. What is the question, though? By the way, you can simplify to $S_n=S_{n-1}^2+S_{n-1}$.
$endgroup$
– SmileyCraft
Jan 6 at 5:44




$begingroup$
Looks fine. What is the question, though? By the way, you can simplify to $S_n=S_{n-1}^2+S_{n-1}$.
$endgroup$
– SmileyCraft
Jan 6 at 5:44












$begingroup$
Thanks. This was the question: Write down the first five values of each of the following recursive sequences. S0 = 1, Sn = (Sn−1)^2 + (Sn−2)^2 + · · · + (S0)^2 for all integers n ⩾ 1
$endgroup$
– llamaro25
Jan 6 at 5:46




$begingroup$
Thanks. This was the question: Write down the first five values of each of the following recursive sequences. S0 = 1, Sn = (Sn−1)^2 + (Sn−2)^2 + · · · + (S0)^2 for all integers n ⩾ 1
$endgroup$
– llamaro25
Jan 6 at 5:46




1




1




$begingroup$
@meromero25: Then you answered your own question? Any why is this interesting?
$endgroup$
– David G. Stork
Jan 6 at 5:50






$begingroup$
@meromero25: Then you answered your own question? Any why is this interesting?
$endgroup$
– David G. Stork
Jan 6 at 5:50














$begingroup$
@DavidG.Stork I wasn't sure if the answer is correct
$endgroup$
– llamaro25
Jan 6 at 5:52




$begingroup$
@DavidG.Stork I wasn't sure if the answer is correct
$endgroup$
– llamaro25
Jan 6 at 5:52












$begingroup$
Just for your curiosity : have a look at oeis.org/… What it seems is that $log(log(S_n))$ is a linear function of $n$.
$endgroup$
– Claude Leibovici
Jan 6 at 6:14






$begingroup$
Just for your curiosity : have a look at oeis.org/… What it seems is that $log(log(S_n))$ is a linear function of $n$.
$endgroup$
– Claude Leibovici
Jan 6 at 6:14












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