Changing order of integration for integral with general bounds
$begingroup$
So I’m asked to change the order of integration in the double integral below. I can’t get to the answer however, I did sketch the function and y seems to reach from -1 tot 8 which is the first part of the new integral. However, I don’t know any further steps...
$X$ is between $x=y+6$ and $x=(y^2)+2y$
$Y$ is between $y=-3$ and $y=2$
$$
int_{y=-3}^{y=2}int_{x=y+6}^{x=(y^2)+2y} y , dxdy
$$
The function is $f(x,y)=y$ and I’m given the integral $dxdy$ which has a value of $-125/12$ for the given interval. How do I change the boundaries?
integration
edited Jan 15 at 18:23
Namaste
1
asked Jan 15 at 17:46
M.F. MeindertsmaM.F. Meindertsma
13
$endgroup$
add a comment |
$begingroup$
So I’m asked to change the order of integration in the double integral below. I can’t get to the answer however, I did sketch the function and y seems to reach from -1 tot 8 which is the first part of the new integral. However, I don’t know any further steps...
$X$ is between $x=y+6$ and $x=(y^2)+2y$
$Y$ is between $y=-3$ and $y=2$
$$
int_{y=-3}^{y=2}int_{x=y+6}^{x=(y^2)+2y} y , dxdy
$$
The function is $f(x,y)=y$ and I’m given the integral $dxdy$ which has a value of $-125/12$ for the given interval. How do I change the boundaries?
integration
edited Jan 15 at 18:23
Namaste
1
asked Jan 15 at 17:46
M.F. MeindertsmaM.F. Meindertsma
13
$endgroup$
add a comment |
$begingroup$
So I’m asked to change the order of integration in the double integral below. I can’t get to the answer however, I did sketch the function and y seems to reach from -1 tot 8 which is the first part of the new integral. However, I don’t know any further steps...
$X$ is between $x=y+6$ and $x=(y^2)+2y$
$Y$ is between $y=-3$ and $y=2$
$$
int_{y=-3}^{y=2}int_{x=y+6}^{x=(y^2)+2y} y , dxdy
$$
The function is $f(x,y)=y$ and I’m given the integral $dxdy$ which has a value of $-125/12$ for the given interval. How do I change the boundaries?
integration
edited Jan 15 at 18:23
Namaste
1
asked Jan 15 at 17:46
M.F. MeindertsmaM.F. Meindertsma
13
$endgroup$
So I’m asked to change the order of integration in the double integral below. I can’t get to the answer however, I did sketch the function and y seems to reach from -1 tot 8 which is the first part of the new integral. However, I don’t know any further steps...
$X$ is between $x=y+6$ and $x=(y^2)+2y$
$Y$ is between $y=-3$ and $y=2$
$$
int_{y=-3}^{y=2}int_{x=y+6}^{x=(y^2)+2y} y , dxdy
$$
The function is $f(x,y)=y$ and I’m given the integral $dxdy$ which has a value of $-125/12$ for the given interval. How do I change the boundaries?
integration
integration
edited Jan 15 at 18:23
Namaste
1
asked Jan 15 at 17:46
M.F. MeindertsmaM.F. Meindertsma
13
edited Jan 15 at 18:23
Namaste
1
asked Jan 15 at 17:46
M.F. MeindertsmaM.F. Meindertsma
13
edited Jan 15 at 18:23
Namaste
1
edited Jan 15 at 18:23
Namaste
1
edited Jan 15 at 18:23
Namaste
1
1
asked Jan 15 at 17:46
M.F. MeindertsmaM.F. Meindertsma
13
asked Jan 15 at 17:46
M.F. MeindertsmaM.F. Meindertsma
13
asked Jan 15 at 17:46
M.F. MeindertsmaM.F. Meindertsma
13
13
add a comment |
add a comment |
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