Probability under Uncertainity












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Consider $B$, $W in E(Omega)$ be two events in an event space $E(Omega)$ where the occurrence of event $W$ uncertain. Let this uncertainty of $W$ be denoted as $overline{W}$.



Possible outcomes of both the events are: $B = {1}$ and $W = {0, 1}$



What could be the probability of event $B$ occurring given that event $W$ is uncertain?.



In short, $P(B = 1|overline{W})$ = ?










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  • $begingroup$
    What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
    $endgroup$
    – LoveTooNap29
    Jan 12 at 17:42










  • $begingroup$
    @LoveTooNap29 You are right! I am scratching my head around this for many hours!
    $endgroup$
    – Harshil
    Jan 12 at 17:50










  • $begingroup$
    Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
    $endgroup$
    – zoli
    Jan 12 at 17:53










  • $begingroup$
    @zoli Description I posted above is identical to the original text! I am also confused with that!
    $endgroup$
    – Harshil
    Jan 13 at 16:00


















0












$begingroup$


Consider $B$, $W in E(Omega)$ be two events in an event space $E(Omega)$ where the occurrence of event $W$ uncertain. Let this uncertainty of $W$ be denoted as $overline{W}$.



Possible outcomes of both the events are: $B = {1}$ and $W = {0, 1}$



What could be the probability of event $B$ occurring given that event $W$ is uncertain?.



In short, $P(B = 1|overline{W})$ = ?










share|cite|improve this question









$endgroup$












  • $begingroup$
    What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
    $endgroup$
    – LoveTooNap29
    Jan 12 at 17:42










  • $begingroup$
    @LoveTooNap29 You are right! I am scratching my head around this for many hours!
    $endgroup$
    – Harshil
    Jan 12 at 17:50










  • $begingroup$
    Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
    $endgroup$
    – zoli
    Jan 12 at 17:53










  • $begingroup$
    @zoli Description I posted above is identical to the original text! I am also confused with that!
    $endgroup$
    – Harshil
    Jan 13 at 16:00
















0












0








0





$begingroup$


Consider $B$, $W in E(Omega)$ be two events in an event space $E(Omega)$ where the occurrence of event $W$ uncertain. Let this uncertainty of $W$ be denoted as $overline{W}$.



Possible outcomes of both the events are: $B = {1}$ and $W = {0, 1}$



What could be the probability of event $B$ occurring given that event $W$ is uncertain?.



In short, $P(B = 1|overline{W})$ = ?










share|cite|improve this question









$endgroup$




Consider $B$, $W in E(Omega)$ be two events in an event space $E(Omega)$ where the occurrence of event $W$ uncertain. Let this uncertainty of $W$ be denoted as $overline{W}$.



Possible outcomes of both the events are: $B = {1}$ and $W = {0, 1}$



What could be the probability of event $B$ occurring given that event $W$ is uncertain?.



In short, $P(B = 1|overline{W})$ = ?







probability






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 12 at 17:28









HarshilHarshil

1034




1034












  • $begingroup$
    What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
    $endgroup$
    – LoveTooNap29
    Jan 12 at 17:42










  • $begingroup$
    @LoveTooNap29 You are right! I am scratching my head around this for many hours!
    $endgroup$
    – Harshil
    Jan 12 at 17:50










  • $begingroup$
    Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
    $endgroup$
    – zoli
    Jan 12 at 17:53










  • $begingroup$
    @zoli Description I posted above is identical to the original text! I am also confused with that!
    $endgroup$
    – Harshil
    Jan 13 at 16:00




















  • $begingroup$
    What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
    $endgroup$
    – LoveTooNap29
    Jan 12 at 17:42










  • $begingroup$
    @LoveTooNap29 You are right! I am scratching my head around this for many hours!
    $endgroup$
    – Harshil
    Jan 12 at 17:50










  • $begingroup$
    Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
    $endgroup$
    – zoli
    Jan 12 at 17:53










  • $begingroup$
    @zoli Description I posted above is identical to the original text! I am also confused with that!
    $endgroup$
    – Harshil
    Jan 13 at 16:00


















$begingroup$
What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
$endgroup$
– LoveTooNap29
Jan 12 at 17:42




$begingroup$
What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
$endgroup$
– LoveTooNap29
Jan 12 at 17:42












$begingroup$
@LoveTooNap29 You are right! I am scratching my head around this for many hours!
$endgroup$
– Harshil
Jan 12 at 17:50




$begingroup$
@LoveTooNap29 You are right! I am scratching my head around this for many hours!
$endgroup$
– Harshil
Jan 12 at 17:50












$begingroup$
Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
$endgroup$
– zoli
Jan 12 at 17:53




$begingroup$
Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
$endgroup$
– zoli
Jan 12 at 17:53












$begingroup$
@zoli Description I posted above is identical to the original text! I am also confused with that!
$endgroup$
– Harshil
Jan 13 at 16:00






$begingroup$
@zoli Description I posted above is identical to the original text! I am also confused with that!
$endgroup$
– Harshil
Jan 13 at 16:00












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