What is the correct value of $int_0^infty dx J_0left( 2 a sinhleft( frac{x}{2} right) right) sin(b x)$?












1












$begingroup$


Integral (6.679.4) in Gradshteyn and Ryzhik claims that
$$
int_0^infty dx J_0left( 2 a sinhleft( frac{x}{2} right) right) sin(b x) = frac{2}{pi} sinh(pi b) left[ K_{ib}(a) right]^2
$$

I think that this is not correct. Here is a screenshot of some numerics in Mathematica:



enter image description here



For random values $a=2.34$ and $b=3$, it seems that the LHS of the above evaluates to $0.408$ while the RHS evaluates to $0.653$, and so they disagree.



I think there are three options:



1. I am making a mistake somehow in the above.



2. Mathematica is defining Bessel functions $J$ or $K$ differently than G&R, which I think is not likely.



2. This is an error in G&R.



In the last case, I have seen that Equation (58) on Page 115 of Erdelyi: Volume 1 Tables of Integral Transforms is the source for G&R (6.679.4). This integral simply stated there without a source, so I have no clue how this integral is derived.



What is $int_0^infty dx J_0left( 2 a sinhleft( frac{x}{2} right) right) sin(b x)$?










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  • 1




    $begingroup$
    A warning: the integral oscillates heavily. In these cases, numerical integration is not always reliable. So, it might be too early to claim an error in G&R.
    $endgroup$
    – Fabian
    Jan 8 at 22:03
















1












$begingroup$


Integral (6.679.4) in Gradshteyn and Ryzhik claims that
$$
int_0^infty dx J_0left( 2 a sinhleft( frac{x}{2} right) right) sin(b x) = frac{2}{pi} sinh(pi b) left[ K_{ib}(a) right]^2
$$

I think that this is not correct. Here is a screenshot of some numerics in Mathematica:



enter image description here



For random values $a=2.34$ and $b=3$, it seems that the LHS of the above evaluates to $0.408$ while the RHS evaluates to $0.653$, and so they disagree.



I think there are three options:



1. I am making a mistake somehow in the above.



2. Mathematica is defining Bessel functions $J$ or $K$ differently than G&R, which I think is not likely.



2. This is an error in G&R.



In the last case, I have seen that Equation (58) on Page 115 of Erdelyi: Volume 1 Tables of Integral Transforms is the source for G&R (6.679.4). This integral simply stated there without a source, so I have no clue how this integral is derived.



What is $int_0^infty dx J_0left( 2 a sinhleft( frac{x}{2} right) right) sin(b x)$?










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    A warning: the integral oscillates heavily. In these cases, numerical integration is not always reliable. So, it might be too early to claim an error in G&R.
    $endgroup$
    – Fabian
    Jan 8 at 22:03














1












1








1





$begingroup$


Integral (6.679.4) in Gradshteyn and Ryzhik claims that
$$
int_0^infty dx J_0left( 2 a sinhleft( frac{x}{2} right) right) sin(b x) = frac{2}{pi} sinh(pi b) left[ K_{ib}(a) right]^2
$$

I think that this is not correct. Here is a screenshot of some numerics in Mathematica:



enter image description here



For random values $a=2.34$ and $b=3$, it seems that the LHS of the above evaluates to $0.408$ while the RHS evaluates to $0.653$, and so they disagree.



I think there are three options:



1. I am making a mistake somehow in the above.



2. Mathematica is defining Bessel functions $J$ or $K$ differently than G&R, which I think is not likely.



2. This is an error in G&R.



In the last case, I have seen that Equation (58) on Page 115 of Erdelyi: Volume 1 Tables of Integral Transforms is the source for G&R (6.679.4). This integral simply stated there without a source, so I have no clue how this integral is derived.



What is $int_0^infty dx J_0left( 2 a sinhleft( frac{x}{2} right) right) sin(b x)$?










share|cite|improve this question









$endgroup$




Integral (6.679.4) in Gradshteyn and Ryzhik claims that
$$
int_0^infty dx J_0left( 2 a sinhleft( frac{x}{2} right) right) sin(b x) = frac{2}{pi} sinh(pi b) left[ K_{ib}(a) right]^2
$$

I think that this is not correct. Here is a screenshot of some numerics in Mathematica:



enter image description here



For random values $a=2.34$ and $b=3$, it seems that the LHS of the above evaluates to $0.408$ while the RHS evaluates to $0.653$, and so they disagree.



I think there are three options:



1. I am making a mistake somehow in the above.



2. Mathematica is defining Bessel functions $J$ or $K$ differently than G&R, which I think is not likely.



2. This is an error in G&R.



In the last case, I have seen that Equation (58) on Page 115 of Erdelyi: Volume 1 Tables of Integral Transforms is the source for G&R (6.679.4). This integral simply stated there without a source, so I have no clue how this integral is derived.



What is $int_0^infty dx J_0left( 2 a sinhleft( frac{x}{2} right) right) sin(b x)$?







integration






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asked Jan 8 at 21:33









Greg.PaulGreg.Paul

787921




787921








  • 1




    $begingroup$
    A warning: the integral oscillates heavily. In these cases, numerical integration is not always reliable. So, it might be too early to claim an error in G&R.
    $endgroup$
    – Fabian
    Jan 8 at 22:03














  • 1




    $begingroup$
    A warning: the integral oscillates heavily. In these cases, numerical integration is not always reliable. So, it might be too early to claim an error in G&R.
    $endgroup$
    – Fabian
    Jan 8 at 22:03








1




1




$begingroup$
A warning: the integral oscillates heavily. In these cases, numerical integration is not always reliable. So, it might be too early to claim an error in G&R.
$endgroup$
– Fabian
Jan 8 at 22:03




$begingroup$
A warning: the integral oscillates heavily. In these cases, numerical integration is not always reliable. So, it might be too early to claim an error in G&R.
$endgroup$
– Fabian
Jan 8 at 22:03










2 Answers
2






active

oldest

votes


















2












$begingroup$

Maple agrees with G&R on the formula, however it has considerable difficulty with the numerical evaluation of the integral as this oscillates very rapidly. But the integral from $0$ to $20$ is given as $.6536634068$, agreeing quite nicely with the theoretical result.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    What an awesome and simple trick! I should have known better than to doubt Gradshteyn and Ryzhik :)
    $endgroup$
    – Greg.Paul
    Jan 9 at 14:14



















1












$begingroup$

Interesting problem, for sure.



Using another CAS, I played with the precision. For Mathematica, your first command would be





f[a_,b_,n_]:=NIntegrate[BesselJ[0, 2 a Sinh[x/2]] Sin[b x], {x, 0, Infinity},
WorkingPrecision -> n]





Below are my results for the integration up to infinity for your particular values.
$$left(
begin{array}{cc}
n & text{result} \
10 & 0.4084616144 \
20 & 0.4084616143 \
30 & 0.6848603276 \
40 & 0.6848603276 \
50 & 0.6554693076 \
60 & 0.6554693076 \
70 & 0.6554693076 \
80 & 0.6554693076 \
90 & 0.6541206739\
100 & 0.6541738396 \
200 & 0.6533938298 \
300 & 0.6534598266 \
400 & 0.6536447955 \
500 & 0.6534985760
end{array}
right)$$
It seems to be very slow convergence (notice the swings of these results even for large values of $n$).



The systematic complain of the CAS was related to the highly oscillatory integrand as Robert Israel commented.






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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

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    active

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    active

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    2












    $begingroup$

    Maple agrees with G&R on the formula, however it has considerable difficulty with the numerical evaluation of the integral as this oscillates very rapidly. But the integral from $0$ to $20$ is given as $.6536634068$, agreeing quite nicely with the theoretical result.






    share|cite|improve this answer









    $endgroup$













    • $begingroup$
      What an awesome and simple trick! I should have known better than to doubt Gradshteyn and Ryzhik :)
      $endgroup$
      – Greg.Paul
      Jan 9 at 14:14
















    2












    $begingroup$

    Maple agrees with G&R on the formula, however it has considerable difficulty with the numerical evaluation of the integral as this oscillates very rapidly. But the integral from $0$ to $20$ is given as $.6536634068$, agreeing quite nicely with the theoretical result.






    share|cite|improve this answer









    $endgroup$













    • $begingroup$
      What an awesome and simple trick! I should have known better than to doubt Gradshteyn and Ryzhik :)
      $endgroup$
      – Greg.Paul
      Jan 9 at 14:14














    2












    2








    2





    $begingroup$

    Maple agrees with G&R on the formula, however it has considerable difficulty with the numerical evaluation of the integral as this oscillates very rapidly. But the integral from $0$ to $20$ is given as $.6536634068$, agreeing quite nicely with the theoretical result.






    share|cite|improve this answer









    $endgroup$



    Maple agrees with G&R on the formula, however it has considerable difficulty with the numerical evaluation of the integral as this oscillates very rapidly. But the integral from $0$ to $20$ is given as $.6536634068$, agreeing quite nicely with the theoretical result.







    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered Jan 8 at 22:03









    Robert IsraelRobert Israel

    330k23219473




    330k23219473












    • $begingroup$
      What an awesome and simple trick! I should have known better than to doubt Gradshteyn and Ryzhik :)
      $endgroup$
      – Greg.Paul
      Jan 9 at 14:14


















    • $begingroup$
      What an awesome and simple trick! I should have known better than to doubt Gradshteyn and Ryzhik :)
      $endgroup$
      – Greg.Paul
      Jan 9 at 14:14
















    $begingroup$
    What an awesome and simple trick! I should have known better than to doubt Gradshteyn and Ryzhik :)
    $endgroup$
    – Greg.Paul
    Jan 9 at 14:14




    $begingroup$
    What an awesome and simple trick! I should have known better than to doubt Gradshteyn and Ryzhik :)
    $endgroup$
    – Greg.Paul
    Jan 9 at 14:14











    1












    $begingroup$

    Interesting problem, for sure.



    Using another CAS, I played with the precision. For Mathematica, your first command would be





    f[a_,b_,n_]:=NIntegrate[BesselJ[0, 2 a Sinh[x/2]] Sin[b x], {x, 0, Infinity},
    WorkingPrecision -> n]





    Below are my results for the integration up to infinity for your particular values.
    $$left(
    begin{array}{cc}
    n & text{result} \
    10 & 0.4084616144 \
    20 & 0.4084616143 \
    30 & 0.6848603276 \
    40 & 0.6848603276 \
    50 & 0.6554693076 \
    60 & 0.6554693076 \
    70 & 0.6554693076 \
    80 & 0.6554693076 \
    90 & 0.6541206739\
    100 & 0.6541738396 \
    200 & 0.6533938298 \
    300 & 0.6534598266 \
    400 & 0.6536447955 \
    500 & 0.6534985760
    end{array}
    right)$$
    It seems to be very slow convergence (notice the swings of these results even for large values of $n$).



    The systematic complain of the CAS was related to the highly oscillatory integrand as Robert Israel commented.






    share|cite|improve this answer









    $endgroup$


















      1












      $begingroup$

      Interesting problem, for sure.



      Using another CAS, I played with the precision. For Mathematica, your first command would be





      f[a_,b_,n_]:=NIntegrate[BesselJ[0, 2 a Sinh[x/2]] Sin[b x], {x, 0, Infinity},
      WorkingPrecision -> n]





      Below are my results for the integration up to infinity for your particular values.
      $$left(
      begin{array}{cc}
      n & text{result} \
      10 & 0.4084616144 \
      20 & 0.4084616143 \
      30 & 0.6848603276 \
      40 & 0.6848603276 \
      50 & 0.6554693076 \
      60 & 0.6554693076 \
      70 & 0.6554693076 \
      80 & 0.6554693076 \
      90 & 0.6541206739\
      100 & 0.6541738396 \
      200 & 0.6533938298 \
      300 & 0.6534598266 \
      400 & 0.6536447955 \
      500 & 0.6534985760
      end{array}
      right)$$
      It seems to be very slow convergence (notice the swings of these results even for large values of $n$).



      The systematic complain of the CAS was related to the highly oscillatory integrand as Robert Israel commented.






      share|cite|improve this answer









      $endgroup$
















        1












        1








        1





        $begingroup$

        Interesting problem, for sure.



        Using another CAS, I played with the precision. For Mathematica, your first command would be





        f[a_,b_,n_]:=NIntegrate[BesselJ[0, 2 a Sinh[x/2]] Sin[b x], {x, 0, Infinity},
        WorkingPrecision -> n]





        Below are my results for the integration up to infinity for your particular values.
        $$left(
        begin{array}{cc}
        n & text{result} \
        10 & 0.4084616144 \
        20 & 0.4084616143 \
        30 & 0.6848603276 \
        40 & 0.6848603276 \
        50 & 0.6554693076 \
        60 & 0.6554693076 \
        70 & 0.6554693076 \
        80 & 0.6554693076 \
        90 & 0.6541206739\
        100 & 0.6541738396 \
        200 & 0.6533938298 \
        300 & 0.6534598266 \
        400 & 0.6536447955 \
        500 & 0.6534985760
        end{array}
        right)$$
        It seems to be very slow convergence (notice the swings of these results even for large values of $n$).



        The systematic complain of the CAS was related to the highly oscillatory integrand as Robert Israel commented.






        share|cite|improve this answer









        $endgroup$



        Interesting problem, for sure.



        Using another CAS, I played with the precision. For Mathematica, your first command would be





        f[a_,b_,n_]:=NIntegrate[BesselJ[0, 2 a Sinh[x/2]] Sin[b x], {x, 0, Infinity},
        WorkingPrecision -> n]





        Below are my results for the integration up to infinity for your particular values.
        $$left(
        begin{array}{cc}
        n & text{result} \
        10 & 0.4084616144 \
        20 & 0.4084616143 \
        30 & 0.6848603276 \
        40 & 0.6848603276 \
        50 & 0.6554693076 \
        60 & 0.6554693076 \
        70 & 0.6554693076 \
        80 & 0.6554693076 \
        90 & 0.6541206739\
        100 & 0.6541738396 \
        200 & 0.6533938298 \
        300 & 0.6534598266 \
        400 & 0.6536447955 \
        500 & 0.6534985760
        end{array}
        right)$$
        It seems to be very slow convergence (notice the swings of these results even for large values of $n$).



        The systematic complain of the CAS was related to the highly oscillatory integrand as Robert Israel commented.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Jan 9 at 7:06









        Claude LeiboviciClaude Leibovici

        125k1158136




        125k1158136






























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