How to Reverse Sort a nested list starting with Uppercase entries?











up vote
8
down vote

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List r:



r= [['Paris', 10], ['amsterdam', 5], ['London', 18], ['london', 15], ['Berlin', 2], ['Stockholm', 4], ['oslo', 14], ['helsinki', 16], ['Zurich', 17]]


If I do a reverse sort:



sorted(r, reverse=True)



[['oslo', 14], ['london', 15], ['helsinki', 16], ['amsterdam', 5], ['Zurich', 17], ['Stockholm', 4], ['Paris', 10], ['London', 18], ['Berlin', 2]]


What I want is to start with Upper case elements and than the lower case elements.



[ ['Zurich', 17], ['Stockholm', 4], ['Paris', 10], ['London', 18], ['Berlin', 2], ['oslo', 14], ['london', 15], ['helsinki', 16], ['amsterdam', 5]]


Is there an easy way in Python3 to sort the list as I want?






python list sorting case







share|improve this question






















  • I think the behaviour is because of the ASCII values of the capital and small letters.
    – Nitin Pawar
    Dec 3 at 11:03






  • 1




    First sort by name, then by "casing": r.sort(key=lambda x: x[0]); r.sort(key=lambda x: x[0].islower()). This works because list.sort uses a stable sorting algorithm (i.e. it preserves the relative order of equal elements). list.sort is also an adaptive sort, which means it can take O(n) time if the input is partially sorted and after the first sort the input is very well partially sorted according to the key x[0][0].islower().
    – Giacomo Alzetta
    Dec 3 at 13:34















up vote
8
down vote

favorite
2












List r:



r= [['Paris', 10], ['amsterdam', 5], ['London', 18], ['london', 15], ['Berlin', 2], ['Stockholm', 4], ['oslo', 14], ['helsinki', 16], ['Zurich', 17]]


If I do a reverse sort:



sorted(r, reverse=True)



[['oslo', 14], ['london', 15], ['helsinki', 16], ['amsterdam', 5], ['Zurich', 17], ['Stockholm', 4], ['Paris', 10], ['London', 18], ['Berlin', 2]]


What I want is to start with Upper case elements and than the lower case elements.



[ ['Zurich', 17], ['Stockholm', 4], ['Paris', 10], ['London', 18], ['Berlin', 2], ['oslo', 14], ['london', 15], ['helsinki', 16], ['amsterdam', 5]]


Is there an easy way in Python3 to sort the list as I want?






python list sorting case







share|improve this question






















  • I think the behaviour is because of the ASCII values of the capital and small letters.
    – Nitin Pawar
    Dec 3 at 11:03






  • 1




    First sort by name, then by "casing": r.sort(key=lambda x: x[0]); r.sort(key=lambda x: x[0].islower()). This works because list.sort uses a stable sorting algorithm (i.e. it preserves the relative order of equal elements). list.sort is also an adaptive sort, which means it can take O(n) time if the input is partially sorted and after the first sort the input is very well partially sorted according to the key x[0][0].islower().
    – Giacomo Alzetta
    Dec 3 at 13:34













up vote
8
down vote

favorite
2









up vote
8
down vote

favorite
2






2





List r:



r= [['Paris', 10], ['amsterdam', 5], ['London', 18], ['london', 15], ['Berlin', 2], ['Stockholm', 4], ['oslo', 14], ['helsinki', 16], ['Zurich', 17]]


If I do a reverse sort:



sorted(r, reverse=True)



[['oslo', 14], ['london', 15], ['helsinki', 16], ['amsterdam', 5], ['Zurich', 17], ['Stockholm', 4], ['Paris', 10], ['London', 18], ['Berlin', 2]]


What I want is to start with Upper case elements and than the lower case elements.



[ ['Zurich', 17], ['Stockholm', 4], ['Paris', 10], ['London', 18], ['Berlin', 2], ['oslo', 14], ['london', 15], ['helsinki', 16], ['amsterdam', 5]]


Is there an easy way in Python3 to sort the list as I want?






python list sorting case







share|improve this question













List r:



r= [['Paris', 10], ['amsterdam', 5], ['London', 18], ['london', 15], ['Berlin', 2], ['Stockholm', 4], ['oslo', 14], ['helsinki', 16], ['Zurich', 17]]


If I do a reverse sort:



sorted(r, reverse=True)



[['oslo', 14], ['london', 15], ['helsinki', 16], ['amsterdam', 5], ['Zurich', 17], ['Stockholm', 4], ['Paris', 10], ['London', 18], ['Berlin', 2]]


What I want is to start with Upper case elements and than the lower case elements.



[ ['Zurich', 17], ['Stockholm', 4], ['Paris', 10], ['London', 18], ['Berlin', 2], ['oslo', 14], ['london', 15], ['helsinki', 16], ['amsterdam', 5]]


Is there an easy way in Python3 to sort the list as I want?






python list sorting case




python list sorting case






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Dec 3 at 11:01









Reman

3,48243572




3,48243572












  • I think the behaviour is because of the ASCII values of the capital and small letters.
    – Nitin Pawar
    Dec 3 at 11:03






  • 1




    First sort by name, then by "casing": r.sort(key=lambda x: x[0]); r.sort(key=lambda x: x[0].islower()). This works because list.sort uses a stable sorting algorithm (i.e. it preserves the relative order of equal elements). list.sort is also an adaptive sort, which means it can take O(n) time if the input is partially sorted and after the first sort the input is very well partially sorted according to the key x[0][0].islower().
    – Giacomo Alzetta
    Dec 3 at 13:34


















  • I think the behaviour is because of the ASCII values of the capital and small letters.
    – Nitin Pawar
    Dec 3 at 11:03






  • 1




    First sort by name, then by "casing": r.sort(key=lambda x: x[0]); r.sort(key=lambda x: x[0].islower()). This works because list.sort uses a stable sorting algorithm (i.e. it preserves the relative order of equal elements). list.sort is also an adaptive sort, which means it can take O(n) time if the input is partially sorted and after the first sort the input is very well partially sorted according to the key x[0][0].islower().
    – Giacomo Alzetta
    Dec 3 at 13:34
















I think the behaviour is because of the ASCII values of the capital and small letters.
– Nitin Pawar
Dec 3 at 11:03




I think the behaviour is because of the ASCII values of the capital and small letters.
– Nitin Pawar
Dec 3 at 11:03




1




1




First sort by name, then by "casing": r.sort(key=lambda x: x[0]); r.sort(key=lambda x: x[0].islower()). This works because list.sort uses a stable sorting algorithm (i.e. it preserves the relative order of equal elements). list.sort is also an adaptive sort, which means it can take O(n) time if the input is partially sorted and after the first sort the input is very well partially sorted according to the key x[0][0].islower().
– Giacomo Alzetta
Dec 3 at 13:34




First sort by name, then by "casing": r.sort(key=lambda x: x[0]); r.sort(key=lambda x: x[0].islower()). This works because list.sort uses a stable sorting algorithm (i.e. it preserves the relative order of equal elements). list.sort is also an adaptive sort, which means it can take O(n) time if the input is partially sorted and after the first sort the input is very well partially sorted according to the key x[0][0].islower().
– Giacomo Alzetta
Dec 3 at 13:34












1 Answer
1






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up vote
16
down vote



accepted










Everything is possible with a custom key function:



>> sorted(r, key=lambda e: (not e[0].islower(), e[0]), reverse=True)

[['Zurich', 17], ['Stockholm', 4], ['Paris', 10], ['London', 18], ['Berlin', 2],

 ['oslo', 14], ['london', 15], ['helsinki', 16], ['amsterdam', 5]]





share|improve this answer

















  • 1




    Great solution. Thanks. It also works the other way around sorted(r, key=lambda e: (not e[0].islower(), e[0])) (=default case sort but starting with lowercase entries).
    – Reman
    Dec 3 at 11:28











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1 Answer
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active

oldest

votes








1 Answer
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active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
16
down vote



accepted










Everything is possible with a custom key function:



>> sorted(r, key=lambda e: (not e[0].islower(), e[0]), reverse=True)

[['Zurich', 17], ['Stockholm', 4], ['Paris', 10], ['London', 18], ['Berlin', 2],

 ['oslo', 14], ['london', 15], ['helsinki', 16], ['amsterdam', 5]]





share|improve this answer

















  • 1




    Great solution. Thanks. It also works the other way around sorted(r, key=lambda e: (not e[0].islower(), e[0])) (=default case sort but starting with lowercase entries).
    – Reman
    Dec 3 at 11:28















up vote
16
down vote



accepted










Everything is possible with a custom key function:



>> sorted(r, key=lambda e: (not e[0].islower(), e[0]), reverse=True)

[['Zurich', 17], ['Stockholm', 4], ['Paris', 10], ['London', 18], ['Berlin', 2],

 ['oslo', 14], ['london', 15], ['helsinki', 16], ['amsterdam', 5]]





share|improve this answer

















  • 1




    Great solution. Thanks. It also works the other way around sorted(r, key=lambda e: (not e[0].islower(), e[0])) (=default case sort but starting with lowercase entries).
    – Reman
    Dec 3 at 11:28













up vote
16
down vote



accepted







up vote
16
down vote



accepted






Everything is possible with a custom key function:



>> sorted(r, key=lambda e: (not e[0].islower(), e[0]), reverse=True)

[['Zurich', 17], ['Stockholm', 4], ['Paris', 10], ['London', 18], ['Berlin', 2],

 ['oslo', 14], ['london', 15], ['helsinki', 16], ['amsterdam', 5]]





share|improve this answer












Everything is possible with a custom key function:



>> sorted(r, key=lambda e: (not e[0].islower(), e[0]), reverse=True)

[['Zurich', 17], ['Stockholm', 4], ['Paris', 10], ['London', 18], ['Berlin', 2],

 ['oslo', 14], ['london', 15], ['helsinki', 16], ['amsterdam', 5]]






share|improve this answer












share|improve this answer



share|improve this answer










answered Dec 3 at 11:06









DeepSpace

35.4k44067




35.4k44067








  • 1




    Great solution. Thanks. It also works the other way around sorted(r, key=lambda e: (not e[0].islower(), e[0])) (=default case sort but starting with lowercase entries).
    – Reman
    Dec 3 at 11:28














  • 1




    Great solution. Thanks. It also works the other way around sorted(r, key=lambda e: (not e[0].islower(), e[0])) (=default case sort but starting with lowercase entries).
    – Reman
    Dec 3 at 11:28








1




1




Great solution. Thanks. It also works the other way around sorted(r, key=lambda e: (not e[0].islower(), e[0])) (=default case sort but starting with lowercase entries).
– Reman
Dec 3 at 11:28




Great solution. Thanks. It also works the other way around sorted(r, key=lambda e: (not e[0].islower(), e[0])) (=default case sort but starting with lowercase entries).
– Reman
Dec 3 at 11:28


















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