How do I transform $-2tan x + sec^2 x $ into the form $(a +b tan x)^2$?
$begingroup$
How does $frac{1}{cos^2 x}$ translate into $tan^2$? I felt like I missed a formula or so, but what?
It obviously asks to turn it into quadratic form of $tan,$ but I’m lacking $sin^2$ .
algebra-precalculus trigonometry
edited Dec 14 '18 at 15:19
Andrews
3551317
asked Dec 14 '18 at 10:53
WangcincayWangcincay
463
$endgroup$
add a comment |
$begingroup$
How does $frac{1}{cos^2 x}$ translate into $tan^2$? I felt like I missed a formula or so, but what?
It obviously asks to turn it into quadratic form of $tan,$ but I’m lacking $sin^2$ .
algebra-precalculus trigonometry
edited Dec 14 '18 at 15:19
Andrews
3551317
asked Dec 14 '18 at 10:53
WangcincayWangcincay
463
$endgroup$
add a comment |
$begingroup$
How does $frac{1}{cos^2 x}$ translate into $tan^2$? I felt like I missed a formula or so, but what?
It obviously asks to turn it into quadratic form of $tan,$ but I’m lacking $sin^2$ .
algebra-precalculus trigonometry
edited Dec 14 '18 at 15:19
Andrews
3551317
asked Dec 14 '18 at 10:53
WangcincayWangcincay
463
$endgroup$
How does $frac{1}{cos^2 x}$ translate into $tan^2$? I felt like I missed a formula or so, but what?
It obviously asks to turn it into quadratic form of $tan,$ but I’m lacking $sin^2$ .
algebra-precalculus trigonometry
algebra-precalculus trigonometry
edited Dec 14 '18 at 15:19
Andrews
3551317
asked Dec 14 '18 at 10:53
WangcincayWangcincay
463
edited Dec 14 '18 at 15:19
Andrews
3551317
asked Dec 14 '18 at 10:53
WangcincayWangcincay
463
edited Dec 14 '18 at 15:19
Andrews
3551317
edited Dec 14 '18 at 15:19
Andrews
3551317
edited Dec 14 '18 at 15:19
Andrews
3551317
3551317
asked Dec 14 '18 at 10:53
WangcincayWangcincay
463
asked Dec 14 '18 at 10:53
WangcincayWangcincay
463
asked Dec 14 '18 at 10:53
WangcincayWangcincay
463
463
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Hint: Use the following well-known identity
$$sec^2 x = 1+tan^2 x$$
which yields
$$-2tan x+tan^2 x+1$$
answered Dec 14 '18 at 10:55
KM101KM101
5,9261523
$endgroup$
add a comment |
$begingroup$
You may use the identity
$$ sec^2 x = 1 + tan^2 x $$
answered Dec 14 '18 at 10:57
Ken HungKen Hung
613
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
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active
oldest
votes
$begingroup$
Hint: Use the following well-known identity
$$sec^2 x = 1+tan^2 x$$
which yields
$$-2tan x+tan^2 x+1$$
answered Dec 14 '18 at 10:55
KM101KM101
5,9261523
$endgroup$
add a comment |
$begingroup$
Hint: Use the following well-known identity
$$sec^2 x = 1+tan^2 x$$
which yields
$$-2tan x+tan^2 x+1$$
answered Dec 14 '18 at 10:55
KM101KM101
5,9261523
$endgroup$
add a comment |
$begingroup$
Hint: Use the following well-known identity
$$sec^2 x = 1+tan^2 x$$
which yields
$$-2tan x+tan^2 x+1$$
answered Dec 14 '18 at 10:55
KM101KM101
5,9261523
$endgroup$
Hint: Use the following well-known identity
$$sec^2 x = 1+tan^2 x$$
which yields
$$-2tan x+tan^2 x+1$$
answered Dec 14 '18 at 10:55
KM101KM101
5,9261523
answered Dec 14 '18 at 10:55
KM101KM101
5,9261523
answered Dec 14 '18 at 10:55
KM101KM101
5,9261523
answered Dec 14 '18 at 10:55
KM101KM101
5,9261523
5,9261523
add a comment |
add a comment |
$begingroup$
You may use the identity
$$ sec^2 x = 1 + tan^2 x $$
answered Dec 14 '18 at 10:57
Ken HungKen Hung
613
$endgroup$
add a comment |
$begingroup$
You may use the identity
$$ sec^2 x = 1 + tan^2 x $$
answered Dec 14 '18 at 10:57
Ken HungKen Hung
613
$endgroup$
add a comment |
$begingroup$
You may use the identity
$$ sec^2 x = 1 + tan^2 x $$
answered Dec 14 '18 at 10:57
Ken HungKen Hung
613
$endgroup$
You may use the identity
$$ sec^2 x = 1 + tan^2 x $$
answered Dec 14 '18 at 10:57
Ken HungKen Hung
613
answered Dec 14 '18 at 10:57
Ken HungKen Hung
613
answered Dec 14 '18 at 10:57
Ken HungKen Hung
613
answered Dec 14 '18 at 10:57
Ken HungKen Hung
613
613
add a comment |
add a comment |
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