What is the purpose of op-amp in the output of Instrumentation amplifier
I encountered a problem while solving an analog circuit.
I just need to know the purpose of the last op-amp (K4) at this circuit:
while solving I understand it just amplify the output voltage from the Instrumentation Amplifier, but there is known purpose for it beside to amplify Vout3.
thanks!
op-amp analog instrumentation-amplifier
asked Dec 10 '18 at 11:48
Michael Astahov
132
add a comment |
I encountered a problem while solving an analog circuit.
I just need to know the purpose of the last op-amp (K4) at this circuit:
while solving I understand it just amplify the output voltage from the Instrumentation Amplifier, but there is known purpose for it beside to amplify Vout3.
thanks!
op-amp analog instrumentation-amplifier
asked Dec 10 '18 at 11:48
Michael Astahov
132
Is this from EEG or EKG or EMG sensors?
– analogsystemsrf
Dec 10 '18 at 13:31
it just a problem from my homework. I know this kind of circuits very common so possibly it used in these sensors.
– Michael Astahov
Dec 11 '18 at 21:23
add a comment |
I encountered a problem while solving an analog circuit.
I just need to know the purpose of the last op-amp (K4) at this circuit:
while solving I understand it just amplify the output voltage from the Instrumentation Amplifier, but there is known purpose for it beside to amplify Vout3.
thanks!
op-amp analog instrumentation-amplifier
asked Dec 10 '18 at 11:48
Michael Astahov
132
I encountered a problem while solving an analog circuit.
I just need to know the purpose of the last op-amp (K4) at this circuit:
while solving I understand it just amplify the output voltage from the Instrumentation Amplifier, but there is known purpose for it beside to amplify Vout3.
thanks!
op-amp analog instrumentation-amplifier
op-amp analog instrumentation-amplifier
asked Dec 10 '18 at 11:48
Michael Astahov
132
asked Dec 10 '18 at 11:48
Michael Astahov
132
asked Dec 10 '18 at 11:48
Michael Astahov
132
asked Dec 10 '18 at 11:48
Michael Astahov
132
asked Dec 10 '18 at 11:48
Michael Astahov
132
132
Is this from EEG or EKG or EMG sensors?
– analogsystemsrf
Dec 10 '18 at 13:31
it just a problem from my homework. I know this kind of circuits very common so possibly it used in these sensors.
– Michael Astahov
Dec 11 '18 at 21:23
add a comment |
Is this from EEG or EKG or EMG sensors?
– analogsystemsrf
Dec 10 '18 at 13:31
it just a problem from my homework. I know this kind of circuits very common so possibly it used in these sensors.
– Michael Astahov
Dec 11 '18 at 21:23
Is this from EEG or EKG or EMG sensors?
– analogsystemsrf
Dec 10 '18 at 13:31
Is this from EEG or EKG or EMG sensors?
– analogsystemsrf
Dec 10 '18 at 13:31
it just a problem from my homework. I know this kind of circuits very common so possibly it used in these sensors.
– Michael Astahov
Dec 11 '18 at 21:23
it just a problem from my homework. I know this kind of circuits very common so possibly it used in these sensors.
– Michael Astahov
Dec 11 '18 at 21:23
add a comment |
1 Answer
1
active
oldest
votes
K4 produces amplification for AC signals whilst providing a DC amplification of 1 (so that DC levels are maintained from the InAmp output to whatever stage follows K4). It might also be used to share the burden of AC signal gain between InAmp and itself thus minimizing slew rate problems in the InAmp.
answered Dec 10 '18 at 11:54
Andy aka
239k10176409
thanks Andy for the quick reponse.
– Michael Astahov
Dec 10 '18 at 12:03
So - the last stage acts as a sort of highpass.
– LvW
Dec 10 '18 at 13:10
@LvW are you asking or saying!
– Andy aka
Dec 10 '18 at 13:12
@Andy aka...there is no question mark. Hence, it is not a question. To me, the transfer function [1+sR2C/(1+sR1C)] is a highpass with a fixed gain of unity at low frequencies. Why are you asking?
– LvW
Dec 10 '18 at 14:51
@LvW it's always best to be careful!!
– Andy aka
Dec 10 '18 at 16:08
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
});
});
}, "mathjax-editing");
StackExchange.ifUsing("editor", function () {
return StackExchange.using("schematics", function () {
StackExchange.schematics.init();
});
}, "cicuitlab");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "135"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2felectronics.stackexchange.com%2fquestions%2f411481%2fwhat-is-the-purpose-of-op-amp-in-the-output-of-instrumentation-amplifier%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
K4 produces amplification for AC signals whilst providing a DC amplification of 1 (so that DC levels are maintained from the InAmp output to whatever stage follows K4). It might also be used to share the burden of AC signal gain between InAmp and itself thus minimizing slew rate problems in the InAmp.
answered Dec 10 '18 at 11:54
Andy aka
239k10176409
thanks Andy for the quick reponse.
– Michael Astahov
Dec 10 '18 at 12:03
So - the last stage acts as a sort of highpass.
– LvW
Dec 10 '18 at 13:10
@LvW are you asking or saying!
– Andy aka
Dec 10 '18 at 13:12
@Andy aka...there is no question mark. Hence, it is not a question. To me, the transfer function [1+sR2C/(1+sR1C)] is a highpass with a fixed gain of unity at low frequencies. Why are you asking?
– LvW
Dec 10 '18 at 14:51
@LvW it's always best to be careful!!
– Andy aka
Dec 10 '18 at 16:08
add a comment |
K4 produces amplification for AC signals whilst providing a DC amplification of 1 (so that DC levels are maintained from the InAmp output to whatever stage follows K4). It might also be used to share the burden of AC signal gain between InAmp and itself thus minimizing slew rate problems in the InAmp.
answered Dec 10 '18 at 11:54
Andy aka
239k10176409
thanks Andy for the quick reponse.
– Michael Astahov
Dec 10 '18 at 12:03
So - the last stage acts as a sort of highpass.
– LvW
Dec 10 '18 at 13:10
@LvW are you asking or saying!
– Andy aka
Dec 10 '18 at 13:12
@Andy aka...there is no question mark. Hence, it is not a question. To me, the transfer function [1+sR2C/(1+sR1C)] is a highpass with a fixed gain of unity at low frequencies. Why are you asking?
– LvW
Dec 10 '18 at 14:51
@LvW it's always best to be careful!!
– Andy aka
Dec 10 '18 at 16:08
add a comment |
K4 produces amplification for AC signals whilst providing a DC amplification of 1 (so that DC levels are maintained from the InAmp output to whatever stage follows K4). It might also be used to share the burden of AC signal gain between InAmp and itself thus minimizing slew rate problems in the InAmp.
answered Dec 10 '18 at 11:54
Andy aka
239k10176409
K4 produces amplification for AC signals whilst providing a DC amplification of 1 (so that DC levels are maintained from the InAmp output to whatever stage follows K4). It might also be used to share the burden of AC signal gain between InAmp and itself thus minimizing slew rate problems in the InAmp.
answered Dec 10 '18 at 11:54
Andy aka
239k10176409
answered Dec 10 '18 at 11:54
Andy aka
239k10176409
answered Dec 10 '18 at 11:54
Andy aka
239k10176409
answered Dec 10 '18 at 11:54
Andy aka
239k10176409
239k10176409
thanks Andy for the quick reponse.
– Michael Astahov
Dec 10 '18 at 12:03
So - the last stage acts as a sort of highpass.
– LvW
Dec 10 '18 at 13:10
@LvW are you asking or saying!
– Andy aka
Dec 10 '18 at 13:12
@Andy aka...there is no question mark. Hence, it is not a question. To me, the transfer function [1+sR2C/(1+sR1C)] is a highpass with a fixed gain of unity at low frequencies. Why are you asking?
– LvW
Dec 10 '18 at 14:51
@LvW it's always best to be careful!!
– Andy aka
Dec 10 '18 at 16:08
add a comment |
thanks Andy for the quick reponse.
– Michael Astahov
Dec 10 '18 at 12:03
So - the last stage acts as a sort of highpass.
– LvW
Dec 10 '18 at 13:10
@LvW are you asking or saying!
– Andy aka
Dec 10 '18 at 13:12
@Andy aka...there is no question mark. Hence, it is not a question. To me, the transfer function [1+sR2C/(1+sR1C)] is a highpass with a fixed gain of unity at low frequencies. Why are you asking?
– LvW
Dec 10 '18 at 14:51
@LvW it's always best to be careful!!
– Andy aka
Dec 10 '18 at 16:08
thanks Andy for the quick reponse.
– Michael Astahov
Dec 10 '18 at 12:03
thanks Andy for the quick reponse.
– Michael Astahov
Dec 10 '18 at 12:03
So - the last stage acts as a sort of highpass.
– LvW
Dec 10 '18 at 13:10
So - the last stage acts as a sort of highpass.
– LvW
Dec 10 '18 at 13:10
@LvW are you asking or saying!
– Andy aka
Dec 10 '18 at 13:12
@LvW are you asking or saying!
– Andy aka
Dec 10 '18 at 13:12
@Andy aka...there is no question mark. Hence, it is not a question. To me, the transfer function [1+sR2C/(1+sR1C)] is a highpass with a fixed gain of unity at low frequencies. Why are you asking?
– LvW
Dec 10 '18 at 14:51
@Andy aka...there is no question mark. Hence, it is not a question. To me, the transfer function [1+sR2C/(1+sR1C)] is a highpass with a fixed gain of unity at low frequencies. Why are you asking?
– LvW
Dec 10 '18 at 14:51
@LvW it's always best to be careful!!
– Andy aka
Dec 10 '18 at 16:08
@LvW it's always best to be careful!!
– Andy aka
Dec 10 '18 at 16:08
add a comment |
Thanks for contributing an answer to Electrical Engineering Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2felectronics.stackexchange.com%2fquestions%2f411481%2fwhat-is-the-purpose-of-op-amp-in-the-output-of-instrumentation-amplifier%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Is this from EEG or EKG or EMG sensors?
– analogsystemsrf
Dec 10 '18 at 13:31
it just a problem from my homework. I know this kind of circuits very common so possibly it used in these sensors.
– Michael Astahov
Dec 11 '18 at 21:23