If $S, S_1, S_2$ be the circles of radii 5,3 and 2 respectively. If $S_1$ and $S_2$ touch externally and they...












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If $S, S_1, S_2$ be the circles of radii 5,3 and 2 respectively. If $S_1$ and $S_2$ touch externally and they touch internally with $S$. The radius of circle $S_3$ which touches externally with $S_1$ and $S_2$ and internally with $S$ is?



I tried making a diagram and figuring out, but cannot bring a relation.










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closed as off-topic by Saad, Paul Frost, Eevee Trainer, KReiser, Lord_Farin Dec 27 '18 at 9:05


This question appears to be off-topic. The users who voted to close gave this specific reason:


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    $begingroup$


    If $S, S_1, S_2$ be the circles of radii 5,3 and 2 respectively. If $S_1$ and $S_2$ touch externally and they touch internally with $S$. The radius of circle $S_3$ which touches externally with $S_1$ and $S_2$ and internally with $S$ is?



    I tried making a diagram and figuring out, but cannot bring a relation.










    share|cite|improve this question









    $endgroup$



    closed as off-topic by Saad, Paul Frost, Eevee Trainer, KReiser, Lord_Farin Dec 27 '18 at 9:05


    This question appears to be off-topic. The users who voted to close gave this specific reason:


    • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Paul Frost, Eevee Trainer, KReiser, Lord_Farin

    If this question can be reworded to fit the rules in the help center, please edit the question.



















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      1





      $begingroup$


      If $S, S_1, S_2$ be the circles of radii 5,3 and 2 respectively. If $S_1$ and $S_2$ touch externally and they touch internally with $S$. The radius of circle $S_3$ which touches externally with $S_1$ and $S_2$ and internally with $S$ is?



      I tried making a diagram and figuring out, but cannot bring a relation.










      share|cite|improve this question









      $endgroup$




      If $S, S_1, S_2$ be the circles of radii 5,3 and 2 respectively. If $S_1$ and $S_2$ touch externally and they touch internally with $S$. The radius of circle $S_3$ which touches externally with $S_1$ and $S_2$ and internally with $S$ is?



      I tried making a diagram and figuring out, but cannot bring a relation.







      geometry circle






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      asked Dec 26 '18 at 3:37









      J. DoeJ. Doe

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      closed as off-topic by Saad, Paul Frost, Eevee Trainer, KReiser, Lord_Farin Dec 27 '18 at 9:05


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Paul Frost, Eevee Trainer, KReiser, Lord_Farin

      If this question can be reworded to fit the rules in the help center, please edit the question.







      closed as off-topic by Saad, Paul Frost, Eevee Trainer, KReiser, Lord_Farin Dec 27 '18 at 9:05


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Paul Frost, Eevee Trainer, KReiser, Lord_Farin

      If this question can be reworded to fit the rules in the help center, please edit the question.






















          1 Answer
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          $begingroup$

          Let $C_1, C_2$ be the centers of the circles $S_1, S_2$ and $C$ the center of the circle $S$. If the circle with center $O$ and radius $r$ touches the circles $S_1, S_2$ externally and $S$ internally, then we have $C_1C_2 = 5$, $OC_1 = r+2$, $OC_2=r+3$, $OC=5-r$. If in the triangle $ABC$, the point $D$ is on $BC$ such that $BD:DC = m:n$, then it is not difficult to show that
          $$ (m+n)^2 AD^2 = (m+n)(m AC^2 + n AB^2) - mn BC^2$$
          (See, Loney, Plane Trigonometry, Page 187, Ex 29).



          Applying this to the triangle $CC_1C_2$, we have
          $$ 25(5-r)^2 = 5(2(r+2)^2 + 3(r+3)^2) - 150$$
          from which we get $r = 30/19$.






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            1 Answer
            1






            active

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            active

            oldest

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            active

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            2












            $begingroup$

            Let $C_1, C_2$ be the centers of the circles $S_1, S_2$ and $C$ the center of the circle $S$. If the circle with center $O$ and radius $r$ touches the circles $S_1, S_2$ externally and $S$ internally, then we have $C_1C_2 = 5$, $OC_1 = r+2$, $OC_2=r+3$, $OC=5-r$. If in the triangle $ABC$, the point $D$ is on $BC$ such that $BD:DC = m:n$, then it is not difficult to show that
            $$ (m+n)^2 AD^2 = (m+n)(m AC^2 + n AB^2) - mn BC^2$$
            (See, Loney, Plane Trigonometry, Page 187, Ex 29).



            Applying this to the triangle $CC_1C_2$, we have
            $$ 25(5-r)^2 = 5(2(r+2)^2 + 3(r+3)^2) - 150$$
            from which we get $r = 30/19$.






            share|cite|improve this answer









            $endgroup$


















              2












              $begingroup$

              Let $C_1, C_2$ be the centers of the circles $S_1, S_2$ and $C$ the center of the circle $S$. If the circle with center $O$ and radius $r$ touches the circles $S_1, S_2$ externally and $S$ internally, then we have $C_1C_2 = 5$, $OC_1 = r+2$, $OC_2=r+3$, $OC=5-r$. If in the triangle $ABC$, the point $D$ is on $BC$ such that $BD:DC = m:n$, then it is not difficult to show that
              $$ (m+n)^2 AD^2 = (m+n)(m AC^2 + n AB^2) - mn BC^2$$
              (See, Loney, Plane Trigonometry, Page 187, Ex 29).



              Applying this to the triangle $CC_1C_2$, we have
              $$ 25(5-r)^2 = 5(2(r+2)^2 + 3(r+3)^2) - 150$$
              from which we get $r = 30/19$.






              share|cite|improve this answer









              $endgroup$
















                2












                2








                2





                $begingroup$

                Let $C_1, C_2$ be the centers of the circles $S_1, S_2$ and $C$ the center of the circle $S$. If the circle with center $O$ and radius $r$ touches the circles $S_1, S_2$ externally and $S$ internally, then we have $C_1C_2 = 5$, $OC_1 = r+2$, $OC_2=r+3$, $OC=5-r$. If in the triangle $ABC$, the point $D$ is on $BC$ such that $BD:DC = m:n$, then it is not difficult to show that
                $$ (m+n)^2 AD^2 = (m+n)(m AC^2 + n AB^2) - mn BC^2$$
                (See, Loney, Plane Trigonometry, Page 187, Ex 29).



                Applying this to the triangle $CC_1C_2$, we have
                $$ 25(5-r)^2 = 5(2(r+2)^2 + 3(r+3)^2) - 150$$
                from which we get $r = 30/19$.






                share|cite|improve this answer









                $endgroup$



                Let $C_1, C_2$ be the centers of the circles $S_1, S_2$ and $C$ the center of the circle $S$. If the circle with center $O$ and radius $r$ touches the circles $S_1, S_2$ externally and $S$ internally, then we have $C_1C_2 = 5$, $OC_1 = r+2$, $OC_2=r+3$, $OC=5-r$. If in the triangle $ABC$, the point $D$ is on $BC$ such that $BD:DC = m:n$, then it is not difficult to show that
                $$ (m+n)^2 AD^2 = (m+n)(m AC^2 + n AB^2) - mn BC^2$$
                (See, Loney, Plane Trigonometry, Page 187, Ex 29).



                Applying this to the triangle $CC_1C_2$, we have
                $$ 25(5-r)^2 = 5(2(r+2)^2 + 3(r+3)^2) - 150$$
                from which we get $r = 30/19$.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Dec 26 '18 at 5:18









                MuralidharanMuralidharan

                43526




                43526















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