When the set of correlated equilibria is a singleton?
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Is there any case where I can say that the set of correlated equilibria is a singleton? I know the set of correlated equilibria includes the set of Nash equilibria, but in which cases they coincide? Is it true that if there is only one Nash equilibrium then there is only one correlated equilibrium?
game-theory
asked Jan 15 at 10:27
GiacomoGiacomo
12
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$begingroup$
Is there any case where I can say that the set of correlated equilibria is a singleton? I know the set of correlated equilibria includes the set of Nash equilibria, but in which cases they coincide? Is it true that if there is only one Nash equilibrium then there is only one correlated equilibrium?
game-theory
asked Jan 15 at 10:27
GiacomoGiacomo
12
$endgroup$
add a comment |
$begingroup$
Is there any case where I can say that the set of correlated equilibria is a singleton? I know the set of correlated equilibria includes the set of Nash equilibria, but in which cases they coincide? Is it true that if there is only one Nash equilibrium then there is only one correlated equilibrium?
game-theory
asked Jan 15 at 10:27
GiacomoGiacomo
12
$endgroup$
Is there any case where I can say that the set of correlated equilibria is a singleton? I know the set of correlated equilibria includes the set of Nash equilibria, but in which cases they coincide? Is it true that if there is only one Nash equilibrium then there is only one correlated equilibrium?
game-theory
game-theory
asked Jan 15 at 10:27
GiacomoGiacomo
12
asked Jan 15 at 10:27
GiacomoGiacomo
12
asked Jan 15 at 10:27
GiacomoGiacomo
12
asked Jan 15 at 10:27
GiacomoGiacomo
12
asked Jan 15 at 10:27
GiacomoGiacomo
12
12
add a comment |
add a comment |
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