How do I read line by line in a file using while loop, and in each iteration, grep each line to compare to a...
up vote
2
down vote
favorite
I have a file called abc.txt with the contents as follows:
1: It is a shell script
2: There are few lines in this file
3: I am good with programming in C, but beginner in shell
4: We are going towards end of file
5: END OF FILE
I want to read each of the file iteratively, and in each iteration I want to compare the line with "I am good with programming in C, but beginner in shell", and then do some processing.
Any help would be greatly appreciated. Thanks!
command-line grep
add a comment |
up vote
2
down vote
favorite
I have a file called abc.txt with the contents as follows:
1: It is a shell script
2: There are few lines in this file
3: I am good with programming in C, but beginner in shell
4: We are going towards end of file
5: END OF FILE
I want to read each of the file iteratively, and in each iteration I want to compare the line with "I am good with programming in C, but beginner in shell", and then do some processing.
Any help would be greatly appreciated. Thanks!
command-line grep
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I have a file called abc.txt with the contents as follows:
1: It is a shell script
2: There are few lines in this file
3: I am good with programming in C, but beginner in shell
4: We are going towards end of file
5: END OF FILE
I want to read each of the file iteratively, and in each iteration I want to compare the line with "I am good with programming in C, but beginner in shell", and then do some processing.
Any help would be greatly appreciated. Thanks!
command-line grep
I have a file called abc.txt with the contents as follows:
1: It is a shell script
2: There are few lines in this file
3: I am good with programming in C, but beginner in shell
4: We are going towards end of file
5: END OF FILE
I want to read each of the file iteratively, and in each iteration I want to compare the line with "I am good with programming in C, but beginner in shell", and then do some processing.
Any help would be greatly appreciated. Thanks!
command-line grep
command-line grep
asked Dec 4 at 17:32
ShellyBelly
656
656
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
7
down vote
Using a shell loop is unnecessary, as grep
already iterates over lines:
grep '^[0-9]: I am good with programming in C, but beginner in shell' input.txt
If there's a matching line, it will be printed. [0-9]
defines range of characters that will be matched. We can also extend that to longer numbers [0-9]*:
(and I think with perl regex -P
option that could be done as [0-9]+:
).
If a shell loop is really necessary, we can use case
statement for pattern matching
while IFS= read -r line; do
case $line in
*": I am good with programming in C") echo "Matched: $line";;
esac
done < input.xt
^[0-9]:
isn't needed at all either, it seems.
– Michael Hampton
Dec 5 at 3:01
@MichaelHampton To be fair, yes, in this case not needed at all - user can get away with just.*I am good with programming in C
or just pick a unique word from that sentence. Or evengrep 'C.*shell'
. There's no and statement in grep, but we could get away withgrep 'shell' | grep 'C'
. Of course, everything depends on user's input data to construct a proper regex pattern.
– Sergiy Kolodyazhnyy
Dec 5 at 4:48
@SergiyKolodyazhnyy, See this question, this is exactly what I need. Please help! askubuntu.com/questions/1098503/…
– ShellyBelly
Dec 5 at 20:35
add a comment |
up vote
7
down vote
Try this sample code to help identify and modify to suit your needs:
#!/usr/bin/env bash
set -e
set -x
while read -r linenum line
do
if [ "$line" = "I am good with programming in C, but beginner in shell" ]
then
# Process things here
echo "same"
fi
done < "$1"
Usage:
Make executable:
chmod +x script.sh
Place script in any folder then run script by passing a file to it:
./script.sh /path/to/data.txt
Info:
-r
: Option passed to read command prevents backslash escapes from being interpreted.
set -e
: Bash option to stop script on first error.
set -x
: Bash option used to debug the scrtip.
"$1"
: The file variable passed to the script in this casedata.txt
linenum
: variable that holds the line numbers when bash splits the read lines into two variables while the other is passed in via thelin
variable.
1
@George So you're using-d" "
to split on whitespace and cut all lines starting from the second one. I'd suggest another way:while IFS= read -r linenum line
. The shell will perform wordsplitting on the input line and place first item ( line numbers ) intolinenum
variable, but all other things will go intoline
variable. Aside from other things,case
statement can be used as alternative to[[
comparison.
– Sergiy Kolodyazhnyy
Dec 4 at 18:44
Can I implement this script in #!/bin/sh ?
– ShellyBelly
Dec 4 at 18:49
@AkshayNandi Yes, but you need to change[[
to[
because[[
is specific tobash
. See my answer for portable solution
– Sergiy Kolodyazhnyy
Dec 4 at 18:52
@SergiyKolodyazhnyy I tried that it didn't do so on the word splitting.
– George Udosen
Dec 4 at 19:36
1
@GeorgeUdosen Ah, yes, I found the issue - it's because ofIFS=
. It unsets the variable temporarily, which is what is used for word splitting.IFS
defaults to whitespace,tab,and newline. And it's a habit, but also for a good reason, to unset it - if there's a leading whitespace ( line starts with space ) it would be gone withoutIFS=
– Sergiy Kolodyazhnyy
Dec 5 at 0:07
|
show 2 more comments
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
7
down vote
Using a shell loop is unnecessary, as grep
already iterates over lines:
grep '^[0-9]: I am good with programming in C, but beginner in shell' input.txt
If there's a matching line, it will be printed. [0-9]
defines range of characters that will be matched. We can also extend that to longer numbers [0-9]*:
(and I think with perl regex -P
option that could be done as [0-9]+:
).
If a shell loop is really necessary, we can use case
statement for pattern matching
while IFS= read -r line; do
case $line in
*": I am good with programming in C") echo "Matched: $line";;
esac
done < input.xt
^[0-9]:
isn't needed at all either, it seems.
– Michael Hampton
Dec 5 at 3:01
@MichaelHampton To be fair, yes, in this case not needed at all - user can get away with just.*I am good with programming in C
or just pick a unique word from that sentence. Or evengrep 'C.*shell'
. There's no and statement in grep, but we could get away withgrep 'shell' | grep 'C'
. Of course, everything depends on user's input data to construct a proper regex pattern.
– Sergiy Kolodyazhnyy
Dec 5 at 4:48
@SergiyKolodyazhnyy, See this question, this is exactly what I need. Please help! askubuntu.com/questions/1098503/…
– ShellyBelly
Dec 5 at 20:35
add a comment |
up vote
7
down vote
Using a shell loop is unnecessary, as grep
already iterates over lines:
grep '^[0-9]: I am good with programming in C, but beginner in shell' input.txt
If there's a matching line, it will be printed. [0-9]
defines range of characters that will be matched. We can also extend that to longer numbers [0-9]*:
(and I think with perl regex -P
option that could be done as [0-9]+:
).
If a shell loop is really necessary, we can use case
statement for pattern matching
while IFS= read -r line; do
case $line in
*": I am good with programming in C") echo "Matched: $line";;
esac
done < input.xt
^[0-9]:
isn't needed at all either, it seems.
– Michael Hampton
Dec 5 at 3:01
@MichaelHampton To be fair, yes, in this case not needed at all - user can get away with just.*I am good with programming in C
or just pick a unique word from that sentence. Or evengrep 'C.*shell'
. There's no and statement in grep, but we could get away withgrep 'shell' | grep 'C'
. Of course, everything depends on user's input data to construct a proper regex pattern.
– Sergiy Kolodyazhnyy
Dec 5 at 4:48
@SergiyKolodyazhnyy, See this question, this is exactly what I need. Please help! askubuntu.com/questions/1098503/…
– ShellyBelly
Dec 5 at 20:35
add a comment |
up vote
7
down vote
up vote
7
down vote
Using a shell loop is unnecessary, as grep
already iterates over lines:
grep '^[0-9]: I am good with programming in C, but beginner in shell' input.txt
If there's a matching line, it will be printed. [0-9]
defines range of characters that will be matched. We can also extend that to longer numbers [0-9]*:
(and I think with perl regex -P
option that could be done as [0-9]+:
).
If a shell loop is really necessary, we can use case
statement for pattern matching
while IFS= read -r line; do
case $line in
*": I am good with programming in C") echo "Matched: $line";;
esac
done < input.xt
Using a shell loop is unnecessary, as grep
already iterates over lines:
grep '^[0-9]: I am good with programming in C, but beginner in shell' input.txt
If there's a matching line, it will be printed. [0-9]
defines range of characters that will be matched. We can also extend that to longer numbers [0-9]*:
(and I think with perl regex -P
option that could be done as [0-9]+:
).
If a shell loop is really necessary, we can use case
statement for pattern matching
while IFS= read -r line; do
case $line in
*": I am good with programming in C") echo "Matched: $line";;
esac
done < input.xt
edited Dec 4 at 19:21
dessert
21.7k55896
21.7k55896
answered Dec 4 at 18:52
Sergiy Kolodyazhnyy
68.9k9143303
68.9k9143303
^[0-9]:
isn't needed at all either, it seems.
– Michael Hampton
Dec 5 at 3:01
@MichaelHampton To be fair, yes, in this case not needed at all - user can get away with just.*I am good with programming in C
or just pick a unique word from that sentence. Or evengrep 'C.*shell'
. There's no and statement in grep, but we could get away withgrep 'shell' | grep 'C'
. Of course, everything depends on user's input data to construct a proper regex pattern.
– Sergiy Kolodyazhnyy
Dec 5 at 4:48
@SergiyKolodyazhnyy, See this question, this is exactly what I need. Please help! askubuntu.com/questions/1098503/…
– ShellyBelly
Dec 5 at 20:35
add a comment |
^[0-9]:
isn't needed at all either, it seems.
– Michael Hampton
Dec 5 at 3:01
@MichaelHampton To be fair, yes, in this case not needed at all - user can get away with just.*I am good with programming in C
or just pick a unique word from that sentence. Or evengrep 'C.*shell'
. There's no and statement in grep, but we could get away withgrep 'shell' | grep 'C'
. Of course, everything depends on user's input data to construct a proper regex pattern.
– Sergiy Kolodyazhnyy
Dec 5 at 4:48
@SergiyKolodyazhnyy, See this question, this is exactly what I need. Please help! askubuntu.com/questions/1098503/…
– ShellyBelly
Dec 5 at 20:35
^[0-9]:
isn't needed at all either, it seems.– Michael Hampton
Dec 5 at 3:01
^[0-9]:
isn't needed at all either, it seems.– Michael Hampton
Dec 5 at 3:01
@MichaelHampton To be fair, yes, in this case not needed at all - user can get away with just
.*I am good with programming in C
or just pick a unique word from that sentence. Or even grep 'C.*shell'
. There's no and statement in grep, but we could get away with grep 'shell' | grep 'C'
. Of course, everything depends on user's input data to construct a proper regex pattern.– Sergiy Kolodyazhnyy
Dec 5 at 4:48
@MichaelHampton To be fair, yes, in this case not needed at all - user can get away with just
.*I am good with programming in C
or just pick a unique word from that sentence. Or even grep 'C.*shell'
. There's no and statement in grep, but we could get away with grep 'shell' | grep 'C'
. Of course, everything depends on user's input data to construct a proper regex pattern.– Sergiy Kolodyazhnyy
Dec 5 at 4:48
@SergiyKolodyazhnyy, See this question, this is exactly what I need. Please help! askubuntu.com/questions/1098503/…
– ShellyBelly
Dec 5 at 20:35
@SergiyKolodyazhnyy, See this question, this is exactly what I need. Please help! askubuntu.com/questions/1098503/…
– ShellyBelly
Dec 5 at 20:35
add a comment |
up vote
7
down vote
Try this sample code to help identify and modify to suit your needs:
#!/usr/bin/env bash
set -e
set -x
while read -r linenum line
do
if [ "$line" = "I am good with programming in C, but beginner in shell" ]
then
# Process things here
echo "same"
fi
done < "$1"
Usage:
Make executable:
chmod +x script.sh
Place script in any folder then run script by passing a file to it:
./script.sh /path/to/data.txt
Info:
-r
: Option passed to read command prevents backslash escapes from being interpreted.
set -e
: Bash option to stop script on first error.
set -x
: Bash option used to debug the scrtip.
"$1"
: The file variable passed to the script in this casedata.txt
linenum
: variable that holds the line numbers when bash splits the read lines into two variables while the other is passed in via thelin
variable.
1
@George So you're using-d" "
to split on whitespace and cut all lines starting from the second one. I'd suggest another way:while IFS= read -r linenum line
. The shell will perform wordsplitting on the input line and place first item ( line numbers ) intolinenum
variable, but all other things will go intoline
variable. Aside from other things,case
statement can be used as alternative to[[
comparison.
– Sergiy Kolodyazhnyy
Dec 4 at 18:44
Can I implement this script in #!/bin/sh ?
– ShellyBelly
Dec 4 at 18:49
@AkshayNandi Yes, but you need to change[[
to[
because[[
is specific tobash
. See my answer for portable solution
– Sergiy Kolodyazhnyy
Dec 4 at 18:52
@SergiyKolodyazhnyy I tried that it didn't do so on the word splitting.
– George Udosen
Dec 4 at 19:36
1
@GeorgeUdosen Ah, yes, I found the issue - it's because ofIFS=
. It unsets the variable temporarily, which is what is used for word splitting.IFS
defaults to whitespace,tab,and newline. And it's a habit, but also for a good reason, to unset it - if there's a leading whitespace ( line starts with space ) it would be gone withoutIFS=
– Sergiy Kolodyazhnyy
Dec 5 at 0:07
|
show 2 more comments
up vote
7
down vote
Try this sample code to help identify and modify to suit your needs:
#!/usr/bin/env bash
set -e
set -x
while read -r linenum line
do
if [ "$line" = "I am good with programming in C, but beginner in shell" ]
then
# Process things here
echo "same"
fi
done < "$1"
Usage:
Make executable:
chmod +x script.sh
Place script in any folder then run script by passing a file to it:
./script.sh /path/to/data.txt
Info:
-r
: Option passed to read command prevents backslash escapes from being interpreted.
set -e
: Bash option to stop script on first error.
set -x
: Bash option used to debug the scrtip.
"$1"
: The file variable passed to the script in this casedata.txt
linenum
: variable that holds the line numbers when bash splits the read lines into two variables while the other is passed in via thelin
variable.
1
@George So you're using-d" "
to split on whitespace and cut all lines starting from the second one. I'd suggest another way:while IFS= read -r linenum line
. The shell will perform wordsplitting on the input line and place first item ( line numbers ) intolinenum
variable, but all other things will go intoline
variable. Aside from other things,case
statement can be used as alternative to[[
comparison.
– Sergiy Kolodyazhnyy
Dec 4 at 18:44
Can I implement this script in #!/bin/sh ?
– ShellyBelly
Dec 4 at 18:49
@AkshayNandi Yes, but you need to change[[
to[
because[[
is specific tobash
. See my answer for portable solution
– Sergiy Kolodyazhnyy
Dec 4 at 18:52
@SergiyKolodyazhnyy I tried that it didn't do so on the word splitting.
– George Udosen
Dec 4 at 19:36
1
@GeorgeUdosen Ah, yes, I found the issue - it's because ofIFS=
. It unsets the variable temporarily, which is what is used for word splitting.IFS
defaults to whitespace,tab,and newline. And it's a habit, but also for a good reason, to unset it - if there's a leading whitespace ( line starts with space ) it would be gone withoutIFS=
– Sergiy Kolodyazhnyy
Dec 5 at 0:07
|
show 2 more comments
up vote
7
down vote
up vote
7
down vote
Try this sample code to help identify and modify to suit your needs:
#!/usr/bin/env bash
set -e
set -x
while read -r linenum line
do
if [ "$line" = "I am good with programming in C, but beginner in shell" ]
then
# Process things here
echo "same"
fi
done < "$1"
Usage:
Make executable:
chmod +x script.sh
Place script in any folder then run script by passing a file to it:
./script.sh /path/to/data.txt
Info:
-r
: Option passed to read command prevents backslash escapes from being interpreted.
set -e
: Bash option to stop script on first error.
set -x
: Bash option used to debug the scrtip.
"$1"
: The file variable passed to the script in this casedata.txt
linenum
: variable that holds the line numbers when bash splits the read lines into two variables while the other is passed in via thelin
variable.
Try this sample code to help identify and modify to suit your needs:
#!/usr/bin/env bash
set -e
set -x
while read -r linenum line
do
if [ "$line" = "I am good with programming in C, but beginner in shell" ]
then
# Process things here
echo "same"
fi
done < "$1"
Usage:
Make executable:
chmod +x script.sh
Place script in any folder then run script by passing a file to it:
./script.sh /path/to/data.txt
Info:
-r
: Option passed to read command prevents backslash escapes from being interpreted.
set -e
: Bash option to stop script on first error.
set -x
: Bash option used to debug the scrtip.
"$1"
: The file variable passed to the script in this casedata.txt
linenum
: variable that holds the line numbers when bash splits the read lines into two variables while the other is passed in via thelin
variable.
edited Dec 5 at 7:42
answered Dec 4 at 18:03
George Udosen
19.1k94266
19.1k94266
1
@George So you're using-d" "
to split on whitespace and cut all lines starting from the second one. I'd suggest another way:while IFS= read -r linenum line
. The shell will perform wordsplitting on the input line and place first item ( line numbers ) intolinenum
variable, but all other things will go intoline
variable. Aside from other things,case
statement can be used as alternative to[[
comparison.
– Sergiy Kolodyazhnyy
Dec 4 at 18:44
Can I implement this script in #!/bin/sh ?
– ShellyBelly
Dec 4 at 18:49
@AkshayNandi Yes, but you need to change[[
to[
because[[
is specific tobash
. See my answer for portable solution
– Sergiy Kolodyazhnyy
Dec 4 at 18:52
@SergiyKolodyazhnyy I tried that it didn't do so on the word splitting.
– George Udosen
Dec 4 at 19:36
1
@GeorgeUdosen Ah, yes, I found the issue - it's because ofIFS=
. It unsets the variable temporarily, which is what is used for word splitting.IFS
defaults to whitespace,tab,and newline. And it's a habit, but also for a good reason, to unset it - if there's a leading whitespace ( line starts with space ) it would be gone withoutIFS=
– Sergiy Kolodyazhnyy
Dec 5 at 0:07
|
show 2 more comments
1
@George So you're using-d" "
to split on whitespace and cut all lines starting from the second one. I'd suggest another way:while IFS= read -r linenum line
. The shell will perform wordsplitting on the input line and place first item ( line numbers ) intolinenum
variable, but all other things will go intoline
variable. Aside from other things,case
statement can be used as alternative to[[
comparison.
– Sergiy Kolodyazhnyy
Dec 4 at 18:44
Can I implement this script in #!/bin/sh ?
– ShellyBelly
Dec 4 at 18:49
@AkshayNandi Yes, but you need to change[[
to[
because[[
is specific tobash
. See my answer for portable solution
– Sergiy Kolodyazhnyy
Dec 4 at 18:52
@SergiyKolodyazhnyy I tried that it didn't do so on the word splitting.
– George Udosen
Dec 4 at 19:36
1
@GeorgeUdosen Ah, yes, I found the issue - it's because ofIFS=
. It unsets the variable temporarily, which is what is used for word splitting.IFS
defaults to whitespace,tab,and newline. And it's a habit, but also for a good reason, to unset it - if there's a leading whitespace ( line starts with space ) it would be gone withoutIFS=
– Sergiy Kolodyazhnyy
Dec 5 at 0:07
1
1
@George So you're using
-d" "
to split on whitespace and cut all lines starting from the second one. I'd suggest another way: while IFS= read -r linenum line
. The shell will perform wordsplitting on the input line and place first item ( line numbers ) into linenum
variable, but all other things will go into line
variable. Aside from other things, case
statement can be used as alternative to [[
comparison.– Sergiy Kolodyazhnyy
Dec 4 at 18:44
@George So you're using
-d" "
to split on whitespace and cut all lines starting from the second one. I'd suggest another way: while IFS= read -r linenum line
. The shell will perform wordsplitting on the input line and place first item ( line numbers ) into linenum
variable, but all other things will go into line
variable. Aside from other things, case
statement can be used as alternative to [[
comparison.– Sergiy Kolodyazhnyy
Dec 4 at 18:44
Can I implement this script in #!/bin/sh ?
– ShellyBelly
Dec 4 at 18:49
Can I implement this script in #!/bin/sh ?
– ShellyBelly
Dec 4 at 18:49
@AkshayNandi Yes, but you need to change
[[
to [
because [[
is specific to bash
. See my answer for portable solution– Sergiy Kolodyazhnyy
Dec 4 at 18:52
@AkshayNandi Yes, but you need to change
[[
to [
because [[
is specific to bash
. See my answer for portable solution– Sergiy Kolodyazhnyy
Dec 4 at 18:52
@SergiyKolodyazhnyy I tried that it didn't do so on the word splitting.
– George Udosen
Dec 4 at 19:36
@SergiyKolodyazhnyy I tried that it didn't do so on the word splitting.
– George Udosen
Dec 4 at 19:36
1
1
@GeorgeUdosen Ah, yes, I found the issue - it's because of
IFS=
. It unsets the variable temporarily, which is what is used for word splitting. IFS
defaults to whitespace,tab,and newline. And it's a habit, but also for a good reason, to unset it - if there's a leading whitespace ( line starts with space ) it would be gone without IFS=
– Sergiy Kolodyazhnyy
Dec 5 at 0:07
@GeorgeUdosen Ah, yes, I found the issue - it's because of
IFS=
. It unsets the variable temporarily, which is what is used for word splitting. IFS
defaults to whitespace,tab,and newline. And it's a habit, but also for a good reason, to unset it - if there's a leading whitespace ( line starts with space ) it would be gone without IFS=
– Sergiy Kolodyazhnyy
Dec 5 at 0:07
|
show 2 more comments
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