Is it correct to think of a negative number as a way of showing that you have a deficit in something?
$begingroup$
Is it correct to think of a negative number as a way of showing that you have a deficit in something? For example,
Let $x$ be a real number such that $x=25$.
Let $y$ be a real number such that $y=27$.
Consider this equality:
$$x-(-2)=y$$
The way I think of it is that $x$ is $y$ with a deficit of $2$ and in order for it to equal $y$ we need to remove that deficit and that's why:
$$ -(-2)=+2$$
It's like we have a deficit in something and we want to remove it by substracting it (the deficit).
Is my intuition correct?
arithmetic real-numbers
edited Dec 15 '18 at 10:27
Blue
47.8k870152
asked Dec 15 '18 at 6:17
Ashraf BenmebarekAshraf Benmebarek
485
$endgroup$
add a comment |
$begingroup$
Is it correct to think of a negative number as a way of showing that you have a deficit in something? For example,
Let $x$ be a real number such that $x=25$.
Let $y$ be a real number such that $y=27$.
Consider this equality:
$$x-(-2)=y$$
The way I think of it is that $x$ is $y$ with a deficit of $2$ and in order for it to equal $y$ we need to remove that deficit and that's why:
$$ -(-2)=+2$$
It's like we have a deficit in something and we want to remove it by substracting it (the deficit).
Is my intuition correct?
arithmetic real-numbers
edited Dec 15 '18 at 10:27
Blue
47.8k870152
asked Dec 15 '18 at 6:17
Ashraf BenmebarekAshraf Benmebarek
485
$endgroup$
add a comment |
$begingroup$
Is it correct to think of a negative number as a way of showing that you have a deficit in something? For example,
Let $x$ be a real number such that $x=25$.
Let $y$ be a real number such that $y=27$.
Consider this equality:
$$x-(-2)=y$$
The way I think of it is that $x$ is $y$ with a deficit of $2$ and in order for it to equal $y$ we need to remove that deficit and that's why:
$$ -(-2)=+2$$
It's like we have a deficit in something and we want to remove it by substracting it (the deficit).
Is my intuition correct?
arithmetic real-numbers
edited Dec 15 '18 at 10:27
Blue
47.8k870152
asked Dec 15 '18 at 6:17
Ashraf BenmebarekAshraf Benmebarek
485
$endgroup$
Is it correct to think of a negative number as a way of showing that you have a deficit in something? For example,
Let $x$ be a real number such that $x=25$.
Let $y$ be a real number such that $y=27$.
Consider this equality:
$$x-(-2)=y$$
The way I think of it is that $x$ is $y$ with a deficit of $2$ and in order for it to equal $y$ we need to remove that deficit and that's why:
$$ -(-2)=+2$$
It's like we have a deficit in something and we want to remove it by substracting it (the deficit).
Is my intuition correct?
arithmetic real-numbers
arithmetic real-numbers
edited Dec 15 '18 at 10:27
Blue
47.8k870152
asked Dec 15 '18 at 6:17
Ashraf BenmebarekAshraf Benmebarek
485
edited Dec 15 '18 at 10:27
Blue
47.8k870152
asked Dec 15 '18 at 6:17
Ashraf BenmebarekAshraf Benmebarek
485
edited Dec 15 '18 at 10:27
Blue
47.8k870152
edited Dec 15 '18 at 10:27
Blue
47.8k870152
edited Dec 15 '18 at 10:27
Blue
47.8k870152
47.8k870152
asked Dec 15 '18 at 6:17
Ashraf BenmebarekAshraf Benmebarek
485
asked Dec 15 '18 at 6:17
Ashraf BenmebarekAshraf Benmebarek
485
asked Dec 15 '18 at 6:17
Ashraf BenmebarekAshraf Benmebarek
485
485
add a comment |
add a comment |
1 Answer
1
active
oldest
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$begingroup$
From the perspective of Group Theory, a negative number is simply an (the) "additive inverse" of a "positive" number. Note: This is more or less an over-simplification, because in $mathbb{R}$ (the set of all real numbers) we have an order relation $le$, and things can get more complicated.
Let $(G,+)$ be a group (If you don't know what a group is, just think of it as a very simple algebraic structure that allows you to perform cancellation). One of the group axioms says that given any element $g$ in $G$, you can find some $tilde{g}$ satisfying
$$g+tilde{g}=tilde{g}+g=0.$$
Then you may ask what $0$ actually is. Again I am not going too deep, so it would be better to treat it as the ordinary $0$ so that the value of any number is unchanged after adding $0$.
Then $tilde{g}$ is called an (the) inverse of $g$. We give it a notation $-g$. Another note that is perhaps hard for you. When you denote something (by using a notation), you have to make sure that it is unique (so you cannot have something like $tilde{g}=2$ and $tilde{g}=3$ simultaneously), and the article "the" has an implicit meaning of uniqueness.
Hence, what is $-2$? $-2$ is just the additive inverse of $2$. So if you have a $2$, after adding $-2$, you get back $0$. This is just something like a deficit of something: suppose you have $2$ apples, and after you have a deficit of $2$ apples, you have no apple left. Alternatively, if your friend got $2$ apples from you, then you have a deficit of $2$ apples. Hence if I add back $2$ apples to you, you have no deficit.
answered Dec 15 '18 at 9:39
tonychow0929tonychow0929
29825
$endgroup$
$begingroup$
Isn't there a real-world example that shows why -(-2)=2 ?
$endgroup$
– Ashraf Benmebarek
Dec 28 '18 at 15:41
add a comment |
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$begingroup$
From the perspective of Group Theory, a negative number is simply an (the) "additive inverse" of a "positive" number. Note: This is more or less an over-simplification, because in $mathbb{R}$ (the set of all real numbers) we have an order relation $le$, and things can get more complicated.
Let $(G,+)$ be a group (If you don't know what a group is, just think of it as a very simple algebraic structure that allows you to perform cancellation). One of the group axioms says that given any element $g$ in $G$, you can find some $tilde{g}$ satisfying
$$g+tilde{g}=tilde{g}+g=0.$$
Then you may ask what $0$ actually is. Again I am not going too deep, so it would be better to treat it as the ordinary $0$ so that the value of any number is unchanged after adding $0$.
Then $tilde{g}$ is called an (the) inverse of $g$. We give it a notation $-g$. Another note that is perhaps hard for you. When you denote something (by using a notation), you have to make sure that it is unique (so you cannot have something like $tilde{g}=2$ and $tilde{g}=3$ simultaneously), and the article "the" has an implicit meaning of uniqueness.
Hence, what is $-2$? $-2$ is just the additive inverse of $2$. So if you have a $2$, after adding $-2$, you get back $0$. This is just something like a deficit of something: suppose you have $2$ apples, and after you have a deficit of $2$ apples, you have no apple left. Alternatively, if your friend got $2$ apples from you, then you have a deficit of $2$ apples. Hence if I add back $2$ apples to you, you have no deficit.
answered Dec 15 '18 at 9:39
tonychow0929tonychow0929
29825
$endgroup$
$begingroup$
Isn't there a real-world example that shows why -(-2)=2 ?
$endgroup$
– Ashraf Benmebarek
Dec 28 '18 at 15:41
add a comment |
$begingroup$
From the perspective of Group Theory, a negative number is simply an (the) "additive inverse" of a "positive" number. Note: This is more or less an over-simplification, because in $mathbb{R}$ (the set of all real numbers) we have an order relation $le$, and things can get more complicated.
Let $(G,+)$ be a group (If you don't know what a group is, just think of it as a very simple algebraic structure that allows you to perform cancellation). One of the group axioms says that given any element $g$ in $G$, you can find some $tilde{g}$ satisfying
$$g+tilde{g}=tilde{g}+g=0.$$
Then you may ask what $0$ actually is. Again I am not going too deep, so it would be better to treat it as the ordinary $0$ so that the value of any number is unchanged after adding $0$.
Then $tilde{g}$ is called an (the) inverse of $g$. We give it a notation $-g$. Another note that is perhaps hard for you. When you denote something (by using a notation), you have to make sure that it is unique (so you cannot have something like $tilde{g}=2$ and $tilde{g}=3$ simultaneously), and the article "the" has an implicit meaning of uniqueness.
Hence, what is $-2$? $-2$ is just the additive inverse of $2$. So if you have a $2$, after adding $-2$, you get back $0$. This is just something like a deficit of something: suppose you have $2$ apples, and after you have a deficit of $2$ apples, you have no apple left. Alternatively, if your friend got $2$ apples from you, then you have a deficit of $2$ apples. Hence if I add back $2$ apples to you, you have no deficit.
answered Dec 15 '18 at 9:39
tonychow0929tonychow0929
29825
$endgroup$
$begingroup$
Isn't there a real-world example that shows why -(-2)=2 ?
$endgroup$
– Ashraf Benmebarek
Dec 28 '18 at 15:41
add a comment |
$begingroup$
From the perspective of Group Theory, a negative number is simply an (the) "additive inverse" of a "positive" number. Note: This is more or less an over-simplification, because in $mathbb{R}$ (the set of all real numbers) we have an order relation $le$, and things can get more complicated.
Let $(G,+)$ be a group (If you don't know what a group is, just think of it as a very simple algebraic structure that allows you to perform cancellation). One of the group axioms says that given any element $g$ in $G$, you can find some $tilde{g}$ satisfying
$$g+tilde{g}=tilde{g}+g=0.$$
Then you may ask what $0$ actually is. Again I am not going too deep, so it would be better to treat it as the ordinary $0$ so that the value of any number is unchanged after adding $0$.
Then $tilde{g}$ is called an (the) inverse of $g$. We give it a notation $-g$. Another note that is perhaps hard for you. When you denote something (by using a notation), you have to make sure that it is unique (so you cannot have something like $tilde{g}=2$ and $tilde{g}=3$ simultaneously), and the article "the" has an implicit meaning of uniqueness.
Hence, what is $-2$? $-2$ is just the additive inverse of $2$. So if you have a $2$, after adding $-2$, you get back $0$. This is just something like a deficit of something: suppose you have $2$ apples, and after you have a deficit of $2$ apples, you have no apple left. Alternatively, if your friend got $2$ apples from you, then you have a deficit of $2$ apples. Hence if I add back $2$ apples to you, you have no deficit.
answered Dec 15 '18 at 9:39
tonychow0929tonychow0929
29825
$endgroup$
From the perspective of Group Theory, a negative number is simply an (the) "additive inverse" of a "positive" number. Note: This is more or less an over-simplification, because in $mathbb{R}$ (the set of all real numbers) we have an order relation $le$, and things can get more complicated.
Let $(G,+)$ be a group (If you don't know what a group is, just think of it as a very simple algebraic structure that allows you to perform cancellation). One of the group axioms says that given any element $g$ in $G$, you can find some $tilde{g}$ satisfying
$$g+tilde{g}=tilde{g}+g=0.$$
Then you may ask what $0$ actually is. Again I am not going too deep, so it would be better to treat it as the ordinary $0$ so that the value of any number is unchanged after adding $0$.
Then $tilde{g}$ is called an (the) inverse of $g$. We give it a notation $-g$. Another note that is perhaps hard for you. When you denote something (by using a notation), you have to make sure that it is unique (so you cannot have something like $tilde{g}=2$ and $tilde{g}=3$ simultaneously), and the article "the" has an implicit meaning of uniqueness.
Hence, what is $-2$? $-2$ is just the additive inverse of $2$. So if you have a $2$, after adding $-2$, you get back $0$. This is just something like a deficit of something: suppose you have $2$ apples, and after you have a deficit of $2$ apples, you have no apple left. Alternatively, if your friend got $2$ apples from you, then you have a deficit of $2$ apples. Hence if I add back $2$ apples to you, you have no deficit.
answered Dec 15 '18 at 9:39
tonychow0929tonychow0929
29825
edited Dec 15 '18 at 9:47
answered Dec 15 '18 at 9:39
tonychow0929tonychow0929
29825
answered Dec 15 '18 at 9:39
tonychow0929tonychow0929
29825
answered Dec 15 '18 at 9:39
tonychow0929tonychow0929
29825
29825
$begingroup$
Isn't there a real-world example that shows why -(-2)=2 ?
$endgroup$
– Ashraf Benmebarek
Dec 28 '18 at 15:41
add a comment |
$begingroup$
Isn't there a real-world example that shows why -(-2)=2 ?
$endgroup$
– Ashraf Benmebarek
Dec 28 '18 at 15:41
$begingroup$
Isn't there a real-world example that shows why -(-2)=2 ?
$endgroup$
– Ashraf Benmebarek
Dec 28 '18 at 15:41
$begingroup$
Isn't there a real-world example that shows why -(-2)=2 ?
$endgroup$
– Ashraf Benmebarek
Dec 28 '18 at 15:41
add a comment |
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