A problem in proving the orientability of projective space
0
$begingroup$
The proof I was reading is this
The problem is the determination seems to be wrong. It should be $frac{(-1)^n}{(y^n)^{n+1}}$, isn’t it? Then how is the proof valid now?
differential-geometry manifolds
asked Dec 25 '18 at 6:20
user150248user150248
34419
$endgroup$
add a comment |
0
$begingroup$
The proof I was reading is this
The problem is the determination seems to be wrong. It should be $frac{(-1)^n}{(y^n)^{n+1}}$, isn’t it? Then how is the proof valid now?
differential-geometry manifolds
asked Dec 25 '18 at 6:20
user150248user150248
34419
$endgroup$
$begingroup$
You're right about the sign. But what is the author assuming about $y^n$? I think it's a bit more complicated than just the passage you quoted would suggest.
$endgroup$
– Ted Shifrin
Dec 26 '18 at 0:38
add a comment |
0
0
0
$begingroup$
The proof I was reading is this
The problem is the determination seems to be wrong. It should be $frac{(-1)^n}{(y^n)^{n+1}}$, isn’t it? Then how is the proof valid now?
differential-geometry manifolds
asked Dec 25 '18 at 6:20
user150248user150248
34419
$endgroup$
The proof I was reading is this
The problem is the determination seems to be wrong. It should be $frac{(-1)^n}{(y^n)^{n+1}}$, isn’t it? Then how is the proof valid now?
differential-geometry manifolds
differential-geometry manifolds
asked Dec 25 '18 at 6:20
user150248user150248
34419
asked Dec 25 '18 at 6:20
user150248user150248
34419
asked Dec 25 '18 at 6:20
user150248user150248
34419
asked Dec 25 '18 at 6:20
user150248user150248
34419
asked Dec 25 '18 at 6:20
user150248user150248
34419
34419
$begingroup$
You're right about the sign. But what is the author assuming about $y^n$? I think it's a bit more complicated than just the passage you quoted would suggest.
$endgroup$
– Ted Shifrin
Dec 26 '18 at 0:38
add a comment |
$begingroup$
You're right about the sign. But what is the author assuming about $y^n$? I think it's a bit more complicated than just the passage you quoted would suggest.
$endgroup$
– Ted Shifrin
Dec 26 '18 at 0:38
$begingroup$
You're right about the sign. But what is the author assuming about $y^n$? I think it's a bit more complicated than just the passage you quoted would suggest.
$endgroup$
– Ted Shifrin
Dec 26 '18 at 0:38
$begingroup$
You're right about the sign. But what is the author assuming about $y^n$? I think it's a bit more complicated than just the passage you quoted would suggest.
$endgroup$
– Ted Shifrin
Dec 26 '18 at 0:38
add a comment |
0
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$begingroup$
You're right about the sign. But what is the author assuming about $y^n$? I think it's a bit more complicated than just the passage you quoted would suggest.
$endgroup$
– Ted Shifrin
Dec 26 '18 at 0:38