Linear Transformation involving polynomial and matrix
$begingroup$
Determine if its linear the transformation
$f:Re_{3} [x]rightarrow M_{2x2}$
such as
$f(ax^3+bx^2+cx+d) = begin{bmatrix}
a-c & 0 \
0&b+d
end{bmatrix}$
for any $ax^3+bx^2+cx+d in Re _{3} [x]$
Im having trouble associating the polynomial with the resulting matrix.
I know I'm supposed to check the two main Linear transformation conditions but I don't know how to aproach this example.
Here's my attempt:
Condition 1: $T(u+v)=T(u)+T(v)$
$f((ax^3+bx^2+cx+d)+(a'x^3+b'x^2+c'x+d'))=f((ax^3+a'x^3)+(bx^2+b'x^2)+(cx+c'x)+(d+d'))=f((a+a')x^3+(b+b')x^2+(c+c')x+(d+d'))=begin{bmatrix}
(a+a')-(c+c') & 0\
0 & (b+b')+(d+d')
end{bmatrix} = begin{bmatrix}
a-c & 0\
0 & b+d
end{bmatrix} + begin{bmatrix}
a'-c' & 0\
0 & b'+d'
end{bmatrix}=f(ax^3+bx^2+cx+d)+f(a'x^3+b'x^2+c'x+d')$
Is this correct?
linear-transformations
$endgroup$
add a comment |
$begingroup$
Determine if its linear the transformation
$f:Re_{3} [x]rightarrow M_{2x2}$
such as
$f(ax^3+bx^2+cx+d) = begin{bmatrix}
a-c & 0 \
0&b+d
end{bmatrix}$
for any $ax^3+bx^2+cx+d in Re _{3} [x]$
Im having trouble associating the polynomial with the resulting matrix.
I know I'm supposed to check the two main Linear transformation conditions but I don't know how to aproach this example.
Here's my attempt:
Condition 1: $T(u+v)=T(u)+T(v)$
$f((ax^3+bx^2+cx+d)+(a'x^3+b'x^2+c'x+d'))=f((ax^3+a'x^3)+(bx^2+b'x^2)+(cx+c'x)+(d+d'))=f((a+a')x^3+(b+b')x^2+(c+c')x+(d+d'))=begin{bmatrix}
(a+a')-(c+c') & 0\
0 & (b+b')+(d+d')
end{bmatrix} = begin{bmatrix}
a-c & 0\
0 & b+d
end{bmatrix} + begin{bmatrix}
a'-c' & 0\
0 & b'+d'
end{bmatrix}=f(ax^3+bx^2+cx+d)+f(a'x^3+b'x^2+c'x+d')$
Is this correct?
linear-transformations
$endgroup$
3
$begingroup$
Looks right to me.
$endgroup$
– saulspatz
Jan 5 at 18:33
3
$begingroup$
Seems fine. ${}{}{}{} $
$endgroup$
– Thomas Shelby
Jan 5 at 18:33
add a comment |
$begingroup$
Determine if its linear the transformation
$f:Re_{3} [x]rightarrow M_{2x2}$
such as
$f(ax^3+bx^2+cx+d) = begin{bmatrix}
a-c & 0 \
0&b+d
end{bmatrix}$
for any $ax^3+bx^2+cx+d in Re _{3} [x]$
Im having trouble associating the polynomial with the resulting matrix.
I know I'm supposed to check the two main Linear transformation conditions but I don't know how to aproach this example.
Here's my attempt:
Condition 1: $T(u+v)=T(u)+T(v)$
$f((ax^3+bx^2+cx+d)+(a'x^3+b'x^2+c'x+d'))=f((ax^3+a'x^3)+(bx^2+b'x^2)+(cx+c'x)+(d+d'))=f((a+a')x^3+(b+b')x^2+(c+c')x+(d+d'))=begin{bmatrix}
(a+a')-(c+c') & 0\
0 & (b+b')+(d+d')
end{bmatrix} = begin{bmatrix}
a-c & 0\
0 & b+d
end{bmatrix} + begin{bmatrix}
a'-c' & 0\
0 & b'+d'
end{bmatrix}=f(ax^3+bx^2+cx+d)+f(a'x^3+b'x^2+c'x+d')$
Is this correct?
linear-transformations
$endgroup$
Determine if its linear the transformation
$f:Re_{3} [x]rightarrow M_{2x2}$
such as
$f(ax^3+bx^2+cx+d) = begin{bmatrix}
a-c & 0 \
0&b+d
end{bmatrix}$
for any $ax^3+bx^2+cx+d in Re _{3} [x]$
Im having trouble associating the polynomial with the resulting matrix.
I know I'm supposed to check the two main Linear transformation conditions but I don't know how to aproach this example.
Here's my attempt:
Condition 1: $T(u+v)=T(u)+T(v)$
$f((ax^3+bx^2+cx+d)+(a'x^3+b'x^2+c'x+d'))=f((ax^3+a'x^3)+(bx^2+b'x^2)+(cx+c'x)+(d+d'))=f((a+a')x^3+(b+b')x^2+(c+c')x+(d+d'))=begin{bmatrix}
(a+a')-(c+c') & 0\
0 & (b+b')+(d+d')
end{bmatrix} = begin{bmatrix}
a-c & 0\
0 & b+d
end{bmatrix} + begin{bmatrix}
a'-c' & 0\
0 & b'+d'
end{bmatrix}=f(ax^3+bx^2+cx+d)+f(a'x^3+b'x^2+c'x+d')$
Is this correct?
linear-transformations
linear-transformations
asked Jan 5 at 18:29
JakcjonesJakcjones
828
828
3
$begingroup$
Looks right to me.
$endgroup$
– saulspatz
Jan 5 at 18:33
3
$begingroup$
Seems fine. ${}{}{}{} $
$endgroup$
– Thomas Shelby
Jan 5 at 18:33
add a comment |
3
$begingroup$
Looks right to me.
$endgroup$
– saulspatz
Jan 5 at 18:33
3
$begingroup$
Seems fine. ${}{}{}{} $
$endgroup$
– Thomas Shelby
Jan 5 at 18:33
3
3
$begingroup$
Looks right to me.
$endgroup$
– saulspatz
Jan 5 at 18:33
$begingroup$
Looks right to me.
$endgroup$
– saulspatz
Jan 5 at 18:33
3
3
$begingroup$
Seems fine. ${}{}{}{} $
$endgroup$
– Thomas Shelby
Jan 5 at 18:33
$begingroup$
Seems fine. ${}{}{}{} $
$endgroup$
– Thomas Shelby
Jan 5 at 18:33
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
That looks fine. Another way to go is this:
Consider the standard basis $$bigl{A_{1,1},A_{2,1},A_{1,2},A_{2,2}bigr}$$ for $M_{2times 2},$ where $A_{i,j}$ is the $2times 2$ matrix of zeroes, except the $i$th row $j$th column entry, which is $1.$ Considering also the standard basis ${x^3,x^2,x,1}$ for $mathfrak{R}_3[x],$ then the given transformation has the matrix representation $$begin{bmatrix}1 & 0 & -1 & 0\0 & 0 & 0 & 0\0 & 0 & 0 & 0\0 & 1 & 0 & 1end{bmatrix}.$$
Since it has a matrix representation, then it's a linear transformation.
$endgroup$
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
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active
oldest
votes
$begingroup$
That looks fine. Another way to go is this:
Consider the standard basis $$bigl{A_{1,1},A_{2,1},A_{1,2},A_{2,2}bigr}$$ for $M_{2times 2},$ where $A_{i,j}$ is the $2times 2$ matrix of zeroes, except the $i$th row $j$th column entry, which is $1.$ Considering also the standard basis ${x^3,x^2,x,1}$ for $mathfrak{R}_3[x],$ then the given transformation has the matrix representation $$begin{bmatrix}1 & 0 & -1 & 0\0 & 0 & 0 & 0\0 & 0 & 0 & 0\0 & 1 & 0 & 1end{bmatrix}.$$
Since it has a matrix representation, then it's a linear transformation.
$endgroup$
add a comment |
$begingroup$
That looks fine. Another way to go is this:
Consider the standard basis $$bigl{A_{1,1},A_{2,1},A_{1,2},A_{2,2}bigr}$$ for $M_{2times 2},$ where $A_{i,j}$ is the $2times 2$ matrix of zeroes, except the $i$th row $j$th column entry, which is $1.$ Considering also the standard basis ${x^3,x^2,x,1}$ for $mathfrak{R}_3[x],$ then the given transformation has the matrix representation $$begin{bmatrix}1 & 0 & -1 & 0\0 & 0 & 0 & 0\0 & 0 & 0 & 0\0 & 1 & 0 & 1end{bmatrix}.$$
Since it has a matrix representation, then it's a linear transformation.
$endgroup$
add a comment |
$begingroup$
That looks fine. Another way to go is this:
Consider the standard basis $$bigl{A_{1,1},A_{2,1},A_{1,2},A_{2,2}bigr}$$ for $M_{2times 2},$ where $A_{i,j}$ is the $2times 2$ matrix of zeroes, except the $i$th row $j$th column entry, which is $1.$ Considering also the standard basis ${x^3,x^2,x,1}$ for $mathfrak{R}_3[x],$ then the given transformation has the matrix representation $$begin{bmatrix}1 & 0 & -1 & 0\0 & 0 & 0 & 0\0 & 0 & 0 & 0\0 & 1 & 0 & 1end{bmatrix}.$$
Since it has a matrix representation, then it's a linear transformation.
$endgroup$
That looks fine. Another way to go is this:
Consider the standard basis $$bigl{A_{1,1},A_{2,1},A_{1,2},A_{2,2}bigr}$$ for $M_{2times 2},$ where $A_{i,j}$ is the $2times 2$ matrix of zeroes, except the $i$th row $j$th column entry, which is $1.$ Considering also the standard basis ${x^3,x^2,x,1}$ for $mathfrak{R}_3[x],$ then the given transformation has the matrix representation $$begin{bmatrix}1 & 0 & -1 & 0\0 & 0 & 0 & 0\0 & 0 & 0 & 0\0 & 1 & 0 & 1end{bmatrix}.$$
Since it has a matrix representation, then it's a linear transformation.
answered Jan 5 at 19:30
Cameron BuieCameron Buie
85.9k772161
85.9k772161
add a comment |
add a comment |
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3
$begingroup$
Looks right to me.
$endgroup$
– saulspatz
Jan 5 at 18:33
3
$begingroup$
Seems fine. ${}{}{}{} $
$endgroup$
– Thomas Shelby
Jan 5 at 18:33