Using the recursion theorem to implement the Sieve of Eratosthenes.












1












$begingroup$


Update: I provided an answer here that shows how to define a mathematical function using the recursion theorem. This function can be reconfigured to compute the prime-counting function, $pi(x)$.



Only one question remains:




Question 1: Has the Sieve of Eratosthenes already been mathematically
revamped as a recursive function?




I did not find the word 'recursion' in the wikipedia article Generating primes, so this theory might be useful.



When running computers to get a list of all primes numbers using recursion, the 'state variables' should be retained for the next computer run.





The initial development was the construction of a Python program that maintained/updated state variables to generate, and keep generating, the list of prime numbers. I was using concepts found in the wiki article The Sieve of Eratosthenes.










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    Why do you think, that the function in your (put-on-hold) question is recursive?
    $endgroup$
    – gammatester
    Nov 14 '18 at 12:08












  • $begingroup$
    @gammatester The python program has state variables that change which each new input. The function $tau$ needs more than one variable to run.
    $endgroup$
    – CopyPasteIt
    Nov 14 '18 at 12:13












  • $begingroup$
    You are aware that multiplication can be defined recursively, hence forbidding it makes no sense?
    $endgroup$
    – Hagen von Eitzen
    Nov 14 '18 at 12:18










  • $begingroup$
    $tau(n)=Gamma(n,2,2)$ with $$Gamma(a,b,c)=begin{cases}1&a=b\0&c=a>b\Gamma(a,b+1,b+1)&c>a>b\Gamma(a,b,b+c)&text{otherwise} end{cases}$$
    $endgroup$
    – Hagen von Eitzen
    Nov 14 '18 at 12:23
















1












$begingroup$


Update: I provided an answer here that shows how to define a mathematical function using the recursion theorem. This function can be reconfigured to compute the prime-counting function, $pi(x)$.



Only one question remains:




Question 1: Has the Sieve of Eratosthenes already been mathematically
revamped as a recursive function?




I did not find the word 'recursion' in the wikipedia article Generating primes, so this theory might be useful.



When running computers to get a list of all primes numbers using recursion, the 'state variables' should be retained for the next computer run.





The initial development was the construction of a Python program that maintained/updated state variables to generate, and keep generating, the list of prime numbers. I was using concepts found in the wiki article The Sieve of Eratosthenes.










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    Why do you think, that the function in your (put-on-hold) question is recursive?
    $endgroup$
    – gammatester
    Nov 14 '18 at 12:08












  • $begingroup$
    @gammatester The python program has state variables that change which each new input. The function $tau$ needs more than one variable to run.
    $endgroup$
    – CopyPasteIt
    Nov 14 '18 at 12:13












  • $begingroup$
    You are aware that multiplication can be defined recursively, hence forbidding it makes no sense?
    $endgroup$
    – Hagen von Eitzen
    Nov 14 '18 at 12:18










  • $begingroup$
    $tau(n)=Gamma(n,2,2)$ with $$Gamma(a,b,c)=begin{cases}1&a=b\0&c=a>b\Gamma(a,b+1,b+1)&c>a>b\Gamma(a,b,b+c)&text{otherwise} end{cases}$$
    $endgroup$
    – Hagen von Eitzen
    Nov 14 '18 at 12:23














1












1








1





$begingroup$


Update: I provided an answer here that shows how to define a mathematical function using the recursion theorem. This function can be reconfigured to compute the prime-counting function, $pi(x)$.



Only one question remains:




Question 1: Has the Sieve of Eratosthenes already been mathematically
revamped as a recursive function?




I did not find the word 'recursion' in the wikipedia article Generating primes, so this theory might be useful.



When running computers to get a list of all primes numbers using recursion, the 'state variables' should be retained for the next computer run.





The initial development was the construction of a Python program that maintained/updated state variables to generate, and keep generating, the list of prime numbers. I was using concepts found in the wiki article The Sieve of Eratosthenes.










share|cite|improve this question











$endgroup$




Update: I provided an answer here that shows how to define a mathematical function using the recursion theorem. This function can be reconfigured to compute the prime-counting function, $pi(x)$.



Only one question remains:




Question 1: Has the Sieve of Eratosthenes already been mathematically
revamped as a recursive function?




I did not find the word 'recursion' in the wikipedia article Generating primes, so this theory might be useful.



When running computers to get a list of all primes numbers using recursion, the 'state variables' should be retained for the next computer run.





The initial development was the construction of a Python program that maintained/updated state variables to generate, and keep generating, the list of prime numbers. I was using concepts found in the wiki article The Sieve of Eratosthenes.







elementary-number-theory prime-numbers computer-science recursion






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 16 '18 at 13:54







CopyPasteIt

















asked Nov 14 '18 at 12:03









CopyPasteItCopyPasteIt

4,2131628




4,2131628








  • 1




    $begingroup$
    Why do you think, that the function in your (put-on-hold) question is recursive?
    $endgroup$
    – gammatester
    Nov 14 '18 at 12:08












  • $begingroup$
    @gammatester The python program has state variables that change which each new input. The function $tau$ needs more than one variable to run.
    $endgroup$
    – CopyPasteIt
    Nov 14 '18 at 12:13












  • $begingroup$
    You are aware that multiplication can be defined recursively, hence forbidding it makes no sense?
    $endgroup$
    – Hagen von Eitzen
    Nov 14 '18 at 12:18










  • $begingroup$
    $tau(n)=Gamma(n,2,2)$ with $$Gamma(a,b,c)=begin{cases}1&a=b\0&c=a>b\Gamma(a,b+1,b+1)&c>a>b\Gamma(a,b,b+c)&text{otherwise} end{cases}$$
    $endgroup$
    – Hagen von Eitzen
    Nov 14 '18 at 12:23














  • 1




    $begingroup$
    Why do you think, that the function in your (put-on-hold) question is recursive?
    $endgroup$
    – gammatester
    Nov 14 '18 at 12:08












  • $begingroup$
    @gammatester The python program has state variables that change which each new input. The function $tau$ needs more than one variable to run.
    $endgroup$
    – CopyPasteIt
    Nov 14 '18 at 12:13












  • $begingroup$
    You are aware that multiplication can be defined recursively, hence forbidding it makes no sense?
    $endgroup$
    – Hagen von Eitzen
    Nov 14 '18 at 12:18










  • $begingroup$
    $tau(n)=Gamma(n,2,2)$ with $$Gamma(a,b,c)=begin{cases}1&a=b\0&c=a>b\Gamma(a,b+1,b+1)&c>a>b\Gamma(a,b,b+c)&text{otherwise} end{cases}$$
    $endgroup$
    – Hagen von Eitzen
    Nov 14 '18 at 12:23








1




1




$begingroup$
Why do you think, that the function in your (put-on-hold) question is recursive?
$endgroup$
– gammatester
Nov 14 '18 at 12:08






$begingroup$
Why do you think, that the function in your (put-on-hold) question is recursive?
$endgroup$
– gammatester
Nov 14 '18 at 12:08














$begingroup$
@gammatester The python program has state variables that change which each new input. The function $tau$ needs more than one variable to run.
$endgroup$
– CopyPasteIt
Nov 14 '18 at 12:13






$begingroup$
@gammatester The python program has state variables that change which each new input. The function $tau$ needs more than one variable to run.
$endgroup$
– CopyPasteIt
Nov 14 '18 at 12:13














$begingroup$
You are aware that multiplication can be defined recursively, hence forbidding it makes no sense?
$endgroup$
– Hagen von Eitzen
Nov 14 '18 at 12:18




$begingroup$
You are aware that multiplication can be defined recursively, hence forbidding it makes no sense?
$endgroup$
– Hagen von Eitzen
Nov 14 '18 at 12:18












$begingroup$
$tau(n)=Gamma(n,2,2)$ with $$Gamma(a,b,c)=begin{cases}1&a=b\0&c=a>b\Gamma(a,b+1,b+1)&c>a>b\Gamma(a,b,b+c)&text{otherwise} end{cases}$$
$endgroup$
– Hagen von Eitzen
Nov 14 '18 at 12:23




$begingroup$
$tau(n)=Gamma(n,2,2)$ with $$Gamma(a,b,c)=begin{cases}1&a=b\0&c=a>b\Gamma(a,b+1,b+1)&c>a>b\Gamma(a,b,b+c)&text{otherwise} end{cases}$$
$endgroup$
– Hagen von Eitzen
Nov 14 '18 at 12:23










2 Answers
2






active

oldest

votes


















2












$begingroup$

The Legendre formula,



https://en.wikipedia.org/wiki/Prime-counting_function#Algorithms_for_evaluating_π(x)
http://mathworld.wolfram.com/LegendresFormula.html



which based on the sieve, is recursive: $phi(x,a)=phi(x,a-1)-phi(frac{x}{p_a},a-1)$. With it you can find $pi(x)=phi(x,a)+a-1$ where $a=pi(sqrt[2]{x})$.



However, I am not sure it is recursive the way you want it to be recursive






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Interestingly, the python update is looking more mathematical - using sets! The function $Gamma(n)$ is 'carrying' the set of all primes less than or equal to $n$ as the first coordinate of a changing relation in $mathbb N times mathbb N$. see math.stackexchange.com/questions/2997737/…
    $endgroup$
    – CopyPasteIt
    Nov 14 '18 at 18:38



















1












$begingroup$

Here $mathbb N = {2,3,4,dots}$.



Let $mathcal P$ denote the set of all finite subsets of $mathbb N times mathbb N$.



We define



$tag 1 gamma_n: mathcal P to mathcal P$
$quad quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad;;; rho mapsto rho cup {(n,n+n)}$



We define



$tag 2 mu_n: mathcal P to mathcal P$
$quad quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad;;; rho mapsto rho cup {(m,n+m) ; | ; (m,n) in rho }$



The mapping $Gamma: mathbb N times mathcal P to mathcal P$ is defined by



$$
Gamma(n,rho) = left{begin{array}{lr}
gamma_n(rho), & text{when } n notin text{Range}(rho)\
mu_n(rho), & text{otherwise}
end{array}right}
$$



Using the recursion theorem, we define



$tag 3 mathtt E: mathbb N cup {1} to mathcal P quad quad text{ by }$
$quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad mathtt E(1) = emptyset$
$quadquad quadquadquadquadquadquadquadquadquadquadquadquadquadquad mathtt E(n+1) = Gamma(n+1,mathtt E(n))$



The function $mathtt E$ has the property that the projection of $mathtt E(n)$ onto the first coordinate is the set of all prime numbers less than or equal to $n$. So, letting $pr_1$ denote this projection, we define



$tag 4 pi': mathbb N to mathbb N$
$quad quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad;;; n mapsto text{#} left[, pr_1(mathtt E(n)),right]$



so that $pi'(n)$ is the set of all primes less than or equal to $n$. It is immediate that this function is the restriction of the prime-counting function $pi$ to $mathbb N$.



Values of $mathtt E(n)$ for $n le 11:$



E(2) = {(2, 4)}
E(3) = {(2, 4), (3, 6)}
E(4) = {(2, 6), (2, 4), (3, 6)}
E(5) = {(2, 6), (5, 10), (2, 4), (3, 6)}
E(6) = {(2, 6), (5, 10), (3, 9), (3, 6), (2, 8), (2, 4)}
E(7) = {(7, 14), (2, 6), (5, 10), (3, 9), (3, 6), (2, 8), (2, 4)}
E(8) = {(7, 14), (2, 6), (5, 10), (3, 9), (3, 6), (2, 8), (2, 4), (2, 10)}
E(9) = {(7, 14), (2, 6), (5, 10), (3, 9), (3, 6), (3, 12), (2, 8), (2, 4), (2, 10)}
E(10) = {(7, 14), (2, 6), (5, 10), (3, 12), (2, 8), (2, 10), (3, 9), (5, 15), (2, 12), (3, 6), (2, 4)}
E(11) = {(7, 14), (2, 6), (5, 10), (3, 12), (2, 8), (11, 22), (2, 10), (3, 9), (5, 15), (2, 12), (3, 6), (2, 4)}


Note: These function values came from the Python program. Since mathematics is not concerned with 'efficiency' in any way, the program was 'dumbed down' so the outputs of $mathtt E$ can contain elements that are no longer used by the recursion algorithm; this made it easier to define the algorithm.






share|cite|improve this answer











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    2 Answers
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    2 Answers
    2






    active

    oldest

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    active

    oldest

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    active

    oldest

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    2












    $begingroup$

    The Legendre formula,



    https://en.wikipedia.org/wiki/Prime-counting_function#Algorithms_for_evaluating_π(x)
    http://mathworld.wolfram.com/LegendresFormula.html



    which based on the sieve, is recursive: $phi(x,a)=phi(x,a-1)-phi(frac{x}{p_a},a-1)$. With it you can find $pi(x)=phi(x,a)+a-1$ where $a=pi(sqrt[2]{x})$.



    However, I am not sure it is recursive the way you want it to be recursive






    share|cite|improve this answer









    $endgroup$













    • $begingroup$
      Interestingly, the python update is looking more mathematical - using sets! The function $Gamma(n)$ is 'carrying' the set of all primes less than or equal to $n$ as the first coordinate of a changing relation in $mathbb N times mathbb N$. see math.stackexchange.com/questions/2997737/…
      $endgroup$
      – CopyPasteIt
      Nov 14 '18 at 18:38
















    2












    $begingroup$

    The Legendre formula,



    https://en.wikipedia.org/wiki/Prime-counting_function#Algorithms_for_evaluating_π(x)
    http://mathworld.wolfram.com/LegendresFormula.html



    which based on the sieve, is recursive: $phi(x,a)=phi(x,a-1)-phi(frac{x}{p_a},a-1)$. With it you can find $pi(x)=phi(x,a)+a-1$ where $a=pi(sqrt[2]{x})$.



    However, I am not sure it is recursive the way you want it to be recursive






    share|cite|improve this answer









    $endgroup$













    • $begingroup$
      Interestingly, the python update is looking more mathematical - using sets! The function $Gamma(n)$ is 'carrying' the set of all primes less than or equal to $n$ as the first coordinate of a changing relation in $mathbb N times mathbb N$. see math.stackexchange.com/questions/2997737/…
      $endgroup$
      – CopyPasteIt
      Nov 14 '18 at 18:38














    2












    2








    2





    $begingroup$

    The Legendre formula,



    https://en.wikipedia.org/wiki/Prime-counting_function#Algorithms_for_evaluating_π(x)
    http://mathworld.wolfram.com/LegendresFormula.html



    which based on the sieve, is recursive: $phi(x,a)=phi(x,a-1)-phi(frac{x}{p_a},a-1)$. With it you can find $pi(x)=phi(x,a)+a-1$ where $a=pi(sqrt[2]{x})$.



    However, I am not sure it is recursive the way you want it to be recursive






    share|cite|improve this answer









    $endgroup$



    The Legendre formula,



    https://en.wikipedia.org/wiki/Prime-counting_function#Algorithms_for_evaluating_π(x)
    http://mathworld.wolfram.com/LegendresFormula.html



    which based on the sieve, is recursive: $phi(x,a)=phi(x,a-1)-phi(frac{x}{p_a},a-1)$. With it you can find $pi(x)=phi(x,a)+a-1$ where $a=pi(sqrt[2]{x})$.



    However, I am not sure it is recursive the way you want it to be recursive







    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered Nov 14 '18 at 18:17









    Collag3nCollag3n

    749211




    749211












    • $begingroup$
      Interestingly, the python update is looking more mathematical - using sets! The function $Gamma(n)$ is 'carrying' the set of all primes less than or equal to $n$ as the first coordinate of a changing relation in $mathbb N times mathbb N$. see math.stackexchange.com/questions/2997737/…
      $endgroup$
      – CopyPasteIt
      Nov 14 '18 at 18:38


















    • $begingroup$
      Interestingly, the python update is looking more mathematical - using sets! The function $Gamma(n)$ is 'carrying' the set of all primes less than or equal to $n$ as the first coordinate of a changing relation in $mathbb N times mathbb N$. see math.stackexchange.com/questions/2997737/…
      $endgroup$
      – CopyPasteIt
      Nov 14 '18 at 18:38
















    $begingroup$
    Interestingly, the python update is looking more mathematical - using sets! The function $Gamma(n)$ is 'carrying' the set of all primes less than or equal to $n$ as the first coordinate of a changing relation in $mathbb N times mathbb N$. see math.stackexchange.com/questions/2997737/…
    $endgroup$
    – CopyPasteIt
    Nov 14 '18 at 18:38




    $begingroup$
    Interestingly, the python update is looking more mathematical - using sets! The function $Gamma(n)$ is 'carrying' the set of all primes less than or equal to $n$ as the first coordinate of a changing relation in $mathbb N times mathbb N$. see math.stackexchange.com/questions/2997737/…
    $endgroup$
    – CopyPasteIt
    Nov 14 '18 at 18:38











    1












    $begingroup$

    Here $mathbb N = {2,3,4,dots}$.



    Let $mathcal P$ denote the set of all finite subsets of $mathbb N times mathbb N$.



    We define



    $tag 1 gamma_n: mathcal P to mathcal P$
    $quad quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad;;; rho mapsto rho cup {(n,n+n)}$



    We define



    $tag 2 mu_n: mathcal P to mathcal P$
    $quad quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad;;; rho mapsto rho cup {(m,n+m) ; | ; (m,n) in rho }$



    The mapping $Gamma: mathbb N times mathcal P to mathcal P$ is defined by



    $$
    Gamma(n,rho) = left{begin{array}{lr}
    gamma_n(rho), & text{when } n notin text{Range}(rho)\
    mu_n(rho), & text{otherwise}
    end{array}right}
    $$



    Using the recursion theorem, we define



    $tag 3 mathtt E: mathbb N cup {1} to mathcal P quad quad text{ by }$
    $quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad mathtt E(1) = emptyset$
    $quadquad quadquadquadquadquadquadquadquadquadquadquadquadquadquad mathtt E(n+1) = Gamma(n+1,mathtt E(n))$



    The function $mathtt E$ has the property that the projection of $mathtt E(n)$ onto the first coordinate is the set of all prime numbers less than or equal to $n$. So, letting $pr_1$ denote this projection, we define



    $tag 4 pi': mathbb N to mathbb N$
    $quad quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad;;; n mapsto text{#} left[, pr_1(mathtt E(n)),right]$



    so that $pi'(n)$ is the set of all primes less than or equal to $n$. It is immediate that this function is the restriction of the prime-counting function $pi$ to $mathbb N$.



    Values of $mathtt E(n)$ for $n le 11:$



    E(2) = {(2, 4)}
    E(3) = {(2, 4), (3, 6)}
    E(4) = {(2, 6), (2, 4), (3, 6)}
    E(5) = {(2, 6), (5, 10), (2, 4), (3, 6)}
    E(6) = {(2, 6), (5, 10), (3, 9), (3, 6), (2, 8), (2, 4)}
    E(7) = {(7, 14), (2, 6), (5, 10), (3, 9), (3, 6), (2, 8), (2, 4)}
    E(8) = {(7, 14), (2, 6), (5, 10), (3, 9), (3, 6), (2, 8), (2, 4), (2, 10)}
    E(9) = {(7, 14), (2, 6), (5, 10), (3, 9), (3, 6), (3, 12), (2, 8), (2, 4), (2, 10)}
    E(10) = {(7, 14), (2, 6), (5, 10), (3, 12), (2, 8), (2, 10), (3, 9), (5, 15), (2, 12), (3, 6), (2, 4)}
    E(11) = {(7, 14), (2, 6), (5, 10), (3, 12), (2, 8), (11, 22), (2, 10), (3, 9), (5, 15), (2, 12), (3, 6), (2, 4)}


    Note: These function values came from the Python program. Since mathematics is not concerned with 'efficiency' in any way, the program was 'dumbed down' so the outputs of $mathtt E$ can contain elements that are no longer used by the recursion algorithm; this made it easier to define the algorithm.






    share|cite|improve this answer











    $endgroup$


















      1












      $begingroup$

      Here $mathbb N = {2,3,4,dots}$.



      Let $mathcal P$ denote the set of all finite subsets of $mathbb N times mathbb N$.



      We define



      $tag 1 gamma_n: mathcal P to mathcal P$
      $quad quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad;;; rho mapsto rho cup {(n,n+n)}$



      We define



      $tag 2 mu_n: mathcal P to mathcal P$
      $quad quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad;;; rho mapsto rho cup {(m,n+m) ; | ; (m,n) in rho }$



      The mapping $Gamma: mathbb N times mathcal P to mathcal P$ is defined by



      $$
      Gamma(n,rho) = left{begin{array}{lr}
      gamma_n(rho), & text{when } n notin text{Range}(rho)\
      mu_n(rho), & text{otherwise}
      end{array}right}
      $$



      Using the recursion theorem, we define



      $tag 3 mathtt E: mathbb N cup {1} to mathcal P quad quad text{ by }$
      $quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad mathtt E(1) = emptyset$
      $quadquad quadquadquadquadquadquadquadquadquadquadquadquadquadquad mathtt E(n+1) = Gamma(n+1,mathtt E(n))$



      The function $mathtt E$ has the property that the projection of $mathtt E(n)$ onto the first coordinate is the set of all prime numbers less than or equal to $n$. So, letting $pr_1$ denote this projection, we define



      $tag 4 pi': mathbb N to mathbb N$
      $quad quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad;;; n mapsto text{#} left[, pr_1(mathtt E(n)),right]$



      so that $pi'(n)$ is the set of all primes less than or equal to $n$. It is immediate that this function is the restriction of the prime-counting function $pi$ to $mathbb N$.



      Values of $mathtt E(n)$ for $n le 11:$



      E(2) = {(2, 4)}
      E(3) = {(2, 4), (3, 6)}
      E(4) = {(2, 6), (2, 4), (3, 6)}
      E(5) = {(2, 6), (5, 10), (2, 4), (3, 6)}
      E(6) = {(2, 6), (5, 10), (3, 9), (3, 6), (2, 8), (2, 4)}
      E(7) = {(7, 14), (2, 6), (5, 10), (3, 9), (3, 6), (2, 8), (2, 4)}
      E(8) = {(7, 14), (2, 6), (5, 10), (3, 9), (3, 6), (2, 8), (2, 4), (2, 10)}
      E(9) = {(7, 14), (2, 6), (5, 10), (3, 9), (3, 6), (3, 12), (2, 8), (2, 4), (2, 10)}
      E(10) = {(7, 14), (2, 6), (5, 10), (3, 12), (2, 8), (2, 10), (3, 9), (5, 15), (2, 12), (3, 6), (2, 4)}
      E(11) = {(7, 14), (2, 6), (5, 10), (3, 12), (2, 8), (11, 22), (2, 10), (3, 9), (5, 15), (2, 12), (3, 6), (2, 4)}


      Note: These function values came from the Python program. Since mathematics is not concerned with 'efficiency' in any way, the program was 'dumbed down' so the outputs of $mathtt E$ can contain elements that are no longer used by the recursion algorithm; this made it easier to define the algorithm.






      share|cite|improve this answer











      $endgroup$
















        1












        1








        1





        $begingroup$

        Here $mathbb N = {2,3,4,dots}$.



        Let $mathcal P$ denote the set of all finite subsets of $mathbb N times mathbb N$.



        We define



        $tag 1 gamma_n: mathcal P to mathcal P$
        $quad quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad;;; rho mapsto rho cup {(n,n+n)}$



        We define



        $tag 2 mu_n: mathcal P to mathcal P$
        $quad quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad;;; rho mapsto rho cup {(m,n+m) ; | ; (m,n) in rho }$



        The mapping $Gamma: mathbb N times mathcal P to mathcal P$ is defined by



        $$
        Gamma(n,rho) = left{begin{array}{lr}
        gamma_n(rho), & text{when } n notin text{Range}(rho)\
        mu_n(rho), & text{otherwise}
        end{array}right}
        $$



        Using the recursion theorem, we define



        $tag 3 mathtt E: mathbb N cup {1} to mathcal P quad quad text{ by }$
        $quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad mathtt E(1) = emptyset$
        $quadquad quadquadquadquadquadquadquadquadquadquadquadquadquadquad mathtt E(n+1) = Gamma(n+1,mathtt E(n))$



        The function $mathtt E$ has the property that the projection of $mathtt E(n)$ onto the first coordinate is the set of all prime numbers less than or equal to $n$. So, letting $pr_1$ denote this projection, we define



        $tag 4 pi': mathbb N to mathbb N$
        $quad quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad;;; n mapsto text{#} left[, pr_1(mathtt E(n)),right]$



        so that $pi'(n)$ is the set of all primes less than or equal to $n$. It is immediate that this function is the restriction of the prime-counting function $pi$ to $mathbb N$.



        Values of $mathtt E(n)$ for $n le 11:$



        E(2) = {(2, 4)}
        E(3) = {(2, 4), (3, 6)}
        E(4) = {(2, 6), (2, 4), (3, 6)}
        E(5) = {(2, 6), (5, 10), (2, 4), (3, 6)}
        E(6) = {(2, 6), (5, 10), (3, 9), (3, 6), (2, 8), (2, 4)}
        E(7) = {(7, 14), (2, 6), (5, 10), (3, 9), (3, 6), (2, 8), (2, 4)}
        E(8) = {(7, 14), (2, 6), (5, 10), (3, 9), (3, 6), (2, 8), (2, 4), (2, 10)}
        E(9) = {(7, 14), (2, 6), (5, 10), (3, 9), (3, 6), (3, 12), (2, 8), (2, 4), (2, 10)}
        E(10) = {(7, 14), (2, 6), (5, 10), (3, 12), (2, 8), (2, 10), (3, 9), (5, 15), (2, 12), (3, 6), (2, 4)}
        E(11) = {(7, 14), (2, 6), (5, 10), (3, 12), (2, 8), (11, 22), (2, 10), (3, 9), (5, 15), (2, 12), (3, 6), (2, 4)}


        Note: These function values came from the Python program. Since mathematics is not concerned with 'efficiency' in any way, the program was 'dumbed down' so the outputs of $mathtt E$ can contain elements that are no longer used by the recursion algorithm; this made it easier to define the algorithm.






        share|cite|improve this answer











        $endgroup$



        Here $mathbb N = {2,3,4,dots}$.



        Let $mathcal P$ denote the set of all finite subsets of $mathbb N times mathbb N$.



        We define



        $tag 1 gamma_n: mathcal P to mathcal P$
        $quad quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad;;; rho mapsto rho cup {(n,n+n)}$



        We define



        $tag 2 mu_n: mathcal P to mathcal P$
        $quad quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad;;; rho mapsto rho cup {(m,n+m) ; | ; (m,n) in rho }$



        The mapping $Gamma: mathbb N times mathcal P to mathcal P$ is defined by



        $$
        Gamma(n,rho) = left{begin{array}{lr}
        gamma_n(rho), & text{when } n notin text{Range}(rho)\
        mu_n(rho), & text{otherwise}
        end{array}right}
        $$



        Using the recursion theorem, we define



        $tag 3 mathtt E: mathbb N cup {1} to mathcal P quad quad text{ by }$
        $quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad mathtt E(1) = emptyset$
        $quadquad quadquadquadquadquadquadquadquadquadquadquadquadquadquad mathtt E(n+1) = Gamma(n+1,mathtt E(n))$



        The function $mathtt E$ has the property that the projection of $mathtt E(n)$ onto the first coordinate is the set of all prime numbers less than or equal to $n$. So, letting $pr_1$ denote this projection, we define



        $tag 4 pi': mathbb N to mathbb N$
        $quad quadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquadquad;;; n mapsto text{#} left[, pr_1(mathtt E(n)),right]$



        so that $pi'(n)$ is the set of all primes less than or equal to $n$. It is immediate that this function is the restriction of the prime-counting function $pi$ to $mathbb N$.



        Values of $mathtt E(n)$ for $n le 11:$



        E(2) = {(2, 4)}
        E(3) = {(2, 4), (3, 6)}
        E(4) = {(2, 6), (2, 4), (3, 6)}
        E(5) = {(2, 6), (5, 10), (2, 4), (3, 6)}
        E(6) = {(2, 6), (5, 10), (3, 9), (3, 6), (2, 8), (2, 4)}
        E(7) = {(7, 14), (2, 6), (5, 10), (3, 9), (3, 6), (2, 8), (2, 4)}
        E(8) = {(7, 14), (2, 6), (5, 10), (3, 9), (3, 6), (2, 8), (2, 4), (2, 10)}
        E(9) = {(7, 14), (2, 6), (5, 10), (3, 9), (3, 6), (3, 12), (2, 8), (2, 4), (2, 10)}
        E(10) = {(7, 14), (2, 6), (5, 10), (3, 12), (2, 8), (2, 10), (3, 9), (5, 15), (2, 12), (3, 6), (2, 4)}
        E(11) = {(7, 14), (2, 6), (5, 10), (3, 12), (2, 8), (11, 22), (2, 10), (3, 9), (5, 15), (2, 12), (3, 6), (2, 4)}


        Note: These function values came from the Python program. Since mathematics is not concerned with 'efficiency' in any way, the program was 'dumbed down' so the outputs of $mathtt E$ can contain elements that are no longer used by the recursion algorithm; this made it easier to define the algorithm.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Nov 16 '18 at 14:07

























        answered Nov 15 '18 at 0:41









        CopyPasteItCopyPasteIt

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