Maximum number of parabolas that can be drawn with a given directrix and tangent at vertex.
$begingroup$
If the equation of the directrix and tangent at the vertex is given then the maximum number of parabola , which can be drawn is. ?
My approach is :- Since directrix can't be changed then only 1 parabola is possible.
conic-sections
asked Jan 5 at 17:48
saket kumarsaket kumar
143113
$endgroup$
add a comment |
$begingroup$
If the equation of the directrix and tangent at the vertex is given then the maximum number of parabola , which can be drawn is. ?
My approach is :- Since directrix can't be changed then only 1 parabola is possible.
conic-sections
asked Jan 5 at 17:48
saket kumarsaket kumar
143113
$endgroup$
$begingroup$
Am I Right ? I.e only one Parabola is possible
$endgroup$
– saket kumar
Jan 5 at 18:01
$begingroup$
If I am not correct then plz explain this in detail
$endgroup$
– saket kumar
Jan 5 at 18:08
1
$begingroup$
Where’s the vertex (and hence focus) of this one parabola? You’re making the same sort of mistake that you made in your previous question.
$endgroup$
– amd
Jan 5 at 19:50
add a comment |
$begingroup$
If the equation of the directrix and tangent at the vertex is given then the maximum number of parabola , which can be drawn is. ?
My approach is :- Since directrix can't be changed then only 1 parabola is possible.
conic-sections
asked Jan 5 at 17:48
saket kumarsaket kumar
143113
$endgroup$
If the equation of the directrix and tangent at the vertex is given then the maximum number of parabola , which can be drawn is. ?
My approach is :- Since directrix can't be changed then only 1 parabola is possible.
conic-sections
conic-sections
asked Jan 5 at 17:48
saket kumarsaket kumar
143113
asked Jan 5 at 17:48
saket kumarsaket kumar
143113
asked Jan 5 at 17:48
saket kumarsaket kumar
143113
asked Jan 5 at 17:48
saket kumarsaket kumar
143113
asked Jan 5 at 17:48
saket kumarsaket kumar
143113
143113
$begingroup$
Am I Right ? I.e only one Parabola is possible
$endgroup$
– saket kumar
Jan 5 at 18:01
$begingroup$
If I am not correct then plz explain this in detail
$endgroup$
– saket kumar
Jan 5 at 18:08
1
$begingroup$
Where’s the vertex (and hence focus) of this one parabola? You’re making the same sort of mistake that you made in your previous question.
$endgroup$
– amd
Jan 5 at 19:50
add a comment |
$begingroup$
Am I Right ? I.e only one Parabola is possible
$endgroup$
– saket kumar
Jan 5 at 18:01
$begingroup$
If I am not correct then plz explain this in detail
$endgroup$
– saket kumar
Jan 5 at 18:08
1
$begingroup$
Where’s the vertex (and hence focus) of this one parabola? You’re making the same sort of mistake that you made in your previous question.
$endgroup$
– amd
Jan 5 at 19:50
$begingroup$
Am I Right ? I.e only one Parabola is possible
$endgroup$
– saket kumar
Jan 5 at 18:01
$begingroup$
Am I Right ? I.e only one Parabola is possible
$endgroup$
– saket kumar
Jan 5 at 18:01
$begingroup$
If I am not correct then plz explain this in detail
$endgroup$
– saket kumar
Jan 5 at 18:08
$begingroup$
If I am not correct then plz explain this in detail
$endgroup$
– saket kumar
Jan 5 at 18:08
1
1
$begingroup$
Where’s the vertex (and hence focus) of this one parabola? You’re making the same sort of mistake that you made in your previous question.
$endgroup$
– amd
Jan 5 at 19:50
$begingroup$
Where’s the vertex (and hence focus) of this one parabola? You’re making the same sort of mistake that you made in your previous question.
$endgroup$
– amd
Jan 5 at 19:50
add a comment |
1 Answer
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$begingroup$
If the directrix and the tangent line at the vertex are given but not the vertex, there exist infinitely many parabolas.
The vertex of such parabola is any point lying at this tangent line.
The width of all these parabolas is the same, because is uniquely determined by the distance between the two given lines ( they are parallel).
answered Jan 5 at 21:45
user376343user376343
3,9584829
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add a comment |
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$begingroup$
If the directrix and the tangent line at the vertex are given but not the vertex, there exist infinitely many parabolas.
The vertex of such parabola is any point lying at this tangent line.
The width of all these parabolas is the same, because is uniquely determined by the distance between the two given lines ( they are parallel).
answered Jan 5 at 21:45
user376343user376343
3,9584829
$endgroup$
add a comment |
$begingroup$
If the directrix and the tangent line at the vertex are given but not the vertex, there exist infinitely many parabolas.
The vertex of such parabola is any point lying at this tangent line.
The width of all these parabolas is the same, because is uniquely determined by the distance between the two given lines ( they are parallel).
answered Jan 5 at 21:45
user376343user376343
3,9584829
$endgroup$
add a comment |
$begingroup$
If the directrix and the tangent line at the vertex are given but not the vertex, there exist infinitely many parabolas.
The vertex of such parabola is any point lying at this tangent line.
The width of all these parabolas is the same, because is uniquely determined by the distance between the two given lines ( they are parallel).
answered Jan 5 at 21:45
user376343user376343
3,9584829
$endgroup$
If the directrix and the tangent line at the vertex are given but not the vertex, there exist infinitely many parabolas.
The vertex of such parabola is any point lying at this tangent line.
The width of all these parabolas is the same, because is uniquely determined by the distance between the two given lines ( they are parallel).
answered Jan 5 at 21:45
user376343user376343
3,9584829
answered Jan 5 at 21:45
user376343user376343
3,9584829
answered Jan 5 at 21:45
user376343user376343
3,9584829
answered Jan 5 at 21:45
user376343user376343
3,9584829
3,9584829
add a comment |
add a comment |
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$begingroup$
Am I Right ? I.e only one Parabola is possible
$endgroup$
– saket kumar
Jan 5 at 18:01
$begingroup$
If I am not correct then plz explain this in detail
$endgroup$
– saket kumar
Jan 5 at 18:08
1
$begingroup$
Where’s the vertex (and hence focus) of this one parabola? You’re making the same sort of mistake that you made in your previous question.
$endgroup$
– amd
Jan 5 at 19:50