How to calculate angle from 2D projection
$begingroup$
I have picture of interior wall. I know that angles A and B are 90deg in reality and I need to calculate angle C.
A in picture is 95 deg
B 123 deg
C 142 deg
geometry
$endgroup$
add a comment |
$begingroup$
I have picture of interior wall. I know that angles A and B are 90deg in reality and I need to calculate angle C.
A in picture is 95 deg
B 123 deg
C 142 deg
geometry
$endgroup$
$begingroup$
Angle C could be anything.
$endgroup$
– Aretino
Jan 14 at 16:13
add a comment |
$begingroup$
I have picture of interior wall. I know that angles A and B are 90deg in reality and I need to calculate angle C.
A in picture is 95 deg
B 123 deg
C 142 deg
geometry
$endgroup$
I have picture of interior wall. I know that angles A and B are 90deg in reality and I need to calculate angle C.
A in picture is 95 deg
B 123 deg
C 142 deg
geometry
geometry
asked Jan 14 at 10:23
atilas1atilas1
1
1
$begingroup$
Angle C could be anything.
$endgroup$
– Aretino
Jan 14 at 16:13
add a comment |
$begingroup$
Angle C could be anything.
$endgroup$
– Aretino
Jan 14 at 16:13
$begingroup$
Angle C could be anything.
$endgroup$
– Aretino
Jan 14 at 16:13
$begingroup$
Angle C could be anything.
$endgroup$
– Aretino
Jan 14 at 16:13
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
You cannot find the real angle C from just the projection angles. The only thing you can know from the picture is that the angle C isn't larger than 142°.
$endgroup$
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3073072%2fhow-to-calculate-angle-from-2d-projection%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You cannot find the real angle C from just the projection angles. The only thing you can know from the picture is that the angle C isn't larger than 142°.
$endgroup$
add a comment |
$begingroup$
You cannot find the real angle C from just the projection angles. The only thing you can know from the picture is that the angle C isn't larger than 142°.
$endgroup$
add a comment |
$begingroup$
You cannot find the real angle C from just the projection angles. The only thing you can know from the picture is that the angle C isn't larger than 142°.
$endgroup$
You cannot find the real angle C from just the projection angles. The only thing you can know from the picture is that the angle C isn't larger than 142°.
answered Jan 14 at 10:29
Vasily MitchVasily Mitch
2,6891312
2,6891312
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3073072%2fhow-to-calculate-angle-from-2d-projection%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
Angle C could be anything.
$endgroup$
– Aretino
Jan 14 at 16:13