how to find circle circumference point from a point inside the circle












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given the image bellow how can i find the points of a circles circumference from a point inside the circle with given X and Y ? also can how to calculate it from a point outside the cirlce ?



https://i.stack.imgur.com/0fv9G.png










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    Your Question seems unclear, What is 'Circumference Point'? As Far I know Circumference is defined as length, but You seem to ask the Circumference of something which is not even a curve. Please Provide details
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    – Abhas Kumar Sinha
    Jan 14 at 10:13
















0












$begingroup$


given the image bellow how can i find the points of a circles circumference from a point inside the circle with given X and Y ? also can how to calculate it from a point outside the cirlce ?



https://i.stack.imgur.com/0fv9G.png










share|cite|improve this question









$endgroup$












  • $begingroup$
    Your Question seems unclear, What is 'Circumference Point'? As Far I know Circumference is defined as length, but You seem to ask the Circumference of something which is not even a curve. Please Provide details
    $endgroup$
    – Abhas Kumar Sinha
    Jan 14 at 10:13














0












0








0





$begingroup$


given the image bellow how can i find the points of a circles circumference from a point inside the circle with given X and Y ? also can how to calculate it from a point outside the cirlce ?



https://i.stack.imgur.com/0fv9G.png










share|cite|improve this question









$endgroup$




given the image bellow how can i find the points of a circles circumference from a point inside the circle with given X and Y ? also can how to calculate it from a point outside the cirlce ?



https://i.stack.imgur.com/0fv9G.png







geometry trigonometry circles






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asked Jan 14 at 9:51









AleksanderAleksander

11




11












  • $begingroup$
    Your Question seems unclear, What is 'Circumference Point'? As Far I know Circumference is defined as length, but You seem to ask the Circumference of something which is not even a curve. Please Provide details
    $endgroup$
    – Abhas Kumar Sinha
    Jan 14 at 10:13


















  • $begingroup$
    Your Question seems unclear, What is 'Circumference Point'? As Far I know Circumference is defined as length, but You seem to ask the Circumference of something which is not even a curve. Please Provide details
    $endgroup$
    – Abhas Kumar Sinha
    Jan 14 at 10:13
















$begingroup$
Your Question seems unclear, What is 'Circumference Point'? As Far I know Circumference is defined as length, but You seem to ask the Circumference of something which is not even a curve. Please Provide details
$endgroup$
– Abhas Kumar Sinha
Jan 14 at 10:13




$begingroup$
Your Question seems unclear, What is 'Circumference Point'? As Far I know Circumference is defined as length, but You seem to ask the Circumference of something which is not even a curve. Please Provide details
$endgroup$
– Abhas Kumar Sinha
Jan 14 at 10:13










2 Answers
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If $(x_0, y_0)$ is the centre of the circle and if $R$ is the ray, then the points of the circle can be represented as $(x_0 + R,costheta, ,y_0 + R,sintheta)$



The point inside or outside the circle can be represented as $M = (x_0 + rho ,cosphi,, y_0 + rho, sinphi)$



Then, the nearest point from $M$ on the circle is:
$$ A = (x_0 + R ,cosphi,, y_0 + R, sinphi)$$



I guess this corresponds to your question ... which was not so clear






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    $begingroup$

    Three given points are vertices of a triangle $triangle.$ The center of the circumcircle of $triangle;$ is the intersection of line bisectors of the sides of $triangle.$ To find the center, it suffices to take two of the bisectors.

    The point of the circle that is nearest to a given point lies on the diameter through the center and the given point. It is the red point at the picture.
    enter image description here






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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

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      active

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      0












      $begingroup$

      If $(x_0, y_0)$ is the centre of the circle and if $R$ is the ray, then the points of the circle can be represented as $(x_0 + R,costheta, ,y_0 + R,sintheta)$



      The point inside or outside the circle can be represented as $M = (x_0 + rho ,cosphi,, y_0 + rho, sinphi)$



      Then, the nearest point from $M$ on the circle is:
      $$ A = (x_0 + R ,cosphi,, y_0 + R, sinphi)$$



      I guess this corresponds to your question ... which was not so clear






      share|cite|improve this answer









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        0












        $begingroup$

        If $(x_0, y_0)$ is the centre of the circle and if $R$ is the ray, then the points of the circle can be represented as $(x_0 + R,costheta, ,y_0 + R,sintheta)$



        The point inside or outside the circle can be represented as $M = (x_0 + rho ,cosphi,, y_0 + rho, sinphi)$



        Then, the nearest point from $M$ on the circle is:
        $$ A = (x_0 + R ,cosphi,, y_0 + R, sinphi)$$



        I guess this corresponds to your question ... which was not so clear






        share|cite|improve this answer









        $endgroup$
















          0












          0








          0





          $begingroup$

          If $(x_0, y_0)$ is the centre of the circle and if $R$ is the ray, then the points of the circle can be represented as $(x_0 + R,costheta, ,y_0 + R,sintheta)$



          The point inside or outside the circle can be represented as $M = (x_0 + rho ,cosphi,, y_0 + rho, sinphi)$



          Then, the nearest point from $M$ on the circle is:
          $$ A = (x_0 + R ,cosphi,, y_0 + R, sinphi)$$



          I guess this corresponds to your question ... which was not so clear






          share|cite|improve this answer









          $endgroup$



          If $(x_0, y_0)$ is the centre of the circle and if $R$ is the ray, then the points of the circle can be represented as $(x_0 + R,costheta, ,y_0 + R,sintheta)$



          The point inside or outside the circle can be represented as $M = (x_0 + rho ,cosphi,, y_0 + rho, sinphi)$



          Then, the nearest point from $M$ on the circle is:
          $$ A = (x_0 + R ,cosphi,, y_0 + R, sinphi)$$



          I guess this corresponds to your question ... which was not so clear







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Jan 14 at 10:39









          DamienDamien

          63714




          63714























              0












              $begingroup$

              Three given points are vertices of a triangle $triangle.$ The center of the circumcircle of $triangle;$ is the intersection of line bisectors of the sides of $triangle.$ To find the center, it suffices to take two of the bisectors.

              The point of the circle that is nearest to a given point lies on the diameter through the center and the given point. It is the red point at the picture.
              enter image description here






              share|cite|improve this answer









              $endgroup$


















                0












                $begingroup$

                Three given points are vertices of a triangle $triangle.$ The center of the circumcircle of $triangle;$ is the intersection of line bisectors of the sides of $triangle.$ To find the center, it suffices to take two of the bisectors.

                The point of the circle that is nearest to a given point lies on the diameter through the center and the given point. It is the red point at the picture.
                enter image description here






                share|cite|improve this answer









                $endgroup$
















                  0












                  0








                  0





                  $begingroup$

                  Three given points are vertices of a triangle $triangle.$ The center of the circumcircle of $triangle;$ is the intersection of line bisectors of the sides of $triangle.$ To find the center, it suffices to take two of the bisectors.

                  The point of the circle that is nearest to a given point lies on the diameter through the center and the given point. It is the red point at the picture.
                  enter image description here






                  share|cite|improve this answer









                  $endgroup$



                  Three given points are vertices of a triangle $triangle.$ The center of the circumcircle of $triangle;$ is the intersection of line bisectors of the sides of $triangle.$ To find the center, it suffices to take two of the bisectors.

                  The point of the circle that is nearest to a given point lies on the diameter through the center and the given point. It is the red point at the picture.
                  enter image description here







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Jan 14 at 12:45









                  user376343user376343

                  3,9834829




                  3,9834829






























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