Polylogarithmic integrals
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I'm a physicist looking at the Fredholm inverse of some integral equation. In attempting to solve the equation I stumbled upon a type of integral of the form
begin{equation}
int frac{prod_{i=1}^N operatorname{Li}_{s_i}(x)}{x+alpha} mathrm dx.
end{equation}
At first glance the above may be integrated by elementary methods, using the relation
begin{equation}
xfrac{mathrm doperatorname{Li}_s(x)}{mathrm dx} = operatorname{Li}_{s-1}(x).
end{equation}
However, in the above it spawns expressions with products of $N+1$ (!!) polylogarithms under the integral sign, after many partial integrations.
I ask this question hoping someone could point me to some reading material that would allow me to solve the above integral.
integration polylogarithm
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add a comment |
$begingroup$
I'm a physicist looking at the Fredholm inverse of some integral equation. In attempting to solve the equation I stumbled upon a type of integral of the form
begin{equation}
int frac{prod_{i=1}^N operatorname{Li}_{s_i}(x)}{x+alpha} mathrm dx.
end{equation}
At first glance the above may be integrated by elementary methods, using the relation
begin{equation}
xfrac{mathrm doperatorname{Li}_s(x)}{mathrm dx} = operatorname{Li}_{s-1}(x).
end{equation}
However, in the above it spawns expressions with products of $N+1$ (!!) polylogarithms under the integral sign, after many partial integrations.
I ask this question hoping someone could point me to some reading material that would allow me to solve the above integral.
integration polylogarithm
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$begingroup$
Note that $$mathrm{Li}_{s}(z)=int_0^zmathrm{Li}_{s-1}(t)frac{mathrm dt}t$$ which may help you to turn the product into the form $$mathrm{Li}^N_{K}(z)$$
$endgroup$
– clathratus
Jan 8 at 22:20
add a comment |
$begingroup$
I'm a physicist looking at the Fredholm inverse of some integral equation. In attempting to solve the equation I stumbled upon a type of integral of the form
begin{equation}
int frac{prod_{i=1}^N operatorname{Li}_{s_i}(x)}{x+alpha} mathrm dx.
end{equation}
At first glance the above may be integrated by elementary methods, using the relation
begin{equation}
xfrac{mathrm doperatorname{Li}_s(x)}{mathrm dx} = operatorname{Li}_{s-1}(x).
end{equation}
However, in the above it spawns expressions with products of $N+1$ (!!) polylogarithms under the integral sign, after many partial integrations.
I ask this question hoping someone could point me to some reading material that would allow me to solve the above integral.
integration polylogarithm
$endgroup$
I'm a physicist looking at the Fredholm inverse of some integral equation. In attempting to solve the equation I stumbled upon a type of integral of the form
begin{equation}
int frac{prod_{i=1}^N operatorname{Li}_{s_i}(x)}{x+alpha} mathrm dx.
end{equation}
At first glance the above may be integrated by elementary methods, using the relation
begin{equation}
xfrac{mathrm doperatorname{Li}_s(x)}{mathrm dx} = operatorname{Li}_{s-1}(x).
end{equation}
However, in the above it spawns expressions with products of $N+1$ (!!) polylogarithms under the integral sign, after many partial integrations.
I ask this question hoping someone could point me to some reading material that would allow me to solve the above integral.
integration polylogarithm
integration polylogarithm
asked Jan 8 at 17:39
10100110101010011010
23929
23929
$begingroup$
Note that $$mathrm{Li}_{s}(z)=int_0^zmathrm{Li}_{s-1}(t)frac{mathrm dt}t$$ which may help you to turn the product into the form $$mathrm{Li}^N_{K}(z)$$
$endgroup$
– clathratus
Jan 8 at 22:20
add a comment |
$begingroup$
Note that $$mathrm{Li}_{s}(z)=int_0^zmathrm{Li}_{s-1}(t)frac{mathrm dt}t$$ which may help you to turn the product into the form $$mathrm{Li}^N_{K}(z)$$
$endgroup$
– clathratus
Jan 8 at 22:20
$begingroup$
Note that $$mathrm{Li}_{s}(z)=int_0^zmathrm{Li}_{s-1}(t)frac{mathrm dt}t$$ which may help you to turn the product into the form $$mathrm{Li}^N_{K}(z)$$
$endgroup$
– clathratus
Jan 8 at 22:20
$begingroup$
Note that $$mathrm{Li}_{s}(z)=int_0^zmathrm{Li}_{s-1}(t)frac{mathrm dt}t$$ which may help you to turn the product into the form $$mathrm{Li}^N_{K}(z)$$
$endgroup$
– clathratus
Jan 8 at 22:20
add a comment |
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$begingroup$
Note that $$mathrm{Li}_{s}(z)=int_0^zmathrm{Li}_{s-1}(t)frac{mathrm dt}t$$ which may help you to turn the product into the form $$mathrm{Li}^N_{K}(z)$$
$endgroup$
– clathratus
Jan 8 at 22:20